00. Distance and Displacement
Motion in One Dimensions

141160 A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point
original image

1 \(\mathrm{B}\)
2 \(\mathrm{C}\)
3 \(\mathrm{D}\)
4 A
Motion in One Dimensions

141162 The velocity of a particle is \(v=v_{0}+g t+F t^{2}\). Its position is \(x=0\) at \(t=0\), then its displacement after time \((t=1)\) is

1 \(\mathrm{v}_{0}+\mathrm{g}+\mathrm{F}\)
2 \(\mathrm{v}_{0}+\frac{\mathrm{g}}{2}+\frac{\mathrm{F}}{3}\)
3 \(\mathrm{v}_{0}+\frac{\mathrm{g}}{2}+\mathrm{F}\)
4 \(\mathrm{v}_{0}+2 \mathrm{~g}+3 \mathrm{~F}\)
Motion in One Dimensions

141163 The displacement ' \(x\) ' (in meter) of a particle of mass ' \(\mathrm{m}\) ' (in \(\mathrm{kg}\) ) moving in one dimension under the action of a force, is related to time ' \(t\) ' (in sec) by, \(t=\sqrt{x}+3\). The displacement of the particle when its velocity is zero, will be

1 \(6 \mathrm{~m}\)
2 \(2 \mathrm{~m}\)
3 \(4 \mathrm{~m}\)
4 \(0 \mathrm{~m}\)
Motion in One Dimensions

141164 A track is in square shape. The length of each side is ' \(a\) '. There exists a pole at each corner as shown below. The person who walks on the track starts at the \(1^{\text {st }}\) pole and reach the \(4^{\text {th }}\) pole. The ratio of distance travelled by the person to displacement is
original image

1 \(\frac{1}{3}\)
2 3
3 \(\frac{2}{3}\)
4 \(\frac{3}{2}\)
Motion in One Dimensions

141160 A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point
original image

1 \(\mathrm{B}\)
2 \(\mathrm{C}\)
3 \(\mathrm{D}\)
4 A
Motion in One Dimensions

141162 The velocity of a particle is \(v=v_{0}+g t+F t^{2}\). Its position is \(x=0\) at \(t=0\), then its displacement after time \((t=1)\) is

1 \(\mathrm{v}_{0}+\mathrm{g}+\mathrm{F}\)
2 \(\mathrm{v}_{0}+\frac{\mathrm{g}}{2}+\frac{\mathrm{F}}{3}\)
3 \(\mathrm{v}_{0}+\frac{\mathrm{g}}{2}+\mathrm{F}\)
4 \(\mathrm{v}_{0}+2 \mathrm{~g}+3 \mathrm{~F}\)
Motion in One Dimensions

141163 The displacement ' \(x\) ' (in meter) of a particle of mass ' \(\mathrm{m}\) ' (in \(\mathrm{kg}\) ) moving in one dimension under the action of a force, is related to time ' \(t\) ' (in sec) by, \(t=\sqrt{x}+3\). The displacement of the particle when its velocity is zero, will be

1 \(6 \mathrm{~m}\)
2 \(2 \mathrm{~m}\)
3 \(4 \mathrm{~m}\)
4 \(0 \mathrm{~m}\)
Motion in One Dimensions

141164 A track is in square shape. The length of each side is ' \(a\) '. There exists a pole at each corner as shown below. The person who walks on the track starts at the \(1^{\text {st }}\) pole and reach the \(4^{\text {th }}\) pole. The ratio of distance travelled by the person to displacement is
original image

1 \(\frac{1}{3}\)
2 3
3 \(\frac{2}{3}\)
4 \(\frac{3}{2}\)
Motion in One Dimensions

141160 A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point
original image

1 \(\mathrm{B}\)
2 \(\mathrm{C}\)
3 \(\mathrm{D}\)
4 A
Motion in One Dimensions

141162 The velocity of a particle is \(v=v_{0}+g t+F t^{2}\). Its position is \(x=0\) at \(t=0\), then its displacement after time \((t=1)\) is

1 \(\mathrm{v}_{0}+\mathrm{g}+\mathrm{F}\)
2 \(\mathrm{v}_{0}+\frac{\mathrm{g}}{2}+\frac{\mathrm{F}}{3}\)
3 \(\mathrm{v}_{0}+\frac{\mathrm{g}}{2}+\mathrm{F}\)
4 \(\mathrm{v}_{0}+2 \mathrm{~g}+3 \mathrm{~F}\)
Motion in One Dimensions

141163 The displacement ' \(x\) ' (in meter) of a particle of mass ' \(\mathrm{m}\) ' (in \(\mathrm{kg}\) ) moving in one dimension under the action of a force, is related to time ' \(t\) ' (in sec) by, \(t=\sqrt{x}+3\). The displacement of the particle when its velocity is zero, will be

1 \(6 \mathrm{~m}\)
2 \(2 \mathrm{~m}\)
3 \(4 \mathrm{~m}\)
4 \(0 \mathrm{~m}\)
Motion in One Dimensions

141164 A track is in square shape. The length of each side is ' \(a\) '. There exists a pole at each corner as shown below. The person who walks on the track starts at the \(1^{\text {st }}\) pole and reach the \(4^{\text {th }}\) pole. The ratio of distance travelled by the person to displacement is
original image

1 \(\frac{1}{3}\)
2 3
3 \(\frac{2}{3}\)
4 \(\frac{3}{2}\)
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Motion in One Dimensions

141160 A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point
original image

1 \(\mathrm{B}\)
2 \(\mathrm{C}\)
3 \(\mathrm{D}\)
4 A
Motion in One Dimensions

141162 The velocity of a particle is \(v=v_{0}+g t+F t^{2}\). Its position is \(x=0\) at \(t=0\), then its displacement after time \((t=1)\) is

1 \(\mathrm{v}_{0}+\mathrm{g}+\mathrm{F}\)
2 \(\mathrm{v}_{0}+\frac{\mathrm{g}}{2}+\frac{\mathrm{F}}{3}\)
3 \(\mathrm{v}_{0}+\frac{\mathrm{g}}{2}+\mathrm{F}\)
4 \(\mathrm{v}_{0}+2 \mathrm{~g}+3 \mathrm{~F}\)
Motion in One Dimensions

141163 The displacement ' \(x\) ' (in meter) of a particle of mass ' \(\mathrm{m}\) ' (in \(\mathrm{kg}\) ) moving in one dimension under the action of a force, is related to time ' \(t\) ' (in sec) by, \(t=\sqrt{x}+3\). The displacement of the particle when its velocity is zero, will be

1 \(6 \mathrm{~m}\)
2 \(2 \mathrm{~m}\)
3 \(4 \mathrm{~m}\)
4 \(0 \mathrm{~m}\)
Motion in One Dimensions

141164 A track is in square shape. The length of each side is ' \(a\) '. There exists a pole at each corner as shown below. The person who walks on the track starts at the \(1^{\text {st }}\) pole and reach the \(4^{\text {th }}\) pole. The ratio of distance travelled by the person to displacement is
original image

1 \(\frac{1}{3}\)
2 3
3 \(\frac{2}{3}\)
4 \(\frac{3}{2}\)