274217
The Magnetic moment (spin only) of $\left[\mathrm{NiCl}_{4}\right]^{2-}$ is-
1 $1.82 \mathrm{BM}$
2 $5.46 \mathrm{BM}$
3 $2.82 \mathrm{BM}$
4 $1.41 \mathrm{BM}$
Explanation:
(C) : In $\left[\mathrm{NiCl}_{4}\right]^{2-}$ complex, $\mathrm{Ni}$ metal is present in +2 oxidation state $\mathrm{Cl}^{-}$is weak field ligand and do not do pairing of metal $3 \mathrm{~d}-$ electrons. $\mathrm{Ni}^{2+}: 3 \mathrm{~d}^{8}$ No, if unpaired election $=2$ Magnetic moment $=\sqrt{\mathrm{n}(\mathrm{n}+2)}=\sqrt{2(2+2)}=\sqrt{8}$ B.M. $=2.82$ B.M.
BCECE-2017
COORDINATION COMPOUNDS
274218
The effective atomic number (EAN) of platinum in potassium hexachloro palatinate (IV) is
1 78
2 74
3 84
4 86
Explanation:
(D) : $\because$ EAN (effective atomic number) $=[\mathrm{Z}-$ oxidation number $]+[2 \times$ number of ligands $]$ For $\mathrm{Pt}$ (platinum) $\mathrm{Z}=78$ Oxidation number $=4$ $\therefore \quad$ EAN $=(78-4)+(2 \times 6)$ $=74+12=86$ (Atomic number Rn)
CG PET -2017
COORDINATION COMPOUNDS
274233
Which of the following is an outer orbital complex?
(B) : $\left[\mathrm{FeF}_{6}\right]^{3-}$ is an outer orbital complex $\mathrm{F}^{-}$act as weak field ligand so pairing of metal $\mathrm{d}$ - electrons not possible. In $\left[\mathrm{FeF}_{6}\right]^{3-}, \mathrm{Fe}$ is in +3 oxidation state. $\mathrm{Fe}^{3+}:[\mathrm{Ar}] 3 \mathrm{~d}^{5}$ Here, the complex formed involved the outer orbitals for hybridization. So the complex is called outer orbital complex.
AMU-2011
COORDINATION COMPOUNDS
274234
Which one of the following pairs of complexes has the effective atomic number equal to 36 for the transition element?
274217
The Magnetic moment (spin only) of $\left[\mathrm{NiCl}_{4}\right]^{2-}$ is-
1 $1.82 \mathrm{BM}$
2 $5.46 \mathrm{BM}$
3 $2.82 \mathrm{BM}$
4 $1.41 \mathrm{BM}$
Explanation:
(C) : In $\left[\mathrm{NiCl}_{4}\right]^{2-}$ complex, $\mathrm{Ni}$ metal is present in +2 oxidation state $\mathrm{Cl}^{-}$is weak field ligand and do not do pairing of metal $3 \mathrm{~d}-$ electrons. $\mathrm{Ni}^{2+}: 3 \mathrm{~d}^{8}$ No, if unpaired election $=2$ Magnetic moment $=\sqrt{\mathrm{n}(\mathrm{n}+2)}=\sqrt{2(2+2)}=\sqrt{8}$ B.M. $=2.82$ B.M.
BCECE-2017
COORDINATION COMPOUNDS
274218
The effective atomic number (EAN) of platinum in potassium hexachloro palatinate (IV) is
1 78
2 74
3 84
4 86
Explanation:
(D) : $\because$ EAN (effective atomic number) $=[\mathrm{Z}-$ oxidation number $]+[2 \times$ number of ligands $]$ For $\mathrm{Pt}$ (platinum) $\mathrm{Z}=78$ Oxidation number $=4$ $\therefore \quad$ EAN $=(78-4)+(2 \times 6)$ $=74+12=86$ (Atomic number Rn)
CG PET -2017
COORDINATION COMPOUNDS
274233
Which of the following is an outer orbital complex?
(B) : $\left[\mathrm{FeF}_{6}\right]^{3-}$ is an outer orbital complex $\mathrm{F}^{-}$act as weak field ligand so pairing of metal $\mathrm{d}$ - electrons not possible. In $\left[\mathrm{FeF}_{6}\right]^{3-}, \mathrm{Fe}$ is in +3 oxidation state. $\mathrm{Fe}^{3+}:[\mathrm{Ar}] 3 \mathrm{~d}^{5}$ Here, the complex formed involved the outer orbitals for hybridization. So the complex is called outer orbital complex.
AMU-2011
COORDINATION COMPOUNDS
274234
Which one of the following pairs of complexes has the effective atomic number equal to 36 for the transition element?
274217
The Magnetic moment (spin only) of $\left[\mathrm{NiCl}_{4}\right]^{2-}$ is-
1 $1.82 \mathrm{BM}$
2 $5.46 \mathrm{BM}$
3 $2.82 \mathrm{BM}$
4 $1.41 \mathrm{BM}$
Explanation:
(C) : In $\left[\mathrm{NiCl}_{4}\right]^{2-}$ complex, $\mathrm{Ni}$ metal is present in +2 oxidation state $\mathrm{Cl}^{-}$is weak field ligand and do not do pairing of metal $3 \mathrm{~d}-$ electrons. $\mathrm{Ni}^{2+}: 3 \mathrm{~d}^{8}$ No, if unpaired election $=2$ Magnetic moment $=\sqrt{\mathrm{n}(\mathrm{n}+2)}=\sqrt{2(2+2)}=\sqrt{8}$ B.M. $=2.82$ B.M.
BCECE-2017
COORDINATION COMPOUNDS
274218
The effective atomic number (EAN) of platinum in potassium hexachloro palatinate (IV) is
1 78
2 74
3 84
4 86
Explanation:
(D) : $\because$ EAN (effective atomic number) $=[\mathrm{Z}-$ oxidation number $]+[2 \times$ number of ligands $]$ For $\mathrm{Pt}$ (platinum) $\mathrm{Z}=78$ Oxidation number $=4$ $\therefore \quad$ EAN $=(78-4)+(2 \times 6)$ $=74+12=86$ (Atomic number Rn)
CG PET -2017
COORDINATION COMPOUNDS
274233
Which of the following is an outer orbital complex?
(B) : $\left[\mathrm{FeF}_{6}\right]^{3-}$ is an outer orbital complex $\mathrm{F}^{-}$act as weak field ligand so pairing of metal $\mathrm{d}$ - electrons not possible. In $\left[\mathrm{FeF}_{6}\right]^{3-}, \mathrm{Fe}$ is in +3 oxidation state. $\mathrm{Fe}^{3+}:[\mathrm{Ar}] 3 \mathrm{~d}^{5}$ Here, the complex formed involved the outer orbitals for hybridization. So the complex is called outer orbital complex.
AMU-2011
COORDINATION COMPOUNDS
274234
Which one of the following pairs of complexes has the effective atomic number equal to 36 for the transition element?
274217
The Magnetic moment (spin only) of $\left[\mathrm{NiCl}_{4}\right]^{2-}$ is-
1 $1.82 \mathrm{BM}$
2 $5.46 \mathrm{BM}$
3 $2.82 \mathrm{BM}$
4 $1.41 \mathrm{BM}$
Explanation:
(C) : In $\left[\mathrm{NiCl}_{4}\right]^{2-}$ complex, $\mathrm{Ni}$ metal is present in +2 oxidation state $\mathrm{Cl}^{-}$is weak field ligand and do not do pairing of metal $3 \mathrm{~d}-$ electrons. $\mathrm{Ni}^{2+}: 3 \mathrm{~d}^{8}$ No, if unpaired election $=2$ Magnetic moment $=\sqrt{\mathrm{n}(\mathrm{n}+2)}=\sqrt{2(2+2)}=\sqrt{8}$ B.M. $=2.82$ B.M.
BCECE-2017
COORDINATION COMPOUNDS
274218
The effective atomic number (EAN) of platinum in potassium hexachloro palatinate (IV) is
1 78
2 74
3 84
4 86
Explanation:
(D) : $\because$ EAN (effective atomic number) $=[\mathrm{Z}-$ oxidation number $]+[2 \times$ number of ligands $]$ For $\mathrm{Pt}$ (platinum) $\mathrm{Z}=78$ Oxidation number $=4$ $\therefore \quad$ EAN $=(78-4)+(2 \times 6)$ $=74+12=86$ (Atomic number Rn)
CG PET -2017
COORDINATION COMPOUNDS
274233
Which of the following is an outer orbital complex?
(B) : $\left[\mathrm{FeF}_{6}\right]^{3-}$ is an outer orbital complex $\mathrm{F}^{-}$act as weak field ligand so pairing of metal $\mathrm{d}$ - electrons not possible. In $\left[\mathrm{FeF}_{6}\right]^{3-}, \mathrm{Fe}$ is in +3 oxidation state. $\mathrm{Fe}^{3+}:[\mathrm{Ar}] 3 \mathrm{~d}^{5}$ Here, the complex formed involved the outer orbitals for hybridization. So the complex is called outer orbital complex.
AMU-2011
COORDINATION COMPOUNDS
274234
Which one of the following pairs of complexes has the effective atomic number equal to 36 for the transition element?
