141039 A fluid of volume $1 \mathrm{~L}$ is subjected to a pressure change $1.0 \times 10^{7} \mathrm{~N} / \mathrm{m}^{2}$. As a result its volume change by $0.4 \mathrm{~cm}^{3}$. The Bulk modulus of the fluid is

141040 Temperature of a gas is $20^{\circ} \mathrm{C}$ and pressure is changed from $1.01 \times 10^{5} \mathrm{~Pa}$ to $1.165 \times 10^{5} \mathrm{~Pa}$. If volume is decreased isothermally by $10 \%$. Bulk modulus of gas is

141041 Young's modulus of rubber is $10^{4} \mathrm{~N} / \mathrm{m}^{2}$ and area of cross-section is $2 \mathrm{~cm}^{2}$. If force of $2 \times 10^{5}$ dyne is applied along its length, then its final length becomes

141042 In the shown figure, length of the rod is $L$, area of cross-section A, Young's modulus of the material of the rod is $Y$. Then, $B$ and $A$ is subjected to a tensile force $F_{A}$ while force applied at end $B, F_{B}$ is lesser than $F_{A}$. Total change in length of the rod will be

141043 Given $\sigma$ is the compressibility of water, $\rho$ is the density of water and $k$ is the bulk modulus of water. What is the energy density of water at the bottom of a lake $h$ meter deep?

141039 A fluid of volume $1 \mathrm{~L}$ is subjected to a pressure change $1.0 \times 10^{7} \mathrm{~N} / \mathrm{m}^{2}$. As a result its volume change by $0.4 \mathrm{~cm}^{3}$. The Bulk modulus of the fluid is

141040 Temperature of a gas is $20^{\circ} \mathrm{C}$ and pressure is changed from $1.01 \times 10^{5} \mathrm{~Pa}$ to $1.165 \times 10^{5} \mathrm{~Pa}$. If volume is decreased isothermally by $10 \%$. Bulk modulus of gas is

141041 Young's modulus of rubber is $10^{4} \mathrm{~N} / \mathrm{m}^{2}$ and area of cross-section is $2 \mathrm{~cm}^{2}$. If force of $2 \times 10^{5}$ dyne is applied along its length, then its final length becomes

141042 In the shown figure, length of the rod is $L$, area of cross-section A, Young's modulus of the material of the rod is $Y$. Then, $B$ and $A$ is subjected to a tensile force $F_{A}$ while force applied at end $B, F_{B}$ is lesser than $F_{A}$. Total change in length of the rod will be

141043 Given $\sigma$ is the compressibility of water, $\rho$ is the density of water and $k$ is the bulk modulus of water. What is the energy density of water at the bottom of a lake $h$ meter deep?

141039 A fluid of volume $1 \mathrm{~L}$ is subjected to a pressure change $1.0 \times 10^{7} \mathrm{~N} / \mathrm{m}^{2}$. As a result its volume change by $0.4 \mathrm{~cm}^{3}$. The Bulk modulus of the fluid is

141040 Temperature of a gas is $20^{\circ} \mathrm{C}$ and pressure is changed from $1.01 \times 10^{5} \mathrm{~Pa}$ to $1.165 \times 10^{5} \mathrm{~Pa}$. If volume is decreased isothermally by $10 \%$. Bulk modulus of gas is

141041 Young's modulus of rubber is $10^{4} \mathrm{~N} / \mathrm{m}^{2}$ and area of cross-section is $2 \mathrm{~cm}^{2}$. If force of $2 \times 10^{5}$ dyne is applied along its length, then its final length becomes

141042 In the shown figure, length of the rod is $L$, area of cross-section A, Young's modulus of the material of the rod is $Y$. Then, $B$ and $A$ is subjected to a tensile force $F_{A}$ while force applied at end $B, F_{B}$ is lesser than $F_{A}$. Total change in length of the rod will be

141043 Given $\sigma$ is the compressibility of water, $\rho$ is the density of water and $k$ is the bulk modulus of water. What is the energy density of water at the bottom of a lake $h$ meter deep?

141039 A fluid of volume $1 \mathrm{~L}$ is subjected to a pressure change $1.0 \times 10^{7} \mathrm{~N} / \mathrm{m}^{2}$. As a result its volume change by $0.4 \mathrm{~cm}^{3}$. The Bulk modulus of the fluid is

141040 Temperature of a gas is $20^{\circ} \mathrm{C}$ and pressure is changed from $1.01 \times 10^{5} \mathrm{~Pa}$ to $1.165 \times 10^{5} \mathrm{~Pa}$. If volume is decreased isothermally by $10 \%$. Bulk modulus of gas is

141041 Young's modulus of rubber is $10^{4} \mathrm{~N} / \mathrm{m}^{2}$ and area of cross-section is $2 \mathrm{~cm}^{2}$. If force of $2 \times 10^{5}$ dyne is applied along its length, then its final length becomes

141042 In the shown figure, length of the rod is $L$, area of cross-section A, Young's modulus of the material of the rod is $Y$. Then, $B$ and $A$ is subjected to a tensile force $F_{A}$ while force applied at end $B, F_{B}$ is lesser than $F_{A}$. Total change in length of the rod will be

141043 Given $\sigma$ is the compressibility of water, $\rho$ is the density of water and $k$ is the bulk modulus of water. What is the energy density of water at the bottom of a lake $h$ meter deep?

141039 A fluid of volume $1 \mathrm{~L}$ is subjected to a pressure change $1.0 \times 10^{7} \mathrm{~N} / \mathrm{m}^{2}$. As a result its volume change by $0.4 \mathrm{~cm}^{3}$. The Bulk modulus of the fluid is

141040 Temperature of a gas is $20^{\circ} \mathrm{C}$ and pressure is changed from $1.01 \times 10^{5} \mathrm{~Pa}$ to $1.165 \times 10^{5} \mathrm{~Pa}$. If volume is decreased isothermally by $10 \%$. Bulk modulus of gas is

141041 Young's modulus of rubber is $10^{4} \mathrm{~N} / \mathrm{m}^{2}$ and area of cross-section is $2 \mathrm{~cm}^{2}$. If force of $2 \times 10^{5}$ dyne is applied along its length, then its final length becomes

141042 In the shown figure, length of the rod is $L$, area of cross-section A, Young's modulus of the material of the rod is $Y$. Then, $B$ and $A$ is subjected to a tensile force $F_{A}$ while force applied at end $B, F_{B}$ is lesser than $F_{A}$. Total change in length of the rod will be

141043 Given $\sigma$ is the compressibility of water, $\rho$ is the density of water and $k$ is the bulk modulus of water. What is the energy density of water at the bottom of a lake $h$ meter deep?