NEET Test Series from KOTA - 10 Papers In MS WORD
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Gravitation
138257
Two spheres of mass $m$ and $M$ are situated in air and the gravitational force between them is 'f. The space around the masses is now filled with of specific gravity 4. The gravitational force will now be
1 $4 \mathrm{f}$
2 $f / 4$
3 $f / 16$
4 $\mathrm{f}$
Explanation:
D Let the distance between the two masses be R. Then, $\mathrm{f}=\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$ Since, gravitational force is independent of specific gravity of the surrounding medium. $\therefore$ The gravitational force will be $\mathrm{f}$.
BCECE 2013
Gravitation
138258
Two identical solid spheres each of radius $r$ and made up of the material of density $\rho$ are kept in contact with each other. The gravitational force between the two spheres will be proportional to:
1 $\rho^{2} r^{4}$
2 $\rho^{4} r^{2}$
3 $\rho^{2} r^{3}$
4 $\rho^{3} r^{2}$
Explanation:
A Mass of each sphere $M_{1}=M_{2}=\rho \cdot V=\rho \frac{4 \pi}{3} r^{3}$ Gravitational force, $F=G \frac{M_{1} M_{2}}{R^{2}}$ $\therefore$ Sphere are kept in contact each other so that the centre distance is $2 \mathrm{r}$ $F=G \frac{\rho^{2}\left(\frac{4}{3} \pi r^{3}\right)^{2}}{(2 r)^{2}}$ $F=\frac{1}{9} \pi^{2} \rho^{2} r^{4} G$ So, $\quad F \propto \rho^{2} r^{4}$
MP PET -2013
Gravitation
138262
A point mass $m$ is placed inside a spherical shell of radius $R$ and mass $M$ at a distance $R / 2$ from the centre of the shell. The gravitational force exerted by the shell on the point mass is-
1 $\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
2 $-\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
3 Zero
4 $4 \frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
Explanation:
C If a point mass is placed inside a uniform spherical shell, the gravitational force on the point mass is zero. Hence, the gravitational force exerted by the shell on the point mass is zero. $\mathrm{E}_{\text {Inside }}=0$ $\text { So, } \mathrm{F}=\mathrm{mE}_{\text {Inside }}=0$
CG PET-22.05.2022
Gravitation
138267
The weight of a body is $9.8 \mathrm{~N}$ at the place where $\mathrm{g}=9.8 \mathrm{~ms}^{-2}$. Its mass is
138257
Two spheres of mass $m$ and $M$ are situated in air and the gravitational force between them is 'f. The space around the masses is now filled with of specific gravity 4. The gravitational force will now be
1 $4 \mathrm{f}$
2 $f / 4$
3 $f / 16$
4 $\mathrm{f}$
Explanation:
D Let the distance between the two masses be R. Then, $\mathrm{f}=\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$ Since, gravitational force is independent of specific gravity of the surrounding medium. $\therefore$ The gravitational force will be $\mathrm{f}$.
BCECE 2013
Gravitation
138258
Two identical solid spheres each of radius $r$ and made up of the material of density $\rho$ are kept in contact with each other. The gravitational force between the two spheres will be proportional to:
1 $\rho^{2} r^{4}$
2 $\rho^{4} r^{2}$
3 $\rho^{2} r^{3}$
4 $\rho^{3} r^{2}$
Explanation:
A Mass of each sphere $M_{1}=M_{2}=\rho \cdot V=\rho \frac{4 \pi}{3} r^{3}$ Gravitational force, $F=G \frac{M_{1} M_{2}}{R^{2}}$ $\therefore$ Sphere are kept in contact each other so that the centre distance is $2 \mathrm{r}$ $F=G \frac{\rho^{2}\left(\frac{4}{3} \pi r^{3}\right)^{2}}{(2 r)^{2}}$ $F=\frac{1}{9} \pi^{2} \rho^{2} r^{4} G$ So, $\quad F \propto \rho^{2} r^{4}$
MP PET -2013
Gravitation
138262
A point mass $m$ is placed inside a spherical shell of radius $R$ and mass $M$ at a distance $R / 2$ from the centre of the shell. The gravitational force exerted by the shell on the point mass is-
1 $\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
2 $-\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
3 Zero
4 $4 \frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
Explanation:
C If a point mass is placed inside a uniform spherical shell, the gravitational force on the point mass is zero. Hence, the gravitational force exerted by the shell on the point mass is zero. $\mathrm{E}_{\text {Inside }}=0$ $\text { So, } \mathrm{F}=\mathrm{mE}_{\text {Inside }}=0$
CG PET-22.05.2022
Gravitation
138267
The weight of a body is $9.8 \mathrm{~N}$ at the place where $\mathrm{g}=9.8 \mathrm{~ms}^{-2}$. Its mass is
138257
Two spheres of mass $m$ and $M$ are situated in air and the gravitational force between them is 'f. The space around the masses is now filled with of specific gravity 4. The gravitational force will now be
1 $4 \mathrm{f}$
2 $f / 4$
3 $f / 16$
4 $\mathrm{f}$
Explanation:
D Let the distance between the two masses be R. Then, $\mathrm{f}=\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$ Since, gravitational force is independent of specific gravity of the surrounding medium. $\therefore$ The gravitational force will be $\mathrm{f}$.
BCECE 2013
Gravitation
138258
Two identical solid spheres each of radius $r$ and made up of the material of density $\rho$ are kept in contact with each other. The gravitational force between the two spheres will be proportional to:
1 $\rho^{2} r^{4}$
2 $\rho^{4} r^{2}$
3 $\rho^{2} r^{3}$
4 $\rho^{3} r^{2}$
Explanation:
A Mass of each sphere $M_{1}=M_{2}=\rho \cdot V=\rho \frac{4 \pi}{3} r^{3}$ Gravitational force, $F=G \frac{M_{1} M_{2}}{R^{2}}$ $\therefore$ Sphere are kept in contact each other so that the centre distance is $2 \mathrm{r}$ $F=G \frac{\rho^{2}\left(\frac{4}{3} \pi r^{3}\right)^{2}}{(2 r)^{2}}$ $F=\frac{1}{9} \pi^{2} \rho^{2} r^{4} G$ So, $\quad F \propto \rho^{2} r^{4}$
MP PET -2013
Gravitation
138262
A point mass $m$ is placed inside a spherical shell of radius $R$ and mass $M$ at a distance $R / 2$ from the centre of the shell. The gravitational force exerted by the shell on the point mass is-
1 $\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
2 $-\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
3 Zero
4 $4 \frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
Explanation:
C If a point mass is placed inside a uniform spherical shell, the gravitational force on the point mass is zero. Hence, the gravitational force exerted by the shell on the point mass is zero. $\mathrm{E}_{\text {Inside }}=0$ $\text { So, } \mathrm{F}=\mathrm{mE}_{\text {Inside }}=0$
CG PET-22.05.2022
Gravitation
138267
The weight of a body is $9.8 \mathrm{~N}$ at the place where $\mathrm{g}=9.8 \mathrm{~ms}^{-2}$. Its mass is
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Gravitation
138257
Two spheres of mass $m$ and $M$ are situated in air and the gravitational force between them is 'f. The space around the masses is now filled with of specific gravity 4. The gravitational force will now be
1 $4 \mathrm{f}$
2 $f / 4$
3 $f / 16$
4 $\mathrm{f}$
Explanation:
D Let the distance between the two masses be R. Then, $\mathrm{f}=\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$ Since, gravitational force is independent of specific gravity of the surrounding medium. $\therefore$ The gravitational force will be $\mathrm{f}$.
BCECE 2013
Gravitation
138258
Two identical solid spheres each of radius $r$ and made up of the material of density $\rho$ are kept in contact with each other. The gravitational force between the two spheres will be proportional to:
1 $\rho^{2} r^{4}$
2 $\rho^{4} r^{2}$
3 $\rho^{2} r^{3}$
4 $\rho^{3} r^{2}$
Explanation:
A Mass of each sphere $M_{1}=M_{2}=\rho \cdot V=\rho \frac{4 \pi}{3} r^{3}$ Gravitational force, $F=G \frac{M_{1} M_{2}}{R^{2}}$ $\therefore$ Sphere are kept in contact each other so that the centre distance is $2 \mathrm{r}$ $F=G \frac{\rho^{2}\left(\frac{4}{3} \pi r^{3}\right)^{2}}{(2 r)^{2}}$ $F=\frac{1}{9} \pi^{2} \rho^{2} r^{4} G$ So, $\quad F \propto \rho^{2} r^{4}$
MP PET -2013
Gravitation
138262
A point mass $m$ is placed inside a spherical shell of radius $R$ and mass $M$ at a distance $R / 2$ from the centre of the shell. The gravitational force exerted by the shell on the point mass is-
1 $\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
2 $-\frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
3 Zero
4 $4 \frac{\mathrm{GMm}}{\mathrm{R}^{2}}$
Explanation:
C If a point mass is placed inside a uniform spherical shell, the gravitational force on the point mass is zero. Hence, the gravitational force exerted by the shell on the point mass is zero. $\mathrm{E}_{\text {Inside }}=0$ $\text { So, } \mathrm{F}=\mathrm{mE}_{\text {Inside }}=0$
CG PET-22.05.2022
Gravitation
138267
The weight of a body is $9.8 \mathrm{~N}$ at the place where $\mathrm{g}=9.8 \mathrm{~ms}^{-2}$. Its mass is
