274174
The correct pair(s) of the ambident nucleophiles is (are)
1 $\mathrm{B}$ and $\mathrm{C}$
2 Only A
3 $\mathrm{A}$ and $\mathrm{C}$
4 Only B
Explanation:
(C) : Ambidentate ligands- Those ligands which have two different donor atoms but only one donor atom is attached to the metal. These ligands are called ambidentate ligands. For example:- $\mathrm{AgCN}$ is covalent and $\mathrm{KCN}$ is ionic compound. $\mathrm{KCN} \longrightarrow \mathrm{K}^{+}+\mathrm{CN}^{-}$ $\mathrm{M} \longleftarrow \mathrm{CN} \Rightarrow \text { Cyanido }$ $\mathrm{AgCN} \longrightarrow \mathrm{Ag}+\mathrm{CN}$ $\mathrm{M} \longleftarrow \mathrm{NC} \Rightarrow \text { Isocyanido }$ $\mathrm{CN}$ has two donor atoms $\mathrm{N}$ and $\mathrm{C}$ but at a time only one atom is donated lone pair of electron to metal in $\mathrm{AgNO}_{2}$ and $\mathrm{KNO}_{2}, \mathrm{NO}_{2}$ has also two donor atom $\mathrm{N}$ and $\mathrm{O}$ but at a time only one atom is attached with metal .
JEE Main 2021
COORDINATION COMPOUNDS
274182
The correct order of field strength of the following ligands is
(C) : According spectrchemical series - Strength order of following ligands - $\mathrm{CO}>\mathrm{CN}^{-}>\mathrm{NO}_{2}^{-}>\mathrm{NH}_{3}>\mathrm{O}^{-2}>\mathrm{C}_{2} \mathrm{O}_{4}^{-2}>\mathrm{N}^{3-}>\mathrm{Cl}^{-}$ Therefore, the field strength of $\mathrm{CO}$ is maximum and $\mathrm{N}^{3-}$ is minimum field strength. So, $\mathrm{CO}>\mathrm{NH}_{3}>\mathrm{C}_{2} \mathrm{O}_{4}^{-2}>\mathrm{N}^{-3}$ is correct option.
06.08.2021]**
COORDINATION COMPOUNDS
274184
The number of bridged $\mathrm{CO}$ ligands present in $\mathrm{Fe}_{2}(\mathrm{CO})_{9}$ and $\mathrm{Co}_{2}(\mathrm{CO})_{8}$, respectively, are
1 2,1
2 2,2
3 2,3
4 3,2
Explanation:
(D) : No. of bridged CO ligands present in - $\mathrm{Fe}_{2}(\mathrm{CO})_{9}=3$ $\mathrm{Co}_{2}(\mathrm{CO})_{8}=2$ Bridged $\mathrm{CO}=3$ $\mathrm{Fe}_{2}(\mathrm{CO})_{9}$ $\mathrm{Co}_{2}(\mathrm{CO})_{8}$ No. of bridging $\mathrm{CO}$ ligands $=2$
05.08.2021 Shift-II]**
COORDINATION COMPOUNDS
274186
The molecule in which hybrid MOs involve only one d-orbital of the central atom is
(D) : $\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2+}$ complex form $\mathrm{dsp}^{2}$ hybridisation and square planar geometry. $\mathrm{CN}^{-}$act as strong field ligand and do pairing of metal d-electrons. $\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2+} \rightarrow \mathrm{Ni}^{2+}: \mathrm{d}^{8}$ Hence, square planar complex is formed by using only one d-orbital of the central atom.
274174
The correct pair(s) of the ambident nucleophiles is (are)
1 $\mathrm{B}$ and $\mathrm{C}$
2 Only A
3 $\mathrm{A}$ and $\mathrm{C}$
4 Only B
Explanation:
(C) : Ambidentate ligands- Those ligands which have two different donor atoms but only one donor atom is attached to the metal. These ligands are called ambidentate ligands. For example:- $\mathrm{AgCN}$ is covalent and $\mathrm{KCN}$ is ionic compound. $\mathrm{KCN} \longrightarrow \mathrm{K}^{+}+\mathrm{CN}^{-}$ $\mathrm{M} \longleftarrow \mathrm{CN} \Rightarrow \text { Cyanido }$ $\mathrm{AgCN} \longrightarrow \mathrm{Ag}+\mathrm{CN}$ $\mathrm{M} \longleftarrow \mathrm{NC} \Rightarrow \text { Isocyanido }$ $\mathrm{CN}$ has two donor atoms $\mathrm{N}$ and $\mathrm{C}$ but at a time only one atom is donated lone pair of electron to metal in $\mathrm{AgNO}_{2}$ and $\mathrm{KNO}_{2}, \mathrm{NO}_{2}$ has also two donor atom $\mathrm{N}$ and $\mathrm{O}$ but at a time only one atom is attached with metal .
JEE Main 2021
COORDINATION COMPOUNDS
274182
The correct order of field strength of the following ligands is
(C) : According spectrchemical series - Strength order of following ligands - $\mathrm{CO}>\mathrm{CN}^{-}>\mathrm{NO}_{2}^{-}>\mathrm{NH}_{3}>\mathrm{O}^{-2}>\mathrm{C}_{2} \mathrm{O}_{4}^{-2}>\mathrm{N}^{3-}>\mathrm{Cl}^{-}$ Therefore, the field strength of $\mathrm{CO}$ is maximum and $\mathrm{N}^{3-}$ is minimum field strength. So, $\mathrm{CO}>\mathrm{NH}_{3}>\mathrm{C}_{2} \mathrm{O}_{4}^{-2}>\mathrm{N}^{-3}$ is correct option.
06.08.2021]**
COORDINATION COMPOUNDS
274184
The number of bridged $\mathrm{CO}$ ligands present in $\mathrm{Fe}_{2}(\mathrm{CO})_{9}$ and $\mathrm{Co}_{2}(\mathrm{CO})_{8}$, respectively, are
1 2,1
2 2,2
3 2,3
4 3,2
Explanation:
(D) : No. of bridged CO ligands present in - $\mathrm{Fe}_{2}(\mathrm{CO})_{9}=3$ $\mathrm{Co}_{2}(\mathrm{CO})_{8}=2$ Bridged $\mathrm{CO}=3$ $\mathrm{Fe}_{2}(\mathrm{CO})_{9}$ $\mathrm{Co}_{2}(\mathrm{CO})_{8}$ No. of bridging $\mathrm{CO}$ ligands $=2$
05.08.2021 Shift-II]**
COORDINATION COMPOUNDS
274186
The molecule in which hybrid MOs involve only one d-orbital of the central atom is
(D) : $\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2+}$ complex form $\mathrm{dsp}^{2}$ hybridisation and square planar geometry. $\mathrm{CN}^{-}$act as strong field ligand and do pairing of metal d-electrons. $\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2+} \rightarrow \mathrm{Ni}^{2+}: \mathrm{d}^{8}$ Hence, square planar complex is formed by using only one d-orbital of the central atom.
274174
The correct pair(s) of the ambident nucleophiles is (are)
1 $\mathrm{B}$ and $\mathrm{C}$
2 Only A
3 $\mathrm{A}$ and $\mathrm{C}$
4 Only B
Explanation:
(C) : Ambidentate ligands- Those ligands which have two different donor atoms but only one donor atom is attached to the metal. These ligands are called ambidentate ligands. For example:- $\mathrm{AgCN}$ is covalent and $\mathrm{KCN}$ is ionic compound. $\mathrm{KCN} \longrightarrow \mathrm{K}^{+}+\mathrm{CN}^{-}$ $\mathrm{M} \longleftarrow \mathrm{CN} \Rightarrow \text { Cyanido }$ $\mathrm{AgCN} \longrightarrow \mathrm{Ag}+\mathrm{CN}$ $\mathrm{M} \longleftarrow \mathrm{NC} \Rightarrow \text { Isocyanido }$ $\mathrm{CN}$ has two donor atoms $\mathrm{N}$ and $\mathrm{C}$ but at a time only one atom is donated lone pair of electron to metal in $\mathrm{AgNO}_{2}$ and $\mathrm{KNO}_{2}, \mathrm{NO}_{2}$ has also two donor atom $\mathrm{N}$ and $\mathrm{O}$ but at a time only one atom is attached with metal .
JEE Main 2021
COORDINATION COMPOUNDS
274182
The correct order of field strength of the following ligands is
(C) : According spectrchemical series - Strength order of following ligands - $\mathrm{CO}>\mathrm{CN}^{-}>\mathrm{NO}_{2}^{-}>\mathrm{NH}_{3}>\mathrm{O}^{-2}>\mathrm{C}_{2} \mathrm{O}_{4}^{-2}>\mathrm{N}^{3-}>\mathrm{Cl}^{-}$ Therefore, the field strength of $\mathrm{CO}$ is maximum and $\mathrm{N}^{3-}$ is minimum field strength. So, $\mathrm{CO}>\mathrm{NH}_{3}>\mathrm{C}_{2} \mathrm{O}_{4}^{-2}>\mathrm{N}^{-3}$ is correct option.
06.08.2021]**
COORDINATION COMPOUNDS
274184
The number of bridged $\mathrm{CO}$ ligands present in $\mathrm{Fe}_{2}(\mathrm{CO})_{9}$ and $\mathrm{Co}_{2}(\mathrm{CO})_{8}$, respectively, are
1 2,1
2 2,2
3 2,3
4 3,2
Explanation:
(D) : No. of bridged CO ligands present in - $\mathrm{Fe}_{2}(\mathrm{CO})_{9}=3$ $\mathrm{Co}_{2}(\mathrm{CO})_{8}=2$ Bridged $\mathrm{CO}=3$ $\mathrm{Fe}_{2}(\mathrm{CO})_{9}$ $\mathrm{Co}_{2}(\mathrm{CO})_{8}$ No. of bridging $\mathrm{CO}$ ligands $=2$
05.08.2021 Shift-II]**
COORDINATION COMPOUNDS
274186
The molecule in which hybrid MOs involve only one d-orbital of the central atom is
(D) : $\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2+}$ complex form $\mathrm{dsp}^{2}$ hybridisation and square planar geometry. $\mathrm{CN}^{-}$act as strong field ligand and do pairing of metal d-electrons. $\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2+} \rightarrow \mathrm{Ni}^{2+}: \mathrm{d}^{8}$ Hence, square planar complex is formed by using only one d-orbital of the central atom.
274174
The correct pair(s) of the ambident nucleophiles is (are)
1 $\mathrm{B}$ and $\mathrm{C}$
2 Only A
3 $\mathrm{A}$ and $\mathrm{C}$
4 Only B
Explanation:
(C) : Ambidentate ligands- Those ligands which have two different donor atoms but only one donor atom is attached to the metal. These ligands are called ambidentate ligands. For example:- $\mathrm{AgCN}$ is covalent and $\mathrm{KCN}$ is ionic compound. $\mathrm{KCN} \longrightarrow \mathrm{K}^{+}+\mathrm{CN}^{-}$ $\mathrm{M} \longleftarrow \mathrm{CN} \Rightarrow \text { Cyanido }$ $\mathrm{AgCN} \longrightarrow \mathrm{Ag}+\mathrm{CN}$ $\mathrm{M} \longleftarrow \mathrm{NC} \Rightarrow \text { Isocyanido }$ $\mathrm{CN}$ has two donor atoms $\mathrm{N}$ and $\mathrm{C}$ but at a time only one atom is donated lone pair of electron to metal in $\mathrm{AgNO}_{2}$ and $\mathrm{KNO}_{2}, \mathrm{NO}_{2}$ has also two donor atom $\mathrm{N}$ and $\mathrm{O}$ but at a time only one atom is attached with metal .
JEE Main 2021
COORDINATION COMPOUNDS
274182
The correct order of field strength of the following ligands is
(C) : According spectrchemical series - Strength order of following ligands - $\mathrm{CO}>\mathrm{CN}^{-}>\mathrm{NO}_{2}^{-}>\mathrm{NH}_{3}>\mathrm{O}^{-2}>\mathrm{C}_{2} \mathrm{O}_{4}^{-2}>\mathrm{N}^{3-}>\mathrm{Cl}^{-}$ Therefore, the field strength of $\mathrm{CO}$ is maximum and $\mathrm{N}^{3-}$ is minimum field strength. So, $\mathrm{CO}>\mathrm{NH}_{3}>\mathrm{C}_{2} \mathrm{O}_{4}^{-2}>\mathrm{N}^{-3}$ is correct option.
06.08.2021]**
COORDINATION COMPOUNDS
274184
The number of bridged $\mathrm{CO}$ ligands present in $\mathrm{Fe}_{2}(\mathrm{CO})_{9}$ and $\mathrm{Co}_{2}(\mathrm{CO})_{8}$, respectively, are
1 2,1
2 2,2
3 2,3
4 3,2
Explanation:
(D) : No. of bridged CO ligands present in - $\mathrm{Fe}_{2}(\mathrm{CO})_{9}=3$ $\mathrm{Co}_{2}(\mathrm{CO})_{8}=2$ Bridged $\mathrm{CO}=3$ $\mathrm{Fe}_{2}(\mathrm{CO})_{9}$ $\mathrm{Co}_{2}(\mathrm{CO})_{8}$ No. of bridging $\mathrm{CO}$ ligands $=2$
05.08.2021 Shift-II]**
COORDINATION COMPOUNDS
274186
The molecule in which hybrid MOs involve only one d-orbital of the central atom is
(D) : $\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2+}$ complex form $\mathrm{dsp}^{2}$ hybridisation and square planar geometry. $\mathrm{CN}^{-}$act as strong field ligand and do pairing of metal d-electrons. $\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2+} \rightarrow \mathrm{Ni}^{2+}: \mathrm{d}^{8}$ Hence, square planar complex is formed by using only one d-orbital of the central atom.
