QBManager

COORDINATION COMPOUNDS

273842 The structure of paramagnetic nickel complex, ${[{NiCl}_{4}]}^{2 -}$ is

1 tetrahedral

2 square planar

3 trigonal bipyramidal

4 distorted octahedral

Explanation:

(A) : The oxidation state of $Ni$ in ${[{NiCl}_{4}]}^{2 -}$ is -
$x + 4 (- 1) = - 2$
$x = + 2$
${Ni}^{2 +} = [Ar] 3 d^{8}$ , unpaired $e^{-} = 2$ (Paramagnetic)
The hybridization of the complex is ${sp}^{3}$ .
Hence, the geometry will be tetrahedral.

AMU-2013

COORDINATION COMPOUNDS

273847 Formula of hexaaqua manganese (II) phosphate is

1

[Mn {(H_{2} O)}_{6}] {PO}_{4}

2

{[Mn {(H_{2} O)}_{6}]}_{3} {PO}_{4}

3

{[Mn {(H_{2} O)}_{6}]}_{3} {({PO}_{4})}_{2}

4

[Mn {(H_{2} O)}_{6}] {({PO}_{4})}_{3}

Explanation:

(C) : The name of the complex is hexa aqua manganese (II) phosphate. The metal contains the +2 oxidation state.
(a) $[Mn {(H_{2} O)}_{6}] {PO}_{4}$
$x + 6 (0) + (- 3) = 0$
(b) ${[Mn {(H_{2} O)}_{6}]}_{3} {PO}_{4}$
$x = + 3$ $3 x + 3 \times 6 \times (0) + (- 3) = 0$
(c) ${[Mn {(H_{2} O)}_{6}]}_{3} {({PO}_{4})}_{2}$
$3 x + 3 \times 6 \times (0) + 2 (- 3) = 0$ $x = + 1$
$3 x = 6$
(d) ${[Mn {(H_{2} O)}_{6}]}_{6} {({PO}_{4})}_{3}$ $6 x + 6 \times 6 (0) + (- 3) \times 3 = 0$
$x = + 2$
$6 X - 9 = 0$
$x = \frac{9}{6} = \frac{3}{2}$
Hence, the correct option will be (c).

CG PET-2012

COORDINATION COMPOUNDS

273798 Match List-I with List-II:
| | List-I | | List-II |
| :--- | :--- | :--- | :--- |
| (a) | $[Co {({NH}_{3})}_{6}] [Cr (CN)_{6}]$ | (i) | Linkage isomerism |
| (b) | $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$ | (ii) | Solvate isomerism |
| (c) | $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ | (iii) | Co-ordination isomerism |
| (d) | cis- ${[{CrCl}_{2} (ox)_{2}]}^{3 -}$ | (iv) | Optical isomerism |
Choose the correct answer from the options given below:

1 (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)

2 (a)-(ii),(b)-(i),,(c)-(iii),(d)-(iv)

3 (a)-(iii),(b)-(i),(c)-(ii), (d)-(iv)

4 (a)-(iv),(b)-(ii),,(c)-(iii),(d)-(i)

Explanation:

(C) :
|Co-ordination complex |Isomerism|
|
|(a) $[Co {({NH}_{3})}_{6}] [Cr (CN)_{6}]$ - Co-ordination isomerism
|(b) $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$ - |Linkage isomerism|
|(c) $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ - |Solvate isomerism|
|(d) cis- ${[{CrCl}_{2} (ox)_{2}]}^{3 -}$ |Optical isomerism|

JEE Main 17.03.2021

COORDINATION COMPOUNDS

273809 The species that can have a trans-isomer is (en=ethane -1,2-diamine, $0 x =$ oxalate)

1

[Pt (en) {Cl}_{2}]

2

{[Cr (en)_{2} (ox)]}^{+}

3

{[Pt (en)_{2} {Cl}_{2}]}^{2 +}

4

[Zn (en) {Cl}_{2}]

Explanation:

(C) : ${[Pt (en)_{2} {Cl}_{2}]}^{2 +}$ is a octahedral complex type of $[M (AA)_{2} B_{2}]$ . It shows the both cis and trans isomerism.

$[Pt (en) {Cl}_{2}], {[Cr (en)_{2} (ox)]}^{+}$ and $[Zn (en) {Cl}_{2}]$ exhibit the only cis isomerism.

JEE Main-2019

COORDINATION COMPOUNDS

273820 How many geometrical isomers are possible with complexes of the type $[M (a b)_{3}]$ ?

1 2

2 4

3 3

4 5

Explanation:

(A) : The type of the complex is $[M (ab)_{3}]$ . It is a octahedral complex which form the facial or meridional isomerism (geometrical isomerism)
original image
Hence, it contains the two geometrical isomer.

Karnataka CET-2018

COORDINATION COMPOUNDS

273842 The structure of paramagnetic nickel complex, ${[{NiCl}_{4}]}^{2 -}$ is

1 tetrahedral

2 square planar

3 trigonal bipyramidal

4 distorted octahedral

Explanation:

(A) : The oxidation state of $Ni$ in ${[{NiCl}_{4}]}^{2 -}$ is -
$x + 4 (- 1) = - 2$
$x = + 2$
${Ni}^{2 +} = [Ar] 3 d^{8}$ , unpaired $e^{-} = 2$ (Paramagnetic)
The hybridization of the complex is ${sp}^{3}$ .
Hence, the geometry will be tetrahedral.

AMU-2013

COORDINATION COMPOUNDS

273847 Formula of hexaaqua manganese (II) phosphate is

1

[Mn {(H_{2} O)}_{6}] {PO}_{4}

2

{[Mn {(H_{2} O)}_{6}]}_{3} {PO}_{4}

3

{[Mn {(H_{2} O)}_{6}]}_{3} {({PO}_{4})}_{2}

4

[Mn {(H_{2} O)}_{6}] {({PO}_{4})}_{3}

Explanation:

(C) : The name of the complex is hexa aqua manganese (II) phosphate. The metal contains the +2 oxidation state.
(a) $[Mn {(H_{2} O)}_{6}] {PO}_{4}$
$x + 6 (0) + (- 3) = 0$
(b) ${[Mn {(H_{2} O)}_{6}]}_{3} {PO}_{4}$
$x = + 3$ $3 x + 3 \times 6 \times (0) + (- 3) = 0$
(c) ${[Mn {(H_{2} O)}_{6}]}_{3} {({PO}_{4})}_{2}$
$3 x + 3 \times 6 \times (0) + 2 (- 3) = 0$ $x = + 1$
$3 x = 6$
(d) ${[Mn {(H_{2} O)}_{6}]}_{6} {({PO}_{4})}_{3}$ $6 x + 6 \times 6 (0) + (- 3) \times 3 = 0$
$x = + 2$
$6 X - 9 = 0$
$x = \frac{9}{6} = \frac{3}{2}$
Hence, the correct option will be (c).

CG PET-2012

COORDINATION COMPOUNDS

273798 Match List-I with List-II:
| | List-I | | List-II |
| :--- | :--- | :--- | :--- |
| (a) | $[Co {({NH}_{3})}_{6}] [Cr (CN)_{6}]$ | (i) | Linkage isomerism |
| (b) | $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$ | (ii) | Solvate isomerism |
| (c) | $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ | (iii) | Co-ordination isomerism |
| (d) | cis- ${[{CrCl}_{2} (ox)_{2}]}^{3 -}$ | (iv) | Optical isomerism |
Choose the correct answer from the options given below:

1 (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)

2 (a)-(ii),(b)-(i),,(c)-(iii),(d)-(iv)

3 (a)-(iii),(b)-(i),(c)-(ii), (d)-(iv)

4 (a)-(iv),(b)-(ii),,(c)-(iii),(d)-(i)

Explanation:

(C) :
|Co-ordination complex |Isomerism|
|
|(a) $[Co {({NH}_{3})}_{6}] [Cr (CN)_{6}]$ - Co-ordination isomerism
|(b) $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$ - |Linkage isomerism|
|(c) $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ - |Solvate isomerism|
|(d) cis- ${[{CrCl}_{2} (ox)_{2}]}^{3 -}$ |Optical isomerism|

JEE Main 17.03.2021

COORDINATION COMPOUNDS

273809 The species that can have a trans-isomer is (en=ethane -1,2-diamine, $0 x =$ oxalate)

1

[Pt (en) {Cl}_{2}]

2

{[Cr (en)_{2} (ox)]}^{+}

3

{[Pt (en)_{2} {Cl}_{2}]}^{2 +}

4

[Zn (en) {Cl}_{2}]

Explanation:

(C) : ${[Pt (en)_{2} {Cl}_{2}]}^{2 +}$ is a octahedral complex type of $[M (AA)_{2} B_{2}]$ . It shows the both cis and trans isomerism.

$[Pt (en) {Cl}_{2}], {[Cr (en)_{2} (ox)]}^{+}$ and $[Zn (en) {Cl}_{2}]$ exhibit the only cis isomerism.

JEE Main-2019

COORDINATION COMPOUNDS

273820 How many geometrical isomers are possible with complexes of the type $[M (a b)_{3}]$ ?

1 2

2 4

3 3

4 5

Explanation:

(A) : The type of the complex is $[M (ab)_{3}]$ . It is a octahedral complex which form the facial or meridional isomerism (geometrical isomerism)
original image
Hence, it contains the two geometrical isomer.

Karnataka CET-2018

COORDINATION COMPOUNDS

273842 The structure of paramagnetic nickel complex, ${[{NiCl}_{4}]}^{2 -}$ is

1 tetrahedral

2 square planar

3 trigonal bipyramidal

4 distorted octahedral

Explanation:

(A) : The oxidation state of $Ni$ in ${[{NiCl}_{4}]}^{2 -}$ is -
$x + 4 (- 1) = - 2$
$x = + 2$
${Ni}^{2 +} = [Ar] 3 d^{8}$ , unpaired $e^{-} = 2$ (Paramagnetic)
The hybridization of the complex is ${sp}^{3}$ .
Hence, the geometry will be tetrahedral.

AMU-2013

COORDINATION COMPOUNDS

273847 Formula of hexaaqua manganese (II) phosphate is

1

[Mn {(H_{2} O)}_{6}] {PO}_{4}

2

{[Mn {(H_{2} O)}_{6}]}_{3} {PO}_{4}

3

{[Mn {(H_{2} O)}_{6}]}_{3} {({PO}_{4})}_{2}

4

[Mn {(H_{2} O)}_{6}] {({PO}_{4})}_{3}

Explanation:

(C) : The name of the complex is hexa aqua manganese (II) phosphate. The metal contains the +2 oxidation state.
(a) $[Mn {(H_{2} O)}_{6}] {PO}_{4}$
$x + 6 (0) + (- 3) = 0$
(b) ${[Mn {(H_{2} O)}_{6}]}_{3} {PO}_{4}$
$x = + 3$ $3 x + 3 \times 6 \times (0) + (- 3) = 0$
(c) ${[Mn {(H_{2} O)}_{6}]}_{3} {({PO}_{4})}_{2}$
$3 x + 3 \times 6 \times (0) + 2 (- 3) = 0$ $x = + 1$
$3 x = 6$
(d) ${[Mn {(H_{2} O)}_{6}]}_{6} {({PO}_{4})}_{3}$ $6 x + 6 \times 6 (0) + (- 3) \times 3 = 0$
$x = + 2$
$6 X - 9 = 0$
$x = \frac{9}{6} = \frac{3}{2}$
Hence, the correct option will be (c).

CG PET-2012

COORDINATION COMPOUNDS

273798 Match List-I with List-II:
| | List-I | | List-II |
| :--- | :--- | :--- | :--- |
| (a) | $[Co {({NH}_{3})}_{6}] [Cr (CN)_{6}]$ | (i) | Linkage isomerism |
| (b) | $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$ | (ii) | Solvate isomerism |
| (c) | $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ | (iii) | Co-ordination isomerism |
| (d) | cis- ${[{CrCl}_{2} (ox)_{2}]}^{3 -}$ | (iv) | Optical isomerism |
Choose the correct answer from the options given below:

1 (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)

2 (a)-(ii),(b)-(i),,(c)-(iii),(d)-(iv)

3 (a)-(iii),(b)-(i),(c)-(ii), (d)-(iv)

4 (a)-(iv),(b)-(ii),,(c)-(iii),(d)-(i)

Explanation:

(C) :
|Co-ordination complex |Isomerism|
|
|(a) $[Co {({NH}_{3})}_{6}] [Cr (CN)_{6}]$ - Co-ordination isomerism
|(b) $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$ - |Linkage isomerism|
|(c) $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ - |Solvate isomerism|
|(d) cis- ${[{CrCl}_{2} (ox)_{2}]}^{3 -}$ |Optical isomerism|

JEE Main 17.03.2021

COORDINATION COMPOUNDS

273809 The species that can have a trans-isomer is (en=ethane -1,2-diamine, $0 x =$ oxalate)

1

[Pt (en) {Cl}_{2}]

2

{[Cr (en)_{2} (ox)]}^{+}

3

{[Pt (en)_{2} {Cl}_{2}]}^{2 +}

4

[Zn (en) {Cl}_{2}]

Explanation:

(C) : ${[Pt (en)_{2} {Cl}_{2}]}^{2 +}$ is a octahedral complex type of $[M (AA)_{2} B_{2}]$ . It shows the both cis and trans isomerism.

$[Pt (en) {Cl}_{2}], {[Cr (en)_{2} (ox)]}^{+}$ and $[Zn (en) {Cl}_{2}]$ exhibit the only cis isomerism.

JEE Main-2019

COORDINATION COMPOUNDS

273820 How many geometrical isomers are possible with complexes of the type $[M (a b)_{3}]$ ?

1 2

2 4

3 3

4 5

Explanation:

(A) : The type of the complex is $[M (ab)_{3}]$ . It is a octahedral complex which form the facial or meridional isomerism (geometrical isomerism)
original image
Hence, it contains the two geometrical isomer.

Karnataka CET-2018

COORDINATION COMPOUNDS

273842 The structure of paramagnetic nickel complex, ${[{NiCl}_{4}]}^{2 -}$ is

1 tetrahedral

2 square planar

3 trigonal bipyramidal

4 distorted octahedral

Explanation:

(A) : The oxidation state of $Ni$ in ${[{NiCl}_{4}]}^{2 -}$ is -
$x + 4 (- 1) = - 2$
$x = + 2$
${Ni}^{2 +} = [Ar] 3 d^{8}$ , unpaired $e^{-} = 2$ (Paramagnetic)
The hybridization of the complex is ${sp}^{3}$ .
Hence, the geometry will be tetrahedral.

AMU-2013

COORDINATION COMPOUNDS

273847 Formula of hexaaqua manganese (II) phosphate is

1

[Mn {(H_{2} O)}_{6}] {PO}_{4}

2

{[Mn {(H_{2} O)}_{6}]}_{3} {PO}_{4}

3

{[Mn {(H_{2} O)}_{6}]}_{3} {({PO}_{4})}_{2}

4

[Mn {(H_{2} O)}_{6}] {({PO}_{4})}_{3}

Explanation:

(C) : The name of the complex is hexa aqua manganese (II) phosphate. The metal contains the +2 oxidation state.
(a) $[Mn {(H_{2} O)}_{6}] {PO}_{4}$
$x + 6 (0) + (- 3) = 0$
(b) ${[Mn {(H_{2} O)}_{6}]}_{3} {PO}_{4}$
$x = + 3$ $3 x + 3 \times 6 \times (0) + (- 3) = 0$
(c) ${[Mn {(H_{2} O)}_{6}]}_{3} {({PO}_{4})}_{2}$
$3 x + 3 \times 6 \times (0) + 2 (- 3) = 0$ $x = + 1$
$3 x = 6$
(d) ${[Mn {(H_{2} O)}_{6}]}_{6} {({PO}_{4})}_{3}$ $6 x + 6 \times 6 (0) + (- 3) \times 3 = 0$
$x = + 2$
$6 X - 9 = 0$
$x = \frac{9}{6} = \frac{3}{2}$
Hence, the correct option will be (c).

CG PET-2012

COORDINATION COMPOUNDS

273798 Match List-I with List-II:
| | List-I | | List-II |
| :--- | :--- | :--- | :--- |
| (a) | $[Co {({NH}_{3})}_{6}] [Cr (CN)_{6}]$ | (i) | Linkage isomerism |
| (b) | $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$ | (ii) | Solvate isomerism |
| (c) | $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ | (iii) | Co-ordination isomerism |
| (d) | cis- ${[{CrCl}_{2} (ox)_{2}]}^{3 -}$ | (iv) | Optical isomerism |
Choose the correct answer from the options given below:

1 (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)

2 (a)-(ii),(b)-(i),,(c)-(iii),(d)-(iv)

3 (a)-(iii),(b)-(i),(c)-(ii), (d)-(iv)

4 (a)-(iv),(b)-(ii),,(c)-(iii),(d)-(i)

Explanation:

(C) :
|Co-ordination complex |Isomerism|
|
|(a) $[Co {({NH}_{3})}_{6}] [Cr (CN)_{6}]$ - Co-ordination isomerism
|(b) $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$ - |Linkage isomerism|
|(c) $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ - |Solvate isomerism|
|(d) cis- ${[{CrCl}_{2} (ox)_{2}]}^{3 -}$ |Optical isomerism|

JEE Main 17.03.2021

COORDINATION COMPOUNDS

273809 The species that can have a trans-isomer is (en=ethane -1,2-diamine, $0 x =$ oxalate)

1

[Pt (en) {Cl}_{2}]

2

{[Cr (en)_{2} (ox)]}^{+}

3

{[Pt (en)_{2} {Cl}_{2}]}^{2 +}

4

[Zn (en) {Cl}_{2}]

Explanation:

(C) : ${[Pt (en)_{2} {Cl}_{2}]}^{2 +}$ is a octahedral complex type of $[M (AA)_{2} B_{2}]$ . It shows the both cis and trans isomerism.

$[Pt (en) {Cl}_{2}], {[Cr (en)_{2} (ox)]}^{+}$ and $[Zn (en) {Cl}_{2}]$ exhibit the only cis isomerism.

JEE Main-2019

COORDINATION COMPOUNDS

273820 How many geometrical isomers are possible with complexes of the type $[M (a b)_{3}]$ ?

1 2

2 4

3 3

4 5

Explanation:

(A) : The type of the complex is $[M (ab)_{3}]$ . It is a octahedral complex which form the facial or meridional isomerism (geometrical isomerism)
original image
Hence, it contains the two geometrical isomer.

Karnataka CET-2018

COORDINATION COMPOUNDS

273842 The structure of paramagnetic nickel complex, ${[{NiCl}_{4}]}^{2 -}$ is

1 tetrahedral

2 square planar

3 trigonal bipyramidal

4 distorted octahedral

Explanation:

(A) : The oxidation state of $Ni$ in ${[{NiCl}_{4}]}^{2 -}$ is -
$x + 4 (- 1) = - 2$
$x = + 2$
${Ni}^{2 +} = [Ar] 3 d^{8}$ , unpaired $e^{-} = 2$ (Paramagnetic)
The hybridization of the complex is ${sp}^{3}$ .
Hence, the geometry will be tetrahedral.

AMU-2013

COORDINATION COMPOUNDS

273847 Formula of hexaaqua manganese (II) phosphate is

1

[Mn {(H_{2} O)}_{6}] {PO}_{4}

2

{[Mn {(H_{2} O)}_{6}]}_{3} {PO}_{4}

3

{[Mn {(H_{2} O)}_{6}]}_{3} {({PO}_{4})}_{2}

4

[Mn {(H_{2} O)}_{6}] {({PO}_{4})}_{3}

Explanation:

(C) : The name of the complex is hexa aqua manganese (II) phosphate. The metal contains the +2 oxidation state.
(a) $[Mn {(H_{2} O)}_{6}] {PO}_{4}$
$x + 6 (0) + (- 3) = 0$
(b) ${[Mn {(H_{2} O)}_{6}]}_{3} {PO}_{4}$
$x = + 3$ $3 x + 3 \times 6 \times (0) + (- 3) = 0$
(c) ${[Mn {(H_{2} O)}_{6}]}_{3} {({PO}_{4})}_{2}$
$3 x + 3 \times 6 \times (0) + 2 (- 3) = 0$ $x = + 1$
$3 x = 6$
(d) ${[Mn {(H_{2} O)}_{6}]}_{6} {({PO}_{4})}_{3}$ $6 x + 6 \times 6 (0) + (- 3) \times 3 = 0$
$x = + 2$
$6 X - 9 = 0$
$x = \frac{9}{6} = \frac{3}{2}$
Hence, the correct option will be (c).

CG PET-2012

COORDINATION COMPOUNDS

273798 Match List-I with List-II:
| | List-I | | List-II |
| :--- | :--- | :--- | :--- |
| (a) | $[Co {({NH}_{3})}_{6}] [Cr (CN)_{6}]$ | (i) | Linkage isomerism |
| (b) | $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$ | (ii) | Solvate isomerism |
| (c) | $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ | (iii) | Co-ordination isomerism |
| (d) | cis- ${[{CrCl}_{2} (ox)_{2}]}^{3 -}$ | (iv) | Optical isomerism |
Choose the correct answer from the options given below:

1 (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)

2 (a)-(ii),(b)-(i),,(c)-(iii),(d)-(iv)

3 (a)-(iii),(b)-(i),(c)-(ii), (d)-(iv)

4 (a)-(iv),(b)-(ii),,(c)-(iii),(d)-(i)

Explanation:

(C) :
|Co-ordination complex |Isomerism|
|
|(a) $[Co {({NH}_{3})}_{6}] [Cr (CN)_{6}]$ - Co-ordination isomerism
|(b) $[Co {({NH}_{3})}_{3} {({NO}_{2})}_{3}]$ - |Linkage isomerism|
|(c) $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ - |Solvate isomerism|
|(d) cis- ${[{CrCl}_{2} (ox)_{2}]}^{3 -}$ |Optical isomerism|

JEE Main 17.03.2021

COORDINATION COMPOUNDS

273809 The species that can have a trans-isomer is (en=ethane -1,2-diamine, $0 x =$ oxalate)

1

[Pt (en) {Cl}_{2}]

2

{[Cr (en)_{2} (ox)]}^{+}

3

{[Pt (en)_{2} {Cl}_{2}]}^{2 +}

4

[Zn (en) {Cl}_{2}]

Explanation:

(C) : ${[Pt (en)_{2} {Cl}_{2}]}^{2 +}$ is a octahedral complex type of $[M (AA)_{2} B_{2}]$ . It shows the both cis and trans isomerism.

$[Pt (en) {Cl}_{2}], {[Cr (en)_{2} (ox)]}^{+}$ and $[Zn (en) {Cl}_{2}]$ exhibit the only cis isomerism.

JEE Main-2019

COORDINATION COMPOUNDS

273820 How many geometrical isomers are possible with complexes of the type $[M (a b)_{3}]$ ?

1 2

2 4

3 3

4 5

Explanation:

(A) : The type of the complex is $[M (ab)_{3}]$ . It is a octahedral complex which form the facial or meridional isomerism (geometrical isomerism)
original image
Hence, it contains the two geometrical isomer.

Karnataka CET-2018

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Question Bank Series

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation: