00. Distance and Displacement
Motion in One Dimensions

141310 A body of mass \(0.4 \mathrm{~kg}\) starting at origin at \(t=0\) with a speed of \(10 \mathrm{~m} / \mathrm{s}\) in the positive \(\mathrm{x}\)-axis direction is subjected to a constant force \(F=8\) \(\mathrm{N}\) towards negative \(\mathrm{x}\)-axis. Calculate the position of the particle after 25 second.

1 \(-6000 \mathrm{~m}\)
2 \(-8000 \mathrm{~m}\)
3 \(+4000 \mathrm{~m}\)
4 \(+7000 \mathrm{~m}\)
Motion in One Dimensions

141311 The displacement of a particle starting from rest \((a t=0)\) is given by the relation \(s=6 t^{2}-t^{3}\) The time in seconds when the velocity of the particle would again be zero is

1 3 seconds
2 4 seconds
3 6 seconds
4 10 seconds
Motion in One Dimensions

141312 From the adjoining graph, the distance travelled by the particle in \(4 \mathrm{sec}\) is
original image

1 \(60 \mathrm{~m}\)
2 \(25 \mathrm{~m}\)
3 \(55 \mathrm{~m}\)
4 \(30 \mathrm{~m}\)
Motion in One Dimensions

141313 A train moves from rest with acceleration \(\alpha\) and in time \(t_{1}\) covers a distance \(x\). It then decelerates to rest at constant retardation \(\beta\) for distance \(y\) in time \(t_{2}\). Then,

1 \(\frac{x}{y}=\frac{\beta}{\alpha}\)
2 \(\frac{\beta}{\alpha}=\frac{t_{1}}{t_{2}}\)
3 \(\mathrm{x}=\mathrm{y}\)
4 \(\frac{x}{y}=\frac{\beta t_{1}}{\alpha t_{2}}\)
Motion in One Dimensions

141310 A body of mass \(0.4 \mathrm{~kg}\) starting at origin at \(t=0\) with a speed of \(10 \mathrm{~m} / \mathrm{s}\) in the positive \(\mathrm{x}\)-axis direction is subjected to a constant force \(F=8\) \(\mathrm{N}\) towards negative \(\mathrm{x}\)-axis. Calculate the position of the particle after 25 second.

1 \(-6000 \mathrm{~m}\)
2 \(-8000 \mathrm{~m}\)
3 \(+4000 \mathrm{~m}\)
4 \(+7000 \mathrm{~m}\)
Motion in One Dimensions

141311 The displacement of a particle starting from rest \((a t=0)\) is given by the relation \(s=6 t^{2}-t^{3}\) The time in seconds when the velocity of the particle would again be zero is

1 3 seconds
2 4 seconds
3 6 seconds
4 10 seconds
Motion in One Dimensions

141312 From the adjoining graph, the distance travelled by the particle in \(4 \mathrm{sec}\) is
original image

1 \(60 \mathrm{~m}\)
2 \(25 \mathrm{~m}\)
3 \(55 \mathrm{~m}\)
4 \(30 \mathrm{~m}\)
Motion in One Dimensions

141313 A train moves from rest with acceleration \(\alpha\) and in time \(t_{1}\) covers a distance \(x\). It then decelerates to rest at constant retardation \(\beta\) for distance \(y\) in time \(t_{2}\). Then,

1 \(\frac{x}{y}=\frac{\beta}{\alpha}\)
2 \(\frac{\beta}{\alpha}=\frac{t_{1}}{t_{2}}\)
3 \(\mathrm{x}=\mathrm{y}\)
4 \(\frac{x}{y}=\frac{\beta t_{1}}{\alpha t_{2}}\)
Motion in One Dimensions

141310 A body of mass \(0.4 \mathrm{~kg}\) starting at origin at \(t=0\) with a speed of \(10 \mathrm{~m} / \mathrm{s}\) in the positive \(\mathrm{x}\)-axis direction is subjected to a constant force \(F=8\) \(\mathrm{N}\) towards negative \(\mathrm{x}\)-axis. Calculate the position of the particle after 25 second.

1 \(-6000 \mathrm{~m}\)
2 \(-8000 \mathrm{~m}\)
3 \(+4000 \mathrm{~m}\)
4 \(+7000 \mathrm{~m}\)
Motion in One Dimensions

141311 The displacement of a particle starting from rest \((a t=0)\) is given by the relation \(s=6 t^{2}-t^{3}\) The time in seconds when the velocity of the particle would again be zero is

1 3 seconds
2 4 seconds
3 6 seconds
4 10 seconds
Motion in One Dimensions

141312 From the adjoining graph, the distance travelled by the particle in \(4 \mathrm{sec}\) is
original image

1 \(60 \mathrm{~m}\)
2 \(25 \mathrm{~m}\)
3 \(55 \mathrm{~m}\)
4 \(30 \mathrm{~m}\)
Motion in One Dimensions

141313 A train moves from rest with acceleration \(\alpha\) and in time \(t_{1}\) covers a distance \(x\). It then decelerates to rest at constant retardation \(\beta\) for distance \(y\) in time \(t_{2}\). Then,

1 \(\frac{x}{y}=\frac{\beta}{\alpha}\)
2 \(\frac{\beta}{\alpha}=\frac{t_{1}}{t_{2}}\)
3 \(\mathrm{x}=\mathrm{y}\)
4 \(\frac{x}{y}=\frac{\beta t_{1}}{\alpha t_{2}}\)
Motion in One Dimensions

141310 A body of mass \(0.4 \mathrm{~kg}\) starting at origin at \(t=0\) with a speed of \(10 \mathrm{~m} / \mathrm{s}\) in the positive \(\mathrm{x}\)-axis direction is subjected to a constant force \(F=8\) \(\mathrm{N}\) towards negative \(\mathrm{x}\)-axis. Calculate the position of the particle after 25 second.

1 \(-6000 \mathrm{~m}\)
2 \(-8000 \mathrm{~m}\)
3 \(+4000 \mathrm{~m}\)
4 \(+7000 \mathrm{~m}\)
Motion in One Dimensions

141311 The displacement of a particle starting from rest \((a t=0)\) is given by the relation \(s=6 t^{2}-t^{3}\) The time in seconds when the velocity of the particle would again be zero is

1 3 seconds
2 4 seconds
3 6 seconds
4 10 seconds
Motion in One Dimensions

141312 From the adjoining graph, the distance travelled by the particle in \(4 \mathrm{sec}\) is
original image

1 \(60 \mathrm{~m}\)
2 \(25 \mathrm{~m}\)
3 \(55 \mathrm{~m}\)
4 \(30 \mathrm{~m}\)
Motion in One Dimensions

141313 A train moves from rest with acceleration \(\alpha\) and in time \(t_{1}\) covers a distance \(x\). It then decelerates to rest at constant retardation \(\beta\) for distance \(y\) in time \(t_{2}\). Then,

1 \(\frac{x}{y}=\frac{\beta}{\alpha}\)
2 \(\frac{\beta}{\alpha}=\frac{t_{1}}{t_{2}}\)
3 \(\mathrm{x}=\mathrm{y}\)
4 \(\frac{x}{y}=\frac{\beta t_{1}}{\alpha t_{2}}\)