Explanation:
C Given,
Mass of first satellite $\left(\mathrm{m}_{1}\right)=\mathrm{m}$
Mass of second satellite $\left(\mathrm{m}_{2}\right)=9 \mathrm{~m}$
And,
$\mathrm{R}_{1}=\mathrm{R}_{2}=\mathrm{R}$
We know that,
Time period of Revolution $(T)=2 \pi \sqrt{\frac{\left(R_{e}+h\right)^{3}}{g R_{e}^{2}}}$
From above $\mathrm{eq}^{\mathrm{n}}$, we can see time period is not dependent on mass of body.
Hence, Time period of revolution is-
$\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}=\frac{1}{1}$