Coagulation is the settling of colloidal particles or precipitation of the solution. Thus, boiling, persistant dialysis and electrophoresis all result in coagulation. Hence, option (d) is not done by coagulation.
UPTU/UPSEE-2010
SOLUTIONS
277556
Which of the following substances show the highest colligative properties?
Colligative properties depend upon number of solute particles. Here $0.1 \mathrm{M}\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}$ contains the maximum particles. So, it has the highest colligative properties. So, option (d) is correct.
TS-EAMCET-19.07.2022 Shift-II
SOLUTIONS
277558
The coagulating power of an electrolyte for arsenious sulphide solution decreases in the order,
It has been observed that, generally, the greater the valence of the flocculating ion added, the greater is its power to cause precipitation. This is known as Hardy-Schulze rule. In the coagulation of a negative solution, the flocculating power is in the order. $\mathrm{Al}^{3+}>\mathrm{Ba}^{2+}>\mathrm{Na}^{+}$.
CG PET-2010
SOLUTIONS
277559
Which of the following ions will have maximum flocculating power for coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ solution?
1 $\mathrm{Na}^{+}$
2 $\mathrm{Al}^{3+}$
3 $\mathrm{Mg}^{2+}$
4 $\mathrm{Ba}^{2+}$
Explanation:
According to Hardy Schulze rule, greater the valency of the coagulating ion, greater is its coagulating power. $\mathrm{Al}^{3+}$ has maximum flocculating power for coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ solution. - The flocculation power in the coagulation of negative solution decreases in the order $\mathbf{A l}^{3+}>\mathbf{B a}^{2+}>\mathbf{N a}^{+}$.
Coagulation is the settling of colloidal particles or precipitation of the solution. Thus, boiling, persistant dialysis and electrophoresis all result in coagulation. Hence, option (d) is not done by coagulation.
UPTU/UPSEE-2010
SOLUTIONS
277556
Which of the following substances show the highest colligative properties?
Colligative properties depend upon number of solute particles. Here $0.1 \mathrm{M}\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}$ contains the maximum particles. So, it has the highest colligative properties. So, option (d) is correct.
TS-EAMCET-19.07.2022 Shift-II
SOLUTIONS
277558
The coagulating power of an electrolyte for arsenious sulphide solution decreases in the order,
It has been observed that, generally, the greater the valence of the flocculating ion added, the greater is its power to cause precipitation. This is known as Hardy-Schulze rule. In the coagulation of a negative solution, the flocculating power is in the order. $\mathrm{Al}^{3+}>\mathrm{Ba}^{2+}>\mathrm{Na}^{+}$.
CG PET-2010
SOLUTIONS
277559
Which of the following ions will have maximum flocculating power for coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ solution?
1 $\mathrm{Na}^{+}$
2 $\mathrm{Al}^{3+}$
3 $\mathrm{Mg}^{2+}$
4 $\mathrm{Ba}^{2+}$
Explanation:
According to Hardy Schulze rule, greater the valency of the coagulating ion, greater is its coagulating power. $\mathrm{Al}^{3+}$ has maximum flocculating power for coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ solution. - The flocculation power in the coagulation of negative solution decreases in the order $\mathbf{A l}^{3+}>\mathbf{B a}^{2+}>\mathbf{N a}^{+}$.
Coagulation is the settling of colloidal particles or precipitation of the solution. Thus, boiling, persistant dialysis and electrophoresis all result in coagulation. Hence, option (d) is not done by coagulation.
UPTU/UPSEE-2010
SOLUTIONS
277556
Which of the following substances show the highest colligative properties?
Colligative properties depend upon number of solute particles. Here $0.1 \mathrm{M}\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}$ contains the maximum particles. So, it has the highest colligative properties. So, option (d) is correct.
TS-EAMCET-19.07.2022 Shift-II
SOLUTIONS
277558
The coagulating power of an electrolyte for arsenious sulphide solution decreases in the order,
It has been observed that, generally, the greater the valence of the flocculating ion added, the greater is its power to cause precipitation. This is known as Hardy-Schulze rule. In the coagulation of a negative solution, the flocculating power is in the order. $\mathrm{Al}^{3+}>\mathrm{Ba}^{2+}>\mathrm{Na}^{+}$.
CG PET-2010
SOLUTIONS
277559
Which of the following ions will have maximum flocculating power for coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ solution?
1 $\mathrm{Na}^{+}$
2 $\mathrm{Al}^{3+}$
3 $\mathrm{Mg}^{2+}$
4 $\mathrm{Ba}^{2+}$
Explanation:
According to Hardy Schulze rule, greater the valency of the coagulating ion, greater is its coagulating power. $\mathrm{Al}^{3+}$ has maximum flocculating power for coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ solution. - The flocculation power in the coagulation of negative solution decreases in the order $\mathbf{A l}^{3+}>\mathbf{B a}^{2+}>\mathbf{N a}^{+}$.
NEET Test Series from KOTA - 10 Papers In MS WORD
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SOLUTIONS
277583
Coagulation is not done by
1 persistant dialysis
2 boiling
3 electrophoresis
4 peptisation
Explanation:
Coagulation is the settling of colloidal particles or precipitation of the solution. Thus, boiling, persistant dialysis and electrophoresis all result in coagulation. Hence, option (d) is not done by coagulation.
UPTU/UPSEE-2010
SOLUTIONS
277556
Which of the following substances show the highest colligative properties?
Colligative properties depend upon number of solute particles. Here $0.1 \mathrm{M}\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}$ contains the maximum particles. So, it has the highest colligative properties. So, option (d) is correct.
TS-EAMCET-19.07.2022 Shift-II
SOLUTIONS
277558
The coagulating power of an electrolyte for arsenious sulphide solution decreases in the order,
It has been observed that, generally, the greater the valence of the flocculating ion added, the greater is its power to cause precipitation. This is known as Hardy-Schulze rule. In the coagulation of a negative solution, the flocculating power is in the order. $\mathrm{Al}^{3+}>\mathrm{Ba}^{2+}>\mathrm{Na}^{+}$.
CG PET-2010
SOLUTIONS
277559
Which of the following ions will have maximum flocculating power for coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ solution?
1 $\mathrm{Na}^{+}$
2 $\mathrm{Al}^{3+}$
3 $\mathrm{Mg}^{2+}$
4 $\mathrm{Ba}^{2+}$
Explanation:
According to Hardy Schulze rule, greater the valency of the coagulating ion, greater is its coagulating power. $\mathrm{Al}^{3+}$ has maximum flocculating power for coagulation of $\mathrm{As}_{2} \mathrm{~S}_{3}$ solution. - The flocculation power in the coagulation of negative solution decreases in the order $\mathbf{A l}^{3+}>\mathbf{B a}^{2+}>\mathbf{N a}^{+}$.
