01. Faraday's Law
ELECTROCHEMISTRY

276007 A constant current of $30 \mathrm{~A}$ is passed through an aqueous solution of $\mathrm{NaCl}$ for a time of 1.00 h. What is the volume of $\mathrm{Cl}_{2}$ gas at STP produced?

1 $30.00 \mathrm{~L}$
2 $25.08 \mathrm{~L}$
3 $12.54 \mathrm{~L}$
4 $1.12 \mathrm{~L}$
ELECTROCHEMISTRY

276008 The number of Faradays needed to reduce $4 \mathrm{~g}$ equivalents of $\mathrm{Cu}^{2+}$ to $\mathrm{Cu}$ metal will be

1 1
2 2
3 $\frac{1}{2}$
4 4 A
ELECTROCHEMISTRY

276010 How long (in hours) must a current of 5.0 amperes be maintained to electroplate $60 \mathrm{~g}$ of calcium from molten $\mathrm{CaCl}_{2}$ ?

1 27 hours
2 8.3 hours
3 11 hours
4 16 hours
ELECTROCHEMISTRY

276011 When a quantity of electricity is passed through $\mathrm{CuSO}_{4}$ solution, $0.16 \mathrm{~g}$ of copper gets deposited. If the same quantity of electricity is passed through acidulated water, then the volume of $\mathrm{H}_{2}$ liberated at $\mathrm{STP}$ will be
$\text { (Given : At. wt. of } \mathrm{Cu}=64 \text { ) }$

1 $4.0 \mathrm{~cm}^{3}$
2 $56 \mathrm{~cm}^{3}$
3 $604 \mathrm{~cm}^{3}$
4 $8.0 \mathrm{~cm}^{3}$
ELECTROCHEMISTRY

276007 A constant current of $30 \mathrm{~A}$ is passed through an aqueous solution of $\mathrm{NaCl}$ for a time of 1.00 h. What is the volume of $\mathrm{Cl}_{2}$ gas at STP produced?

1 $30.00 \mathrm{~L}$
2 $25.08 \mathrm{~L}$
3 $12.54 \mathrm{~L}$
4 $1.12 \mathrm{~L}$
ELECTROCHEMISTRY

276008 The number of Faradays needed to reduce $4 \mathrm{~g}$ equivalents of $\mathrm{Cu}^{2+}$ to $\mathrm{Cu}$ metal will be

1 1
2 2
3 $\frac{1}{2}$
4 4 A
ELECTROCHEMISTRY

276010 How long (in hours) must a current of 5.0 amperes be maintained to electroplate $60 \mathrm{~g}$ of calcium from molten $\mathrm{CaCl}_{2}$ ?

1 27 hours
2 8.3 hours
3 11 hours
4 16 hours
ELECTROCHEMISTRY

276011 When a quantity of electricity is passed through $\mathrm{CuSO}_{4}$ solution, $0.16 \mathrm{~g}$ of copper gets deposited. If the same quantity of electricity is passed through acidulated water, then the volume of $\mathrm{H}_{2}$ liberated at $\mathrm{STP}$ will be
$\text { (Given : At. wt. of } \mathrm{Cu}=64 \text { ) }$

1 $4.0 \mathrm{~cm}^{3}$
2 $56 \mathrm{~cm}^{3}$
3 $604 \mathrm{~cm}^{3}$
4 $8.0 \mathrm{~cm}^{3}$
ELECTROCHEMISTRY

276007 A constant current of $30 \mathrm{~A}$ is passed through an aqueous solution of $\mathrm{NaCl}$ for a time of 1.00 h. What is the volume of $\mathrm{Cl}_{2}$ gas at STP produced?

1 $30.00 \mathrm{~L}$
2 $25.08 \mathrm{~L}$
3 $12.54 \mathrm{~L}$
4 $1.12 \mathrm{~L}$
ELECTROCHEMISTRY

276008 The number of Faradays needed to reduce $4 \mathrm{~g}$ equivalents of $\mathrm{Cu}^{2+}$ to $\mathrm{Cu}$ metal will be

1 1
2 2
3 $\frac{1}{2}$
4 4 A
ELECTROCHEMISTRY

276010 How long (in hours) must a current of 5.0 amperes be maintained to electroplate $60 \mathrm{~g}$ of calcium from molten $\mathrm{CaCl}_{2}$ ?

1 27 hours
2 8.3 hours
3 11 hours
4 16 hours
ELECTROCHEMISTRY

276011 When a quantity of electricity is passed through $\mathrm{CuSO}_{4}$ solution, $0.16 \mathrm{~g}$ of copper gets deposited. If the same quantity of electricity is passed through acidulated water, then the volume of $\mathrm{H}_{2}$ liberated at $\mathrm{STP}$ will be
$\text { (Given : At. wt. of } \mathrm{Cu}=64 \text { ) }$

1 $4.0 \mathrm{~cm}^{3}$
2 $56 \mathrm{~cm}^{3}$
3 $604 \mathrm{~cm}^{3}$
4 $8.0 \mathrm{~cm}^{3}$
ELECTROCHEMISTRY

276007 A constant current of $30 \mathrm{~A}$ is passed through an aqueous solution of $\mathrm{NaCl}$ for a time of 1.00 h. What is the volume of $\mathrm{Cl}_{2}$ gas at STP produced?

1 $30.00 \mathrm{~L}$
2 $25.08 \mathrm{~L}$
3 $12.54 \mathrm{~L}$
4 $1.12 \mathrm{~L}$
ELECTROCHEMISTRY

276008 The number of Faradays needed to reduce $4 \mathrm{~g}$ equivalents of $\mathrm{Cu}^{2+}$ to $\mathrm{Cu}$ metal will be

1 1
2 2
3 $\frac{1}{2}$
4 4 A
ELECTROCHEMISTRY

276010 How long (in hours) must a current of 5.0 amperes be maintained to electroplate $60 \mathrm{~g}$ of calcium from molten $\mathrm{CaCl}_{2}$ ?

1 27 hours
2 8.3 hours
3 11 hours
4 16 hours
ELECTROCHEMISTRY

276011 When a quantity of electricity is passed through $\mathrm{CuSO}_{4}$ solution, $0.16 \mathrm{~g}$ of copper gets deposited. If the same quantity of electricity is passed through acidulated water, then the volume of $\mathrm{H}_{2}$ liberated at $\mathrm{STP}$ will be
$\text { (Given : At. wt. of } \mathrm{Cu}=64 \text { ) }$

1 $4.0 \mathrm{~cm}^{3}$
2 $56 \mathrm{~cm}^{3}$
3 $604 \mathrm{~cm}^{3}$
4 $8.0 \mathrm{~cm}^{3}$