09. Heat Engine, Carnot’s Cycle and Refrigeration (COP)
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Thermodynamics

148577 A Carnot engine works between $27^{\circ} \mathrm{C}$ and $127^{\circ} \mathrm{C}$. Heat supplied by the source is $500 \mathrm{~J}$. Then heat ejected to the sink is:

1 $1000 \mathrm{~J}$
2 $667 \mathrm{~J}$
3 $375 \mathrm{~J}$
4 $500 \mathrm{~J}$
AIIMS-25.05.2019(E) Shift-2
Thermodynamics

148578 For a refrigerator, heat absorbed from source is $800 \mathrm{~J}$ and heat supplied to sink is $500 \mathrm{~J}$ then find coefficient of performance.

1 $\frac{5}{8}$
2 $\frac{8}{5}$
3 $\frac{5}{3}$
4 $\frac{3}{5}$
AIIMS-25.05.2019(E) Shift-2
Thermodynamics

148579 Carnot engine efficiency is equal to $1 / 7$. If the temperature of the sink is reduced by $65 \mathrm{~K}$, the efficiency becomes $1 / 4$. The temperature of source and the sink in the first case are respectively.

1 $610 \mathrm{~K}, 520 \mathrm{~K}$
2 $520 \mathrm{~K}, 606.67 \mathrm{~K}$
3 $606.67 \mathrm{~K}, 520 \mathrm{~K}$
4 $520 \mathrm{~K}, 610 \mathrm{~K}$
BCECE-2016
Thermodynamics

148580 In a Carnot engine, the temperature of reservoir is $927^{\circ} \mathrm{C}$ and that of sink is $127^{\circ} \mathrm{C}$. If the work done by the engine when it transfer heat from reservoir to sink is $12.6 \times 10^{6} \mathrm{~J}$. The quantity of heat absorbed by the engine from the reservoir is-

1 $18.9 \times 10^{6} \mathrm{~J}$
2 $20.5 \times 10^{6} \mathrm{~J}$
3 $15.7 \times 10^{6} \mathrm{~J}$
4 $12.6 \times 10^{6} \mathrm{~J}$
BCECE-2018
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Thermodynamics

148577 A Carnot engine works between $27^{\circ} \mathrm{C}$ and $127^{\circ} \mathrm{C}$. Heat supplied by the source is $500 \mathrm{~J}$. Then heat ejected to the sink is:

1 $1000 \mathrm{~J}$
2 $667 \mathrm{~J}$
3 $375 \mathrm{~J}$
4 $500 \mathrm{~J}$
AIIMS-25.05.2019(E) Shift-2
Thermodynamics

148578 For a refrigerator, heat absorbed from source is $800 \mathrm{~J}$ and heat supplied to sink is $500 \mathrm{~J}$ then find coefficient of performance.

1 $\frac{5}{8}$
2 $\frac{8}{5}$
3 $\frac{5}{3}$
4 $\frac{3}{5}$
AIIMS-25.05.2019(E) Shift-2
Thermodynamics

148579 Carnot engine efficiency is equal to $1 / 7$. If the temperature of the sink is reduced by $65 \mathrm{~K}$, the efficiency becomes $1 / 4$. The temperature of source and the sink in the first case are respectively.

1 $610 \mathrm{~K}, 520 \mathrm{~K}$
2 $520 \mathrm{~K}, 606.67 \mathrm{~K}$
3 $606.67 \mathrm{~K}, 520 \mathrm{~K}$
4 $520 \mathrm{~K}, 610 \mathrm{~K}$
BCECE-2016
Thermodynamics

148580 In a Carnot engine, the temperature of reservoir is $927^{\circ} \mathrm{C}$ and that of sink is $127^{\circ} \mathrm{C}$. If the work done by the engine when it transfer heat from reservoir to sink is $12.6 \times 10^{6} \mathrm{~J}$. The quantity of heat absorbed by the engine from the reservoir is-

1 $18.9 \times 10^{6} \mathrm{~J}$
2 $20.5 \times 10^{6} \mathrm{~J}$
3 $15.7 \times 10^{6} \mathrm{~J}$
4 $12.6 \times 10^{6} \mathrm{~J}$
BCECE-2018
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Thermodynamics

148577 A Carnot engine works between $27^{\circ} \mathrm{C}$ and $127^{\circ} \mathrm{C}$. Heat supplied by the source is $500 \mathrm{~J}$. Then heat ejected to the sink is:

1 $1000 \mathrm{~J}$
2 $667 \mathrm{~J}$
3 $375 \mathrm{~J}$
4 $500 \mathrm{~J}$
AIIMS-25.05.2019(E) Shift-2
Thermodynamics

148578 For a refrigerator, heat absorbed from source is $800 \mathrm{~J}$ and heat supplied to sink is $500 \mathrm{~J}$ then find coefficient of performance.

1 $\frac{5}{8}$
2 $\frac{8}{5}$
3 $\frac{5}{3}$
4 $\frac{3}{5}$
AIIMS-25.05.2019(E) Shift-2
Thermodynamics

148579 Carnot engine efficiency is equal to $1 / 7$. If the temperature of the sink is reduced by $65 \mathrm{~K}$, the efficiency becomes $1 / 4$. The temperature of source and the sink in the first case are respectively.

1 $610 \mathrm{~K}, 520 \mathrm{~K}$
2 $520 \mathrm{~K}, 606.67 \mathrm{~K}$
3 $606.67 \mathrm{~K}, 520 \mathrm{~K}$
4 $520 \mathrm{~K}, 610 \mathrm{~K}$
BCECE-2016
Thermodynamics

148580 In a Carnot engine, the temperature of reservoir is $927^{\circ} \mathrm{C}$ and that of sink is $127^{\circ} \mathrm{C}$. If the work done by the engine when it transfer heat from reservoir to sink is $12.6 \times 10^{6} \mathrm{~J}$. The quantity of heat absorbed by the engine from the reservoir is-

1 $18.9 \times 10^{6} \mathrm{~J}$
2 $20.5 \times 10^{6} \mathrm{~J}$
3 $15.7 \times 10^{6} \mathrm{~J}$
4 $12.6 \times 10^{6} \mathrm{~J}$
BCECE-2018
For More Updates join with Us
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Thermodynamics

148577 A Carnot engine works between $27^{\circ} \mathrm{C}$ and $127^{\circ} \mathrm{C}$. Heat supplied by the source is $500 \mathrm{~J}$. Then heat ejected to the sink is:

1 $1000 \mathrm{~J}$
2 $667 \mathrm{~J}$
3 $375 \mathrm{~J}$
4 $500 \mathrm{~J}$
AIIMS-25.05.2019(E) Shift-2
Thermodynamics

148578 For a refrigerator, heat absorbed from source is $800 \mathrm{~J}$ and heat supplied to sink is $500 \mathrm{~J}$ then find coefficient of performance.

1 $\frac{5}{8}$
2 $\frac{8}{5}$
3 $\frac{5}{3}$
4 $\frac{3}{5}$
AIIMS-25.05.2019(E) Shift-2
Thermodynamics

148579 Carnot engine efficiency is equal to $1 / 7$. If the temperature of the sink is reduced by $65 \mathrm{~K}$, the efficiency becomes $1 / 4$. The temperature of source and the sink in the first case are respectively.

1 $610 \mathrm{~K}, 520 \mathrm{~K}$
2 $520 \mathrm{~K}, 606.67 \mathrm{~K}$
3 $606.67 \mathrm{~K}, 520 \mathrm{~K}$
4 $520 \mathrm{~K}, 610 \mathrm{~K}$
BCECE-2016
Thermodynamics

148580 In a Carnot engine, the temperature of reservoir is $927^{\circ} \mathrm{C}$ and that of sink is $127^{\circ} \mathrm{C}$. If the work done by the engine when it transfer heat from reservoir to sink is $12.6 \times 10^{6} \mathrm{~J}$. The quantity of heat absorbed by the engine from the reservoir is-

1 $18.9 \times 10^{6} \mathrm{~J}$
2 $20.5 \times 10^{6} \mathrm{~J}$
3 $15.7 \times 10^{6} \mathrm{~J}$
4 $12.6 \times 10^{6} \mathrm{~J}$
BCECE-2018