(B) : $\quad$ Complexes, (I) $\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}, \quad$ (II) $\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ and ligands $-\mathrm{NH}_{3},-\mathrm{H}_{2} \mathrm{O}$ and $-\mathrm{NO}_{2}^{-}$ respectively. The field strength order of the ligands is $\mathrm{H}_{2} \mathrm{O}<\mathrm{NH}_{3}<\mathrm{NO}_{2}^{-}$ So, the order CFSE values : $\triangle_{0}$ II $<\triangle_{0}$ I $<\triangle_{0}$ III We know, $\mathrm{E}=\frac{\mathrm{hc}}{\lambda}$ or $\mathrm{E} \propto \frac{1}{\lambda}$ So, the order of wavelength of absorption in visible region will be $\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}\left(\mathrm{NO}_{2}\right)_{6}\right]^{4-}$
AP EAMCET (Engg.) 17.09.2020 Shift-I
COORDINATION COMPOUNDS
274372
For the ions $\mathrm{Zn}^{2+}, \mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ which among the following statement is correct? (Atomic number of $\mathrm{Zn}=\mathbf{3 0}, \mathrm{Ni}=28$ and $\mathrm{Cr}=$ 24)
1 All these are colourless
2 All these are coloured
3 Only $\mathrm{Ni}^{2+}$ is coloured and $\mathrm{Zn}^{2+}$ and $\mathrm{Cr}^{3+}$ are colourless
4 Only $\mathrm{Zn}^{2+}$ is colourless and $\mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ are coloured
Explanation:
(D) : Electronic configuration of $\mathrm{Zn}^{2+}[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^{0}, \mathrm{Ni}^{2+}[\mathrm{Ar}] 3 \mathrm{~d}^{8}, 4 \mathrm{~s}^{0}$ $\mathrm{Cr}^{3}+[\mathrm{Ar}] 3 \mathrm{~d}^{3}, 4 \mathrm{~s}^{0}$ $\mathrm{Zn}^{2+}$ colourless (no unpaired electron) $\mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ coloured due to unpaired electrons. There is d-d transition of electron, so the solution of ions will be coloured.
AIIMS 26 May 2019 (Morning)
COORDINATION COMPOUNDS
274377
Assertion: $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+} \rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{H}_{2} \mathrm{O}\right]^{3+}$ color continuously changes. Reason: Larger wavelength will be absorbed.
1 If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
(A) : $\mathrm{H}_{2} \mathrm{O}$ is a weaker ligand than $\mathrm{NH}_{3}$. So, larger wavelength will be absorbed.
AIIMS-27 May
COORDINATION COMPOUNDS
274378
Assertion : $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ while converting, color continuously changes. Reason: CFSE increases during change.
1 If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
(A) $\because \mathrm{Cr}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^4 \quad \because \mathrm{Cr}^{3+}=[\mathrm{Ar}] 3 \mathrm{~d}^3$ $\mathrm{CFSE}=[-0.4 \times 3+0.6 \times 1] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=[-1.2] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=[-1.2+0.6] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=-1.2 \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=-0.6 \Delta_{\mathrm{o}}$ Hence, CFSE increases during the changing from $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ to $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$.
(B) : $\quad$ Complexes, (I) $\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}, \quad$ (II) $\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ and ligands $-\mathrm{NH}_{3},-\mathrm{H}_{2} \mathrm{O}$ and $-\mathrm{NO}_{2}^{-}$ respectively. The field strength order of the ligands is $\mathrm{H}_{2} \mathrm{O}<\mathrm{NH}_{3}<\mathrm{NO}_{2}^{-}$ So, the order CFSE values : $\triangle_{0}$ II $<\triangle_{0}$ I $<\triangle_{0}$ III We know, $\mathrm{E}=\frac{\mathrm{hc}}{\lambda}$ or $\mathrm{E} \propto \frac{1}{\lambda}$ So, the order of wavelength of absorption in visible region will be $\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}\left(\mathrm{NO}_{2}\right)_{6}\right]^{4-}$
AP EAMCET (Engg.) 17.09.2020 Shift-I
COORDINATION COMPOUNDS
274372
For the ions $\mathrm{Zn}^{2+}, \mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ which among the following statement is correct? (Atomic number of $\mathrm{Zn}=\mathbf{3 0}, \mathrm{Ni}=28$ and $\mathrm{Cr}=$ 24)
1 All these are colourless
2 All these are coloured
3 Only $\mathrm{Ni}^{2+}$ is coloured and $\mathrm{Zn}^{2+}$ and $\mathrm{Cr}^{3+}$ are colourless
4 Only $\mathrm{Zn}^{2+}$ is colourless and $\mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ are coloured
Explanation:
(D) : Electronic configuration of $\mathrm{Zn}^{2+}[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^{0}, \mathrm{Ni}^{2+}[\mathrm{Ar}] 3 \mathrm{~d}^{8}, 4 \mathrm{~s}^{0}$ $\mathrm{Cr}^{3}+[\mathrm{Ar}] 3 \mathrm{~d}^{3}, 4 \mathrm{~s}^{0}$ $\mathrm{Zn}^{2+}$ colourless (no unpaired electron) $\mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ coloured due to unpaired electrons. There is d-d transition of electron, so the solution of ions will be coloured.
AIIMS 26 May 2019 (Morning)
COORDINATION COMPOUNDS
274377
Assertion: $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+} \rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{H}_{2} \mathrm{O}\right]^{3+}$ color continuously changes. Reason: Larger wavelength will be absorbed.
1 If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
(A) : $\mathrm{H}_{2} \mathrm{O}$ is a weaker ligand than $\mathrm{NH}_{3}$. So, larger wavelength will be absorbed.
AIIMS-27 May
COORDINATION COMPOUNDS
274378
Assertion : $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ while converting, color continuously changes. Reason: CFSE increases during change.
1 If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
(A) $\because \mathrm{Cr}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^4 \quad \because \mathrm{Cr}^{3+}=[\mathrm{Ar}] 3 \mathrm{~d}^3$ $\mathrm{CFSE}=[-0.4 \times 3+0.6 \times 1] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=[-1.2] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=[-1.2+0.6] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=-1.2 \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=-0.6 \Delta_{\mathrm{o}}$ Hence, CFSE increases during the changing from $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ to $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$.
(B) : $\quad$ Complexes, (I) $\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}, \quad$ (II) $\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ and ligands $-\mathrm{NH}_{3},-\mathrm{H}_{2} \mathrm{O}$ and $-\mathrm{NO}_{2}^{-}$ respectively. The field strength order of the ligands is $\mathrm{H}_{2} \mathrm{O}<\mathrm{NH}_{3}<\mathrm{NO}_{2}^{-}$ So, the order CFSE values : $\triangle_{0}$ II $<\triangle_{0}$ I $<\triangle_{0}$ III We know, $\mathrm{E}=\frac{\mathrm{hc}}{\lambda}$ or $\mathrm{E} \propto \frac{1}{\lambda}$ So, the order of wavelength of absorption in visible region will be $\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}\left(\mathrm{NO}_{2}\right)_{6}\right]^{4-}$
AP EAMCET (Engg.) 17.09.2020 Shift-I
COORDINATION COMPOUNDS
274372
For the ions $\mathrm{Zn}^{2+}, \mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ which among the following statement is correct? (Atomic number of $\mathrm{Zn}=\mathbf{3 0}, \mathrm{Ni}=28$ and $\mathrm{Cr}=$ 24)
1 All these are colourless
2 All these are coloured
3 Only $\mathrm{Ni}^{2+}$ is coloured and $\mathrm{Zn}^{2+}$ and $\mathrm{Cr}^{3+}$ are colourless
4 Only $\mathrm{Zn}^{2+}$ is colourless and $\mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ are coloured
Explanation:
(D) : Electronic configuration of $\mathrm{Zn}^{2+}[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^{0}, \mathrm{Ni}^{2+}[\mathrm{Ar}] 3 \mathrm{~d}^{8}, 4 \mathrm{~s}^{0}$ $\mathrm{Cr}^{3}+[\mathrm{Ar}] 3 \mathrm{~d}^{3}, 4 \mathrm{~s}^{0}$ $\mathrm{Zn}^{2+}$ colourless (no unpaired electron) $\mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ coloured due to unpaired electrons. There is d-d transition of electron, so the solution of ions will be coloured.
AIIMS 26 May 2019 (Morning)
COORDINATION COMPOUNDS
274377
Assertion: $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+} \rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{H}_{2} \mathrm{O}\right]^{3+}$ color continuously changes. Reason: Larger wavelength will be absorbed.
1 If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
(A) : $\mathrm{H}_{2} \mathrm{O}$ is a weaker ligand than $\mathrm{NH}_{3}$. So, larger wavelength will be absorbed.
AIIMS-27 May
COORDINATION COMPOUNDS
274378
Assertion : $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ while converting, color continuously changes. Reason: CFSE increases during change.
1 If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
(A) $\because \mathrm{Cr}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^4 \quad \because \mathrm{Cr}^{3+}=[\mathrm{Ar}] 3 \mathrm{~d}^3$ $\mathrm{CFSE}=[-0.4 \times 3+0.6 \times 1] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=[-1.2] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=[-1.2+0.6] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=-1.2 \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=-0.6 \Delta_{\mathrm{o}}$ Hence, CFSE increases during the changing from $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ to $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$.
(B) : $\quad$ Complexes, (I) $\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}, \quad$ (II) $\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ and ligands $-\mathrm{NH}_{3},-\mathrm{H}_{2} \mathrm{O}$ and $-\mathrm{NO}_{2}^{-}$ respectively. The field strength order of the ligands is $\mathrm{H}_{2} \mathrm{O}<\mathrm{NH}_{3}<\mathrm{NO}_{2}^{-}$ So, the order CFSE values : $\triangle_{0}$ II $<\triangle_{0}$ I $<\triangle_{0}$ III We know, $\mathrm{E}=\frac{\mathrm{hc}}{\lambda}$ or $\mathrm{E} \propto \frac{1}{\lambda}$ So, the order of wavelength of absorption in visible region will be $\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}\left(\mathrm{NO}_{2}\right)_{6}\right]^{4-}$
AP EAMCET (Engg.) 17.09.2020 Shift-I
COORDINATION COMPOUNDS
274372
For the ions $\mathrm{Zn}^{2+}, \mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ which among the following statement is correct? (Atomic number of $\mathrm{Zn}=\mathbf{3 0}, \mathrm{Ni}=28$ and $\mathrm{Cr}=$ 24)
1 All these are colourless
2 All these are coloured
3 Only $\mathrm{Ni}^{2+}$ is coloured and $\mathrm{Zn}^{2+}$ and $\mathrm{Cr}^{3+}$ are colourless
4 Only $\mathrm{Zn}^{2+}$ is colourless and $\mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ are coloured
Explanation:
(D) : Electronic configuration of $\mathrm{Zn}^{2+}[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^{0}, \mathrm{Ni}^{2+}[\mathrm{Ar}] 3 \mathrm{~d}^{8}, 4 \mathrm{~s}^{0}$ $\mathrm{Cr}^{3}+[\mathrm{Ar}] 3 \mathrm{~d}^{3}, 4 \mathrm{~s}^{0}$ $\mathrm{Zn}^{2+}$ colourless (no unpaired electron) $\mathrm{Ni}^{2+}$ and $\mathrm{Cr}^{3+}$ coloured due to unpaired electrons. There is d-d transition of electron, so the solution of ions will be coloured.
AIIMS 26 May 2019 (Morning)
COORDINATION COMPOUNDS
274377
Assertion: $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+} \rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{H}_{2} \mathrm{O}\right]^{3+}$ color continuously changes. Reason: Larger wavelength will be absorbed.
1 If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
(A) : $\mathrm{H}_{2} \mathrm{O}$ is a weaker ligand than $\mathrm{NH}_{3}$. So, larger wavelength will be absorbed.
AIIMS-27 May
COORDINATION COMPOUNDS
274378
Assertion : $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ while converting, color continuously changes. Reason: CFSE increases during change.
1 If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
(A) $\because \mathrm{Cr}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^4 \quad \because \mathrm{Cr}^{3+}=[\mathrm{Ar}] 3 \mathrm{~d}^3$ $\mathrm{CFSE}=[-0.4 \times 3+0.6 \times 1] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=[-1.2] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=[-1.2+0.6] \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=-1.2 \Delta_{\mathrm{o}}$ $\mathrm{CFSE}=-0.6 \Delta_{\mathrm{o}}$ Hence, CFSE increases during the changing from $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ to $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$.
