QBManager

GENERAL ORGANIC CHEMISTRY

231521 The enolic form of acetone contains-

1

10 σ

-bonds,

2 π

-bonds and 1 lone pair

2

9 σ

-bonds,

2 π

-bonds and 2 lone pair

3

8 σ

-bonds,

2 π

-bonds and 2 lone pair

4

9 σ

-bonds,

1 π

-bonds and 2 lone pair

Explanation:

(D) :

$9 σ$ -bond, $1 π$ -bond, 2-lone pair

BCECE-2015

GENERAL ORGANIC CHEMISTRY

231523 An organic compound $X$ on treatment with PCC in dichloromethane gives the compound $Y$ . Compound $Y$ reacts with $I_{2}$ and alkali to form yellow precipitate of triiodomethane. The compound $X$ is

1

{CH}_{3} CHO

2

{CH}_{3} {COCH}_{3}

3

{CH}_{3} {CH}_{2} OH

4

{CH}_{3} COOH

Explanation:

Alcohol reacts with weak oxidising agent (PCC) to form the aldehyde or Ketone.
${CH}_{3} {CH}_{2} OH + PCC \overset{{CH}_{2} {CH}_{2}}{⟶} {CH}_{3} - CHO \underset{NaOH}{\overset{I_{2}}{⟶}} {CHI}_{3} + {HCOO}^{-} {Na}^{+}$

Karnataka CET-2021

GENERAL ORGANIC CHEMISTRY

231524 Which of the following compound is amphoteric in nature?

1

2

{CH}_{3} COOH

3

4

{CH}_{3} {CONH}_{2}

BCECE-2016

GENERAL ORGANIC CHEMISTRY

231527 Arrange benzene, n-hexane and ethyne in decreasing order of their acidic behavior

1 benzene

>

n-hexane

>

ethyne

2 n-hexane

>

Benzene

>

ethyne

3 ethyne

>

n-hexane

>

benzene

4 ethyne

>

benzene

>

n-hexane

Explanation:

The given compounds are benzene, n-hexane and ethyne i.e.
original image
As we know that, percentage of s-character is directly proportional to the electronegativity of corresponding atom. Ethyne has more \% of s-character due to which share pair electron withdrawing by carbon atom and partial positive charge generated on hydrogen atom. So, ethyne has more acidic character than benzene and nhexane respectively. Hence, the correct order is : ethyne $>$ Benzene $>$ n-hexane.

Kerala CEE-29.08.2021

GENERAL ORGANIC CHEMISTRY

231521 The enolic form of acetone contains-

1

10 σ

-bonds,

2 π

-bonds and 1 lone pair

2

9 σ

-bonds,

2 π

-bonds and 2 lone pair

3

8 σ

-bonds,

2 π

-bonds and 2 lone pair

4

9 σ

-bonds,

1 π

-bonds and 2 lone pair

Explanation:

(D) :

$9 σ$ -bond, $1 π$ -bond, 2-lone pair

BCECE-2015

GENERAL ORGANIC CHEMISTRY

231523 An organic compound $X$ on treatment with PCC in dichloromethane gives the compound $Y$ . Compound $Y$ reacts with $I_{2}$ and alkali to form yellow precipitate of triiodomethane. The compound $X$ is

1

{CH}_{3} CHO

2

{CH}_{3} {COCH}_{3}

3

{CH}_{3} {CH}_{2} OH

4

{CH}_{3} COOH

Explanation:

Alcohol reacts with weak oxidising agent (PCC) to form the aldehyde or Ketone.
${CH}_{3} {CH}_{2} OH + PCC \overset{{CH}_{2} {CH}_{2}}{⟶} {CH}_{3} - CHO \underset{NaOH}{\overset{I_{2}}{⟶}} {CHI}_{3} + {HCOO}^{-} {Na}^{+}$

Karnataka CET-2021

GENERAL ORGANIC CHEMISTRY

231524 Which of the following compound is amphoteric in nature?

1

2

{CH}_{3} COOH

3

4

{CH}_{3} {CONH}_{2}

BCECE-2016

GENERAL ORGANIC CHEMISTRY

231527 Arrange benzene, n-hexane and ethyne in decreasing order of their acidic behavior

1 benzene

>

n-hexane

>

ethyne

2 n-hexane

>

Benzene

>

ethyne

3 ethyne

>

n-hexane

>

benzene

4 ethyne

>

benzene

>

n-hexane

Explanation:

The given compounds are benzene, n-hexane and ethyne i.e.
original image
As we know that, percentage of s-character is directly proportional to the electronegativity of corresponding atom. Ethyne has more \% of s-character due to which share pair electron withdrawing by carbon atom and partial positive charge generated on hydrogen atom. So, ethyne has more acidic character than benzene and nhexane respectively. Hence, the correct order is : ethyne $>$ Benzene $>$ n-hexane.

Kerala CEE-29.08.2021

GENERAL ORGANIC CHEMISTRY

231521 The enolic form of acetone contains-

1

10 σ

-bonds,

2 π

-bonds and 1 lone pair

2

9 σ

-bonds,

2 π

-bonds and 2 lone pair

3

8 σ

-bonds,

2 π

-bonds and 2 lone pair

4

9 σ

-bonds,

1 π

-bonds and 2 lone pair

Explanation:

(D) :

$9 σ$ -bond, $1 π$ -bond, 2-lone pair

BCECE-2015

GENERAL ORGANIC CHEMISTRY

231523 An organic compound $X$ on treatment with PCC in dichloromethane gives the compound $Y$ . Compound $Y$ reacts with $I_{2}$ and alkali to form yellow precipitate of triiodomethane. The compound $X$ is

1

{CH}_{3} CHO

2

{CH}_{3} {COCH}_{3}

3

{CH}_{3} {CH}_{2} OH

4

{CH}_{3} COOH

Explanation:

Alcohol reacts with weak oxidising agent (PCC) to form the aldehyde or Ketone.
${CH}_{3} {CH}_{2} OH + PCC \overset{{CH}_{2} {CH}_{2}}{⟶} {CH}_{3} - CHO \underset{NaOH}{\overset{I_{2}}{⟶}} {CHI}_{3} + {HCOO}^{-} {Na}^{+}$

Karnataka CET-2021

GENERAL ORGANIC CHEMISTRY

231524 Which of the following compound is amphoteric in nature?

1

2

{CH}_{3} COOH

3

4

{CH}_{3} {CONH}_{2}

BCECE-2016

GENERAL ORGANIC CHEMISTRY

231527 Arrange benzene, n-hexane and ethyne in decreasing order of their acidic behavior

1 benzene

>

n-hexane

>

ethyne

2 n-hexane

>

Benzene

>

ethyne

3 ethyne

>

n-hexane

>

benzene

4 ethyne

>

benzene

>

n-hexane

Explanation:

The given compounds are benzene, n-hexane and ethyne i.e.
original image
As we know that, percentage of s-character is directly proportional to the electronegativity of corresponding atom. Ethyne has more \% of s-character due to which share pair electron withdrawing by carbon atom and partial positive charge generated on hydrogen atom. So, ethyne has more acidic character than benzene and nhexane respectively. Hence, the correct order is : ethyne $>$ Benzene $>$ n-hexane.

Kerala CEE-29.08.2021

GENERAL ORGANIC CHEMISTRY

231521 The enolic form of acetone contains-

1

10 σ

-bonds,

2 π

-bonds and 1 lone pair

2

9 σ

-bonds,

2 π

-bonds and 2 lone pair

3

8 σ

-bonds,

2 π

-bonds and 2 lone pair

4

9 σ

-bonds,

1 π

-bonds and 2 lone pair

Explanation:

(D) :

$9 σ$ -bond, $1 π$ -bond, 2-lone pair

BCECE-2015

GENERAL ORGANIC CHEMISTRY

231523 An organic compound $X$ on treatment with PCC in dichloromethane gives the compound $Y$ . Compound $Y$ reacts with $I_{2}$ and alkali to form yellow precipitate of triiodomethane. The compound $X$ is

1

{CH}_{3} CHO

2

{CH}_{3} {COCH}_{3}

3

{CH}_{3} {CH}_{2} OH

4

{CH}_{3} COOH

Explanation:

Alcohol reacts with weak oxidising agent (PCC) to form the aldehyde or Ketone.
${CH}_{3} {CH}_{2} OH + PCC \overset{{CH}_{2} {CH}_{2}}{⟶} {CH}_{3} - CHO \underset{NaOH}{\overset{I_{2}}{⟶}} {CHI}_{3} + {HCOO}^{-} {Na}^{+}$

Karnataka CET-2021

GENERAL ORGANIC CHEMISTRY

231524 Which of the following compound is amphoteric in nature?

1

2

{CH}_{3} COOH

3

4

{CH}_{3} {CONH}_{2}

BCECE-2016

GENERAL ORGANIC CHEMISTRY

231527 Arrange benzene, n-hexane and ethyne in decreasing order of their acidic behavior

1 benzene

>

n-hexane

>

ethyne

2 n-hexane

>

Benzene

>

ethyne

3 ethyne

>

n-hexane

>

benzene

4 ethyne

>

benzene

>

n-hexane

Explanation:

The given compounds are benzene, n-hexane and ethyne i.e.
original image
As we know that, percentage of s-character is directly proportional to the electronegativity of corresponding atom. Ethyne has more \% of s-character due to which share pair electron withdrawing by carbon atom and partial positive charge generated on hydrogen atom. So, ethyne has more acidic character than benzene and nhexane respectively. Hence, the correct order is : ethyne $>$ Benzene $>$ n-hexane.

Kerala CEE-29.08.2021

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