QBManager

COORDINATION COMPOUNDS

273805 ${CuSO}_{4}$ reacts with $KCN$ solution and forms

1

K_{3} [Cu (CN)_{4}]

2

[Cu (CN)]

3

[Cu (CN)_{2}]

4

K_{4} [Cu (CN)_{6}]

Explanation:

(A) : Copper sulphate is dissolved in potassium cyanide solution. Copper sulphate reacts with potassium cyanide to form potassium sulphate and cupric cyanide-
$\underset{Copper sulphate}{{CuSO}_{4}} + \underset{\begin{matrix} Potassium \\ cyanide \end{matrix}}{2 KCN} \to \underset{\begin{matrix} Potassium \\ Sulphate \end{matrix}}{K_{2} {SO}_{4}} + \underset{\begin{matrix} Cypric \\ cyanide \end{matrix}}{Cu (CN)_{2}}$
Cupric Cyanide is unstable. It decomposes to form cuprous cyanide and cyanogens gas.
$2 Cu (CN)_{2} ⟶ 2 CuCN + (CN)_{2}$
In this reaction, cupric cyanide is reduced to cuprous cyanide. One mole of cuprous cyanide reacts with three moles of potassium cyanide to form the complex compound.
$CuCN + 3 KCN ⟶ K_{3} [Cu (CN)_{4}]$

COMEDK-2020

COORDINATION COMPOUNDS

273808 Which of the following complex ion shows geometrical isomerism ?

1

{[Cr {(H_{2} O)}_{4} C_{2}]}^{+}

2

{[Pt {({NH}_{3})}_{3} C ℓ]}^{+}

3

{[Co {({NH}_{3})}_{6}]}^{3 +}

4

{[Co (CN)_{5} (NC)]}^{3 -}

Explanation:

(A) : ${[Cr {(H_{2} O)}_{4} {Cl}_{2}]}^{+}$ shows geometrical isomerism. It is complex compounds of $[{MA}_{4} B_{2}]$ type.

${[Pt {({NH}_{3})}_{3} C ℓ]}^{+}$ ,
${[Co {({NH}_{3})}_{6}]}^{3 +}$
${[Co (CN)_{5} (NC)]}^{3 -}$ do not show stereoisomerism.

AP EAMCET (Engg.) 18.09.2020

COORDINATION COMPOUNDS

273821 How many geometrical isomers are possible with complexes of the type $[M (a b)_{3}]$ ?
9. $[Fe {({NO}_{2})}_{3} {Cl}_{3}]$ and $[Fe (O - NO)_{3} {Cl}_{3}]$ shows}

1 linkage isomerism

2 geometrical isomerism

3 optical isomerism

4 hydrate isomerism
Ans. (a)
Exp: (A) :

[Fe {({NO}_{2})}_{3} {Cl}_{3}]

and

[Fe (ONO)_{3}) {Cl}_{3}]

shows the linkage isomerism because it contains the

{NO}_{2}

ligands.

Explanation:

(A) : The type of the complex is $[M (ab)_{3}]$ . It is a octahedral complex which form the facial or meridional isomerism (geometrical isomerism)
original image
Hence, it contains the two geometrical isomer.
(a.) linkage isomerism
(b.) geometrical isomerism
(c.) optical isomerism
(d.) hydrate isomerism
Ans. (a)
Exp: (A) : $[Fe {({NO}_{2})}_{3} {Cl}_{3}]$ and $[Fe (ONO)_{3}) {Cl}_{3}]$ shows the linkage isomerism because it contains the ${NO}_{2}$ ligands.

Karnataka CET-2018

COORDINATION COMPOUNDS

273824 The correct statement for the isomerism associated with the following complex ions is:
(A) ${[Ni {(H_{2} O)}_{5} {NH}_{3}]}^{2 +}$ ,
(B) ${[Ni {(H_{2} O)}_{4} {({NH}_{3})}_{2}]}^{2 +}$ and
(C) ${[Ni {(H_{2} O)}_{3} {({NH}_{3})}_{3}]}^{2 +}$ is:

1 (A) and (B) show only geometrical isomerism.

2 (A) and (B) show geometrical and optical isomerism.

3 (B) and (C) show geometrical and optical isomerism.

4 (B) and (C) show only geometrical isomerism.

Explanation:

(D) :
(A) For monodentate ligands A and B, no isomers are possible for $[{MA}_{5} B]$ type of complex. Hence, ${[Ni {(H_{2} O)}_{5} {NH}_{3}]}^{2 +}$ does not show the geometrical as well as optical isomerism.
(B) $[{MA}_{4} B_{2}]$ i.e. ${[Ni {(H_{2} O)}_{4} {({NH}_{3})}_{2}]}^{2 +}$ type of octahedral complexes exist as cis and trans isomer (geometrical isomerism).
original image
(C) $[{MA}_{3} B_{3}]$ i.e. ${[Ni {(H_{2} O)}_{3} {({NH}_{3})}_{3}]}^{2 +}$ type of octahedral complexes are known to give cis and trans isomers (Geometrical isomerism)
- When the three ligands are in the same triangular face of the octahedron, the compound is called facial or face-isomer. When the three ligands are on the same equatorial plane of the octahedron i.e. around the meridian of the octahedron, the compound is called meridional or mer isomer.

AIIMS-27 May

COORDINATION COMPOUNDS

273805 ${CuSO}_{4}$ reacts with $KCN$ solution and forms

1

K_{3} [Cu (CN)_{4}]

2

[Cu (CN)]

3

[Cu (CN)_{2}]

4

K_{4} [Cu (CN)_{6}]

Explanation:

(A) : Copper sulphate is dissolved in potassium cyanide solution. Copper sulphate reacts with potassium cyanide to form potassium sulphate and cupric cyanide-
$\underset{Copper sulphate}{{CuSO}_{4}} + \underset{\begin{matrix} Potassium \\ cyanide \end{matrix}}{2 KCN} \to \underset{\begin{matrix} Potassium \\ Sulphate \end{matrix}}{K_{2} {SO}_{4}} + \underset{\begin{matrix} Cypric \\ cyanide \end{matrix}}{Cu (CN)_{2}}$
Cupric Cyanide is unstable. It decomposes to form cuprous cyanide and cyanogens gas.
$2 Cu (CN)_{2} ⟶ 2 CuCN + (CN)_{2}$
In this reaction, cupric cyanide is reduced to cuprous cyanide. One mole of cuprous cyanide reacts with three moles of potassium cyanide to form the complex compound.
$CuCN + 3 KCN ⟶ K_{3} [Cu (CN)_{4}]$

COMEDK-2020

COORDINATION COMPOUNDS

273808 Which of the following complex ion shows geometrical isomerism ?

1

{[Cr {(H_{2} O)}_{4} C_{2}]}^{+}

2

{[Pt {({NH}_{3})}_{3} C ℓ]}^{+}

3

{[Co {({NH}_{3})}_{6}]}^{3 +}

4

{[Co (CN)_{5} (NC)]}^{3 -}

Explanation:

(A) : ${[Cr {(H_{2} O)}_{4} {Cl}_{2}]}^{+}$ shows geometrical isomerism. It is complex compounds of $[{MA}_{4} B_{2}]$ type.

${[Pt {({NH}_{3})}_{3} C ℓ]}^{+}$ ,
${[Co {({NH}_{3})}_{6}]}^{3 +}$
${[Co (CN)_{5} (NC)]}^{3 -}$ do not show stereoisomerism.

AP EAMCET (Engg.) 18.09.2020

COORDINATION COMPOUNDS

273821 How many geometrical isomers are possible with complexes of the type $[M (a b)_{3}]$ ?
9. $[Fe {({NO}_{2})}_{3} {Cl}_{3}]$ and $[Fe (O - NO)_{3} {Cl}_{3}]$ shows}

1 linkage isomerism

2 geometrical isomerism

3 optical isomerism

4 hydrate isomerism
Ans. (a)
Exp: (A) :

[Fe {({NO}_{2})}_{3} {Cl}_{3}]

and

[Fe (ONO)_{3}) {Cl}_{3}]

shows the linkage isomerism because it contains the

{NO}_{2}

ligands.

Explanation:

(A) : The type of the complex is $[M (ab)_{3}]$ . It is a octahedral complex which form the facial or meridional isomerism (geometrical isomerism)
original image
Hence, it contains the two geometrical isomer.
(a.) linkage isomerism
(b.) geometrical isomerism
(c.) optical isomerism
(d.) hydrate isomerism
Ans. (a)
Exp: (A) : $[Fe {({NO}_{2})}_{3} {Cl}_{3}]$ and $[Fe (ONO)_{3}) {Cl}_{3}]$ shows the linkage isomerism because it contains the ${NO}_{2}$ ligands.

Karnataka CET-2018

COORDINATION COMPOUNDS

273824 The correct statement for the isomerism associated with the following complex ions is:
(A) ${[Ni {(H_{2} O)}_{5} {NH}_{3}]}^{2 +}$ ,
(B) ${[Ni {(H_{2} O)}_{4} {({NH}_{3})}_{2}]}^{2 +}$ and
(C) ${[Ni {(H_{2} O)}_{3} {({NH}_{3})}_{3}]}^{2 +}$ is:

1 (A) and (B) show only geometrical isomerism.

2 (A) and (B) show geometrical and optical isomerism.

3 (B) and (C) show geometrical and optical isomerism.

4 (B) and (C) show only geometrical isomerism.

Explanation:

(D) :
(A) For monodentate ligands A and B, no isomers are possible for $[{MA}_{5} B]$ type of complex. Hence, ${[Ni {(H_{2} O)}_{5} {NH}_{3}]}^{2 +}$ does not show the geometrical as well as optical isomerism.
(B) $[{MA}_{4} B_{2}]$ i.e. ${[Ni {(H_{2} O)}_{4} {({NH}_{3})}_{2}]}^{2 +}$ type of octahedral complexes exist as cis and trans isomer (geometrical isomerism).
original image
(C) $[{MA}_{3} B_{3}]$ i.e. ${[Ni {(H_{2} O)}_{3} {({NH}_{3})}_{3}]}^{2 +}$ type of octahedral complexes are known to give cis and trans isomers (Geometrical isomerism)
- When the three ligands are in the same triangular face of the octahedron, the compound is called facial or face-isomer. When the three ligands are on the same equatorial plane of the octahedron i.e. around the meridian of the octahedron, the compound is called meridional or mer isomer.

AIIMS-27 May

COORDINATION COMPOUNDS

273805 ${CuSO}_{4}$ reacts with $KCN$ solution and forms

1

K_{3} [Cu (CN)_{4}]

2

[Cu (CN)]

3

[Cu (CN)_{2}]

4

K_{4} [Cu (CN)_{6}]

Explanation:

(A) : Copper sulphate is dissolved in potassium cyanide solution. Copper sulphate reacts with potassium cyanide to form potassium sulphate and cupric cyanide-
$\underset{Copper sulphate}{{CuSO}_{4}} + \underset{\begin{matrix} Potassium \\ cyanide \end{matrix}}{2 KCN} \to \underset{\begin{matrix} Potassium \\ Sulphate \end{matrix}}{K_{2} {SO}_{4}} + \underset{\begin{matrix} Cypric \\ cyanide \end{matrix}}{Cu (CN)_{2}}$
Cupric Cyanide is unstable. It decomposes to form cuprous cyanide and cyanogens gas.
$2 Cu (CN)_{2} ⟶ 2 CuCN + (CN)_{2}$
In this reaction, cupric cyanide is reduced to cuprous cyanide. One mole of cuprous cyanide reacts with three moles of potassium cyanide to form the complex compound.
$CuCN + 3 KCN ⟶ K_{3} [Cu (CN)_{4}]$

COMEDK-2020

COORDINATION COMPOUNDS

273808 Which of the following complex ion shows geometrical isomerism ?

1

{[Cr {(H_{2} O)}_{4} C_{2}]}^{+}

2

{[Pt {({NH}_{3})}_{3} C ℓ]}^{+}

3

{[Co {({NH}_{3})}_{6}]}^{3 +}

4

{[Co (CN)_{5} (NC)]}^{3 -}

Explanation:

(A) : ${[Cr {(H_{2} O)}_{4} {Cl}_{2}]}^{+}$ shows geometrical isomerism. It is complex compounds of $[{MA}_{4} B_{2}]$ type.

${[Pt {({NH}_{3})}_{3} C ℓ]}^{+}$ ,
${[Co {({NH}_{3})}_{6}]}^{3 +}$
${[Co (CN)_{5} (NC)]}^{3 -}$ do not show stereoisomerism.

AP EAMCET (Engg.) 18.09.2020

COORDINATION COMPOUNDS

273821 How many geometrical isomers are possible with complexes of the type $[M (a b)_{3}]$ ?
9. $[Fe {({NO}_{2})}_{3} {Cl}_{3}]$ and $[Fe (O - NO)_{3} {Cl}_{3}]$ shows}

1 linkage isomerism

2 geometrical isomerism

3 optical isomerism

4 hydrate isomerism
Ans. (a)
Exp: (A) :

[Fe {({NO}_{2})}_{3} {Cl}_{3}]

and

[Fe (ONO)_{3}) {Cl}_{3}]

shows the linkage isomerism because it contains the

{NO}_{2}

ligands.

Explanation:

(A) : The type of the complex is $[M (ab)_{3}]$ . It is a octahedral complex which form the facial or meridional isomerism (geometrical isomerism)
original image
Hence, it contains the two geometrical isomer.
(a.) linkage isomerism
(b.) geometrical isomerism
(c.) optical isomerism
(d.) hydrate isomerism
Ans. (a)
Exp: (A) : $[Fe {({NO}_{2})}_{3} {Cl}_{3}]$ and $[Fe (ONO)_{3}) {Cl}_{3}]$ shows the linkage isomerism because it contains the ${NO}_{2}$ ligands.

Karnataka CET-2018

COORDINATION COMPOUNDS

273824 The correct statement for the isomerism associated with the following complex ions is:
(A) ${[Ni {(H_{2} O)}_{5} {NH}_{3}]}^{2 +}$ ,
(B) ${[Ni {(H_{2} O)}_{4} {({NH}_{3})}_{2}]}^{2 +}$ and
(C) ${[Ni {(H_{2} O)}_{3} {({NH}_{3})}_{3}]}^{2 +}$ is:

1 (A) and (B) show only geometrical isomerism.

2 (A) and (B) show geometrical and optical isomerism.

3 (B) and (C) show geometrical and optical isomerism.

4 (B) and (C) show only geometrical isomerism.

Explanation:

(D) :
(A) For monodentate ligands A and B, no isomers are possible for $[{MA}_{5} B]$ type of complex. Hence, ${[Ni {(H_{2} O)}_{5} {NH}_{3}]}^{2 +}$ does not show the geometrical as well as optical isomerism.
(B) $[{MA}_{4} B_{2}]$ i.e. ${[Ni {(H_{2} O)}_{4} {({NH}_{3})}_{2}]}^{2 +}$ type of octahedral complexes exist as cis and trans isomer (geometrical isomerism).
original image
(C) $[{MA}_{3} B_{3}]$ i.e. ${[Ni {(H_{2} O)}_{3} {({NH}_{3})}_{3}]}^{2 +}$ type of octahedral complexes are known to give cis and trans isomers (Geometrical isomerism)
- When the three ligands are in the same triangular face of the octahedron, the compound is called facial or face-isomer. When the three ligands are on the same equatorial plane of the octahedron i.e. around the meridian of the octahedron, the compound is called meridional or mer isomer.

AIIMS-27 May

COORDINATION COMPOUNDS

273805 ${CuSO}_{4}$ reacts with $KCN$ solution and forms

1

K_{3} [Cu (CN)_{4}]

2

[Cu (CN)]

3

[Cu (CN)_{2}]

4

K_{4} [Cu (CN)_{6}]

Explanation:

(A) : Copper sulphate is dissolved in potassium cyanide solution. Copper sulphate reacts with potassium cyanide to form potassium sulphate and cupric cyanide-
$\underset{Copper sulphate}{{CuSO}_{4}} + \underset{\begin{matrix} Potassium \\ cyanide \end{matrix}}{2 KCN} \to \underset{\begin{matrix} Potassium \\ Sulphate \end{matrix}}{K_{2} {SO}_{4}} + \underset{\begin{matrix} Cypric \\ cyanide \end{matrix}}{Cu (CN)_{2}}$
Cupric Cyanide is unstable. It decomposes to form cuprous cyanide and cyanogens gas.
$2 Cu (CN)_{2} ⟶ 2 CuCN + (CN)_{2}$
In this reaction, cupric cyanide is reduced to cuprous cyanide. One mole of cuprous cyanide reacts with three moles of potassium cyanide to form the complex compound.
$CuCN + 3 KCN ⟶ K_{3} [Cu (CN)_{4}]$

COMEDK-2020

COORDINATION COMPOUNDS

273808 Which of the following complex ion shows geometrical isomerism ?

1

{[Cr {(H_{2} O)}_{4} C_{2}]}^{+}

2

{[Pt {({NH}_{3})}_{3} C ℓ]}^{+}

3

{[Co {({NH}_{3})}_{6}]}^{3 +}

4

{[Co (CN)_{5} (NC)]}^{3 -}

Explanation:

(A) : ${[Cr {(H_{2} O)}_{4} {Cl}_{2}]}^{+}$ shows geometrical isomerism. It is complex compounds of $[{MA}_{4} B_{2}]$ type.

${[Pt {({NH}_{3})}_{3} C ℓ]}^{+}$ ,
${[Co {({NH}_{3})}_{6}]}^{3 +}$
${[Co (CN)_{5} (NC)]}^{3 -}$ do not show stereoisomerism.

AP EAMCET (Engg.) 18.09.2020

COORDINATION COMPOUNDS

273821 How many geometrical isomers are possible with complexes of the type $[M (a b)_{3}]$ ?
9. $[Fe {({NO}_{2})}_{3} {Cl}_{3}]$ and $[Fe (O - NO)_{3} {Cl}_{3}]$ shows}

1 linkage isomerism

2 geometrical isomerism

3 optical isomerism

4 hydrate isomerism
Ans. (a)
Exp: (A) :

[Fe {({NO}_{2})}_{3} {Cl}_{3}]

and

[Fe (ONO)_{3}) {Cl}_{3}]

shows the linkage isomerism because it contains the

{NO}_{2}

ligands.

Explanation:

(A) : The type of the complex is $[M (ab)_{3}]$ . It is a octahedral complex which form the facial or meridional isomerism (geometrical isomerism)
original image
Hence, it contains the two geometrical isomer.
(a.) linkage isomerism
(b.) geometrical isomerism
(c.) optical isomerism
(d.) hydrate isomerism
Ans. (a)
Exp: (A) : $[Fe {({NO}_{2})}_{3} {Cl}_{3}]$ and $[Fe (ONO)_{3}) {Cl}_{3}]$ shows the linkage isomerism because it contains the ${NO}_{2}$ ligands.

Karnataka CET-2018

COORDINATION COMPOUNDS

273824 The correct statement for the isomerism associated with the following complex ions is:
(A) ${[Ni {(H_{2} O)}_{5} {NH}_{3}]}^{2 +}$ ,
(B) ${[Ni {(H_{2} O)}_{4} {({NH}_{3})}_{2}]}^{2 +}$ and
(C) ${[Ni {(H_{2} O)}_{3} {({NH}_{3})}_{3}]}^{2 +}$ is:

1 (A) and (B) show only geometrical isomerism.

2 (A) and (B) show geometrical and optical isomerism.

3 (B) and (C) show geometrical and optical isomerism.

4 (B) and (C) show only geometrical isomerism.

Explanation:

(D) :
(A) For monodentate ligands A and B, no isomers are possible for $[{MA}_{5} B]$ type of complex. Hence, ${[Ni {(H_{2} O)}_{5} {NH}_{3}]}^{2 +}$ does not show the geometrical as well as optical isomerism.
(B) $[{MA}_{4} B_{2}]$ i.e. ${[Ni {(H_{2} O)}_{4} {({NH}_{3})}_{2}]}^{2 +}$ type of octahedral complexes exist as cis and trans isomer (geometrical isomerism).
original image
(C) $[{MA}_{3} B_{3}]$ i.e. ${[Ni {(H_{2} O)}_{3} {({NH}_{3})}_{3}]}^{2 +}$ type of octahedral complexes are known to give cis and trans isomers (Geometrical isomerism)
- When the three ligands are in the same triangular face of the octahedron, the compound is called facial or face-isomer. When the three ligands are on the same equatorial plane of the octahedron i.e. around the meridian of the octahedron, the compound is called meridional or mer isomer.

AIIMS-27 May

Question Bank Series

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