270599
Two particles each of mass ' \(m\) ' are placed at \(A\) and \(C\) are such \(A B=B C=L\). The gravitational force on the third particle placed at \(D\) at a distance \(L\) on the perpendicular bisector of the line \(A C\) is
1 \(\frac{G m^{2}}{L^{2}}\) along \(B D\)
2 \(\frac{G m^{2}}{\sqrt{2} L^{2}}\) along \(D B\)
270542
The gravitational force between two particles of masses \(m_{1}\) and \(m_{2}\) seperated by certain distance in air medium is \(F\). If they are taken to vacuum and separated by the same distance, then the gravitational force between them will be
1 greater than\(F\)
2 less than\(F\)
3 \(F\)
4 Zero
Explanation:
Gravitational force does not depend upon the medium between the masses.
Gravitation
270543
The mass of a ball is four times the mass of another ball. When these balls are separated by a distance of \(10 \mathrm{~cm}\), the gravitational force between them is \(6.67 \times 10^{-7} \mathrm{~N}\). The masses of the two balls are ( in \(\mathrm{kg}\) )
270544
Gravitational force between two point masses \(m\) and \(M\) separated by a distance \(r\) is \(F\). Now if a point mass \(3 \mathrm{~m}\) is placed next to \(\mathrm{m}\), the force on \(M\) due to \(m\) becomes
1 \(F\)
2 \(2 \mathrm{~F}\)
3 \(3 F\)
4 \(4 \mathrm{~F}\)
Explanation:
\(F=\frac{G m_{1} m_{2}}{r^{2}} ;\) Gravitational force between two point masses is independent of the presence of other masses.
Gravitation
270545
Three uniform spheres each of mass \(m\) and diameter \(D\) are kept in such a way that each touches the other two, then magnitude of the gravitational force on any one sphere due to the other two is
1 \(\frac{3 G m^{2}}{D^{2}}\)
2 \(\frac{2 \sqrt{3} G m^{2}}{D^{2}}\)
3 \(\frac{\sqrt{3 G m^{2}}}{4 D^{2}}\)
4 \(\frac{\sqrt{3} G m^{2}}{D^{2}}\)
Explanation:
Gravitational force on one sphere due to the other two is \(F=\sqrt{F_{1}^{2}+F_{2}^{2}+2 F_{1} F_{2} \operatorname{Cos} \theta}=\sqrt{3} F_{1}\) But \(F_{1}=\frac{G m^{2}}{D^{2}} \Rightarrow F=\frac{\sqrt{3} G m^{2}}{D^{2}} \quad\left(\because F_{1}=F_{2}\right)\)
270599
Two particles each of mass ' \(m\) ' are placed at \(A\) and \(C\) are such \(A B=B C=L\). The gravitational force on the third particle placed at \(D\) at a distance \(L\) on the perpendicular bisector of the line \(A C\) is
1 \(\frac{G m^{2}}{L^{2}}\) along \(B D\)
2 \(\frac{G m^{2}}{\sqrt{2} L^{2}}\) along \(D B\)
270542
The gravitational force between two particles of masses \(m_{1}\) and \(m_{2}\) seperated by certain distance in air medium is \(F\). If they are taken to vacuum and separated by the same distance, then the gravitational force between them will be
1 greater than\(F\)
2 less than\(F\)
3 \(F\)
4 Zero
Explanation:
Gravitational force does not depend upon the medium between the masses.
Gravitation
270543
The mass of a ball is four times the mass of another ball. When these balls are separated by a distance of \(10 \mathrm{~cm}\), the gravitational force between them is \(6.67 \times 10^{-7} \mathrm{~N}\). The masses of the two balls are ( in \(\mathrm{kg}\) )
270544
Gravitational force between two point masses \(m\) and \(M\) separated by a distance \(r\) is \(F\). Now if a point mass \(3 \mathrm{~m}\) is placed next to \(\mathrm{m}\), the force on \(M\) due to \(m\) becomes
1 \(F\)
2 \(2 \mathrm{~F}\)
3 \(3 F\)
4 \(4 \mathrm{~F}\)
Explanation:
\(F=\frac{G m_{1} m_{2}}{r^{2}} ;\) Gravitational force between two point masses is independent of the presence of other masses.
Gravitation
270545
Three uniform spheres each of mass \(m\) and diameter \(D\) are kept in such a way that each touches the other two, then magnitude of the gravitational force on any one sphere due to the other two is
1 \(\frac{3 G m^{2}}{D^{2}}\)
2 \(\frac{2 \sqrt{3} G m^{2}}{D^{2}}\)
3 \(\frac{\sqrt{3 G m^{2}}}{4 D^{2}}\)
4 \(\frac{\sqrt{3} G m^{2}}{D^{2}}\)
Explanation:
Gravitational force on one sphere due to the other two is \(F=\sqrt{F_{1}^{2}+F_{2}^{2}+2 F_{1} F_{2} \operatorname{Cos} \theta}=\sqrt{3} F_{1}\) But \(F_{1}=\frac{G m^{2}}{D^{2}} \Rightarrow F=\frac{\sqrt{3} G m^{2}}{D^{2}} \quad\left(\because F_{1}=F_{2}\right)\)
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Gravitation
270599
Two particles each of mass ' \(m\) ' are placed at \(A\) and \(C\) are such \(A B=B C=L\). The gravitational force on the third particle placed at \(D\) at a distance \(L\) on the perpendicular bisector of the line \(A C\) is
1 \(\frac{G m^{2}}{L^{2}}\) along \(B D\)
2 \(\frac{G m^{2}}{\sqrt{2} L^{2}}\) along \(D B\)
270542
The gravitational force between two particles of masses \(m_{1}\) and \(m_{2}\) seperated by certain distance in air medium is \(F\). If they are taken to vacuum and separated by the same distance, then the gravitational force between them will be
1 greater than\(F\)
2 less than\(F\)
3 \(F\)
4 Zero
Explanation:
Gravitational force does not depend upon the medium between the masses.
Gravitation
270543
The mass of a ball is four times the mass of another ball. When these balls are separated by a distance of \(10 \mathrm{~cm}\), the gravitational force between them is \(6.67 \times 10^{-7} \mathrm{~N}\). The masses of the two balls are ( in \(\mathrm{kg}\) )
270544
Gravitational force between two point masses \(m\) and \(M\) separated by a distance \(r\) is \(F\). Now if a point mass \(3 \mathrm{~m}\) is placed next to \(\mathrm{m}\), the force on \(M\) due to \(m\) becomes
1 \(F\)
2 \(2 \mathrm{~F}\)
3 \(3 F\)
4 \(4 \mathrm{~F}\)
Explanation:
\(F=\frac{G m_{1} m_{2}}{r^{2}} ;\) Gravitational force between two point masses is independent of the presence of other masses.
Gravitation
270545
Three uniform spheres each of mass \(m\) and diameter \(D\) are kept in such a way that each touches the other two, then magnitude of the gravitational force on any one sphere due to the other two is
1 \(\frac{3 G m^{2}}{D^{2}}\)
2 \(\frac{2 \sqrt{3} G m^{2}}{D^{2}}\)
3 \(\frac{\sqrt{3 G m^{2}}}{4 D^{2}}\)
4 \(\frac{\sqrt{3} G m^{2}}{D^{2}}\)
Explanation:
Gravitational force on one sphere due to the other two is \(F=\sqrt{F_{1}^{2}+F_{2}^{2}+2 F_{1} F_{2} \operatorname{Cos} \theta}=\sqrt{3} F_{1}\) But \(F_{1}=\frac{G m^{2}}{D^{2}} \Rightarrow F=\frac{\sqrt{3} G m^{2}}{D^{2}} \quad\left(\because F_{1}=F_{2}\right)\)
270599
Two particles each of mass ' \(m\) ' are placed at \(A\) and \(C\) are such \(A B=B C=L\). The gravitational force on the third particle placed at \(D\) at a distance \(L\) on the perpendicular bisector of the line \(A C\) is
1 \(\frac{G m^{2}}{L^{2}}\) along \(B D\)
2 \(\frac{G m^{2}}{\sqrt{2} L^{2}}\) along \(D B\)
270542
The gravitational force between two particles of masses \(m_{1}\) and \(m_{2}\) seperated by certain distance in air medium is \(F\). If they are taken to vacuum and separated by the same distance, then the gravitational force between them will be
1 greater than\(F\)
2 less than\(F\)
3 \(F\)
4 Zero
Explanation:
Gravitational force does not depend upon the medium between the masses.
Gravitation
270543
The mass of a ball is four times the mass of another ball. When these balls are separated by a distance of \(10 \mathrm{~cm}\), the gravitational force between them is \(6.67 \times 10^{-7} \mathrm{~N}\). The masses of the two balls are ( in \(\mathrm{kg}\) )
270544
Gravitational force between two point masses \(m\) and \(M\) separated by a distance \(r\) is \(F\). Now if a point mass \(3 \mathrm{~m}\) is placed next to \(\mathrm{m}\), the force on \(M\) due to \(m\) becomes
1 \(F\)
2 \(2 \mathrm{~F}\)
3 \(3 F\)
4 \(4 \mathrm{~F}\)
Explanation:
\(F=\frac{G m_{1} m_{2}}{r^{2}} ;\) Gravitational force between two point masses is independent of the presence of other masses.
Gravitation
270545
Three uniform spheres each of mass \(m\) and diameter \(D\) are kept in such a way that each touches the other two, then magnitude of the gravitational force on any one sphere due to the other two is
1 \(\frac{3 G m^{2}}{D^{2}}\)
2 \(\frac{2 \sqrt{3} G m^{2}}{D^{2}}\)
3 \(\frac{\sqrt{3 G m^{2}}}{4 D^{2}}\)
4 \(\frac{\sqrt{3} G m^{2}}{D^{2}}\)
Explanation:
Gravitational force on one sphere due to the other two is \(F=\sqrt{F_{1}^{2}+F_{2}^{2}+2 F_{1} F_{2} \operatorname{Cos} \theta}=\sqrt{3} F_{1}\) But \(F_{1}=\frac{G m^{2}}{D^{2}} \Rightarrow F=\frac{\sqrt{3} G m^{2}}{D^{2}} \quad\left(\because F_{1}=F_{2}\right)\)
270599
Two particles each of mass ' \(m\) ' are placed at \(A\) and \(C\) are such \(A B=B C=L\). The gravitational force on the third particle placed at \(D\) at a distance \(L\) on the perpendicular bisector of the line \(A C\) is
1 \(\frac{G m^{2}}{L^{2}}\) along \(B D\)
2 \(\frac{G m^{2}}{\sqrt{2} L^{2}}\) along \(D B\)
270542
The gravitational force between two particles of masses \(m_{1}\) and \(m_{2}\) seperated by certain distance in air medium is \(F\). If they are taken to vacuum and separated by the same distance, then the gravitational force between them will be
1 greater than\(F\)
2 less than\(F\)
3 \(F\)
4 Zero
Explanation:
Gravitational force does not depend upon the medium between the masses.
Gravitation
270543
The mass of a ball is four times the mass of another ball. When these balls are separated by a distance of \(10 \mathrm{~cm}\), the gravitational force between them is \(6.67 \times 10^{-7} \mathrm{~N}\). The masses of the two balls are ( in \(\mathrm{kg}\) )
270544
Gravitational force between two point masses \(m\) and \(M\) separated by a distance \(r\) is \(F\). Now if a point mass \(3 \mathrm{~m}\) is placed next to \(\mathrm{m}\), the force on \(M\) due to \(m\) becomes
1 \(F\)
2 \(2 \mathrm{~F}\)
3 \(3 F\)
4 \(4 \mathrm{~F}\)
Explanation:
\(F=\frac{G m_{1} m_{2}}{r^{2}} ;\) Gravitational force between two point masses is independent of the presence of other masses.
Gravitation
270545
Three uniform spheres each of mass \(m\) and diameter \(D\) are kept in such a way that each touches the other two, then magnitude of the gravitational force on any one sphere due to the other two is
1 \(\frac{3 G m^{2}}{D^{2}}\)
2 \(\frac{2 \sqrt{3} G m^{2}}{D^{2}}\)
3 \(\frac{\sqrt{3 G m^{2}}}{4 D^{2}}\)
4 \(\frac{\sqrt{3} G m^{2}}{D^{2}}\)
Explanation:
Gravitational force on one sphere due to the other two is \(F=\sqrt{F_{1}^{2}+F_{2}^{2}+2 F_{1} F_{2} \operatorname{Cos} \theta}=\sqrt{3} F_{1}\) But \(F_{1}=\frac{G m^{2}}{D^{2}} \Rightarrow F=\frac{\sqrt{3} G m^{2}}{D^{2}} \quad\left(\because F_{1}=F_{2}\right)\)