149612 A bowl filled with very hot soup cools from $98^{\circ} \mathrm{C}$ to $86^{\circ} \mathrm{C}$ in 2 minute when the room temperature is $22^{\circ} \mathrm{C}$.
How long it will take to cool from $75^{\circ} \mathrm{C}$ to $69^{\circ} \mathrm{C}$ ?

149613 Hot water cools from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in the first $10 \mathrm{~min}$ and to $42^{\circ} \mathrm{C}$ in the next $10 \mathrm{~min}$. Then the temperature of the surrounding is:

149614 The rate of loss of heat of a body is directly proportional to the difference of temperature of the body and the surroundings. This statement is known as

149616 A liquid cools from $70^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in 5 minutes. Find the time taken by the liquid to cool from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$, if the temperature of the surrounding is constant at $30^{\circ} \mathrm{C}$.

149617 A body cools from $100^{\circ} \mathrm{C}$ to $70^{\circ} \mathrm{C}$ in $8 \mathrm{~s}$. if the room temperature is $15^{\circ} \mathrm{C}$ and assuming Newton's law of cooling holds goods, then time required for the body to cool from $70^{0} \mathrm{C}$ to $40^{\circ} \mathrm{C}$ is

149612 A bowl filled with very hot soup cools from $98^{\circ} \mathrm{C}$ to $86^{\circ} \mathrm{C}$ in 2 minute when the room temperature is $22^{\circ} \mathrm{C}$.
How long it will take to cool from $75^{\circ} \mathrm{C}$ to $69^{\circ} \mathrm{C}$ ?

149613 Hot water cools from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in the first $10 \mathrm{~min}$ and to $42^{\circ} \mathrm{C}$ in the next $10 \mathrm{~min}$. Then the temperature of the surrounding is:

149614 The rate of loss of heat of a body is directly proportional to the difference of temperature of the body and the surroundings. This statement is known as

149616 A liquid cools from $70^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in 5 minutes. Find the time taken by the liquid to cool from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$, if the temperature of the surrounding is constant at $30^{\circ} \mathrm{C}$.

149617 A body cools from $100^{\circ} \mathrm{C}$ to $70^{\circ} \mathrm{C}$ in $8 \mathrm{~s}$. if the room temperature is $15^{\circ} \mathrm{C}$ and assuming Newton's law of cooling holds goods, then time required for the body to cool from $70^{0} \mathrm{C}$ to $40^{\circ} \mathrm{C}$ is

149612 A bowl filled with very hot soup cools from $98^{\circ} \mathrm{C}$ to $86^{\circ} \mathrm{C}$ in 2 minute when the room temperature is $22^{\circ} \mathrm{C}$.
How long it will take to cool from $75^{\circ} \mathrm{C}$ to $69^{\circ} \mathrm{C}$ ?

149613 Hot water cools from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in the first $10 \mathrm{~min}$ and to $42^{\circ} \mathrm{C}$ in the next $10 \mathrm{~min}$. Then the temperature of the surrounding is:

149614 The rate of loss of heat of a body is directly proportional to the difference of temperature of the body and the surroundings. This statement is known as

149616 A liquid cools from $70^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in 5 minutes. Find the time taken by the liquid to cool from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$, if the temperature of the surrounding is constant at $30^{\circ} \mathrm{C}$.

149617 A body cools from $100^{\circ} \mathrm{C}$ to $70^{\circ} \mathrm{C}$ in $8 \mathrm{~s}$. if the room temperature is $15^{\circ} \mathrm{C}$ and assuming Newton's law of cooling holds goods, then time required for the body to cool from $70^{0} \mathrm{C}$ to $40^{\circ} \mathrm{C}$ is

149612 A bowl filled with very hot soup cools from $98^{\circ} \mathrm{C}$ to $86^{\circ} \mathrm{C}$ in 2 minute when the room temperature is $22^{\circ} \mathrm{C}$.
How long it will take to cool from $75^{\circ} \mathrm{C}$ to $69^{\circ} \mathrm{C}$ ?

149613 Hot water cools from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in the first $10 \mathrm{~min}$ and to $42^{\circ} \mathrm{C}$ in the next $10 \mathrm{~min}$. Then the temperature of the surrounding is:

149614 The rate of loss of heat of a body is directly proportional to the difference of temperature of the body and the surroundings. This statement is known as

149616 A liquid cools from $70^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in 5 minutes. Find the time taken by the liquid to cool from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$, if the temperature of the surrounding is constant at $30^{\circ} \mathrm{C}$.

149617 A body cools from $100^{\circ} \mathrm{C}$ to $70^{\circ} \mathrm{C}$ in $8 \mathrm{~s}$. if the room temperature is $15^{\circ} \mathrm{C}$ and assuming Newton's law of cooling holds goods, then time required for the body to cool from $70^{0} \mathrm{C}$ to $40^{\circ} \mathrm{C}$ is

149612 A bowl filled with very hot soup cools from $98^{\circ} \mathrm{C}$ to $86^{\circ} \mathrm{C}$ in 2 minute when the room temperature is $22^{\circ} \mathrm{C}$.
How long it will take to cool from $75^{\circ} \mathrm{C}$ to $69^{\circ} \mathrm{C}$ ?

149613 Hot water cools from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in the first $10 \mathrm{~min}$ and to $42^{\circ} \mathrm{C}$ in the next $10 \mathrm{~min}$. Then the temperature of the surrounding is:

149614 The rate of loss of heat of a body is directly proportional to the difference of temperature of the body and the surroundings. This statement is known as

149616 A liquid cools from $70^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in 5 minutes. Find the time taken by the liquid to cool from $60^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$, if the temperature of the surrounding is constant at $30^{\circ} \mathrm{C}$.

149617 A body cools from $100^{\circ} \mathrm{C}$ to $70^{\circ} \mathrm{C}$ in $8 \mathrm{~s}$. if the room temperature is $15^{\circ} \mathrm{C}$ and assuming Newton's law of cooling holds goods, then time required for the body to cool from $70^{0} \mathrm{C}$ to $40^{\circ} \mathrm{C}$ is