90989
Identify the product of the following reaction.
1
2
3
4
Explanation:
$\mathrm{CCl}_{3}$ is a meta directing group. A meta directing group is withdraws electron from all the nuclear position. As a result, electron density falls at all the nuclear positions but the decrease is much more at o and p-positions than at m-positions. Hence the electrophile attack preferentially at $\mathrm{m}$ position
Shift-II]**
HALOALKANES AND HALOARENES
90981
The major product formed in the following reaction is:
1
2
3
4
Explanation:
**[JEE Main 2021
HALOALKANES AND HALOARENES
90990
What is the final product (major) ' $A$ ' in the given reaction?
1
2
3
4
Explanation:
The given reaction is :
Shift-I]**
HALOALKANES AND HALOARENES
90991
The product formed in the first step of the reaction of with excess $\mathrm{Mg} / \mathrm{Et}_{2} \mathrm{O}\left(\mathrm{Et}=\mathrm{C}_{2} \mathrm{H}_{5}\right)$ is :
1
2
3
4
Explanation:
In the first step reaction 2,4-dibromohexane reacts with excess of $\mathrm{Mg} / \mathrm{H}_{2} \mathrm{O}$ to give the following product;
90989
Identify the product of the following reaction.
1
2
3
4
Explanation:
$\mathrm{CCl}_{3}$ is a meta directing group. A meta directing group is withdraws electron from all the nuclear position. As a result, electron density falls at all the nuclear positions but the decrease is much more at o and p-positions than at m-positions. Hence the electrophile attack preferentially at $\mathrm{m}$ position
Shift-II]**
HALOALKANES AND HALOARENES
90981
The major product formed in the following reaction is:
1
2
3
4
Explanation:
**[JEE Main 2021
HALOALKANES AND HALOARENES
90990
What is the final product (major) ' $A$ ' in the given reaction?
1
2
3
4
Explanation:
The given reaction is :
Shift-I]**
HALOALKANES AND HALOARENES
90991
The product formed in the first step of the reaction of with excess $\mathrm{Mg} / \mathrm{Et}_{2} \mathrm{O}\left(\mathrm{Et}=\mathrm{C}_{2} \mathrm{H}_{5}\right)$ is :
1
2
3
4
Explanation:
In the first step reaction 2,4-dibromohexane reacts with excess of $\mathrm{Mg} / \mathrm{H}_{2} \mathrm{O}$ to give the following product;
90989
Identify the product of the following reaction.
1
2
3
4
Explanation:
$\mathrm{CCl}_{3}$ is a meta directing group. A meta directing group is withdraws electron from all the nuclear position. As a result, electron density falls at all the nuclear positions but the decrease is much more at o and p-positions than at m-positions. Hence the electrophile attack preferentially at $\mathrm{m}$ position
Shift-II]**
HALOALKANES AND HALOARENES
90981
The major product formed in the following reaction is:
1
2
3
4
Explanation:
**[JEE Main 2021
HALOALKANES AND HALOARENES
90990
What is the final product (major) ' $A$ ' in the given reaction?
1
2
3
4
Explanation:
The given reaction is :
Shift-I]**
HALOALKANES AND HALOARENES
90991
The product formed in the first step of the reaction of with excess $\mathrm{Mg} / \mathrm{Et}_{2} \mathrm{O}\left(\mathrm{Et}=\mathrm{C}_{2} \mathrm{H}_{5}\right)$ is :
1
2
3
4
Explanation:
In the first step reaction 2,4-dibromohexane reacts with excess of $\mathrm{Mg} / \mathrm{H}_{2} \mathrm{O}$ to give the following product;
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HALOALKANES AND HALOARENES
90989
Identify the product of the following reaction.
1
2
3
4
Explanation:
$\mathrm{CCl}_{3}$ is a meta directing group. A meta directing group is withdraws electron from all the nuclear position. As a result, electron density falls at all the nuclear positions but the decrease is much more at o and p-positions than at m-positions. Hence the electrophile attack preferentially at $\mathrm{m}$ position
Shift-II]**
HALOALKANES AND HALOARENES
90981
The major product formed in the following reaction is:
1
2
3
4
Explanation:
**[JEE Main 2021
HALOALKANES AND HALOARENES
90990
What is the final product (major) ' $A$ ' in the given reaction?
1
2
3
4
Explanation:
The given reaction is :
Shift-I]**
HALOALKANES AND HALOARENES
90991
The product formed in the first step of the reaction of with excess $\mathrm{Mg} / \mathrm{Et}_{2} \mathrm{O}\left(\mathrm{Et}=\mathrm{C}_{2} \mathrm{H}_{5}\right)$ is :
1
2
3
4
Explanation:
In the first step reaction 2,4-dibromohexane reacts with excess of $\mathrm{Mg} / \mathrm{H}_{2} \mathrm{O}$ to give the following product;