141807 A stone falls freely under gravity. It covers distance \(d_{1}\) and \(d_{2}\) in the first 4 second, and the next 8 seconds respectively. The ratio \(\frac{d_{2}}{d_{1}}\) is

141809 A rocket lifts off from ground and accelerate upwards at \(1 \mathrm{~m} / \mathrm{s}^{2} .20\) seconds after lift off a piece breaks off from the bottom of rocket. After breaking off, how much time it takes approximately to reach the ground?
(Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141810 Two balls are released from the same position at a height of \(500 \mathrm{~m}\) above ground, one after the other, with an interval of \(1 \mathrm{~s}\). What is the distance between the two balls when the first hits ground? (Acceleration due to gravity \(\mathrm{g}=\) \(10 \mathrm{~m} / \mathrm{s}^{2}\) )

141811 A ball thrown upwards vertically reaches a height \(25 \mathrm{~m}\) in \(1 \mathrm{~s}\). The ratio of total distance covered by the ball in time \(t=2 \mathrm{~s}\) and \(t=4 \mathrm{~s}\) is (use \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141807 A stone falls freely under gravity. It covers distance \(d_{1}\) and \(d_{2}\) in the first 4 second, and the next 8 seconds respectively. The ratio \(\frac{d_{2}}{d_{1}}\) is

141809 A rocket lifts off from ground and accelerate upwards at \(1 \mathrm{~m} / \mathrm{s}^{2} .20\) seconds after lift off a piece breaks off from the bottom of rocket. After breaking off, how much time it takes approximately to reach the ground?
(Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141810 Two balls are released from the same position at a height of \(500 \mathrm{~m}\) above ground, one after the other, with an interval of \(1 \mathrm{~s}\). What is the distance between the two balls when the first hits ground? (Acceleration due to gravity \(\mathrm{g}=\) \(10 \mathrm{~m} / \mathrm{s}^{2}\) )

141811 A ball thrown upwards vertically reaches a height \(25 \mathrm{~m}\) in \(1 \mathrm{~s}\). The ratio of total distance covered by the ball in time \(t=2 \mathrm{~s}\) and \(t=4 \mathrm{~s}\) is (use \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141807 A stone falls freely under gravity. It covers distance \(d_{1}\) and \(d_{2}\) in the first 4 second, and the next 8 seconds respectively. The ratio \(\frac{d_{2}}{d_{1}}\) is

141809 A rocket lifts off from ground and accelerate upwards at \(1 \mathrm{~m} / \mathrm{s}^{2} .20\) seconds after lift off a piece breaks off from the bottom of rocket. After breaking off, how much time it takes approximately to reach the ground?
(Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141810 Two balls are released from the same position at a height of \(500 \mathrm{~m}\) above ground, one after the other, with an interval of \(1 \mathrm{~s}\). What is the distance between the two balls when the first hits ground? (Acceleration due to gravity \(\mathrm{g}=\) \(10 \mathrm{~m} / \mathrm{s}^{2}\) )

141811 A ball thrown upwards vertically reaches a height \(25 \mathrm{~m}\) in \(1 \mathrm{~s}\). The ratio of total distance covered by the ball in time \(t=2 \mathrm{~s}\) and \(t=4 \mathrm{~s}\) is (use \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141807 A stone falls freely under gravity. It covers distance \(d_{1}\) and \(d_{2}\) in the first 4 second, and the next 8 seconds respectively. The ratio \(\frac{d_{2}}{d_{1}}\) is

141809 A rocket lifts off from ground and accelerate upwards at \(1 \mathrm{~m} / \mathrm{s}^{2} .20\) seconds after lift off a piece breaks off from the bottom of rocket. After breaking off, how much time it takes approximately to reach the ground?
(Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141810 Two balls are released from the same position at a height of \(500 \mathrm{~m}\) above ground, one after the other, with an interval of \(1 \mathrm{~s}\). What is the distance between the two balls when the first hits ground? (Acceleration due to gravity \(\mathrm{g}=\) \(10 \mathrm{~m} / \mathrm{s}^{2}\) )

141811 A ball thrown upwards vertically reaches a height \(25 \mathrm{~m}\) in \(1 \mathrm{~s}\). The ratio of total distance covered by the ball in time \(t=2 \mathrm{~s}\) and \(t=4 \mathrm{~s}\) is (use \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )