141838 A hot air balloon is rising upward with acceleration \(2.5 \mathrm{~m} / \mathrm{s}^{2}\). The ratio of air density outside the balloon to that inside will be (Assume \(g=10 \mathrm{~m} / \mathrm{s}^{2}\), Neglect the mass of balloon fabric)

141839 A particle is thrown vertically up with a velocity of \(100 \mathrm{~m} \mathrm{~s}^{-1}\). What will be the time taken by the body to reach the ground? Assume \(\mathrm{g}=10 \mathrm{~N}\).

141840 A ball is dropped from top of a tower of \(100 \mathrm{~m}\) height. Simultaneously another ball was thrown upward from bottom of the tower with a speed of \(50 \mathrm{~m} / \mathrm{s}\). They will cross each other \(\operatorname{after}\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

141841 A stone is dropped from a height of \(100 \mathrm{~m}\), while another one is projected vertically upwards from the ground with a velocity of 25 \(\mathrm{m} / \mathrm{s}\) at the same time.
The time in seconds after which they will have the same height is (acceleration due to gravity, \(\mathbf{g}=\mathbf{1 0} \mathbf{m s}^{-\mathbf{2}}\) )

141838 A hot air balloon is rising upward with acceleration \(2.5 \mathrm{~m} / \mathrm{s}^{2}\). The ratio of air density outside the balloon to that inside will be (Assume \(g=10 \mathrm{~m} / \mathrm{s}^{2}\), Neglect the mass of balloon fabric)

141839 A particle is thrown vertically up with a velocity of \(100 \mathrm{~m} \mathrm{~s}^{-1}\). What will be the time taken by the body to reach the ground? Assume \(\mathrm{g}=10 \mathrm{~N}\).

141840 A ball is dropped from top of a tower of \(100 \mathrm{~m}\) height. Simultaneously another ball was thrown upward from bottom of the tower with a speed of \(50 \mathrm{~m} / \mathrm{s}\). They will cross each other \(\operatorname{after}\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

141841 A stone is dropped from a height of \(100 \mathrm{~m}\), while another one is projected vertically upwards from the ground with a velocity of 25 \(\mathrm{m} / \mathrm{s}\) at the same time.
The time in seconds after which they will have the same height is (acceleration due to gravity, \(\mathbf{g}=\mathbf{1 0} \mathbf{m s}^{-\mathbf{2}}\) )

141838 A hot air balloon is rising upward with acceleration \(2.5 \mathrm{~m} / \mathrm{s}^{2}\). The ratio of air density outside the balloon to that inside will be (Assume \(g=10 \mathrm{~m} / \mathrm{s}^{2}\), Neglect the mass of balloon fabric)

141839 A particle is thrown vertically up with a velocity of \(100 \mathrm{~m} \mathrm{~s}^{-1}\). What will be the time taken by the body to reach the ground? Assume \(\mathrm{g}=10 \mathrm{~N}\).

141840 A ball is dropped from top of a tower of \(100 \mathrm{~m}\) height. Simultaneously another ball was thrown upward from bottom of the tower with a speed of \(50 \mathrm{~m} / \mathrm{s}\). They will cross each other \(\operatorname{after}\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

141841 A stone is dropped from a height of \(100 \mathrm{~m}\), while another one is projected vertically upwards from the ground with a velocity of 25 \(\mathrm{m} / \mathrm{s}\) at the same time.
The time in seconds after which they will have the same height is (acceleration due to gravity, \(\mathbf{g}=\mathbf{1 0} \mathbf{m s}^{-\mathbf{2}}\) )

141838 A hot air balloon is rising upward with acceleration \(2.5 \mathrm{~m} / \mathrm{s}^{2}\). The ratio of air density outside the balloon to that inside will be (Assume \(g=10 \mathrm{~m} / \mathrm{s}^{2}\), Neglect the mass of balloon fabric)

141839 A particle is thrown vertically up with a velocity of \(100 \mathrm{~m} \mathrm{~s}^{-1}\). What will be the time taken by the body to reach the ground? Assume \(\mathrm{g}=10 \mathrm{~N}\).

141840 A ball is dropped from top of a tower of \(100 \mathrm{~m}\) height. Simultaneously another ball was thrown upward from bottom of the tower with a speed of \(50 \mathrm{~m} / \mathrm{s}\). They will cross each other \(\operatorname{after}\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

141841 A stone is dropped from a height of \(100 \mathrm{~m}\), while another one is projected vertically upwards from the ground with a velocity of 25 \(\mathrm{m} / \mathrm{s}\) at the same time.
The time in seconds after which they will have the same height is (acceleration due to gravity, \(\mathbf{g}=\mathbf{1 0} \mathbf{m s}^{-\mathbf{2}}\) )