Explanation:
A Given,
Voltage $\mathrm{V}=10 \mathrm{~V}$
Resistance $=\mathrm{R}_{1}=6 \Omega, \mathrm{R}_{2}=12 \Omega, \mathrm{R}_{3}=6 \Omega$

Resistance $\mathrm{R}_{1}$ and $\mathrm{R}_{2}$ in parallel,
So, the Resistance, $R^{\prime}=\frac{12 \times 6}{12+6}$
$=4 \Omega$
Equivalent Resistance $\mathrm{R}_{\mathrm{eq}}=4+6$
$=10 \Omega$
Current, $i=\frac{V}{R}$
$=\frac{10}{10}=1 \mathrm{~A}$
$\mathrm{V}_{\mathrm{AC}}=10 \mathrm{~V}$
$\mathrm{V}_{\mathrm{AB}}+\mathrm{V}_{\mathrm{BC}}=10$
$\therefore \quad \mathrm{V}_{\mathrm{AB}}=10-6$
$=4 \mathrm{~V}$