91089
The major product obtained when chlorobenzene is nitrated with $\mathrm{HNO}_{3}+$ conc. $\mathrm{H}_{2} \mathrm{SO}_{4}$ is
1 1-chloro-4-nitrobenzene
2 1-chloro-2-nitrobenzene
3 1-chloro-3-nitrobenzene
4 1-chloro-1-nitrobenzene.
Explanation:
The nitration of chlorobenzene give the two product which one is 1-chloro-2-nitrobenzene and other 1-chloro-4-nitrobenzene. The major product is 1chloror-4-nitrobenzene (Chloronitrobenzene) because 1chloro-2-nitrobenzene is disfavoured due to inductive effect and steric hindrance.
**[COMEDK 2014]**
HALOALKANES AND HALOARENES
91092
Amongst the following, the compound which is most difficult to sulphonate is-
1 benzene
2 nitrobenzene
3 toluene
4 chlorobenzene
Explanation:
$\mathrm{NO}_{2}$ group is electron withdrawing group and deactivation group. Sulphonation of nitrobenzene is most difficult.
**[BCECE-2011]**
HALOALKANES AND HALOARENES
91093
Which one is most reactive towards $S_{N} 1$ reaction?
In $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{C}\left(\mathrm{CH}_{3}\right)\left(\mathrm{C}_{6} \mathrm{H}_{5}\right) \mathrm{Br}$ formed carbocation will be $3^{\circ}$ and order of reactivity for $\mathrm{S}_{\mathrm{N}} 1$ will be $3^{\circ}>2^{\circ}>1^{\circ}$. So - $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{C}\left(\mathrm{CH}_{3}\right)\left(\mathrm{C}_{6} \mathrm{H}_{5}\right) \mathrm{Br}$ is most reactive towards $\mathrm{S}_{\mathrm{N}} 1$ reaction.
**[AIPMT -2010]**
HALOALKANES AND HALOARENES
91094
The best method to separate the mixture of ortho and Para nitrophenol $(1: 1)$ is
1 vaporisation
2 colour spectrum
3 distillation
4 crystallistion
Explanation:
Ortho and para nitrophenol is separated by distillation because p-nitrophenol has higher boiling point than p-nitrophenol due to H-bonding.
91089
The major product obtained when chlorobenzene is nitrated with $\mathrm{HNO}_{3}+$ conc. $\mathrm{H}_{2} \mathrm{SO}_{4}$ is
1 1-chloro-4-nitrobenzene
2 1-chloro-2-nitrobenzene
3 1-chloro-3-nitrobenzene
4 1-chloro-1-nitrobenzene.
Explanation:
The nitration of chlorobenzene give the two product which one is 1-chloro-2-nitrobenzene and other 1-chloro-4-nitrobenzene. The major product is 1chloror-4-nitrobenzene (Chloronitrobenzene) because 1chloro-2-nitrobenzene is disfavoured due to inductive effect and steric hindrance.
**[COMEDK 2014]**
HALOALKANES AND HALOARENES
91092
Amongst the following, the compound which is most difficult to sulphonate is-
1 benzene
2 nitrobenzene
3 toluene
4 chlorobenzene
Explanation:
$\mathrm{NO}_{2}$ group is electron withdrawing group and deactivation group. Sulphonation of nitrobenzene is most difficult.
**[BCECE-2011]**
HALOALKANES AND HALOARENES
91093
Which one is most reactive towards $S_{N} 1$ reaction?
In $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{C}\left(\mathrm{CH}_{3}\right)\left(\mathrm{C}_{6} \mathrm{H}_{5}\right) \mathrm{Br}$ formed carbocation will be $3^{\circ}$ and order of reactivity for $\mathrm{S}_{\mathrm{N}} 1$ will be $3^{\circ}>2^{\circ}>1^{\circ}$. So - $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{C}\left(\mathrm{CH}_{3}\right)\left(\mathrm{C}_{6} \mathrm{H}_{5}\right) \mathrm{Br}$ is most reactive towards $\mathrm{S}_{\mathrm{N}} 1$ reaction.
**[AIPMT -2010]**
HALOALKANES AND HALOARENES
91094
The best method to separate the mixture of ortho and Para nitrophenol $(1: 1)$ is
1 vaporisation
2 colour spectrum
3 distillation
4 crystallistion
Explanation:
Ortho and para nitrophenol is separated by distillation because p-nitrophenol has higher boiling point than p-nitrophenol due to H-bonding.
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HALOALKANES AND HALOARENES
91089
The major product obtained when chlorobenzene is nitrated with $\mathrm{HNO}_{3}+$ conc. $\mathrm{H}_{2} \mathrm{SO}_{4}$ is
1 1-chloro-4-nitrobenzene
2 1-chloro-2-nitrobenzene
3 1-chloro-3-nitrobenzene
4 1-chloro-1-nitrobenzene.
Explanation:
The nitration of chlorobenzene give the two product which one is 1-chloro-2-nitrobenzene and other 1-chloro-4-nitrobenzene. The major product is 1chloror-4-nitrobenzene (Chloronitrobenzene) because 1chloro-2-nitrobenzene is disfavoured due to inductive effect and steric hindrance.
**[COMEDK 2014]**
HALOALKANES AND HALOARENES
91092
Amongst the following, the compound which is most difficult to sulphonate is-
1 benzene
2 nitrobenzene
3 toluene
4 chlorobenzene
Explanation:
$\mathrm{NO}_{2}$ group is electron withdrawing group and deactivation group. Sulphonation of nitrobenzene is most difficult.
**[BCECE-2011]**
HALOALKANES AND HALOARENES
91093
Which one is most reactive towards $S_{N} 1$ reaction?
In $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{C}\left(\mathrm{CH}_{3}\right)\left(\mathrm{C}_{6} \mathrm{H}_{5}\right) \mathrm{Br}$ formed carbocation will be $3^{\circ}$ and order of reactivity for $\mathrm{S}_{\mathrm{N}} 1$ will be $3^{\circ}>2^{\circ}>1^{\circ}$. So - $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{C}\left(\mathrm{CH}_{3}\right)\left(\mathrm{C}_{6} \mathrm{H}_{5}\right) \mathrm{Br}$ is most reactive towards $\mathrm{S}_{\mathrm{N}} 1$ reaction.
**[AIPMT -2010]**
HALOALKANES AND HALOARENES
91094
The best method to separate the mixture of ortho and Para nitrophenol $(1: 1)$ is
1 vaporisation
2 colour spectrum
3 distillation
4 crystallistion
Explanation:
Ortho and para nitrophenol is separated by distillation because p-nitrophenol has higher boiling point than p-nitrophenol due to H-bonding.
91089
The major product obtained when chlorobenzene is nitrated with $\mathrm{HNO}_{3}+$ conc. $\mathrm{H}_{2} \mathrm{SO}_{4}$ is
1 1-chloro-4-nitrobenzene
2 1-chloro-2-nitrobenzene
3 1-chloro-3-nitrobenzene
4 1-chloro-1-nitrobenzene.
Explanation:
The nitration of chlorobenzene give the two product which one is 1-chloro-2-nitrobenzene and other 1-chloro-4-nitrobenzene. The major product is 1chloror-4-nitrobenzene (Chloronitrobenzene) because 1chloro-2-nitrobenzene is disfavoured due to inductive effect and steric hindrance.
**[COMEDK 2014]**
HALOALKANES AND HALOARENES
91092
Amongst the following, the compound which is most difficult to sulphonate is-
1 benzene
2 nitrobenzene
3 toluene
4 chlorobenzene
Explanation:
$\mathrm{NO}_{2}$ group is electron withdrawing group and deactivation group. Sulphonation of nitrobenzene is most difficult.
**[BCECE-2011]**
HALOALKANES AND HALOARENES
91093
Which one is most reactive towards $S_{N} 1$ reaction?
In $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{C}\left(\mathrm{CH}_{3}\right)\left(\mathrm{C}_{6} \mathrm{H}_{5}\right) \mathrm{Br}$ formed carbocation will be $3^{\circ}$ and order of reactivity for $\mathrm{S}_{\mathrm{N}} 1$ will be $3^{\circ}>2^{\circ}>1^{\circ}$. So - $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{C}\left(\mathrm{CH}_{3}\right)\left(\mathrm{C}_{6} \mathrm{H}_{5}\right) \mathrm{Br}$ is most reactive towards $\mathrm{S}_{\mathrm{N}} 1$ reaction.
**[AIPMT -2010]**
HALOALKANES AND HALOARENES
91094
The best method to separate the mixture of ortho and Para nitrophenol $(1: 1)$ is
1 vaporisation
2 colour spectrum
3 distillation
4 crystallistion
Explanation:
Ortho and para nitrophenol is separated by distillation because p-nitrophenol has higher boiling point than p-nitrophenol due to H-bonding.
