QBManager

AMINES

278850 In Gattermann reaction, a diazonium group is replaced by $\underset{―}{X}$ using $\underset{―}{Y} . \underset{―}{X}$ and $\underset{―}{Y}$ are
$\underset{―}{X}$ - $Y$

1

{Cl}^{Θ}

-

Cu / HCl

2

{Cl}^{\oplus}

-

{CuCl}_{2} / HCl

3

{Cl}^{Θ}

-

{CuCl}_{2} / HCl

4

{Cl}_{2}

-

{Cu}_{2} O / HCl

VITEEE- 2009

AMINES

278857 Which of the following is the most stable diazonium salt?

1

C_{6} H_{5} {CH}_{2} N_{2}^{+} X^{-}

2

{CH}_{3} N_{2}^{+} X^{-}

3

{CH}_{3} {CH}_{2} N_{2}^{+} X^{-}

4

C_{6} H_{5} N_{2}^{+} X^{-}

MHT CET-2015

AMINES

278858 Reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution results in the formation of the following compound

1 hydrazobenzene

2 azobenzene

3 aniline

4 phenyl hydroxyl amine

Explanation:

The reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution to give the hydrazobenzene as a final product.
original image

AP-EAMCET- (Engg.) - 2010

AMINES

278859 In the diazotization of aryl amine the use of nitrous acid is

1 it suppresses hydrolysis of phenol

2 it is a source of electrophilic nitrosonium ion

3 it neutralizes the base liberated

4 all of the above

Explanation:

In diazotization reaction of aryl amine the electrophile is nitrosonium ion.
$O = N - OH + H^{+} ⇌ O = N - \overset{+}{O} H_{2} \to \underset{\begin{matrix} Nitrosonium \\ ion \end{matrix}}{\overset{+}{N}} + H_{2} O$

AMU-2011

AMINES

278860 Nitrobenzene can be converted into azobenzene by reduction with

1

Zn, {NH}_{4} Cl, Δ

2

Zn / NaOH, {CH}_{3} OH

3

Zn / NaOH

4

{LiAlH}_{4}

, ether

Explanation:

Nitrobenzene can be converted into azobenzene, on reduction in the presence of $Zn / NaOH$ in ${CH}_{3} OH$ .
original image

VITEEE- 2010

AMINES

278850 In Gattermann reaction, a diazonium group is replaced by $\underset{―}{X}$ using $\underset{―}{Y} . \underset{―}{X}$ and $\underset{―}{Y}$ are
$\underset{―}{X}$ - $Y$

1

{Cl}^{Θ}

-

Cu / HCl

2

{Cl}^{\oplus}

-

{CuCl}_{2} / HCl

3

{Cl}^{Θ}

-

{CuCl}_{2} / HCl

4

{Cl}_{2}

-

{Cu}_{2} O / HCl

VITEEE- 2009

AMINES

278857 Which of the following is the most stable diazonium salt?

1

C_{6} H_{5} {CH}_{2} N_{2}^{+} X^{-}

2

{CH}_{3} N_{2}^{+} X^{-}

3

{CH}_{3} {CH}_{2} N_{2}^{+} X^{-}

4

C_{6} H_{5} N_{2}^{+} X^{-}

MHT CET-2015

AMINES

278858 Reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution results in the formation of the following compound

1 hydrazobenzene

2 azobenzene

3 aniline

4 phenyl hydroxyl amine

Explanation:

The reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution to give the hydrazobenzene as a final product.
original image

AP-EAMCET- (Engg.) - 2010

AMINES

278859 In the diazotization of aryl amine the use of nitrous acid is

1 it suppresses hydrolysis of phenol

2 it is a source of electrophilic nitrosonium ion

3 it neutralizes the base liberated

4 all of the above

Explanation:

In diazotization reaction of aryl amine the electrophile is nitrosonium ion.
$O = N - OH + H^{+} ⇌ O = N - \overset{+}{O} H_{2} \to \underset{\begin{matrix} Nitrosonium \\ ion \end{matrix}}{\overset{+}{N}} + H_{2} O$

AMU-2011

AMINES

278860 Nitrobenzene can be converted into azobenzene by reduction with

1

Zn, {NH}_{4} Cl, Δ

2

Zn / NaOH, {CH}_{3} OH

3

Zn / NaOH

4

{LiAlH}_{4}

, ether

Explanation:

Nitrobenzene can be converted into azobenzene, on reduction in the presence of $Zn / NaOH$ in ${CH}_{3} OH$ .
original image

VITEEE- 2010

AMINES

278850 In Gattermann reaction, a diazonium group is replaced by $\underset{―}{X}$ using $\underset{―}{Y} . \underset{―}{X}$ and $\underset{―}{Y}$ are
$\underset{―}{X}$ - $Y$

1

{Cl}^{Θ}

-

Cu / HCl

2

{Cl}^{\oplus}

-

{CuCl}_{2} / HCl

3

{Cl}^{Θ}

-

{CuCl}_{2} / HCl

4

{Cl}_{2}

-

{Cu}_{2} O / HCl

VITEEE- 2009

AMINES

278857 Which of the following is the most stable diazonium salt?

1

C_{6} H_{5} {CH}_{2} N_{2}^{+} X^{-}

2

{CH}_{3} N_{2}^{+} X^{-}

3

{CH}_{3} {CH}_{2} N_{2}^{+} X^{-}

4

C_{6} H_{5} N_{2}^{+} X^{-}

MHT CET-2015

AMINES

278858 Reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution results in the formation of the following compound

1 hydrazobenzene

2 azobenzene

3 aniline

4 phenyl hydroxyl amine

Explanation:

The reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution to give the hydrazobenzene as a final product.
original image

AP-EAMCET- (Engg.) - 2010

AMINES

278859 In the diazotization of aryl amine the use of nitrous acid is

1 it suppresses hydrolysis of phenol

2 it is a source of electrophilic nitrosonium ion

3 it neutralizes the base liberated

4 all of the above

Explanation:

In diazotization reaction of aryl amine the electrophile is nitrosonium ion.
$O = N - OH + H^{+} ⇌ O = N - \overset{+}{O} H_{2} \to \underset{\begin{matrix} Nitrosonium \\ ion \end{matrix}}{\overset{+}{N}} + H_{2} O$

AMU-2011

AMINES

278860 Nitrobenzene can be converted into azobenzene by reduction with

1

Zn, {NH}_{4} Cl, Δ

2

Zn / NaOH, {CH}_{3} OH

3

Zn / NaOH

4

{LiAlH}_{4}

, ether

Explanation:

Nitrobenzene can be converted into azobenzene, on reduction in the presence of $Zn / NaOH$ in ${CH}_{3} OH$ .
original image

VITEEE- 2010

AMINES

278850 In Gattermann reaction, a diazonium group is replaced by $\underset{―}{X}$ using $\underset{―}{Y} . \underset{―}{X}$ and $\underset{―}{Y}$ are
$\underset{―}{X}$ - $Y$

1

{Cl}^{Θ}

-

Cu / HCl

2

{Cl}^{\oplus}

-

{CuCl}_{2} / HCl

3

{Cl}^{Θ}

-

{CuCl}_{2} / HCl

4

{Cl}_{2}

-

{Cu}_{2} O / HCl

VITEEE- 2009

AMINES

278857 Which of the following is the most stable diazonium salt?

1

C_{6} H_{5} {CH}_{2} N_{2}^{+} X^{-}

2

{CH}_{3} N_{2}^{+} X^{-}

3

{CH}_{3} {CH}_{2} N_{2}^{+} X^{-}

4

C_{6} H_{5} N_{2}^{+} X^{-}

MHT CET-2015

AMINES

278858 Reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution results in the formation of the following compound

1 hydrazobenzene

2 azobenzene

3 aniline

4 phenyl hydroxyl amine

Explanation:

The reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution to give the hydrazobenzene as a final product.
original image

AP-EAMCET- (Engg.) - 2010

AMINES

278859 In the diazotization of aryl amine the use of nitrous acid is

1 it suppresses hydrolysis of phenol

2 it is a source of electrophilic nitrosonium ion

3 it neutralizes the base liberated

4 all of the above

Explanation:

In diazotization reaction of aryl amine the electrophile is nitrosonium ion.
$O = N - OH + H^{+} ⇌ O = N - \overset{+}{O} H_{2} \to \underset{\begin{matrix} Nitrosonium \\ ion \end{matrix}}{\overset{+}{N}} + H_{2} O$

AMU-2011

AMINES

278860 Nitrobenzene can be converted into azobenzene by reduction with

1

Zn, {NH}_{4} Cl, Δ

2

Zn / NaOH, {CH}_{3} OH

3

Zn / NaOH

4

{LiAlH}_{4}

, ether

Explanation:

Nitrobenzene can be converted into azobenzene, on reduction in the presence of $Zn / NaOH$ in ${CH}_{3} OH$ .
original image

VITEEE- 2010

AMINES

278850 In Gattermann reaction, a diazonium group is replaced by $\underset{―}{X}$ using $\underset{―}{Y} . \underset{―}{X}$ and $\underset{―}{Y}$ are
$\underset{―}{X}$ - $Y$

1

{Cl}^{Θ}

-

Cu / HCl

2

{Cl}^{\oplus}

-

{CuCl}_{2} / HCl

3

{Cl}^{Θ}

-

{CuCl}_{2} / HCl

4

{Cl}_{2}

-

{Cu}_{2} O / HCl

VITEEE- 2009

AMINES

278857 Which of the following is the most stable diazonium salt?

1

C_{6} H_{5} {CH}_{2} N_{2}^{+} X^{-}

2

{CH}_{3} N_{2}^{+} X^{-}

3

{CH}_{3} {CH}_{2} N_{2}^{+} X^{-}

4

C_{6} H_{5} N_{2}^{+} X^{-}

MHT CET-2015

AMINES

278858 Reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution results in the formation of the following compound

1 hydrazobenzene

2 azobenzene

3 aniline

4 phenyl hydroxyl amine

Explanation:

The reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution to give the hydrazobenzene as a final product.
original image

AP-EAMCET- (Engg.) - 2010

AMINES

278859 In the diazotization of aryl amine the use of nitrous acid is

1 it suppresses hydrolysis of phenol

2 it is a source of electrophilic nitrosonium ion

3 it neutralizes the base liberated

4 all of the above

Explanation:

In diazotization reaction of aryl amine the electrophile is nitrosonium ion.
$O = N - OH + H^{+} ⇌ O = N - \overset{+}{O} H_{2} \to \underset{\begin{matrix} Nitrosonium \\ ion \end{matrix}}{\overset{+}{N}} + H_{2} O$

AMU-2011

AMINES

278860 Nitrobenzene can be converted into azobenzene by reduction with

1

Zn, {NH}_{4} Cl, Δ

2

Zn / NaOH, {CH}_{3} OH

3

Zn / NaOH

4

{LiAlH}_{4}

, ether

Explanation:

Nitrobenzene can be converted into azobenzene, on reduction in the presence of $Zn / NaOH$ in ${CH}_{3} OH$ .
original image

VITEEE- 2010