141953 At the moment \(t=0\). a time dependent force \(F\) \(=\) at (where a is constant equal to \(1 \mathrm{Ns}^{-1}\) ) is applied to a body of mass \(1 \mathrm{~kg}\) resting on a smooth horizontal plane as shown in the figure. If the direction of this force makes am angle \(45^{\circ}\) with the horizontal. Then the velocity of the body at the moment it leaves the plane is (Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )

141954 A bar of mass \(m\) resting on a smooth horizontal plane starts moving due to a constant force \(F\). In the process of its rectilinear motion the angle \(\theta\) between the direction of this force and the horizontal varies as \(\theta=k x\), where \(k\) is a constant and \(x\) is the distance traversed by the bar from its initial position. The velocity (v) of the bar as a function of the angle \(\theta\) is

141955 A small block slides down on a smooth inclined plane, starting from rest at time \(t=0\). Let \(S_{n}\) be the distance travelled by the block in the interval \(t=n-1\) to \(t=n\). Then, the ratio \(\frac{S_{n}}{S_{n+1}}\) is

141956 A small block slides down on a smooth inclined plane, starting from rest at time \(t=0\). Let \(S_{n}\) be the distance travelled by the block in the interval \(t=n-1\) to \(t=n\). Then, the ratio \(\frac{S_{n}}{S_{n+1}}\) is

141953 At the moment \(t=0\). a time dependent force \(F\) \(=\) at (where a is constant equal to \(1 \mathrm{Ns}^{-1}\) ) is applied to a body of mass \(1 \mathrm{~kg}\) resting on a smooth horizontal plane as shown in the figure. If the direction of this force makes am angle \(45^{\circ}\) with the horizontal. Then the velocity of the body at the moment it leaves the plane is (Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )

141954 A bar of mass \(m\) resting on a smooth horizontal plane starts moving due to a constant force \(F\). In the process of its rectilinear motion the angle \(\theta\) between the direction of this force and the horizontal varies as \(\theta=k x\), where \(k\) is a constant and \(x\) is the distance traversed by the bar from its initial position. The velocity (v) of the bar as a function of the angle \(\theta\) is

141955 A small block slides down on a smooth inclined plane, starting from rest at time \(t=0\). Let \(S_{n}\) be the distance travelled by the block in the interval \(t=n-1\) to \(t=n\). Then, the ratio \(\frac{S_{n}}{S_{n+1}}\) is

141956 A small block slides down on a smooth inclined plane, starting from rest at time \(t=0\). Let \(S_{n}\) be the distance travelled by the block in the interval \(t=n-1\) to \(t=n\). Then, the ratio \(\frac{S_{n}}{S_{n+1}}\) is

141953 At the moment \(t=0\). a time dependent force \(F\) \(=\) at (where a is constant equal to \(1 \mathrm{Ns}^{-1}\) ) is applied to a body of mass \(1 \mathrm{~kg}\) resting on a smooth horizontal plane as shown in the figure. If the direction of this force makes am angle \(45^{\circ}\) with the horizontal. Then the velocity of the body at the moment it leaves the plane is (Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )

141954 A bar of mass \(m\) resting on a smooth horizontal plane starts moving due to a constant force \(F\). In the process of its rectilinear motion the angle \(\theta\) between the direction of this force and the horizontal varies as \(\theta=k x\), where \(k\) is a constant and \(x\) is the distance traversed by the bar from its initial position. The velocity (v) of the bar as a function of the angle \(\theta\) is

141955 A small block slides down on a smooth inclined plane, starting from rest at time \(t=0\). Let \(S_{n}\) be the distance travelled by the block in the interval \(t=n-1\) to \(t=n\). Then, the ratio \(\frac{S_{n}}{S_{n+1}}\) is

141956 A small block slides down on a smooth inclined plane, starting from rest at time \(t=0\). Let \(S_{n}\) be the distance travelled by the block in the interval \(t=n-1\) to \(t=n\). Then, the ratio \(\frac{S_{n}}{S_{n+1}}\) is

141953 At the moment \(t=0\). a time dependent force \(F\) \(=\) at (where a is constant equal to \(1 \mathrm{Ns}^{-1}\) ) is applied to a body of mass \(1 \mathrm{~kg}\) resting on a smooth horizontal plane as shown in the figure. If the direction of this force makes am angle \(45^{\circ}\) with the horizontal. Then the velocity of the body at the moment it leaves the plane is (Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )

141954 A bar of mass \(m\) resting on a smooth horizontal plane starts moving due to a constant force \(F\). In the process of its rectilinear motion the angle \(\theta\) between the direction of this force and the horizontal varies as \(\theta=k x\), where \(k\) is a constant and \(x\) is the distance traversed by the bar from its initial position. The velocity (v) of the bar as a function of the angle \(\theta\) is

141955 A small block slides down on a smooth inclined plane, starting from rest at time \(t=0\). Let \(S_{n}\) be the distance travelled by the block in the interval \(t=n-1\) to \(t=n\). Then, the ratio \(\frac{S_{n}}{S_{n+1}}\) is

141956 A small block slides down on a smooth inclined plane, starting from rest at time \(t=0\). Let \(S_{n}\) be the distance travelled by the block in the interval \(t=n-1\) to \(t=n\). Then, the ratio \(\frac{S_{n}}{S_{n+1}}\) is