149766 Three particles each of mass \(1 \mathrm{~kg}\) are placed at the corners of a right angled triangle \(A O B . O\) Being the origin of the coordinate system \((\mathrm{OA}\) and \(O B\) ) along positive \(X\)-direction and positive Y-direction). If \(\mathrm{OA}=\mathrm{OB}=1 \mathrm{~m}\), the positive vector of the centre of mass (in meters) is:

149767 Four particles, each of mass \(1 \mathrm{~kg}\), are placed at the corners of a square of side \(1 \mathrm{~m}\) in the \(X-Y\) plane. If the point of intersection of the diagonals of the square, is taken as the origin, the co-ordinates of the centre of mass are:

149768 One end of a thin uniform rod of length \(L\) and mass \(M_{1}\) is riveted to the centre of a uniform circular disc of radius \(r\) and mass \(M_{2}\), so that both are coplanar. The centre of mass of the combination from the centre of the disc is:

149769 A uniform rod of length one meter is bent at its midpoint to make \(90^{\circ}\) angle. The distance of the centre of mass from the centre of rod is:

149766 Three particles each of mass \(1 \mathrm{~kg}\) are placed at the corners of a right angled triangle \(A O B . O\) Being the origin of the coordinate system \((\mathrm{OA}\) and \(O B\) ) along positive \(X\)-direction and positive Y-direction). If \(\mathrm{OA}=\mathrm{OB}=1 \mathrm{~m}\), the positive vector of the centre of mass (in meters) is:

149767 Four particles, each of mass \(1 \mathrm{~kg}\), are placed at the corners of a square of side \(1 \mathrm{~m}\) in the \(X-Y\) plane. If the point of intersection of the diagonals of the square, is taken as the origin, the co-ordinates of the centre of mass are:

149768 One end of a thin uniform rod of length \(L\) and mass \(M_{1}\) is riveted to the centre of a uniform circular disc of radius \(r\) and mass \(M_{2}\), so that both are coplanar. The centre of mass of the combination from the centre of the disc is:

149769 A uniform rod of length one meter is bent at its midpoint to make \(90^{\circ}\) angle. The distance of the centre of mass from the centre of rod is:

149766 Three particles each of mass \(1 \mathrm{~kg}\) are placed at the corners of a right angled triangle \(A O B . O\) Being the origin of the coordinate system \((\mathrm{OA}\) and \(O B\) ) along positive \(X\)-direction and positive Y-direction). If \(\mathrm{OA}=\mathrm{OB}=1 \mathrm{~m}\), the positive vector of the centre of mass (in meters) is:

149767 Four particles, each of mass \(1 \mathrm{~kg}\), are placed at the corners of a square of side \(1 \mathrm{~m}\) in the \(X-Y\) plane. If the point of intersection of the diagonals of the square, is taken as the origin, the co-ordinates of the centre of mass are:

149768 One end of a thin uniform rod of length \(L\) and mass \(M_{1}\) is riveted to the centre of a uniform circular disc of radius \(r\) and mass \(M_{2}\), so that both are coplanar. The centre of mass of the combination from the centre of the disc is:

149769 A uniform rod of length one meter is bent at its midpoint to make \(90^{\circ}\) angle. The distance of the centre of mass from the centre of rod is:

149766 Three particles each of mass \(1 \mathrm{~kg}\) are placed at the corners of a right angled triangle \(A O B . O\) Being the origin of the coordinate system \((\mathrm{OA}\) and \(O B\) ) along positive \(X\)-direction and positive Y-direction). If \(\mathrm{OA}=\mathrm{OB}=1 \mathrm{~m}\), the positive vector of the centre of mass (in meters) is:

149767 Four particles, each of mass \(1 \mathrm{~kg}\), are placed at the corners of a square of side \(1 \mathrm{~m}\) in the \(X-Y\) plane. If the point of intersection of the diagonals of the square, is taken as the origin, the co-ordinates of the centre of mass are:

149768 One end of a thin uniform rod of length \(L\) and mass \(M_{1}\) is riveted to the centre of a uniform circular disc of radius \(r\) and mass \(M_{2}\), so that both are coplanar. The centre of mass of the combination from the centre of the disc is:

149769 A uniform rod of length one meter is bent at its midpoint to make \(90^{\circ}\) angle. The distance of the centre of mass from the centre of rod is: