138729 The ratio of the radii of two planets $r_{1}$ and $r_{2}$ is $k$. The ratio of acceleration due to gravity on them is $r$. Then the ratio of the escape velocities from them, will be :

138730 Assertion: Even when orbit of a satellite is elliptical, its plane of rotation passes through the centre of earth.
Reason: According to law of conservation of angular momentum, the plane of rotation of satellite always remains same.

138732 If the period of revolution of a nearest satellite around a planet of radius $R$ is $T$ then its period of revolution around another planet, having radius $3 R$ and same density will be-

138733 A satellite is moving in a circular orbit at a certain height above the earth's surface. It takes $5.26 \times 10^{3} \mathrm{~s}$ to complete one revolution with a centripetal acceleration equal to $9.32 \mathrm{~m} / \mathrm{s}^{2}$. The height of satellite orbiting above the earth is-
(Earth's radius $=6.37 \times 10^{6} \mathrm{~m}$ )

138729 The ratio of the radii of two planets $r_{1}$ and $r_{2}$ is $k$. The ratio of acceleration due to gravity on them is $r$. Then the ratio of the escape velocities from them, will be :

138730 Assertion: Even when orbit of a satellite is elliptical, its plane of rotation passes through the centre of earth.
Reason: According to law of conservation of angular momentum, the plane of rotation of satellite always remains same.

138732 If the period of revolution of a nearest satellite around a planet of radius $R$ is $T$ then its period of revolution around another planet, having radius $3 R$ and same density will be-

138733 A satellite is moving in a circular orbit at a certain height above the earth's surface. It takes $5.26 \times 10^{3} \mathrm{~s}$ to complete one revolution with a centripetal acceleration equal to $9.32 \mathrm{~m} / \mathrm{s}^{2}$. The height of satellite orbiting above the earth is-
(Earth's radius $=6.37 \times 10^{6} \mathrm{~m}$ )

138729 The ratio of the radii of two planets $r_{1}$ and $r_{2}$ is $k$. The ratio of acceleration due to gravity on them is $r$. Then the ratio of the escape velocities from them, will be :

138730 Assertion: Even when orbit of a satellite is elliptical, its plane of rotation passes through the centre of earth.
Reason: According to law of conservation of angular momentum, the plane of rotation of satellite always remains same.

138732 If the period of revolution of a nearest satellite around a planet of radius $R$ is $T$ then its period of revolution around another planet, having radius $3 R$ and same density will be-

138733 A satellite is moving in a circular orbit at a certain height above the earth's surface. It takes $5.26 \times 10^{3} \mathrm{~s}$ to complete one revolution with a centripetal acceleration equal to $9.32 \mathrm{~m} / \mathrm{s}^{2}$. The height of satellite orbiting above the earth is-
(Earth's radius $=6.37 \times 10^{6} \mathrm{~m}$ )

138729 The ratio of the radii of two planets $r_{1}$ and $r_{2}$ is $k$. The ratio of acceleration due to gravity on them is $r$. Then the ratio of the escape velocities from them, will be :

138730 Assertion: Even when orbit of a satellite is elliptical, its plane of rotation passes through the centre of earth.
Reason: According to law of conservation of angular momentum, the plane of rotation of satellite always remains same.

138732 If the period of revolution of a nearest satellite around a planet of radius $R$ is $T$ then its period of revolution around another planet, having radius $3 R$ and same density will be-

138733 A satellite is moving in a circular orbit at a certain height above the earth's surface. It takes $5.26 \times 10^{3} \mathrm{~s}$ to complete one revolution with a centripetal acceleration equal to $9.32 \mathrm{~m} / \mathrm{s}^{2}$. The height of satellite orbiting above the earth is-
(Earth's radius $=6.37 \times 10^{6} \mathrm{~m}$ )