148138 When a system is taken from state $\mathrm{i}$ to a state $f$ along path iaf, $\mathbf{Q}=50 \mathrm{~J}$ and $\mathrm{W}=20 \mathrm{~J}$. Along path $\operatorname{ib} f, Q=35 \mathrm{~J}$. If $\mathrm{W}=-13 \mathrm{~J}$ for the curved return path $f \mathrm{Q}$ for this path is

148139 If $C_{P}$ and $C_{V}$ are molar heats at constant pressure and constant volume respectively and $R$ is gas constant for 1 mole, then the correct relation is

148141 Match the columns for the first law of thermodynamics.
A) Adiabatic processes - I) $\mathrm{W} \neq 0, \Delta \mathrm{E}_{\text {int }} \neq \mathrm{Q}$
B) Constant - Volume - II) $\mathrm{Q}=\mathrm{W} ; \Delta \mathrm{E}_{\text {int }}=0$ processes
C) Isothermal processes - III) $\mathrm{Q}=0 ; \Delta \mathrm{E}_{\text {int }}=-\mathrm{W}$
D) Constant-pressure - IV) $\mathrm{W}=0 ; \Delta \mathrm{E}_{\text {int }}=\mathrm{Q}$ processes
(W-Work done, $\mathrm{Q}$ - heat absorbed, $\Delta \mathrm{E}_{\text {int }}-$ change of internal energy)
The correct match is

148146 In a thermodynamic process the pressure of a fixed mass of a gas is changed in such a manner that the gas released 30 joules of heat and 18 joules of work was done on the gas. If the initial internal energy of the gas was 60 joules, the final internal energy will be:

148138 When a system is taken from state $\mathrm{i}$ to a state $f$ along path iaf, $\mathbf{Q}=50 \mathrm{~J}$ and $\mathrm{W}=20 \mathrm{~J}$. Along path $\operatorname{ib} f, Q=35 \mathrm{~J}$. If $\mathrm{W}=-13 \mathrm{~J}$ for the curved return path $f \mathrm{Q}$ for this path is

148139 If $C_{P}$ and $C_{V}$ are molar heats at constant pressure and constant volume respectively and $R$ is gas constant for 1 mole, then the correct relation is

148141 Match the columns for the first law of thermodynamics.
A) Adiabatic processes - I) $\mathrm{W} \neq 0, \Delta \mathrm{E}_{\text {int }} \neq \mathrm{Q}$
B) Constant - Volume - II) $\mathrm{Q}=\mathrm{W} ; \Delta \mathrm{E}_{\text {int }}=0$ processes
C) Isothermal processes - III) $\mathrm{Q}=0 ; \Delta \mathrm{E}_{\text {int }}=-\mathrm{W}$
D) Constant-pressure - IV) $\mathrm{W}=0 ; \Delta \mathrm{E}_{\text {int }}=\mathrm{Q}$ processes
(W-Work done, $\mathrm{Q}$ - heat absorbed, $\Delta \mathrm{E}_{\text {int }}-$ change of internal energy)
The correct match is

148146 In a thermodynamic process the pressure of a fixed mass of a gas is changed in such a manner that the gas released 30 joules of heat and 18 joules of work was done on the gas. If the initial internal energy of the gas was 60 joules, the final internal energy will be:

148138 When a system is taken from state $\mathrm{i}$ to a state $f$ along path iaf, $\mathbf{Q}=50 \mathrm{~J}$ and $\mathrm{W}=20 \mathrm{~J}$. Along path $\operatorname{ib} f, Q=35 \mathrm{~J}$. If $\mathrm{W}=-13 \mathrm{~J}$ for the curved return path $f \mathrm{Q}$ for this path is

148139 If $C_{P}$ and $C_{V}$ are molar heats at constant pressure and constant volume respectively and $R$ is gas constant for 1 mole, then the correct relation is

148141 Match the columns for the first law of thermodynamics.
A) Adiabatic processes - I) $\mathrm{W} \neq 0, \Delta \mathrm{E}_{\text {int }} \neq \mathrm{Q}$
B) Constant - Volume - II) $\mathrm{Q}=\mathrm{W} ; \Delta \mathrm{E}_{\text {int }}=0$ processes
C) Isothermal processes - III) $\mathrm{Q}=0 ; \Delta \mathrm{E}_{\text {int }}=-\mathrm{W}$
D) Constant-pressure - IV) $\mathrm{W}=0 ; \Delta \mathrm{E}_{\text {int }}=\mathrm{Q}$ processes
(W-Work done, $\mathrm{Q}$ - heat absorbed, $\Delta \mathrm{E}_{\text {int }}-$ change of internal energy)
The correct match is

148146 In a thermodynamic process the pressure of a fixed mass of a gas is changed in such a manner that the gas released 30 joules of heat and 18 joules of work was done on the gas. If the initial internal energy of the gas was 60 joules, the final internal energy will be:

148138 When a system is taken from state $\mathrm{i}$ to a state $f$ along path iaf, $\mathbf{Q}=50 \mathrm{~J}$ and $\mathrm{W}=20 \mathrm{~J}$. Along path $\operatorname{ib} f, Q=35 \mathrm{~J}$. If $\mathrm{W}=-13 \mathrm{~J}$ for the curved return path $f \mathrm{Q}$ for this path is

148139 If $C_{P}$ and $C_{V}$ are molar heats at constant pressure and constant volume respectively and $R$ is gas constant for 1 mole, then the correct relation is

148141 Match the columns for the first law of thermodynamics.
A) Adiabatic processes - I) $\mathrm{W} \neq 0, \Delta \mathrm{E}_{\text {int }} \neq \mathrm{Q}$
B) Constant - Volume - II) $\mathrm{Q}=\mathrm{W} ; \Delta \mathrm{E}_{\text {int }}=0$ processes
C) Isothermal processes - III) $\mathrm{Q}=0 ; \Delta \mathrm{E}_{\text {int }}=-\mathrm{W}$
D) Constant-pressure - IV) $\mathrm{W}=0 ; \Delta \mathrm{E}_{\text {int }}=\mathrm{Q}$ processes
(W-Work done, $\mathrm{Q}$ - heat absorbed, $\Delta \mathrm{E}_{\text {int }}-$ change of internal energy)
The correct match is

148146 In a thermodynamic process the pressure of a fixed mass of a gas is changed in such a manner that the gas released 30 joules of heat and 18 joules of work was done on the gas. If the initial internal energy of the gas was 60 joules, the final internal energy will be: