NEET Test Series from KOTA - 10 Papers In MS WORD
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Rotational Motion
150454
Which of the following is true about the angular momentum of a cylinder down a slope without slipping:
1 its magnitude changes but the direction remains same
2 both magnitude and direction change
3 only the direction change
4 neither change
Explanation:
A We know, Angular momentum \(=\mathrm{mvr}\) The direction remains always same but the magnitude of velocity changes when the cylinder rolls. Then, angular momentum's magnitude changes but the direction remain same.
AIIMS-2011
Rotational Motion
269417
A solid sphere rolls down without slipping from rest on a\(30^{\circ}\) incline. Its linear acceleration is
1 \(5 g / 7\)
2 \(5 g / 14\)
3 \(2 g / 3\)
4 \(g / 3\)
Explanation:
\(a=\frac{g \sin \theta}{1+\frac{k^{2}}{R^{2}}}\)
Rotational Motion
269416
A shaft rotating at\(3000 \mathrm{rpm}\) is transmitting a power of \(3.14 \mathrm{KW}\). The magnitude of the driving torque is
1 \(6 \mathrm{Nm}\)
2 \(10 \mathrm{Nm}\)
3 \(15 \mathrm{Nm}\)
4 \(22 \mathrm{Nm}\)
Explanation:
\(p=\pi \omega\)
Rotational Motion
269418
A hollow sphere rolls down a\(30^{\circ}\) incline of length \(6 \mathrm{~m}\) without slipping. The speed of cen tre of mass at the bottom of plane is
1 \(6 \mathrm{~ms}^{-1}\)
2 \(3 m s^{-1}\)
3 \(6 \sqrt{2} \mathrm{~ms}^{-1}\)
4 \(3 \sqrt{2} m s^{-1}\)
Explanation:
\(v=\sqrt{\frac{2 g l \sin \theta}{1+\frac{k^{2}}{R^{2}}}}\)
150454
Which of the following is true about the angular momentum of a cylinder down a slope without slipping:
1 its magnitude changes but the direction remains same
2 both magnitude and direction change
3 only the direction change
4 neither change
Explanation:
A We know, Angular momentum \(=\mathrm{mvr}\) The direction remains always same but the magnitude of velocity changes when the cylinder rolls. Then, angular momentum's magnitude changes but the direction remain same.
AIIMS-2011
Rotational Motion
269417
A solid sphere rolls down without slipping from rest on a\(30^{\circ}\) incline. Its linear acceleration is
1 \(5 g / 7\)
2 \(5 g / 14\)
3 \(2 g / 3\)
4 \(g / 3\)
Explanation:
\(a=\frac{g \sin \theta}{1+\frac{k^{2}}{R^{2}}}\)
Rotational Motion
269416
A shaft rotating at\(3000 \mathrm{rpm}\) is transmitting a power of \(3.14 \mathrm{KW}\). The magnitude of the driving torque is
1 \(6 \mathrm{Nm}\)
2 \(10 \mathrm{Nm}\)
3 \(15 \mathrm{Nm}\)
4 \(22 \mathrm{Nm}\)
Explanation:
\(p=\pi \omega\)
Rotational Motion
269418
A hollow sphere rolls down a\(30^{\circ}\) incline of length \(6 \mathrm{~m}\) without slipping. The speed of cen tre of mass at the bottom of plane is
1 \(6 \mathrm{~ms}^{-1}\)
2 \(3 m s^{-1}\)
3 \(6 \sqrt{2} \mathrm{~ms}^{-1}\)
4 \(3 \sqrt{2} m s^{-1}\)
Explanation:
\(v=\sqrt{\frac{2 g l \sin \theta}{1+\frac{k^{2}}{R^{2}}}}\)
150454
Which of the following is true about the angular momentum of a cylinder down a slope without slipping:
1 its magnitude changes but the direction remains same
2 both magnitude and direction change
3 only the direction change
4 neither change
Explanation:
A We know, Angular momentum \(=\mathrm{mvr}\) The direction remains always same but the magnitude of velocity changes when the cylinder rolls. Then, angular momentum's magnitude changes but the direction remain same.
AIIMS-2011
Rotational Motion
269417
A solid sphere rolls down without slipping from rest on a\(30^{\circ}\) incline. Its linear acceleration is
1 \(5 g / 7\)
2 \(5 g / 14\)
3 \(2 g / 3\)
4 \(g / 3\)
Explanation:
\(a=\frac{g \sin \theta}{1+\frac{k^{2}}{R^{2}}}\)
Rotational Motion
269416
A shaft rotating at\(3000 \mathrm{rpm}\) is transmitting a power of \(3.14 \mathrm{KW}\). The magnitude of the driving torque is
1 \(6 \mathrm{Nm}\)
2 \(10 \mathrm{Nm}\)
3 \(15 \mathrm{Nm}\)
4 \(22 \mathrm{Nm}\)
Explanation:
\(p=\pi \omega\)
Rotational Motion
269418
A hollow sphere rolls down a\(30^{\circ}\) incline of length \(6 \mathrm{~m}\) without slipping. The speed of cen tre of mass at the bottom of plane is
1 \(6 \mathrm{~ms}^{-1}\)
2 \(3 m s^{-1}\)
3 \(6 \sqrt{2} \mathrm{~ms}^{-1}\)
4 \(3 \sqrt{2} m s^{-1}\)
Explanation:
\(v=\sqrt{\frac{2 g l \sin \theta}{1+\frac{k^{2}}{R^{2}}}}\)
150454
Which of the following is true about the angular momentum of a cylinder down a slope without slipping:
1 its magnitude changes but the direction remains same
2 both magnitude and direction change
3 only the direction change
4 neither change
Explanation:
A We know, Angular momentum \(=\mathrm{mvr}\) The direction remains always same but the magnitude of velocity changes when the cylinder rolls. Then, angular momentum's magnitude changes but the direction remain same.
AIIMS-2011
Rotational Motion
269417
A solid sphere rolls down without slipping from rest on a\(30^{\circ}\) incline. Its linear acceleration is
1 \(5 g / 7\)
2 \(5 g / 14\)
3 \(2 g / 3\)
4 \(g / 3\)
Explanation:
\(a=\frac{g \sin \theta}{1+\frac{k^{2}}{R^{2}}}\)
Rotational Motion
269416
A shaft rotating at\(3000 \mathrm{rpm}\) is transmitting a power of \(3.14 \mathrm{KW}\). The magnitude of the driving torque is
1 \(6 \mathrm{Nm}\)
2 \(10 \mathrm{Nm}\)
3 \(15 \mathrm{Nm}\)
4 \(22 \mathrm{Nm}\)
Explanation:
\(p=\pi \omega\)
Rotational Motion
269418
A hollow sphere rolls down a\(30^{\circ}\) incline of length \(6 \mathrm{~m}\) without slipping. The speed of cen tre of mass at the bottom of plane is
1 \(6 \mathrm{~ms}^{-1}\)
2 \(3 m s^{-1}\)
3 \(6 \sqrt{2} \mathrm{~ms}^{-1}\)
4 \(3 \sqrt{2} m s^{-1}\)
Explanation:
\(v=\sqrt{\frac{2 g l \sin \theta}{1+\frac{k^{2}}{R^{2}}}}\)
