Explanation:
D Given, \(u=10 \mathrm{~m} / \mathrm{s}, \mathrm{v}=20 \mathrm{~m} / \mathrm{s}, \mathrm{s}=135 \mathrm{~m}\)
We know that, \(\mathrm{v}=\mathrm{u}+\) at
\(20 =10+a t\)
\(a =\frac{10}{t}\)
Now, \(\quad \mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}\)
\(135=10 \times t+\frac{1}{2} \times \frac{10}{t}(t)^{2}\)
\(135=10 t+5 t \Rightarrow 135=15 t\)
\(t=9 \sec\)