03. Moment of Inertia, Radius of Gyration
Rotational Motion

150101 Three particles, each of mass ' \(m\) ' grams situated at the vertices of an equilateral \(\triangle \mathrm{ABC}\) of side ' \(a\) ' \(\mathrm{cm}\) (as shown in the figure). The moment of inertia of the system about a line \(A X\) perpendicular to \(A B\) and in the plane of \(A B C\) in \(g-\mathrm{cm}^{2}\) units will be
original image

1 \(2 \mathrm{ma}^{2}\)
2 \(\frac{3}{2} \mathrm{ma}^{2}\)
3 \(\frac{3}{4} \mathrm{ma}^{2}\)
4 \(\frac{5}{4} \mathrm{ma}^{2}\)
Rotational Motion

150103 From a circular ring of mass \(M\) and radius \(R\), an arc corresponding to a \(\mathbf{9 0}^{\circ}\) sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is \(K\) times \(M^{2}\). Then, the value of \(K\) is

1 \(\frac{3}{4}\)
2 \(\frac{7}{8}\)
3 \(\frac{1}{4}\)
4 \(\frac{1}{8}\)
Rotational Motion

150104 A wheel having moment of inertia \(40 \mathrm{~kg} \cdot \mathrm{m}^{2}\) about its axis, rotates at \(50 \mathrm{rpm}\). The angular retardation required to stop this wheel in 90 seconds is rad.s \({ }^{-2}\)

1 \(\frac{\pi}{45}\)
2 \(\frac{\pi}{30}\)
3 \(\frac{\pi}{54}\)
4 \(\frac{\pi}{24}\)
Rotational Motion

150105 If an energy of \(684 \mathrm{~J}\) is needed to increase the speed of a fly wheel from \(180 \mathrm{rpm}\) to \(360 \mathrm{rpm}\), then find its moment of inertia.

1 \(0.7 \mathrm{~kg} . \mathrm{m}^{2}\)
2 \(1.28 \mathrm{~kg} \cdot \mathrm{m}_{2}^{2}\)
3 \(2.75 \mathrm{~kg} \cdot \mathrm{m}^{2}\)
4 \(7.28 \mathrm{~kg} \cdot \mathrm{m}^{2}\)
Rotational Motion

150106 The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 Å . Given, mass of carbon atom is \(\mathbf{1 2}\) a.m.u. and mass of oxygen atom is 16 a.m.u. Calculate the position of the centre of mass of the carbon monoxide molecule.

1 \(6.3 \AA\) from the Carbon atom
2 \(1.0 \AA\) from the Oxygen atom
3 \(0.63 \AA\) from the Carbon atom
4 \(0.12 \AA\) from the Oxygen atom
Rotational Motion

150101 Three particles, each of mass ' \(m\) ' grams situated at the vertices of an equilateral \(\triangle \mathrm{ABC}\) of side ' \(a\) ' \(\mathrm{cm}\) (as shown in the figure). The moment of inertia of the system about a line \(A X\) perpendicular to \(A B\) and in the plane of \(A B C\) in \(g-\mathrm{cm}^{2}\) units will be
original image

1 \(2 \mathrm{ma}^{2}\)
2 \(\frac{3}{2} \mathrm{ma}^{2}\)
3 \(\frac{3}{4} \mathrm{ma}^{2}\)
4 \(\frac{5}{4} \mathrm{ma}^{2}\)
Rotational Motion

150103 From a circular ring of mass \(M\) and radius \(R\), an arc corresponding to a \(\mathbf{9 0}^{\circ}\) sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is \(K\) times \(M^{2}\). Then, the value of \(K\) is

1 \(\frac{3}{4}\)
2 \(\frac{7}{8}\)
3 \(\frac{1}{4}\)
4 \(\frac{1}{8}\)
Rotational Motion

150104 A wheel having moment of inertia \(40 \mathrm{~kg} \cdot \mathrm{m}^{2}\) about its axis, rotates at \(50 \mathrm{rpm}\). The angular retardation required to stop this wheel in 90 seconds is rad.s \({ }^{-2}\)

1 \(\frac{\pi}{45}\)
2 \(\frac{\pi}{30}\)
3 \(\frac{\pi}{54}\)
4 \(\frac{\pi}{24}\)
Rotational Motion

150105 If an energy of \(684 \mathrm{~J}\) is needed to increase the speed of a fly wheel from \(180 \mathrm{rpm}\) to \(360 \mathrm{rpm}\), then find its moment of inertia.

1 \(0.7 \mathrm{~kg} . \mathrm{m}^{2}\)
2 \(1.28 \mathrm{~kg} \cdot \mathrm{m}_{2}^{2}\)
3 \(2.75 \mathrm{~kg} \cdot \mathrm{m}^{2}\)
4 \(7.28 \mathrm{~kg} \cdot \mathrm{m}^{2}\)
Rotational Motion

150106 The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 Å . Given, mass of carbon atom is \(\mathbf{1 2}\) a.m.u. and mass of oxygen atom is 16 a.m.u. Calculate the position of the centre of mass of the carbon monoxide molecule.

1 \(6.3 \AA\) from the Carbon atom
2 \(1.0 \AA\) from the Oxygen atom
3 \(0.63 \AA\) from the Carbon atom
4 \(0.12 \AA\) from the Oxygen atom
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Rotational Motion

150101 Three particles, each of mass ' \(m\) ' grams situated at the vertices of an equilateral \(\triangle \mathrm{ABC}\) of side ' \(a\) ' \(\mathrm{cm}\) (as shown in the figure). The moment of inertia of the system about a line \(A X\) perpendicular to \(A B\) and in the plane of \(A B C\) in \(g-\mathrm{cm}^{2}\) units will be
original image

1 \(2 \mathrm{ma}^{2}\)
2 \(\frac{3}{2} \mathrm{ma}^{2}\)
3 \(\frac{3}{4} \mathrm{ma}^{2}\)
4 \(\frac{5}{4} \mathrm{ma}^{2}\)
Rotational Motion

150103 From a circular ring of mass \(M\) and radius \(R\), an arc corresponding to a \(\mathbf{9 0}^{\circ}\) sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is \(K\) times \(M^{2}\). Then, the value of \(K\) is

1 \(\frac{3}{4}\)
2 \(\frac{7}{8}\)
3 \(\frac{1}{4}\)
4 \(\frac{1}{8}\)
Rotational Motion

150104 A wheel having moment of inertia \(40 \mathrm{~kg} \cdot \mathrm{m}^{2}\) about its axis, rotates at \(50 \mathrm{rpm}\). The angular retardation required to stop this wheel in 90 seconds is rad.s \({ }^{-2}\)

1 \(\frac{\pi}{45}\)
2 \(\frac{\pi}{30}\)
3 \(\frac{\pi}{54}\)
4 \(\frac{\pi}{24}\)
Rotational Motion

150105 If an energy of \(684 \mathrm{~J}\) is needed to increase the speed of a fly wheel from \(180 \mathrm{rpm}\) to \(360 \mathrm{rpm}\), then find its moment of inertia.

1 \(0.7 \mathrm{~kg} . \mathrm{m}^{2}\)
2 \(1.28 \mathrm{~kg} \cdot \mathrm{m}_{2}^{2}\)
3 \(2.75 \mathrm{~kg} \cdot \mathrm{m}^{2}\)
4 \(7.28 \mathrm{~kg} \cdot \mathrm{m}^{2}\)
Rotational Motion

150106 The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 Å . Given, mass of carbon atom is \(\mathbf{1 2}\) a.m.u. and mass of oxygen atom is 16 a.m.u. Calculate the position of the centre of mass of the carbon monoxide molecule.

1 \(6.3 \AA\) from the Carbon atom
2 \(1.0 \AA\) from the Oxygen atom
3 \(0.63 \AA\) from the Carbon atom
4 \(0.12 \AA\) from the Oxygen atom
Rotational Motion

150101 Three particles, each of mass ' \(m\) ' grams situated at the vertices of an equilateral \(\triangle \mathrm{ABC}\) of side ' \(a\) ' \(\mathrm{cm}\) (as shown in the figure). The moment of inertia of the system about a line \(A X\) perpendicular to \(A B\) and in the plane of \(A B C\) in \(g-\mathrm{cm}^{2}\) units will be
original image

1 \(2 \mathrm{ma}^{2}\)
2 \(\frac{3}{2} \mathrm{ma}^{2}\)
3 \(\frac{3}{4} \mathrm{ma}^{2}\)
4 \(\frac{5}{4} \mathrm{ma}^{2}\)
Rotational Motion

150103 From a circular ring of mass \(M\) and radius \(R\), an arc corresponding to a \(\mathbf{9 0}^{\circ}\) sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is \(K\) times \(M^{2}\). Then, the value of \(K\) is

1 \(\frac{3}{4}\)
2 \(\frac{7}{8}\)
3 \(\frac{1}{4}\)
4 \(\frac{1}{8}\)
Rotational Motion

150104 A wheel having moment of inertia \(40 \mathrm{~kg} \cdot \mathrm{m}^{2}\) about its axis, rotates at \(50 \mathrm{rpm}\). The angular retardation required to stop this wheel in 90 seconds is rad.s \({ }^{-2}\)

1 \(\frac{\pi}{45}\)
2 \(\frac{\pi}{30}\)
3 \(\frac{\pi}{54}\)
4 \(\frac{\pi}{24}\)
Rotational Motion

150105 If an energy of \(684 \mathrm{~J}\) is needed to increase the speed of a fly wheel from \(180 \mathrm{rpm}\) to \(360 \mathrm{rpm}\), then find its moment of inertia.

1 \(0.7 \mathrm{~kg} . \mathrm{m}^{2}\)
2 \(1.28 \mathrm{~kg} \cdot \mathrm{m}_{2}^{2}\)
3 \(2.75 \mathrm{~kg} \cdot \mathrm{m}^{2}\)
4 \(7.28 \mathrm{~kg} \cdot \mathrm{m}^{2}\)
Rotational Motion

150106 The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 Å . Given, mass of carbon atom is \(\mathbf{1 2}\) a.m.u. and mass of oxygen atom is 16 a.m.u. Calculate the position of the centre of mass of the carbon monoxide molecule.

1 \(6.3 \AA\) from the Carbon atom
2 \(1.0 \AA\) from the Oxygen atom
3 \(0.63 \AA\) from the Carbon atom
4 \(0.12 \AA\) from the Oxygen atom
Rotational Motion

150101 Three particles, each of mass ' \(m\) ' grams situated at the vertices of an equilateral \(\triangle \mathrm{ABC}\) of side ' \(a\) ' \(\mathrm{cm}\) (as shown in the figure). The moment of inertia of the system about a line \(A X\) perpendicular to \(A B\) and in the plane of \(A B C\) in \(g-\mathrm{cm}^{2}\) units will be
original image

1 \(2 \mathrm{ma}^{2}\)
2 \(\frac{3}{2} \mathrm{ma}^{2}\)
3 \(\frac{3}{4} \mathrm{ma}^{2}\)
4 \(\frac{5}{4} \mathrm{ma}^{2}\)
Rotational Motion

150103 From a circular ring of mass \(M\) and radius \(R\), an arc corresponding to a \(\mathbf{9 0}^{\circ}\) sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is \(K\) times \(M^{2}\). Then, the value of \(K\) is

1 \(\frac{3}{4}\)
2 \(\frac{7}{8}\)
3 \(\frac{1}{4}\)
4 \(\frac{1}{8}\)
Rotational Motion

150104 A wheel having moment of inertia \(40 \mathrm{~kg} \cdot \mathrm{m}^{2}\) about its axis, rotates at \(50 \mathrm{rpm}\). The angular retardation required to stop this wheel in 90 seconds is rad.s \({ }^{-2}\)

1 \(\frac{\pi}{45}\)
2 \(\frac{\pi}{30}\)
3 \(\frac{\pi}{54}\)
4 \(\frac{\pi}{24}\)
Rotational Motion

150105 If an energy of \(684 \mathrm{~J}\) is needed to increase the speed of a fly wheel from \(180 \mathrm{rpm}\) to \(360 \mathrm{rpm}\), then find its moment of inertia.

1 \(0.7 \mathrm{~kg} . \mathrm{m}^{2}\)
2 \(1.28 \mathrm{~kg} \cdot \mathrm{m}_{2}^{2}\)
3 \(2.75 \mathrm{~kg} \cdot \mathrm{m}^{2}\)
4 \(7.28 \mathrm{~kg} \cdot \mathrm{m}^{2}\)
Rotational Motion

150106 The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 Å . Given, mass of carbon atom is \(\mathbf{1 2}\) a.m.u. and mass of oxygen atom is 16 a.m.u. Calculate the position of the centre of mass of the carbon monoxide molecule.

1 \(6.3 \AA\) from the Carbon atom
2 \(1.0 \AA\) from the Oxygen atom
3 \(0.63 \AA\) from the Carbon atom
4 \(0.12 \AA\) from the Oxygen atom