231296
Write correct decreasing order of acidic strength?
1 I $>$ II $>$ III $>$ IV
2 I $>$ III $>$ IV $>$ II
3 IV $>$ III $>$ II $>$ I
4 IV $>$ III $>$ I $>$ II
Explanation:
Carboxylic acid is higher acidic than the alcohol. Hence (ii), (iii) and (iv) is more acidic than (i). -I effect Increase the acidity and $+\mathrm{I}$ effect decrease. $+\mathrm{M}$ effect decrease the acidity more than the $+\mathrm{I}$ effect Hence the decreasing order of acidity is-
AIIMS-27 May
GENERAL ORGANIC CHEMISTRY
231297
The correct order of nucleophilicity of the following species is (i) $\mathrm{OH}^{-}$ (ii) $\mathrm{HS}^{-}$ (iii) $\mathrm{Ph}-\mathrm{O}^{-}$ (iv) $\mathrm{C}_{2} \mathrm{H}_{5}-\mathrm{O}^{-}$
1 i $>$ ii $>$ iii $>$ iv
2 ii $>$ iv $>$ i $>$ iii
3 ii $>$ iii $>$ i $>$ iv
4 iii $>$ iv $>$ i $>$ ii
Explanation:
The conjugate acids of unucleophiles is - $\mathrm{H}_{2} \mathrm{O}, \mathrm{H}_{2} \mathrm{~S}, \mathrm{Ph}-\mathrm{OH}$, and $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$ Nucleophilicity depends on the conjugate acid and delocalization of -ve change in benzene ring. Strong acid better nucleophile than weak. Hence the order of nucleophilicity is - Due to delocalization is least nucleophisity.
2018 (E)]**
GENERAL ORGANIC CHEMISTRY
231299
Consider the following bromides: The correct order of $S_{N} 1$ reactivity is
1 $\mathrm{B}>\mathrm{C}>\mathrm{A}$
2 $\mathrm{B}>\mathrm{A}>\mathrm{C}$
3 $\mathrm{C}>\mathrm{B}>\mathrm{A}$
4 A $>$ B $>$ C
Explanation:
(A): In the $\mathrm{S}_{\mathrm{N}} 1$ reaction, carbocation is form during the reaction. The reactivity of intermediate depends upon the stability of intermediate. The following carbocation are formed- As we know that allylic carbocation is most stable than $2^{\circ}$ carbocation because of delocalization of $\pi-\mathrm{e}^{-}$in allylic carbocation. $2^{\circ}$-corbocation is more stable than $1^{\circ}$-carbocation because of maximum no of $\alpha-\mathrm{H}$. Hence, the correct order of reactivity towards $\mathrm{S}_{\mathrm{N}} 1$ reaction will be $\mathrm{B}>\mathrm{C}>\mathrm{A}$
AIIMS-2016
GENERAL ORGANIC CHEMISTRY
231300
The strongest ortho - para and strongest metadirecting groups respectively are
1 $-\mathrm{NO}_{2}$ and $-\mathrm{NH}_{2}$
2 $-\mathrm{CONH}_{2}$ and $-\mathrm{NH}_{2}$
3 $-\mathrm{NH}_{2}$ and $-\mathrm{CONH}_{2}$
4 $-\mathrm{NH}_{2}$ and $-\mathrm{NO}_{2}$
Explanation:
That group which push the electron in benzene ring by any method which is $+\mathrm{I},+\mathrm{M}$, or $+\mathrm{R}$, have strongest ortho-para towards electrophilic substitution reaction e.g. - The group which pull the electrons towards itself from benzene ring by any method such as $-\mathrm{I}-\mathrm{M}$, or $-\mathrm{R}$, have strong meta position towards electrophile substitution reaction because positive change at ortho and position and then electrophile will attack on meta position e.g.
AIIMS-2017
GENERAL ORGANIC CHEMISTRY
231301
Among the following compounds (I-III), the correct order of reactivity towards electrophilic substitution reaction is
1 II $>$ III $>$ I
2 III $<$ I $<$ II
3 I $>$ II $>$ III
4 I $=$ II $>$ III
Explanation:
Electrophile attack at that position which have nucleophile or higher the electron cloud. Hence the $+\mathrm{I}$ and $+\mathrm{M}$ effect is favourable condition for electrophile substitution reaction and $-\mathrm{I}$ and $-\mathrm{M}$ effect is disfavour of S-E reaction. Hence the decreasing order of reactivity is-
231296
Write correct decreasing order of acidic strength?
1 I $>$ II $>$ III $>$ IV
2 I $>$ III $>$ IV $>$ II
3 IV $>$ III $>$ II $>$ I
4 IV $>$ III $>$ I $>$ II
Explanation:
Carboxylic acid is higher acidic than the alcohol. Hence (ii), (iii) and (iv) is more acidic than (i). -I effect Increase the acidity and $+\mathrm{I}$ effect decrease. $+\mathrm{M}$ effect decrease the acidity more than the $+\mathrm{I}$ effect Hence the decreasing order of acidity is-
AIIMS-27 May
GENERAL ORGANIC CHEMISTRY
231297
The correct order of nucleophilicity of the following species is (i) $\mathrm{OH}^{-}$ (ii) $\mathrm{HS}^{-}$ (iii) $\mathrm{Ph}-\mathrm{O}^{-}$ (iv) $\mathrm{C}_{2} \mathrm{H}_{5}-\mathrm{O}^{-}$
1 i $>$ ii $>$ iii $>$ iv
2 ii $>$ iv $>$ i $>$ iii
3 ii $>$ iii $>$ i $>$ iv
4 iii $>$ iv $>$ i $>$ ii
Explanation:
The conjugate acids of unucleophiles is - $\mathrm{H}_{2} \mathrm{O}, \mathrm{H}_{2} \mathrm{~S}, \mathrm{Ph}-\mathrm{OH}$, and $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$ Nucleophilicity depends on the conjugate acid and delocalization of -ve change in benzene ring. Strong acid better nucleophile than weak. Hence the order of nucleophilicity is - Due to delocalization is least nucleophisity.
2018 (E)]**
GENERAL ORGANIC CHEMISTRY
231299
Consider the following bromides: The correct order of $S_{N} 1$ reactivity is
1 $\mathrm{B}>\mathrm{C}>\mathrm{A}$
2 $\mathrm{B}>\mathrm{A}>\mathrm{C}$
3 $\mathrm{C}>\mathrm{B}>\mathrm{A}$
4 A $>$ B $>$ C
Explanation:
(A): In the $\mathrm{S}_{\mathrm{N}} 1$ reaction, carbocation is form during the reaction. The reactivity of intermediate depends upon the stability of intermediate. The following carbocation are formed- As we know that allylic carbocation is most stable than $2^{\circ}$ carbocation because of delocalization of $\pi-\mathrm{e}^{-}$in allylic carbocation. $2^{\circ}$-corbocation is more stable than $1^{\circ}$-carbocation because of maximum no of $\alpha-\mathrm{H}$. Hence, the correct order of reactivity towards $\mathrm{S}_{\mathrm{N}} 1$ reaction will be $\mathrm{B}>\mathrm{C}>\mathrm{A}$
AIIMS-2016
GENERAL ORGANIC CHEMISTRY
231300
The strongest ortho - para and strongest metadirecting groups respectively are
1 $-\mathrm{NO}_{2}$ and $-\mathrm{NH}_{2}$
2 $-\mathrm{CONH}_{2}$ and $-\mathrm{NH}_{2}$
3 $-\mathrm{NH}_{2}$ and $-\mathrm{CONH}_{2}$
4 $-\mathrm{NH}_{2}$ and $-\mathrm{NO}_{2}$
Explanation:
That group which push the electron in benzene ring by any method which is $+\mathrm{I},+\mathrm{M}$, or $+\mathrm{R}$, have strongest ortho-para towards electrophilic substitution reaction e.g. - The group which pull the electrons towards itself from benzene ring by any method such as $-\mathrm{I}-\mathrm{M}$, or $-\mathrm{R}$, have strong meta position towards electrophile substitution reaction because positive change at ortho and position and then electrophile will attack on meta position e.g.
AIIMS-2017
GENERAL ORGANIC CHEMISTRY
231301
Among the following compounds (I-III), the correct order of reactivity towards electrophilic substitution reaction is
1 II $>$ III $>$ I
2 III $<$ I $<$ II
3 I $>$ II $>$ III
4 I $=$ II $>$ III
Explanation:
Electrophile attack at that position which have nucleophile or higher the electron cloud. Hence the $+\mathrm{I}$ and $+\mathrm{M}$ effect is favourable condition for electrophile substitution reaction and $-\mathrm{I}$ and $-\mathrm{M}$ effect is disfavour of S-E reaction. Hence the decreasing order of reactivity is-
NEET Test Series from KOTA - 10 Papers In MS WORD
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GENERAL ORGANIC CHEMISTRY
231296
Write correct decreasing order of acidic strength?
1 I $>$ II $>$ III $>$ IV
2 I $>$ III $>$ IV $>$ II
3 IV $>$ III $>$ II $>$ I
4 IV $>$ III $>$ I $>$ II
Explanation:
Carboxylic acid is higher acidic than the alcohol. Hence (ii), (iii) and (iv) is more acidic than (i). -I effect Increase the acidity and $+\mathrm{I}$ effect decrease. $+\mathrm{M}$ effect decrease the acidity more than the $+\mathrm{I}$ effect Hence the decreasing order of acidity is-
AIIMS-27 May
GENERAL ORGANIC CHEMISTRY
231297
The correct order of nucleophilicity of the following species is (i) $\mathrm{OH}^{-}$ (ii) $\mathrm{HS}^{-}$ (iii) $\mathrm{Ph}-\mathrm{O}^{-}$ (iv) $\mathrm{C}_{2} \mathrm{H}_{5}-\mathrm{O}^{-}$
1 i $>$ ii $>$ iii $>$ iv
2 ii $>$ iv $>$ i $>$ iii
3 ii $>$ iii $>$ i $>$ iv
4 iii $>$ iv $>$ i $>$ ii
Explanation:
The conjugate acids of unucleophiles is - $\mathrm{H}_{2} \mathrm{O}, \mathrm{H}_{2} \mathrm{~S}, \mathrm{Ph}-\mathrm{OH}$, and $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$ Nucleophilicity depends on the conjugate acid and delocalization of -ve change in benzene ring. Strong acid better nucleophile than weak. Hence the order of nucleophilicity is - Due to delocalization is least nucleophisity.
2018 (E)]**
GENERAL ORGANIC CHEMISTRY
231299
Consider the following bromides: The correct order of $S_{N} 1$ reactivity is
1 $\mathrm{B}>\mathrm{C}>\mathrm{A}$
2 $\mathrm{B}>\mathrm{A}>\mathrm{C}$
3 $\mathrm{C}>\mathrm{B}>\mathrm{A}$
4 A $>$ B $>$ C
Explanation:
(A): In the $\mathrm{S}_{\mathrm{N}} 1$ reaction, carbocation is form during the reaction. The reactivity of intermediate depends upon the stability of intermediate. The following carbocation are formed- As we know that allylic carbocation is most stable than $2^{\circ}$ carbocation because of delocalization of $\pi-\mathrm{e}^{-}$in allylic carbocation. $2^{\circ}$-corbocation is more stable than $1^{\circ}$-carbocation because of maximum no of $\alpha-\mathrm{H}$. Hence, the correct order of reactivity towards $\mathrm{S}_{\mathrm{N}} 1$ reaction will be $\mathrm{B}>\mathrm{C}>\mathrm{A}$
AIIMS-2016
GENERAL ORGANIC CHEMISTRY
231300
The strongest ortho - para and strongest metadirecting groups respectively are
1 $-\mathrm{NO}_{2}$ and $-\mathrm{NH}_{2}$
2 $-\mathrm{CONH}_{2}$ and $-\mathrm{NH}_{2}$
3 $-\mathrm{NH}_{2}$ and $-\mathrm{CONH}_{2}$
4 $-\mathrm{NH}_{2}$ and $-\mathrm{NO}_{2}$
Explanation:
That group which push the electron in benzene ring by any method which is $+\mathrm{I},+\mathrm{M}$, or $+\mathrm{R}$, have strongest ortho-para towards electrophilic substitution reaction e.g. - The group which pull the electrons towards itself from benzene ring by any method such as $-\mathrm{I}-\mathrm{M}$, or $-\mathrm{R}$, have strong meta position towards electrophile substitution reaction because positive change at ortho and position and then electrophile will attack on meta position e.g.
AIIMS-2017
GENERAL ORGANIC CHEMISTRY
231301
Among the following compounds (I-III), the correct order of reactivity towards electrophilic substitution reaction is
1 II $>$ III $>$ I
2 III $<$ I $<$ II
3 I $>$ II $>$ III
4 I $=$ II $>$ III
Explanation:
Electrophile attack at that position which have nucleophile or higher the electron cloud. Hence the $+\mathrm{I}$ and $+\mathrm{M}$ effect is favourable condition for electrophile substitution reaction and $-\mathrm{I}$ and $-\mathrm{M}$ effect is disfavour of S-E reaction. Hence the decreasing order of reactivity is-
231296
Write correct decreasing order of acidic strength?
1 I $>$ II $>$ III $>$ IV
2 I $>$ III $>$ IV $>$ II
3 IV $>$ III $>$ II $>$ I
4 IV $>$ III $>$ I $>$ II
Explanation:
Carboxylic acid is higher acidic than the alcohol. Hence (ii), (iii) and (iv) is more acidic than (i). -I effect Increase the acidity and $+\mathrm{I}$ effect decrease. $+\mathrm{M}$ effect decrease the acidity more than the $+\mathrm{I}$ effect Hence the decreasing order of acidity is-
AIIMS-27 May
GENERAL ORGANIC CHEMISTRY
231297
The correct order of nucleophilicity of the following species is (i) $\mathrm{OH}^{-}$ (ii) $\mathrm{HS}^{-}$ (iii) $\mathrm{Ph}-\mathrm{O}^{-}$ (iv) $\mathrm{C}_{2} \mathrm{H}_{5}-\mathrm{O}^{-}$
1 i $>$ ii $>$ iii $>$ iv
2 ii $>$ iv $>$ i $>$ iii
3 ii $>$ iii $>$ i $>$ iv
4 iii $>$ iv $>$ i $>$ ii
Explanation:
The conjugate acids of unucleophiles is - $\mathrm{H}_{2} \mathrm{O}, \mathrm{H}_{2} \mathrm{~S}, \mathrm{Ph}-\mathrm{OH}$, and $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$ Nucleophilicity depends on the conjugate acid and delocalization of -ve change in benzene ring. Strong acid better nucleophile than weak. Hence the order of nucleophilicity is - Due to delocalization is least nucleophisity.
2018 (E)]**
GENERAL ORGANIC CHEMISTRY
231299
Consider the following bromides: The correct order of $S_{N} 1$ reactivity is
1 $\mathrm{B}>\mathrm{C}>\mathrm{A}$
2 $\mathrm{B}>\mathrm{A}>\mathrm{C}$
3 $\mathrm{C}>\mathrm{B}>\mathrm{A}$
4 A $>$ B $>$ C
Explanation:
(A): In the $\mathrm{S}_{\mathrm{N}} 1$ reaction, carbocation is form during the reaction. The reactivity of intermediate depends upon the stability of intermediate. The following carbocation are formed- As we know that allylic carbocation is most stable than $2^{\circ}$ carbocation because of delocalization of $\pi-\mathrm{e}^{-}$in allylic carbocation. $2^{\circ}$-corbocation is more stable than $1^{\circ}$-carbocation because of maximum no of $\alpha-\mathrm{H}$. Hence, the correct order of reactivity towards $\mathrm{S}_{\mathrm{N}} 1$ reaction will be $\mathrm{B}>\mathrm{C}>\mathrm{A}$
AIIMS-2016
GENERAL ORGANIC CHEMISTRY
231300
The strongest ortho - para and strongest metadirecting groups respectively are
1 $-\mathrm{NO}_{2}$ and $-\mathrm{NH}_{2}$
2 $-\mathrm{CONH}_{2}$ and $-\mathrm{NH}_{2}$
3 $-\mathrm{NH}_{2}$ and $-\mathrm{CONH}_{2}$
4 $-\mathrm{NH}_{2}$ and $-\mathrm{NO}_{2}$
Explanation:
That group which push the electron in benzene ring by any method which is $+\mathrm{I},+\mathrm{M}$, or $+\mathrm{R}$, have strongest ortho-para towards electrophilic substitution reaction e.g. - The group which pull the electrons towards itself from benzene ring by any method such as $-\mathrm{I}-\mathrm{M}$, or $-\mathrm{R}$, have strong meta position towards electrophile substitution reaction because positive change at ortho and position and then electrophile will attack on meta position e.g.
AIIMS-2017
GENERAL ORGANIC CHEMISTRY
231301
Among the following compounds (I-III), the correct order of reactivity towards electrophilic substitution reaction is
1 II $>$ III $>$ I
2 III $<$ I $<$ II
3 I $>$ II $>$ III
4 I $=$ II $>$ III
Explanation:
Electrophile attack at that position which have nucleophile or higher the electron cloud. Hence the $+\mathrm{I}$ and $+\mathrm{M}$ effect is favourable condition for electrophile substitution reaction and $-\mathrm{I}$ and $-\mathrm{M}$ effect is disfavour of S-E reaction. Hence the decreasing order of reactivity is-
231296
Write correct decreasing order of acidic strength?
1 I $>$ II $>$ III $>$ IV
2 I $>$ III $>$ IV $>$ II
3 IV $>$ III $>$ II $>$ I
4 IV $>$ III $>$ I $>$ II
Explanation:
Carboxylic acid is higher acidic than the alcohol. Hence (ii), (iii) and (iv) is more acidic than (i). -I effect Increase the acidity and $+\mathrm{I}$ effect decrease. $+\mathrm{M}$ effect decrease the acidity more than the $+\mathrm{I}$ effect Hence the decreasing order of acidity is-
AIIMS-27 May
GENERAL ORGANIC CHEMISTRY
231297
The correct order of nucleophilicity of the following species is (i) $\mathrm{OH}^{-}$ (ii) $\mathrm{HS}^{-}$ (iii) $\mathrm{Ph}-\mathrm{O}^{-}$ (iv) $\mathrm{C}_{2} \mathrm{H}_{5}-\mathrm{O}^{-}$
1 i $>$ ii $>$ iii $>$ iv
2 ii $>$ iv $>$ i $>$ iii
3 ii $>$ iii $>$ i $>$ iv
4 iii $>$ iv $>$ i $>$ ii
Explanation:
The conjugate acids of unucleophiles is - $\mathrm{H}_{2} \mathrm{O}, \mathrm{H}_{2} \mathrm{~S}, \mathrm{Ph}-\mathrm{OH}$, and $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$ Nucleophilicity depends on the conjugate acid and delocalization of -ve change in benzene ring. Strong acid better nucleophile than weak. Hence the order of nucleophilicity is - Due to delocalization is least nucleophisity.
2018 (E)]**
GENERAL ORGANIC CHEMISTRY
231299
Consider the following bromides: The correct order of $S_{N} 1$ reactivity is
1 $\mathrm{B}>\mathrm{C}>\mathrm{A}$
2 $\mathrm{B}>\mathrm{A}>\mathrm{C}$
3 $\mathrm{C}>\mathrm{B}>\mathrm{A}$
4 A $>$ B $>$ C
Explanation:
(A): In the $\mathrm{S}_{\mathrm{N}} 1$ reaction, carbocation is form during the reaction. The reactivity of intermediate depends upon the stability of intermediate. The following carbocation are formed- As we know that allylic carbocation is most stable than $2^{\circ}$ carbocation because of delocalization of $\pi-\mathrm{e}^{-}$in allylic carbocation. $2^{\circ}$-corbocation is more stable than $1^{\circ}$-carbocation because of maximum no of $\alpha-\mathrm{H}$. Hence, the correct order of reactivity towards $\mathrm{S}_{\mathrm{N}} 1$ reaction will be $\mathrm{B}>\mathrm{C}>\mathrm{A}$
AIIMS-2016
GENERAL ORGANIC CHEMISTRY
231300
The strongest ortho - para and strongest metadirecting groups respectively are
1 $-\mathrm{NO}_{2}$ and $-\mathrm{NH}_{2}$
2 $-\mathrm{CONH}_{2}$ and $-\mathrm{NH}_{2}$
3 $-\mathrm{NH}_{2}$ and $-\mathrm{CONH}_{2}$
4 $-\mathrm{NH}_{2}$ and $-\mathrm{NO}_{2}$
Explanation:
That group which push the electron in benzene ring by any method which is $+\mathrm{I},+\mathrm{M}$, or $+\mathrm{R}$, have strongest ortho-para towards electrophilic substitution reaction e.g. - The group which pull the electrons towards itself from benzene ring by any method such as $-\mathrm{I}-\mathrm{M}$, or $-\mathrm{R}$, have strong meta position towards electrophile substitution reaction because positive change at ortho and position and then electrophile will attack on meta position e.g.
AIIMS-2017
GENERAL ORGANIC CHEMISTRY
231301
Among the following compounds (I-III), the correct order of reactivity towards electrophilic substitution reaction is
1 II $>$ III $>$ I
2 III $<$ I $<$ II
3 I $>$ II $>$ III
4 I $=$ II $>$ III
Explanation:
Electrophile attack at that position which have nucleophile or higher the electron cloud. Hence the $+\mathrm{I}$ and $+\mathrm{M}$ effect is favourable condition for electrophile substitution reaction and $-\mathrm{I}$ and $-\mathrm{M}$ effect is disfavour of S-E reaction. Hence the decreasing order of reactivity is-
is least nucleophisity.
