139872 The current voltage relation of diode is given by \(I=\left(e^{1000 V / T}-1\right) \mathrm{mA}\), where the applied voltage \(V\) is in volt and the temperature \(T\) is in kelvin. If a student makes an error measuring \(\pm 0.01 \mathrm{~V}\) while measuring the current of \(5 \mathrm{~mA}\) at \(300 \mathrm{~K}\), what will be the error in the value of current in \(\mathbf{m A}\) ?
139873 The length of a pendulum is measured as 1.01 \(\mathrm{m}\) and time for 30 oscillations is measured as one minute \(3 \mathrm{~s}\). Error length is \(0.01 \mathrm{~m}\) and error in time is \(3 \mathrm{~s}\). The percentage error in the measurement of acceleration due to gravity is
139872 The current voltage relation of diode is given by \(I=\left(e^{1000 V / T}-1\right) \mathrm{mA}\), where the applied voltage \(V\) is in volt and the temperature \(T\) is in kelvin. If a student makes an error measuring \(\pm 0.01 \mathrm{~V}\) while measuring the current of \(5 \mathrm{~mA}\) at \(300 \mathrm{~K}\), what will be the error in the value of current in \(\mathbf{m A}\) ?
139873 The length of a pendulum is measured as 1.01 \(\mathrm{m}\) and time for 30 oscillations is measured as one minute \(3 \mathrm{~s}\). Error length is \(0.01 \mathrm{~m}\) and error in time is \(3 \mathrm{~s}\). The percentage error in the measurement of acceleration due to gravity is
139872 The current voltage relation of diode is given by \(I=\left(e^{1000 V / T}-1\right) \mathrm{mA}\), where the applied voltage \(V\) is in volt and the temperature \(T\) is in kelvin. If a student makes an error measuring \(\pm 0.01 \mathrm{~V}\) while measuring the current of \(5 \mathrm{~mA}\) at \(300 \mathrm{~K}\), what will be the error in the value of current in \(\mathbf{m A}\) ?
139873 The length of a pendulum is measured as 1.01 \(\mathrm{m}\) and time for 30 oscillations is measured as one minute \(3 \mathrm{~s}\). Error length is \(0.01 \mathrm{~m}\) and error in time is \(3 \mathrm{~s}\). The percentage error in the measurement of acceleration due to gravity is
139872 The current voltage relation of diode is given by \(I=\left(e^{1000 V / T}-1\right) \mathrm{mA}\), where the applied voltage \(V\) is in volt and the temperature \(T\) is in kelvin. If a student makes an error measuring \(\pm 0.01 \mathrm{~V}\) while measuring the current of \(5 \mathrm{~mA}\) at \(300 \mathrm{~K}\), what will be the error in the value of current in \(\mathbf{m A}\) ?
139873 The length of a pendulum is measured as 1.01 \(\mathrm{m}\) and time for 30 oscillations is measured as one minute \(3 \mathrm{~s}\). Error length is \(0.01 \mathrm{~m}\) and error in time is \(3 \mathrm{~s}\). The percentage error in the measurement of acceleration due to gravity is
139872 The current voltage relation of diode is given by \(I=\left(e^{1000 V / T}-1\right) \mathrm{mA}\), where the applied voltage \(V\) is in volt and the temperature \(T\) is in kelvin. If a student makes an error measuring \(\pm 0.01 \mathrm{~V}\) while measuring the current of \(5 \mathrm{~mA}\) at \(300 \mathrm{~K}\), what will be the error in the value of current in \(\mathbf{m A}\) ?
139873 The length of a pendulum is measured as 1.01 \(\mathrm{m}\) and time for 30 oscillations is measured as one minute \(3 \mathrm{~s}\). Error length is \(0.01 \mathrm{~m}\) and error in time is \(3 \mathrm{~s}\). The percentage error in the measurement of acceleration due to gravity is