04. Friction, and Inclined Plane Friction Motion
Laws of Motion

146183 If the coefficient of static friction between shoes of a runner and the track is 0.85 , the greatest acceleration that can be generated by the runner is (here, \(g\) gravitational acceleration)

1 \(1.85 \mathrm{~g}\)
2 \(g\)
3 \(0.85 \mathrm{~g}\)
4 \(0.15 \mathrm{~g}\)
Laws of Motion

146184 A body of mass \(m=1 \mathrm{~kg}\) is moving in a medium and experiences a fractions force \(F=-k v\), where \(v\) is the speed of the body. The initial speed is \(v_{0}=10 \mathrm{~ms}^{-1}\) and after \(10 \mathrm{~s}\), its energy becomes half of initial energy. Then, the value of \(k\) is

1 \(10 \ln \sqrt{2}\)
2 \(\ln \sqrt{2}\)
3 \(\frac{\ln 2}{20}\)
4 \(10 \ln 2\)
5 \(\ln 2\)
Laws of Motion

146185 Two charged particles of each of mass \(3 \mathrm{~g}\) and charge \(0.2 \mu \mathrm{C}\) stay in (vacuum) equilibrium on a horizontal surface with a separation of \(20 \mathrm{~cm}\). the coefficient of friction is
\(\left[\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9} \mathbf{N m}^{2} \mathrm{C}^{-2}\right]\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)

1 0.20
2 0.18
3 0.25
4 0.30
Laws of Motion

146186 Two wedges each of mass \(600 \mathrm{~g}\) are placed next to each other on a rough horizontal surface. The coefficient of static friction between the wedges and the surface is 0.4 . A cube of mass ' \(M\) ' is balanced on the wedges as shown in the figure. If there is no friction between the cube and wedges, the largest mass ' \(M\) ' of the cube that can be balanced without motion of the wedges is \(\mathbf{k g}\).

1 0.8
2 0.6
3 0.3
4 1.2
Laws of Motion

146183 If the coefficient of static friction between shoes of a runner and the track is 0.85 , the greatest acceleration that can be generated by the runner is (here, \(g\) gravitational acceleration)

1 \(1.85 \mathrm{~g}\)
2 \(g\)
3 \(0.85 \mathrm{~g}\)
4 \(0.15 \mathrm{~g}\)
Laws of Motion

146184 A body of mass \(m=1 \mathrm{~kg}\) is moving in a medium and experiences a fractions force \(F=-k v\), where \(v\) is the speed of the body. The initial speed is \(v_{0}=10 \mathrm{~ms}^{-1}\) and after \(10 \mathrm{~s}\), its energy becomes half of initial energy. Then, the value of \(k\) is

1 \(10 \ln \sqrt{2}\)
2 \(\ln \sqrt{2}\)
3 \(\frac{\ln 2}{20}\)
4 \(10 \ln 2\)
5 \(\ln 2\)
Laws of Motion

146185 Two charged particles of each of mass \(3 \mathrm{~g}\) and charge \(0.2 \mu \mathrm{C}\) stay in (vacuum) equilibrium on a horizontal surface with a separation of \(20 \mathrm{~cm}\). the coefficient of friction is
\(\left[\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9} \mathbf{N m}^{2} \mathrm{C}^{-2}\right]\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)

1 0.20
2 0.18
3 0.25
4 0.30
Laws of Motion

146186 Two wedges each of mass \(600 \mathrm{~g}\) are placed next to each other on a rough horizontal surface. The coefficient of static friction between the wedges and the surface is 0.4 . A cube of mass ' \(M\) ' is balanced on the wedges as shown in the figure. If there is no friction between the cube and wedges, the largest mass ' \(M\) ' of the cube that can be balanced without motion of the wedges is \(\mathbf{k g}\).

1 0.8
2 0.6
3 0.3
4 1.2
Laws of Motion

146183 If the coefficient of static friction between shoes of a runner and the track is 0.85 , the greatest acceleration that can be generated by the runner is (here, \(g\) gravitational acceleration)

1 \(1.85 \mathrm{~g}\)
2 \(g\)
3 \(0.85 \mathrm{~g}\)
4 \(0.15 \mathrm{~g}\)
Laws of Motion

146184 A body of mass \(m=1 \mathrm{~kg}\) is moving in a medium and experiences a fractions force \(F=-k v\), where \(v\) is the speed of the body. The initial speed is \(v_{0}=10 \mathrm{~ms}^{-1}\) and after \(10 \mathrm{~s}\), its energy becomes half of initial energy. Then, the value of \(k\) is

1 \(10 \ln \sqrt{2}\)
2 \(\ln \sqrt{2}\)
3 \(\frac{\ln 2}{20}\)
4 \(10 \ln 2\)
5 \(\ln 2\)
Laws of Motion

146185 Two charged particles of each of mass \(3 \mathrm{~g}\) and charge \(0.2 \mu \mathrm{C}\) stay in (vacuum) equilibrium on a horizontal surface with a separation of \(20 \mathrm{~cm}\). the coefficient of friction is
\(\left[\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9} \mathbf{N m}^{2} \mathrm{C}^{-2}\right]\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)

1 0.20
2 0.18
3 0.25
4 0.30
Laws of Motion

146186 Two wedges each of mass \(600 \mathrm{~g}\) are placed next to each other on a rough horizontal surface. The coefficient of static friction between the wedges and the surface is 0.4 . A cube of mass ' \(M\) ' is balanced on the wedges as shown in the figure. If there is no friction between the cube and wedges, the largest mass ' \(M\) ' of the cube that can be balanced without motion of the wedges is \(\mathbf{k g}\).

1 0.8
2 0.6
3 0.3
4 1.2
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Laws of Motion

146183 If the coefficient of static friction between shoes of a runner and the track is 0.85 , the greatest acceleration that can be generated by the runner is (here, \(g\) gravitational acceleration)

1 \(1.85 \mathrm{~g}\)
2 \(g\)
3 \(0.85 \mathrm{~g}\)
4 \(0.15 \mathrm{~g}\)
Laws of Motion

146184 A body of mass \(m=1 \mathrm{~kg}\) is moving in a medium and experiences a fractions force \(F=-k v\), where \(v\) is the speed of the body. The initial speed is \(v_{0}=10 \mathrm{~ms}^{-1}\) and after \(10 \mathrm{~s}\), its energy becomes half of initial energy. Then, the value of \(k\) is

1 \(10 \ln \sqrt{2}\)
2 \(\ln \sqrt{2}\)
3 \(\frac{\ln 2}{20}\)
4 \(10 \ln 2\)
5 \(\ln 2\)
Laws of Motion

146185 Two charged particles of each of mass \(3 \mathrm{~g}\) and charge \(0.2 \mu \mathrm{C}\) stay in (vacuum) equilibrium on a horizontal surface with a separation of \(20 \mathrm{~cm}\). the coefficient of friction is
\(\left[\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9} \mathbf{N m}^{2} \mathrm{C}^{-2}\right]\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)

1 0.20
2 0.18
3 0.25
4 0.30
Laws of Motion

146186 Two wedges each of mass \(600 \mathrm{~g}\) are placed next to each other on a rough horizontal surface. The coefficient of static friction between the wedges and the surface is 0.4 . A cube of mass ' \(M\) ' is balanced on the wedges as shown in the figure. If there is no friction between the cube and wedges, the largest mass ' \(M\) ' of the cube that can be balanced without motion of the wedges is \(\mathbf{k g}\).

1 0.8
2 0.6
3 0.3
4 1.2