150296 A ball of radius \(\mathrm{R}\) rolls without slipping. Find the fraction of total energy associated with its rotational energy, if the radius of the gyration of the ball about an axis passing through its centre of mass is \(K\).

150297 A sphere is rolling on a horizontal surface without slipping. The ratio of the rotational K.E. to the total kinetic energy of the sphere is

150298 The moment of inertia of a body about a given axis is \(1.2 \mathrm{~kg} \mathrm{~m}^{2}\). Initially the body is at rest. In order to produce a rotational kinetic energy of \(1500 \mathrm{~J}\), an angular acceleration of \(25 \mathrm{rad} / \mathrm{s}^{2}\) must be applied about that axis for a duration of-

150299 The angular momentum of a wheel having a rotational inertia of \(0.2 \mathrm{~kg} \mathrm{~m}^{2}\) about its symmetric axis decreases from 4 to \(2 \mathrm{~kg} \mathrm{~m}^{2} \mathrm{~s}^{-1}\) in 4s. The average power of the wheel is

150300 A circular disc of weight \(500 \mathrm{~N}\) and of radius 1 \(m\) is started from rest by a constant horizontal force of \(25 \mathrm{~N}\) applied tangentially to the disc. The kinetic energy of the disc after time \(t=2\) [Acceleration due to gravity \(=\mathbf{1 0} \mathbf{~ m s}^{-2}\) ]

150296 A ball of radius \(\mathrm{R}\) rolls without slipping. Find the fraction of total energy associated with its rotational energy, if the radius of the gyration of the ball about an axis passing through its centre of mass is \(K\).

150297 A sphere is rolling on a horizontal surface without slipping. The ratio of the rotational K.E. to the total kinetic energy of the sphere is

150298 The moment of inertia of a body about a given axis is \(1.2 \mathrm{~kg} \mathrm{~m}^{2}\). Initially the body is at rest. In order to produce a rotational kinetic energy of \(1500 \mathrm{~J}\), an angular acceleration of \(25 \mathrm{rad} / \mathrm{s}^{2}\) must be applied about that axis for a duration of-

150299 The angular momentum of a wheel having a rotational inertia of \(0.2 \mathrm{~kg} \mathrm{~m}^{2}\) about its symmetric axis decreases from 4 to \(2 \mathrm{~kg} \mathrm{~m}^{2} \mathrm{~s}^{-1}\) in 4s. The average power of the wheel is

150300 A circular disc of weight \(500 \mathrm{~N}\) and of radius 1 \(m\) is started from rest by a constant horizontal force of \(25 \mathrm{~N}\) applied tangentially to the disc. The kinetic energy of the disc after time \(t=2\) [Acceleration due to gravity \(=\mathbf{1 0} \mathbf{~ m s}^{-2}\) ]

150296 A ball of radius \(\mathrm{R}\) rolls without slipping. Find the fraction of total energy associated with its rotational energy, if the radius of the gyration of the ball about an axis passing through its centre of mass is \(K\).

150297 A sphere is rolling on a horizontal surface without slipping. The ratio of the rotational K.E. to the total kinetic energy of the sphere is

150298 The moment of inertia of a body about a given axis is \(1.2 \mathrm{~kg} \mathrm{~m}^{2}\). Initially the body is at rest. In order to produce a rotational kinetic energy of \(1500 \mathrm{~J}\), an angular acceleration of \(25 \mathrm{rad} / \mathrm{s}^{2}\) must be applied about that axis for a duration of-

150299 The angular momentum of a wheel having a rotational inertia of \(0.2 \mathrm{~kg} \mathrm{~m}^{2}\) about its symmetric axis decreases from 4 to \(2 \mathrm{~kg} \mathrm{~m}^{2} \mathrm{~s}^{-1}\) in 4s. The average power of the wheel is

150300 A circular disc of weight \(500 \mathrm{~N}\) and of radius 1 \(m\) is started from rest by a constant horizontal force of \(25 \mathrm{~N}\) applied tangentially to the disc. The kinetic energy of the disc after time \(t=2\) [Acceleration due to gravity \(=\mathbf{1 0} \mathbf{~ m s}^{-2}\) ]

150296 A ball of radius \(\mathrm{R}\) rolls without slipping. Find the fraction of total energy associated with its rotational energy, if the radius of the gyration of the ball about an axis passing through its centre of mass is \(K\).

150297 A sphere is rolling on a horizontal surface without slipping. The ratio of the rotational K.E. to the total kinetic energy of the sphere is

150298 The moment of inertia of a body about a given axis is \(1.2 \mathrm{~kg} \mathrm{~m}^{2}\). Initially the body is at rest. In order to produce a rotational kinetic energy of \(1500 \mathrm{~J}\), an angular acceleration of \(25 \mathrm{rad} / \mathrm{s}^{2}\) must be applied about that axis for a duration of-

150299 The angular momentum of a wheel having a rotational inertia of \(0.2 \mathrm{~kg} \mathrm{~m}^{2}\) about its symmetric axis decreases from 4 to \(2 \mathrm{~kg} \mathrm{~m}^{2} \mathrm{~s}^{-1}\) in 4s. The average power of the wheel is

150300 A circular disc of weight \(500 \mathrm{~N}\) and of radius 1 \(m\) is started from rest by a constant horizontal force of \(25 \mathrm{~N}\) applied tangentially to the disc. The kinetic energy of the disc after time \(t=2\) [Acceleration due to gravity \(=\mathbf{1 0} \mathbf{~ m s}^{-2}\) ]

150296 A ball of radius \(\mathrm{R}\) rolls without slipping. Find the fraction of total energy associated with its rotational energy, if the radius of the gyration of the ball about an axis passing through its centre of mass is \(K\).

150297 A sphere is rolling on a horizontal surface without slipping. The ratio of the rotational K.E. to the total kinetic energy of the sphere is

150298 The moment of inertia of a body about a given axis is \(1.2 \mathrm{~kg} \mathrm{~m}^{2}\). Initially the body is at rest. In order to produce a rotational kinetic energy of \(1500 \mathrm{~J}\), an angular acceleration of \(25 \mathrm{rad} / \mathrm{s}^{2}\) must be applied about that axis for a duration of-

150299 The angular momentum of a wheel having a rotational inertia of \(0.2 \mathrm{~kg} \mathrm{~m}^{2}\) about its symmetric axis decreases from 4 to \(2 \mathrm{~kg} \mathrm{~m}^{2} \mathrm{~s}^{-1}\) in 4s. The average power of the wheel is

150300 A circular disc of weight \(500 \mathrm{~N}\) and of radius 1 \(m\) is started from rest by a constant horizontal force of \(25 \mathrm{~N}\) applied tangentially to the disc. The kinetic energy of the disc after time \(t=2\) [Acceleration due to gravity \(=\mathbf{1 0} \mathbf{~ m s}^{-2}\) ]