01. Speed, Velocity and Acceleration
Motion in One Dimensions

141463 A thin uniform rod of length \(L\) is resting against a wall and the floor as shown in the figure. Its lower end \(A\) is pulled towards left with a constant velocity \(v\). Then the downward velocity \(v^{\prime}\) of the other end \(B\) when the rod makes an angle \(\theta\) with the floor is
original image

1 \(v\)
2 \(v \cos \theta\)
3 \(v \sin \theta\)
4 \(v \cot \theta\)
Motion in One Dimensions

141464 A body starting from rest at \(t=0\) moves along a straight line with a constant acceleration. At \(t\) \(=2 \mathrm{~s}\), the body reverses its direction keeping the acceleration same. The body returns to the initial position at \(t=t_{0}\), then \(t_{0}\) is

1 \(4 \mathrm{~s}\)
2 \((4+2 \sqrt{2}) \mathrm{s}\)
3 \((2+2 \sqrt{2}) \mathrm{s}\)
4 \((4+4 \sqrt{2}) \mathrm{s}\)
Motion in One Dimensions

141465 The velocity of an object moving in a straight line path is given as a function of time by \(v=6 t\) \(-3 t^{2}\), where \(\mathrm{v}\) is in \(\mathrm{ms}^{-1}, t\) is in \(\mathrm{s}\). The average velocity of the object between, \(t=0\) and \(t=2\) is

1 0
2 \(3 \mathrm{~ms}^{-1}\)
3 \(2 \mathrm{~ms}^{-1}\)
4 \(4 \mathrm{~ms}^{-1}\)
Motion in One Dimensions

141466 The velocity time graph of a body moving in a straight line is shown in fig. Find the displacement and distance travelled by the body in 10 seconds.
original image

1 \(50 \mathrm{~m}, 90 \mathrm{~m}\),
2 \(5 \mathrm{~m}, 9 \mathrm{~m}\)
3 \(9 \mathrm{~m}, 5 \mathrm{~m}\)
4 \(90 \mathrm{~m}, 50 \mathrm{~m}\)
Motion in One Dimensions

141463 A thin uniform rod of length \(L\) is resting against a wall and the floor as shown in the figure. Its lower end \(A\) is pulled towards left with a constant velocity \(v\). Then the downward velocity \(v^{\prime}\) of the other end \(B\) when the rod makes an angle \(\theta\) with the floor is
original image

1 \(v\)
2 \(v \cos \theta\)
3 \(v \sin \theta\)
4 \(v \cot \theta\)
Motion in One Dimensions

141464 A body starting from rest at \(t=0\) moves along a straight line with a constant acceleration. At \(t\) \(=2 \mathrm{~s}\), the body reverses its direction keeping the acceleration same. The body returns to the initial position at \(t=t_{0}\), then \(t_{0}\) is

1 \(4 \mathrm{~s}\)
2 \((4+2 \sqrt{2}) \mathrm{s}\)
3 \((2+2 \sqrt{2}) \mathrm{s}\)
4 \((4+4 \sqrt{2}) \mathrm{s}\)
Motion in One Dimensions

141465 The velocity of an object moving in a straight line path is given as a function of time by \(v=6 t\) \(-3 t^{2}\), where \(\mathrm{v}\) is in \(\mathrm{ms}^{-1}, t\) is in \(\mathrm{s}\). The average velocity of the object between, \(t=0\) and \(t=2\) is

1 0
2 \(3 \mathrm{~ms}^{-1}\)
3 \(2 \mathrm{~ms}^{-1}\)
4 \(4 \mathrm{~ms}^{-1}\)
Motion in One Dimensions

141466 The velocity time graph of a body moving in a straight line is shown in fig. Find the displacement and distance travelled by the body in 10 seconds.
original image

1 \(50 \mathrm{~m}, 90 \mathrm{~m}\),
2 \(5 \mathrm{~m}, 9 \mathrm{~m}\)
3 \(9 \mathrm{~m}, 5 \mathrm{~m}\)
4 \(90 \mathrm{~m}, 50 \mathrm{~m}\)
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Motion in One Dimensions

141463 A thin uniform rod of length \(L\) is resting against a wall and the floor as shown in the figure. Its lower end \(A\) is pulled towards left with a constant velocity \(v\). Then the downward velocity \(v^{\prime}\) of the other end \(B\) when the rod makes an angle \(\theta\) with the floor is
original image

1 \(v\)
2 \(v \cos \theta\)
3 \(v \sin \theta\)
4 \(v \cot \theta\)
Motion in One Dimensions

141464 A body starting from rest at \(t=0\) moves along a straight line with a constant acceleration. At \(t\) \(=2 \mathrm{~s}\), the body reverses its direction keeping the acceleration same. The body returns to the initial position at \(t=t_{0}\), then \(t_{0}\) is

1 \(4 \mathrm{~s}\)
2 \((4+2 \sqrt{2}) \mathrm{s}\)
3 \((2+2 \sqrt{2}) \mathrm{s}\)
4 \((4+4 \sqrt{2}) \mathrm{s}\)
Motion in One Dimensions

141465 The velocity of an object moving in a straight line path is given as a function of time by \(v=6 t\) \(-3 t^{2}\), where \(\mathrm{v}\) is in \(\mathrm{ms}^{-1}, t\) is in \(\mathrm{s}\). The average velocity of the object between, \(t=0\) and \(t=2\) is

1 0
2 \(3 \mathrm{~ms}^{-1}\)
3 \(2 \mathrm{~ms}^{-1}\)
4 \(4 \mathrm{~ms}^{-1}\)
Motion in One Dimensions

141466 The velocity time graph of a body moving in a straight line is shown in fig. Find the displacement and distance travelled by the body in 10 seconds.
original image

1 \(50 \mathrm{~m}, 90 \mathrm{~m}\),
2 \(5 \mathrm{~m}, 9 \mathrm{~m}\)
3 \(9 \mathrm{~m}, 5 \mathrm{~m}\)
4 \(90 \mathrm{~m}, 50 \mathrm{~m}\)
Motion in One Dimensions

141463 A thin uniform rod of length \(L\) is resting against a wall and the floor as shown in the figure. Its lower end \(A\) is pulled towards left with a constant velocity \(v\). Then the downward velocity \(v^{\prime}\) of the other end \(B\) when the rod makes an angle \(\theta\) with the floor is
original image

1 \(v\)
2 \(v \cos \theta\)
3 \(v \sin \theta\)
4 \(v \cot \theta\)
Motion in One Dimensions

141464 A body starting from rest at \(t=0\) moves along a straight line with a constant acceleration. At \(t\) \(=2 \mathrm{~s}\), the body reverses its direction keeping the acceleration same. The body returns to the initial position at \(t=t_{0}\), then \(t_{0}\) is

1 \(4 \mathrm{~s}\)
2 \((4+2 \sqrt{2}) \mathrm{s}\)
3 \((2+2 \sqrt{2}) \mathrm{s}\)
4 \((4+4 \sqrt{2}) \mathrm{s}\)
Motion in One Dimensions

141465 The velocity of an object moving in a straight line path is given as a function of time by \(v=6 t\) \(-3 t^{2}\), where \(\mathrm{v}\) is in \(\mathrm{ms}^{-1}, t\) is in \(\mathrm{s}\). The average velocity of the object between, \(t=0\) and \(t=2\) is

1 0
2 \(3 \mathrm{~ms}^{-1}\)
3 \(2 \mathrm{~ms}^{-1}\)
4 \(4 \mathrm{~ms}^{-1}\)
Motion in One Dimensions

141466 The velocity time graph of a body moving in a straight line is shown in fig. Find the displacement and distance travelled by the body in 10 seconds.
original image

1 \(50 \mathrm{~m}, 90 \mathrm{~m}\),
2 \(5 \mathrm{~m}, 9 \mathrm{~m}\)
3 \(9 \mathrm{~m}, 5 \mathrm{~m}\)
4 \(90 \mathrm{~m}, 50 \mathrm{~m}\)