00. Distance and Displacement
Motion in One Dimensions

141221 The displacement (r) of a particle varies with time ( \(t\) ) according to the relation \(x=\frac{a}{b}\left(1-e^{-b t}\right)\).Then

1 at \(\mathrm{t}=1 / \mathrm{b}\), the displacement will be \(\left(1-\mathrm{e}^{-1}\right)\)
2 at \(t=0\), velocity of the particle is ' \(a b\) '
3 maximum displacement of the particle is \(\frac{a}{b}\)
4 none of the above statement are correct
Motion in One Dimensions

141222 A particle is moving along the \(\mathbf{Y}\)-axis. The position of the particle from the origin as a function of time \((t)\) is given as \(y(t)=10 \mathrm{te}^{-2 t}\). How far is the particle from the origin when it stops momentarily? ( \(\mathrm{y}\) is given in units of metre and \(t\) is in units of second)

1 \(5 \mathrm{~m}\)
2 \(5 \mathrm{e} \mathrm{m}\)
3 \(\frac{5}{\mathrm{e}} \mathrm{m}\)
4 \(10 \mathrm{~m}\)
Motion in One Dimensions

141223 An airplane flies \(400 \mathrm{~m}\) north and \(300 \mathrm{~m}\) south and flies \(1200 \mathrm{~m}\) upwards, then net displacement is

1 \(1400 \mathrm{~m}\)
2 \(1500 \mathrm{~m}\)
3 \(1200 \mathrm{~m}\)
4 \(1100 \mathrm{~m}\)
Motion in One Dimensions

141225 A moving body is covering distances which are proportional to square of the time. Then the acceleration of the body is

1 constant but not zero
2 increasing
3 zero
4 decreasing
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Motion in One Dimensions

141221 The displacement (r) of a particle varies with time ( \(t\) ) according to the relation \(x=\frac{a}{b}\left(1-e^{-b t}\right)\).Then

1 at \(\mathrm{t}=1 / \mathrm{b}\), the displacement will be \(\left(1-\mathrm{e}^{-1}\right)\)
2 at \(t=0\), velocity of the particle is ' \(a b\) '
3 maximum displacement of the particle is \(\frac{a}{b}\)
4 none of the above statement are correct
Motion in One Dimensions

141222 A particle is moving along the \(\mathbf{Y}\)-axis. The position of the particle from the origin as a function of time \((t)\) is given as \(y(t)=10 \mathrm{te}^{-2 t}\). How far is the particle from the origin when it stops momentarily? ( \(\mathrm{y}\) is given in units of metre and \(t\) is in units of second)

1 \(5 \mathrm{~m}\)
2 \(5 \mathrm{e} \mathrm{m}\)
3 \(\frac{5}{\mathrm{e}} \mathrm{m}\)
4 \(10 \mathrm{~m}\)
Motion in One Dimensions

141223 An airplane flies \(400 \mathrm{~m}\) north and \(300 \mathrm{~m}\) south and flies \(1200 \mathrm{~m}\) upwards, then net displacement is

1 \(1400 \mathrm{~m}\)
2 \(1500 \mathrm{~m}\)
3 \(1200 \mathrm{~m}\)
4 \(1100 \mathrm{~m}\)
Motion in One Dimensions

141225 A moving body is covering distances which are proportional to square of the time. Then the acceleration of the body is

1 constant but not zero
2 increasing
3 zero
4 decreasing
Motion in One Dimensions

141221 The displacement (r) of a particle varies with time ( \(t\) ) according to the relation \(x=\frac{a}{b}\left(1-e^{-b t}\right)\).Then

1 at \(\mathrm{t}=1 / \mathrm{b}\), the displacement will be \(\left(1-\mathrm{e}^{-1}\right)\)
2 at \(t=0\), velocity of the particle is ' \(a b\) '
3 maximum displacement of the particle is \(\frac{a}{b}\)
4 none of the above statement are correct
Motion in One Dimensions

141222 A particle is moving along the \(\mathbf{Y}\)-axis. The position of the particle from the origin as a function of time \((t)\) is given as \(y(t)=10 \mathrm{te}^{-2 t}\). How far is the particle from the origin when it stops momentarily? ( \(\mathrm{y}\) is given in units of metre and \(t\) is in units of second)

1 \(5 \mathrm{~m}\)
2 \(5 \mathrm{e} \mathrm{m}\)
3 \(\frac{5}{\mathrm{e}} \mathrm{m}\)
4 \(10 \mathrm{~m}\)
Motion in One Dimensions

141223 An airplane flies \(400 \mathrm{~m}\) north and \(300 \mathrm{~m}\) south and flies \(1200 \mathrm{~m}\) upwards, then net displacement is

1 \(1400 \mathrm{~m}\)
2 \(1500 \mathrm{~m}\)
3 \(1200 \mathrm{~m}\)
4 \(1100 \mathrm{~m}\)
Motion in One Dimensions

141225 A moving body is covering distances which are proportional to square of the time. Then the acceleration of the body is

1 constant but not zero
2 increasing
3 zero
4 decreasing
Motion in One Dimensions

141221 The displacement (r) of a particle varies with time ( \(t\) ) according to the relation \(x=\frac{a}{b}\left(1-e^{-b t}\right)\).Then

1 at \(\mathrm{t}=1 / \mathrm{b}\), the displacement will be \(\left(1-\mathrm{e}^{-1}\right)\)
2 at \(t=0\), velocity of the particle is ' \(a b\) '
3 maximum displacement of the particle is \(\frac{a}{b}\)
4 none of the above statement are correct
Motion in One Dimensions

141222 A particle is moving along the \(\mathbf{Y}\)-axis. The position of the particle from the origin as a function of time \((t)\) is given as \(y(t)=10 \mathrm{te}^{-2 t}\). How far is the particle from the origin when it stops momentarily? ( \(\mathrm{y}\) is given in units of metre and \(t\) is in units of second)

1 \(5 \mathrm{~m}\)
2 \(5 \mathrm{e} \mathrm{m}\)
3 \(\frac{5}{\mathrm{e}} \mathrm{m}\)
4 \(10 \mathrm{~m}\)
Motion in One Dimensions

141223 An airplane flies \(400 \mathrm{~m}\) north and \(300 \mathrm{~m}\) south and flies \(1200 \mathrm{~m}\) upwards, then net displacement is

1 \(1400 \mathrm{~m}\)
2 \(1500 \mathrm{~m}\)
3 \(1200 \mathrm{~m}\)
4 \(1100 \mathrm{~m}\)
Motion in One Dimensions

141225 A moving body is covering distances which are proportional to square of the time. Then the acceleration of the body is

1 constant but not zero
2 increasing
3 zero
4 decreasing