141834 A gun and a target are at the same horizontal level separated by a distance of \(600 \mathrm{~m}\). The bullet is fired from the gun with a velocity of \(500 \mathrm{~ms}^{-1}\). In order to hit the target, the gun should be aimed to a height \(h\) above the target. The value of \(h\) is
(Acceleration due to gravity, \(g=10 \mathbf{~ m s}^{-\mathbf{2}}\) )

141835 Ball-1 is dropped from the top of a building from rest. At the same moment, ball-2 is thrown upward towards ball-1 with a speed 14 \(\mathrm{m} / \mathrm{s}\) from a point \(21 \mathrm{~m}\) below the top of building. How far will the ball-1 have dropped when it passes ball-2. (Assume, acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\).)

141831 Assertion : When a body is dropped or thrown upward from the same height, it would reach the ground at the same time.
Reason : Direction of projection does not affect the time of flight.

141836 A ball is thrown vertically upward from the ground at time, \(t=0 \mathrm{~s}\). It passes the top of a tower at \(t=3 \mathrm{~s}\) and \(2 \mathrm{~s}\) later it reaches and its maximum height. The height of the tower is (Acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141837 A ball is projected vertically up from ground. Boy A standing at the window of first floor of a nearly building observes that the time interval between the ball crossing him while going up and the ball crossing him while going down is 2s. Another boy B standing on the second floor notices that time interval between the ball passing him twice, during up motion and down motion is \(1 \mathrm{~s}\). Calculate the difference between the vertical positions of boy \(B\) and boy \(A\) (Assume, acceleration due to gravity, \(g=10\) \(\mathbf{m} / \mathbf{s}^{2}\) )

141834 A gun and a target are at the same horizontal level separated by a distance of \(600 \mathrm{~m}\). The bullet is fired from the gun with a velocity of \(500 \mathrm{~ms}^{-1}\). In order to hit the target, the gun should be aimed to a height \(h\) above the target. The value of \(h\) is
(Acceleration due to gravity, \(g=10 \mathbf{~ m s}^{-\mathbf{2}}\) )

141835 Ball-1 is dropped from the top of a building from rest. At the same moment, ball-2 is thrown upward towards ball-1 with a speed 14 \(\mathrm{m} / \mathrm{s}\) from a point \(21 \mathrm{~m}\) below the top of building. How far will the ball-1 have dropped when it passes ball-2. (Assume, acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\).)

141831 Assertion : When a body is dropped or thrown upward from the same height, it would reach the ground at the same time.
Reason : Direction of projection does not affect the time of flight.

141836 A ball is thrown vertically upward from the ground at time, \(t=0 \mathrm{~s}\). It passes the top of a tower at \(t=3 \mathrm{~s}\) and \(2 \mathrm{~s}\) later it reaches and its maximum height. The height of the tower is (Acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141837 A ball is projected vertically up from ground. Boy A standing at the window of first floor of a nearly building observes that the time interval between the ball crossing him while going up and the ball crossing him while going down is 2s. Another boy B standing on the second floor notices that time interval between the ball passing him twice, during up motion and down motion is \(1 \mathrm{~s}\). Calculate the difference between the vertical positions of boy \(B\) and boy \(A\) (Assume, acceleration due to gravity, \(g=10\) \(\mathbf{m} / \mathbf{s}^{2}\) )

141834 A gun and a target are at the same horizontal level separated by a distance of \(600 \mathrm{~m}\). The bullet is fired from the gun with a velocity of \(500 \mathrm{~ms}^{-1}\). In order to hit the target, the gun should be aimed to a height \(h\) above the target. The value of \(h\) is
(Acceleration due to gravity, \(g=10 \mathbf{~ m s}^{-\mathbf{2}}\) )

141835 Ball-1 is dropped from the top of a building from rest. At the same moment, ball-2 is thrown upward towards ball-1 with a speed 14 \(\mathrm{m} / \mathrm{s}\) from a point \(21 \mathrm{~m}\) below the top of building. How far will the ball-1 have dropped when it passes ball-2. (Assume, acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\).)

141831 Assertion : When a body is dropped or thrown upward from the same height, it would reach the ground at the same time.
Reason : Direction of projection does not affect the time of flight.

141836 A ball is thrown vertically upward from the ground at time, \(t=0 \mathrm{~s}\). It passes the top of a tower at \(t=3 \mathrm{~s}\) and \(2 \mathrm{~s}\) later it reaches and its maximum height. The height of the tower is (Acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141837 A ball is projected vertically up from ground. Boy A standing at the window of first floor of a nearly building observes that the time interval between the ball crossing him while going up and the ball crossing him while going down is 2s. Another boy B standing on the second floor notices that time interval between the ball passing him twice, during up motion and down motion is \(1 \mathrm{~s}\). Calculate the difference between the vertical positions of boy \(B\) and boy \(A\) (Assume, acceleration due to gravity, \(g=10\) \(\mathbf{m} / \mathbf{s}^{2}\) )

141834 A gun and a target are at the same horizontal level separated by a distance of \(600 \mathrm{~m}\). The bullet is fired from the gun with a velocity of \(500 \mathrm{~ms}^{-1}\). In order to hit the target, the gun should be aimed to a height \(h\) above the target. The value of \(h\) is
(Acceleration due to gravity, \(g=10 \mathbf{~ m s}^{-\mathbf{2}}\) )

141835 Ball-1 is dropped from the top of a building from rest. At the same moment, ball-2 is thrown upward towards ball-1 with a speed 14 \(\mathrm{m} / \mathrm{s}\) from a point \(21 \mathrm{~m}\) below the top of building. How far will the ball-1 have dropped when it passes ball-2. (Assume, acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\).)

141831 Assertion : When a body is dropped or thrown upward from the same height, it would reach the ground at the same time.
Reason : Direction of projection does not affect the time of flight.

141836 A ball is thrown vertically upward from the ground at time, \(t=0 \mathrm{~s}\). It passes the top of a tower at \(t=3 \mathrm{~s}\) and \(2 \mathrm{~s}\) later it reaches and its maximum height. The height of the tower is (Acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141837 A ball is projected vertically up from ground. Boy A standing at the window of first floor of a nearly building observes that the time interval between the ball crossing him while going up and the ball crossing him while going down is 2s. Another boy B standing on the second floor notices that time interval between the ball passing him twice, during up motion and down motion is \(1 \mathrm{~s}\). Calculate the difference between the vertical positions of boy \(B\) and boy \(A\) (Assume, acceleration due to gravity, \(g=10\) \(\mathbf{m} / \mathbf{s}^{2}\) )

141834 A gun and a target are at the same horizontal level separated by a distance of \(600 \mathrm{~m}\). The bullet is fired from the gun with a velocity of \(500 \mathrm{~ms}^{-1}\). In order to hit the target, the gun should be aimed to a height \(h\) above the target. The value of \(h\) is
(Acceleration due to gravity, \(g=10 \mathbf{~ m s}^{-\mathbf{2}}\) )

141835 Ball-1 is dropped from the top of a building from rest. At the same moment, ball-2 is thrown upward towards ball-1 with a speed 14 \(\mathrm{m} / \mathrm{s}\) from a point \(21 \mathrm{~m}\) below the top of building. How far will the ball-1 have dropped when it passes ball-2. (Assume, acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\).)

141831 Assertion : When a body is dropped or thrown upward from the same height, it would reach the ground at the same time.
Reason : Direction of projection does not affect the time of flight.

141836 A ball is thrown vertically upward from the ground at time, \(t=0 \mathrm{~s}\). It passes the top of a tower at \(t=3 \mathrm{~s}\) and \(2 \mathrm{~s}\) later it reaches and its maximum height. The height of the tower is (Acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141837 A ball is projected vertically up from ground. Boy A standing at the window of first floor of a nearly building observes that the time interval between the ball crossing him while going up and the ball crossing him while going down is 2s. Another boy B standing on the second floor notices that time interval between the ball passing him twice, during up motion and down motion is \(1 \mathrm{~s}\). Calculate the difference between the vertical positions of boy \(B\) and boy \(A\) (Assume, acceleration due to gravity, \(g=10\) \(\mathbf{m} / \mathbf{s}^{2}\) )