152530 To get maximum current through a resistance of $2.5 \Omega$, one can use $m$ rows of cells, each row having $n$ cells. The internal resistance of each cell is $0.5 \Omega$. What are the values of $n$ and $m$, if the total number of cells is 45 ?

152532 When a resistor of $11 \Omega$ is connected in series with a electric cell. The current following in it is $0.5 \mathrm{~A}$. Instead when a resistor of $5 \Omega$ is connected to the same electric cell in series, the current increases by $0.4 \mathrm{~A}$. The internal resistance of the cell is

152533 The denial cell is balanced on $125 \mathrm{~cm}$ length of a potentiometer. Now, the cell is short circuited by a resistance of $2 \Omega$ and the balance is obtained at $100 \mathrm{~cm}$. The internal resistance of the denial cell is

152534 A potential difference across the terminals of a battery is $50 \mathrm{~V}$ when 11 A current is drawn and $60 \mathrm{~V}$, When 1 A current is drawn. The emf and the internal resistance of the batter are

152530 To get maximum current through a resistance of $2.5 \Omega$, one can use $m$ rows of cells, each row having $n$ cells. The internal resistance of each cell is $0.5 \Omega$. What are the values of $n$ and $m$, if the total number of cells is 45 ?

152532 When a resistor of $11 \Omega$ is connected in series with a electric cell. The current following in it is $0.5 \mathrm{~A}$. Instead when a resistor of $5 \Omega$ is connected to the same electric cell in series, the current increases by $0.4 \mathrm{~A}$. The internal resistance of the cell is

152533 The denial cell is balanced on $125 \mathrm{~cm}$ length of a potentiometer. Now, the cell is short circuited by a resistance of $2 \Omega$ and the balance is obtained at $100 \mathrm{~cm}$. The internal resistance of the denial cell is

152534 A potential difference across the terminals of a battery is $50 \mathrm{~V}$ when 11 A current is drawn and $60 \mathrm{~V}$, When 1 A current is drawn. The emf and the internal resistance of the batter are

152530 To get maximum current through a resistance of $2.5 \Omega$, one can use $m$ rows of cells, each row having $n$ cells. The internal resistance of each cell is $0.5 \Omega$. What are the values of $n$ and $m$, if the total number of cells is 45 ?

152532 When a resistor of $11 \Omega$ is connected in series with a electric cell. The current following in it is $0.5 \mathrm{~A}$. Instead when a resistor of $5 \Omega$ is connected to the same electric cell in series, the current increases by $0.4 \mathrm{~A}$. The internal resistance of the cell is

152533 The denial cell is balanced on $125 \mathrm{~cm}$ length of a potentiometer. Now, the cell is short circuited by a resistance of $2 \Omega$ and the balance is obtained at $100 \mathrm{~cm}$. The internal resistance of the denial cell is

152534 A potential difference across the terminals of a battery is $50 \mathrm{~V}$ when 11 A current is drawn and $60 \mathrm{~V}$, When 1 A current is drawn. The emf and the internal resistance of the batter are

152530 To get maximum current through a resistance of $2.5 \Omega$, one can use $m$ rows of cells, each row having $n$ cells. The internal resistance of each cell is $0.5 \Omega$. What are the values of $n$ and $m$, if the total number of cells is 45 ?

152532 When a resistor of $11 \Omega$ is connected in series with a electric cell. The current following in it is $0.5 \mathrm{~A}$. Instead when a resistor of $5 \Omega$ is connected to the same electric cell in series, the current increases by $0.4 \mathrm{~A}$. The internal resistance of the cell is

152533 The denial cell is balanced on $125 \mathrm{~cm}$ length of a potentiometer. Now, the cell is short circuited by a resistance of $2 \Omega$ and the balance is obtained at $100 \mathrm{~cm}$. The internal resistance of the denial cell is

152534 A potential difference across the terminals of a battery is $50 \mathrm{~V}$ when 11 A current is drawn and $60 \mathrm{~V}$, When 1 A current is drawn. The emf and the internal resistance of the batter are