143556 What is the torque of a force \(3 \hat{i}+7 \hat{j}+4 \hat{k}\) about the origin, if the force acts on a particle whose position vector is \(2 \hat{i}+2 \hat{j}+1 \hat{k}\) ?

143559 A certain vector in the \(x y\) plane has an \(x\) component of \(12 \mathrm{~m}\) and a y-component of \(8 \mathrm{~m}\). It is then rotated in the \(x y\) plane so that its \(x\) component is halved. Then its new \(y\) component is approximately

143560 Figure shows three forces \(\overrightarrow{\mathrm{F}}_{1}, \overrightarrow{\mathrm{F}}_{2}\) and \(\overrightarrow{\mathrm{F}}_{3}\) acting along the sides of an equilateral triangle. If the total torque acting at point ' \(O\) ' (centre of the triangle) is zero then the magnitude of \(\vec{F}_{3}\) is

143561 Two forces each of magnitude ' \(P\) ' act at right angles. Their effect is neutralized by a third force acting along their bisector in opposite direction. The magnitude of the third force is \(\left[\cos \frac{\pi}{2}=0\right]\)

143556 What is the torque of a force \(3 \hat{i}+7 \hat{j}+4 \hat{k}\) about the origin, if the force acts on a particle whose position vector is \(2 \hat{i}+2 \hat{j}+1 \hat{k}\) ?

143559 A certain vector in the \(x y\) plane has an \(x\) component of \(12 \mathrm{~m}\) and a y-component of \(8 \mathrm{~m}\). It is then rotated in the \(x y\) plane so that its \(x\) component is halved. Then its new \(y\) component is approximately

143560 Figure shows three forces \(\overrightarrow{\mathrm{F}}_{1}, \overrightarrow{\mathrm{F}}_{2}\) and \(\overrightarrow{\mathrm{F}}_{3}\) acting along the sides of an equilateral triangle. If the total torque acting at point ' \(O\) ' (centre of the triangle) is zero then the magnitude of \(\vec{F}_{3}\) is

143561 Two forces each of magnitude ' \(P\) ' act at right angles. Their effect is neutralized by a third force acting along their bisector in opposite direction. The magnitude of the third force is \(\left[\cos \frac{\pi}{2}=0\right]\)

143556 What is the torque of a force \(3 \hat{i}+7 \hat{j}+4 \hat{k}\) about the origin, if the force acts on a particle whose position vector is \(2 \hat{i}+2 \hat{j}+1 \hat{k}\) ?

143559 A certain vector in the \(x y\) plane has an \(x\) component of \(12 \mathrm{~m}\) and a y-component of \(8 \mathrm{~m}\). It is then rotated in the \(x y\) plane so that its \(x\) component is halved. Then its new \(y\) component is approximately

143560 Figure shows three forces \(\overrightarrow{\mathrm{F}}_{1}, \overrightarrow{\mathrm{F}}_{2}\) and \(\overrightarrow{\mathrm{F}}_{3}\) acting along the sides of an equilateral triangle. If the total torque acting at point ' \(O\) ' (centre of the triangle) is zero then the magnitude of \(\vec{F}_{3}\) is

143561 Two forces each of magnitude ' \(P\) ' act at right angles. Their effect is neutralized by a third force acting along their bisector in opposite direction. The magnitude of the third force is \(\left[\cos \frac{\pi}{2}=0\right]\)

143556 What is the torque of a force \(3 \hat{i}+7 \hat{j}+4 \hat{k}\) about the origin, if the force acts on a particle whose position vector is \(2 \hat{i}+2 \hat{j}+1 \hat{k}\) ?

143559 A certain vector in the \(x y\) plane has an \(x\) component of \(12 \mathrm{~m}\) and a y-component of \(8 \mathrm{~m}\). It is then rotated in the \(x y\) plane so that its \(x\) component is halved. Then its new \(y\) component is approximately

143560 Figure shows three forces \(\overrightarrow{\mathrm{F}}_{1}, \overrightarrow{\mathrm{F}}_{2}\) and \(\overrightarrow{\mathrm{F}}_{3}\) acting along the sides of an equilateral triangle. If the total torque acting at point ' \(O\) ' (centre of the triangle) is zero then the magnitude of \(\vec{F}_{3}\) is

143561 Two forces each of magnitude ' \(P\) ' act at right angles. Their effect is neutralized by a third force acting along their bisector in opposite direction. The magnitude of the third force is \(\left[\cos \frac{\pi}{2}=0\right]\)