146484 Steam at $100^{\circ} \mathrm{C}$ is passed into $20 \mathrm{~g}$ of water at $10^{\circ} \mathrm{C}$. When water acquires a temperature of $80^{\circ} \mathrm{C}$, the mass of water present will be [Take specific heat of water $=1 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}$ and latent heat of steam $=540 \mathrm{cal} \mathrm{g}^{-1}$ ]

146486 A Centigrade and a Fahrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers $140^{\circ}$.What is the fall in temperature as registered by the Centigrade thermometer?

146487 The quantities of heat required to raise the temperature of two solid copper spheres of radii $r_{1}$ and $r_{2}\left(r_{1}=1.5 r_{2}\right)$ through $1 K$ are in the ratio

146488 On a new scale of temperature (which is linear) and called the $\mathrm{W}$ scale, the freezing and boiling points of water are $39^{\circ} \mathrm{W}$ and $239^{\circ} \mathrm{W}$ respectively. What will be the temperature on the new scale, corresponding to a temperature of $39^{\circ} \mathrm{C}$ on the celsius scale ?

146484 Steam at $100^{\circ} \mathrm{C}$ is passed into $20 \mathrm{~g}$ of water at $10^{\circ} \mathrm{C}$. When water acquires a temperature of $80^{\circ} \mathrm{C}$, the mass of water present will be [Take specific heat of water $=1 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}$ and latent heat of steam $=540 \mathrm{cal} \mathrm{g}^{-1}$ ]

146486 A Centigrade and a Fahrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers $140^{\circ}$.What is the fall in temperature as registered by the Centigrade thermometer?

146487 The quantities of heat required to raise the temperature of two solid copper spheres of radii $r_{1}$ and $r_{2}\left(r_{1}=1.5 r_{2}\right)$ through $1 K$ are in the ratio

146488 On a new scale of temperature (which is linear) and called the $\mathrm{W}$ scale, the freezing and boiling points of water are $39^{\circ} \mathrm{W}$ and $239^{\circ} \mathrm{W}$ respectively. What will be the temperature on the new scale, corresponding to a temperature of $39^{\circ} \mathrm{C}$ on the celsius scale ?

146484 Steam at $100^{\circ} \mathrm{C}$ is passed into $20 \mathrm{~g}$ of water at $10^{\circ} \mathrm{C}$. When water acquires a temperature of $80^{\circ} \mathrm{C}$, the mass of water present will be [Take specific heat of water $=1 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}$ and latent heat of steam $=540 \mathrm{cal} \mathrm{g}^{-1}$ ]

146486 A Centigrade and a Fahrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers $140^{\circ}$.What is the fall in temperature as registered by the Centigrade thermometer?

146487 The quantities of heat required to raise the temperature of two solid copper spheres of radii $r_{1}$ and $r_{2}\left(r_{1}=1.5 r_{2}\right)$ through $1 K$ are in the ratio

146488 On a new scale of temperature (which is linear) and called the $\mathrm{W}$ scale, the freezing and boiling points of water are $39^{\circ} \mathrm{W}$ and $239^{\circ} \mathrm{W}$ respectively. What will be the temperature on the new scale, corresponding to a temperature of $39^{\circ} \mathrm{C}$ on the celsius scale ?

146484 Steam at $100^{\circ} \mathrm{C}$ is passed into $20 \mathrm{~g}$ of water at $10^{\circ} \mathrm{C}$. When water acquires a temperature of $80^{\circ} \mathrm{C}$, the mass of water present will be [Take specific heat of water $=1 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}$ and latent heat of steam $=540 \mathrm{cal} \mathrm{g}^{-1}$ ]

146486 A Centigrade and a Fahrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers $140^{\circ}$.What is the fall in temperature as registered by the Centigrade thermometer?

146487 The quantities of heat required to raise the temperature of two solid copper spheres of radii $r_{1}$ and $r_{2}\left(r_{1}=1.5 r_{2}\right)$ through $1 K$ are in the ratio

146488 On a new scale of temperature (which is linear) and called the $\mathrm{W}$ scale, the freezing and boiling points of water are $39^{\circ} \mathrm{W}$ and $239^{\circ} \mathrm{W}$ respectively. What will be the temperature on the new scale, corresponding to a temperature of $39^{\circ} \mathrm{C}$ on the celsius scale ?