139991
The pitch of a screw gauge is \(0.5 \mathrm{~mm}\). Its head scale contains 50 divisions The least count of the screw gauge is
1 \(0.0001 \mathrm{~cm}\)
2 \(0.0025 \mathrm{~cm}\)
3 \(0.01 \mathrm{~cm}\)
4 \(0.001 \mathrm{~cm}\)
Explanation:
D \(\mathrm{LC}=\frac{\text { Pitch of screw }}{20 \text { of head serew divisions }}\) \(\mathrm{LC}=\frac{0.5 \mathrm{~mm}}{50}=\frac{0.1 \mathrm{~mm}}{10}\) \(\mathrm{LC}=0.1 \times 0.1=0.01 \mathrm{~mm}=0.001 \mathrm{~cm}\).
SCRA-2013
Units and Measurements
139992
Each division on the main scale is \(1 \mathrm{~mm}\). Which one of the following vernier scales will give vernier constant equal to \(0.01 \mathrm{~mm}\) ?
1 \(9 \mathrm{~mm}\) divided by 10 divisions
2 \(95 \mathrm{~mm}\) divided by 100 divisions
3 \(99 \mathrm{~mm}\) divided by 100 divisions
4 \(9 \mathrm{~mm}\) divided by 100 divisions
Explanation:
C Least count \(=1\) MSD -1 VSD \(1 \mathrm{VSD} =1 \mathrm{MSD}-\mathrm{LC}\) \(=1 \mathrm{~mm}-0.01 \mathrm{~mm}=0.99 \mathrm{~mm}\) \(\therefore 1 \mathrm{VSD}=99 \mathrm{~mm}\) divided by 100 divisions.
SCRA-2010
Units and Measurements
139995
A spherometer has 20 threads per cm. Its circular scale has 100 divisions. The least count of the sphere is
1 \(5 \mu \mathrm{m}\)
2 \(50 \mu \mathrm{m}\)
3 \(0.5 \mu \mathrm{m}\)
4 \(0.05 \mu \mathrm{m}\)
Explanation:
A Here, for 20 threads per \(\mathrm{cm}\) pitch \(=0.05 \mathrm{~cm}\) L.C. \(=\frac{\text { Pitch }}{\text { No. of division }}=\frac{0.05}{100} \mathrm{~cm}=5 \times 10^{-6} \mathrm{~m}\) \(=5 \mu \mathrm{m}\)
SRMJEE - 2015
Units and Measurements
139974
An experiment is performed to find the refractive index of glass using a travelling microscope. In this experiment, distances are measured by
1 a vernier scale provided on the microscope
2 a standard laboratory scale
3 a meter scale provided on the microscope
4 a screw gauge provided on the microscope
Explanation:
A To find the refraction index of glass using a travelling microscope, a Vernier scale is provided on the microscope is used
139991
The pitch of a screw gauge is \(0.5 \mathrm{~mm}\). Its head scale contains 50 divisions The least count of the screw gauge is
1 \(0.0001 \mathrm{~cm}\)
2 \(0.0025 \mathrm{~cm}\)
3 \(0.01 \mathrm{~cm}\)
4 \(0.001 \mathrm{~cm}\)
Explanation:
D \(\mathrm{LC}=\frac{\text { Pitch of screw }}{20 \text { of head serew divisions }}\) \(\mathrm{LC}=\frac{0.5 \mathrm{~mm}}{50}=\frac{0.1 \mathrm{~mm}}{10}\) \(\mathrm{LC}=0.1 \times 0.1=0.01 \mathrm{~mm}=0.001 \mathrm{~cm}\).
SCRA-2013
Units and Measurements
139992
Each division on the main scale is \(1 \mathrm{~mm}\). Which one of the following vernier scales will give vernier constant equal to \(0.01 \mathrm{~mm}\) ?
1 \(9 \mathrm{~mm}\) divided by 10 divisions
2 \(95 \mathrm{~mm}\) divided by 100 divisions
3 \(99 \mathrm{~mm}\) divided by 100 divisions
4 \(9 \mathrm{~mm}\) divided by 100 divisions
Explanation:
C Least count \(=1\) MSD -1 VSD \(1 \mathrm{VSD} =1 \mathrm{MSD}-\mathrm{LC}\) \(=1 \mathrm{~mm}-0.01 \mathrm{~mm}=0.99 \mathrm{~mm}\) \(\therefore 1 \mathrm{VSD}=99 \mathrm{~mm}\) divided by 100 divisions.
SCRA-2010
Units and Measurements
139995
A spherometer has 20 threads per cm. Its circular scale has 100 divisions. The least count of the sphere is
1 \(5 \mu \mathrm{m}\)
2 \(50 \mu \mathrm{m}\)
3 \(0.5 \mu \mathrm{m}\)
4 \(0.05 \mu \mathrm{m}\)
Explanation:
A Here, for 20 threads per \(\mathrm{cm}\) pitch \(=0.05 \mathrm{~cm}\) L.C. \(=\frac{\text { Pitch }}{\text { No. of division }}=\frac{0.05}{100} \mathrm{~cm}=5 \times 10^{-6} \mathrm{~m}\) \(=5 \mu \mathrm{m}\)
SRMJEE - 2015
Units and Measurements
139974
An experiment is performed to find the refractive index of glass using a travelling microscope. In this experiment, distances are measured by
1 a vernier scale provided on the microscope
2 a standard laboratory scale
3 a meter scale provided on the microscope
4 a screw gauge provided on the microscope
Explanation:
A To find the refraction index of glass using a travelling microscope, a Vernier scale is provided on the microscope is used
139991
The pitch of a screw gauge is \(0.5 \mathrm{~mm}\). Its head scale contains 50 divisions The least count of the screw gauge is
1 \(0.0001 \mathrm{~cm}\)
2 \(0.0025 \mathrm{~cm}\)
3 \(0.01 \mathrm{~cm}\)
4 \(0.001 \mathrm{~cm}\)
Explanation:
D \(\mathrm{LC}=\frac{\text { Pitch of screw }}{20 \text { of head serew divisions }}\) \(\mathrm{LC}=\frac{0.5 \mathrm{~mm}}{50}=\frac{0.1 \mathrm{~mm}}{10}\) \(\mathrm{LC}=0.1 \times 0.1=0.01 \mathrm{~mm}=0.001 \mathrm{~cm}\).
SCRA-2013
Units and Measurements
139992
Each division on the main scale is \(1 \mathrm{~mm}\). Which one of the following vernier scales will give vernier constant equal to \(0.01 \mathrm{~mm}\) ?
1 \(9 \mathrm{~mm}\) divided by 10 divisions
2 \(95 \mathrm{~mm}\) divided by 100 divisions
3 \(99 \mathrm{~mm}\) divided by 100 divisions
4 \(9 \mathrm{~mm}\) divided by 100 divisions
Explanation:
C Least count \(=1\) MSD -1 VSD \(1 \mathrm{VSD} =1 \mathrm{MSD}-\mathrm{LC}\) \(=1 \mathrm{~mm}-0.01 \mathrm{~mm}=0.99 \mathrm{~mm}\) \(\therefore 1 \mathrm{VSD}=99 \mathrm{~mm}\) divided by 100 divisions.
SCRA-2010
Units and Measurements
139995
A spherometer has 20 threads per cm. Its circular scale has 100 divisions. The least count of the sphere is
1 \(5 \mu \mathrm{m}\)
2 \(50 \mu \mathrm{m}\)
3 \(0.5 \mu \mathrm{m}\)
4 \(0.05 \mu \mathrm{m}\)
Explanation:
A Here, for 20 threads per \(\mathrm{cm}\) pitch \(=0.05 \mathrm{~cm}\) L.C. \(=\frac{\text { Pitch }}{\text { No. of division }}=\frac{0.05}{100} \mathrm{~cm}=5 \times 10^{-6} \mathrm{~m}\) \(=5 \mu \mathrm{m}\)
SRMJEE - 2015
Units and Measurements
139974
An experiment is performed to find the refractive index of glass using a travelling microscope. In this experiment, distances are measured by
1 a vernier scale provided on the microscope
2 a standard laboratory scale
3 a meter scale provided on the microscope
4 a screw gauge provided on the microscope
Explanation:
A To find the refraction index of glass using a travelling microscope, a Vernier scale is provided on the microscope is used
139991
The pitch of a screw gauge is \(0.5 \mathrm{~mm}\). Its head scale contains 50 divisions The least count of the screw gauge is
1 \(0.0001 \mathrm{~cm}\)
2 \(0.0025 \mathrm{~cm}\)
3 \(0.01 \mathrm{~cm}\)
4 \(0.001 \mathrm{~cm}\)
Explanation:
D \(\mathrm{LC}=\frac{\text { Pitch of screw }}{20 \text { of head serew divisions }}\) \(\mathrm{LC}=\frac{0.5 \mathrm{~mm}}{50}=\frac{0.1 \mathrm{~mm}}{10}\) \(\mathrm{LC}=0.1 \times 0.1=0.01 \mathrm{~mm}=0.001 \mathrm{~cm}\).
SCRA-2013
Units and Measurements
139992
Each division on the main scale is \(1 \mathrm{~mm}\). Which one of the following vernier scales will give vernier constant equal to \(0.01 \mathrm{~mm}\) ?
1 \(9 \mathrm{~mm}\) divided by 10 divisions
2 \(95 \mathrm{~mm}\) divided by 100 divisions
3 \(99 \mathrm{~mm}\) divided by 100 divisions
4 \(9 \mathrm{~mm}\) divided by 100 divisions
Explanation:
C Least count \(=1\) MSD -1 VSD \(1 \mathrm{VSD} =1 \mathrm{MSD}-\mathrm{LC}\) \(=1 \mathrm{~mm}-0.01 \mathrm{~mm}=0.99 \mathrm{~mm}\) \(\therefore 1 \mathrm{VSD}=99 \mathrm{~mm}\) divided by 100 divisions.
SCRA-2010
Units and Measurements
139995
A spherometer has 20 threads per cm. Its circular scale has 100 divisions. The least count of the sphere is
1 \(5 \mu \mathrm{m}\)
2 \(50 \mu \mathrm{m}\)
3 \(0.5 \mu \mathrm{m}\)
4 \(0.05 \mu \mathrm{m}\)
Explanation:
A Here, for 20 threads per \(\mathrm{cm}\) pitch \(=0.05 \mathrm{~cm}\) L.C. \(=\frac{\text { Pitch }}{\text { No. of division }}=\frac{0.05}{100} \mathrm{~cm}=5 \times 10^{-6} \mathrm{~m}\) \(=5 \mu \mathrm{m}\)
SRMJEE - 2015
Units and Measurements
139974
An experiment is performed to find the refractive index of glass using a travelling microscope. In this experiment, distances are measured by
1 a vernier scale provided on the microscope
2 a standard laboratory scale
3 a meter scale provided on the microscope
4 a screw gauge provided on the microscope
Explanation:
A To find the refraction index of glass using a travelling microscope, a Vernier scale is provided on the microscope is used
