QBManager

SOLUTIONS

277499 Henry's constant (in kbar) for four gases $α, β, γ$ and $δ$ in water at $298 K$ is given below :
| | $α$ | $β$ | $γ$ | $δ$ |
| :---: | :---: | :---: | :---: | :---: |
| $K_{H}$ | 50 | 2 | $2 \times 10^{- 5}$ | 0.5 |
density of water $= 10^{3} kg m^{- 3}$ at $298 K$ ). This table implies that

1

α

has the highest solubility in water at a given pressure

2 Solubility of

γ

at

308 K

is lower than at

298 K

3 The pressure of a 55.5 molal solution of

γ

is 1 bar

4 The pressure of a 55.5 molal solution of

δ

is 250 bar

Explanation:

$: P_{γ} = K_{H} X_{γ}$
$\begin{aligned} P_{γ} & = 2 \times 10^{- 15} \times \frac{55.5}{55.5 + \frac{1000}{18}} \\ = 2 \times 10^{- 2} bar \end{aligned}$
Now for,
$\begin{aligned} P_{δ} & = K_{H} X_{δ} \\ P_{δ} & = 0.5 \times \frac{55.5}{55.5 + \frac{1000}{18}} \\ = 0.249 K bar \\ = 249 bar \end{aligned}$
So, it is clear that $P = K_{H}$
Where $X =$ mole fraction of gas in liquid.
On increasing temperature solubility of gases decreases.

[JEE Main 2020

SOLUTIONS

277518 Which one of the following salts give an acidic solution in water?

1

{CH}_{3} COONa

2

{NH}_{4} Cl

3

NaCl

4

{CH}_{3} {COONH}_{4}

Explanation:

${NH}_{4} Cl ⇌ {NH}_{4} + {Cl}^{-}$
${NH}_{4} Cl + H_{2} O ⇌ {NH}_{4} OH + H^{+} {Cl}^{-}$
So, ${NH}_{4} Cl$ salt gives an acidic solution in water.

CG PET -2007

SOLUTIONS

277519 Normal solution is

1 inert solution

2 acidic solution

3 one litre containing one equivalent

4 basic solution

Explanation:

Normal solution has one gram equivalent of solute dissolved in $1 L$ of solution.

UP CPMT-2005

SOLUTIONS

277495 The pair of components which cannot exist together in solution is

1

{NaHCO}_{3}

and

NaOH

2

{NaHCO}_{3}

and

H_{2} O

3

{NaHCO}_{3}

and

{Na}_{2} {CO}_{3}

4

{Na}_{2} {CO}_{3}

and

NaOH

Explanation:

From the given options, ${NaHCO}_{3}$ and $NaOH$ is the only pair cannot exist together in the solution.
${NaHCO}_{3}$ is acidic and is decomposed by $NaOH$ forming ${Na}_{2} {CO}_{3}$ . The reaction is a follows:
${NaHCO}_{3} + NaOH \to {Na}_{2} {CO}_{3} + H_{2} O$

Assam CEE-2014

SOLUTIONS

277501 Which one of the following statements regarding Henry's law is not correct?

1 Different gases have different

K_{H}

(Henry's law constant) values at the same temperature

2 Higher the value of

K_{H}

at a given pressure, higher is the solubility of the gas in the liquids

3 The value of

K_{H}

increases with increase of temperature and

K_{H}

is function of the nature of the gas

4 The partial pressure of the gas in vapour phase is proportional to the mole fraction of the gas in the solution

Explanation:

For liquid solution,
$P_{Gas} = K_{H} \times X_{Gas}$
So, higher the value of $K_{H}$ at 0 given pressure, higher is the solubility of the gas in the liquids.

[JEE Main-09.01.2019 Shift-I]

SOLUTIONS

277499 Henry's constant (in kbar) for four gases $α, β, γ$ and $δ$ in water at $298 K$ is given below :
| | $α$ | $β$ | $γ$ | $δ$ |
| :---: | :---: | :---: | :---: | :---: |
| $K_{H}$ | 50 | 2 | $2 \times 10^{- 5}$ | 0.5 |
density of water $= 10^{3} kg m^{- 3}$ at $298 K$ ). This table implies that

1

α

has the highest solubility in water at a given pressure

2 Solubility of

γ

at

308 K

is lower than at

298 K

3 The pressure of a 55.5 molal solution of

γ

is 1 bar

4 The pressure of a 55.5 molal solution of

δ

is 250 bar

Explanation:

$: P_{γ} = K_{H} X_{γ}$
$\begin{aligned} P_{γ} & = 2 \times 10^{- 15} \times \frac{55.5}{55.5 + \frac{1000}{18}} \\ = 2 \times 10^{- 2} bar \end{aligned}$
Now for,
$\begin{aligned} P_{δ} & = K_{H} X_{δ} \\ P_{δ} & = 0.5 \times \frac{55.5}{55.5 + \frac{1000}{18}} \\ = 0.249 K bar \\ = 249 bar \end{aligned}$
So, it is clear that $P = K_{H}$
Where $X =$ mole fraction of gas in liquid.
On increasing temperature solubility of gases decreases.

[JEE Main 2020

SOLUTIONS

277518 Which one of the following salts give an acidic solution in water?

1

{CH}_{3} COONa

2

{NH}_{4} Cl

3

NaCl

4

{CH}_{3} {COONH}_{4}

Explanation:

${NH}_{4} Cl ⇌ {NH}_{4} + {Cl}^{-}$
${NH}_{4} Cl + H_{2} O ⇌ {NH}_{4} OH + H^{+} {Cl}^{-}$
So, ${NH}_{4} Cl$ salt gives an acidic solution in water.

CG PET -2007

SOLUTIONS

277519 Normal solution is

1 inert solution

2 acidic solution

3 one litre containing one equivalent

4 basic solution

Explanation:

Normal solution has one gram equivalent of solute dissolved in $1 L$ of solution.

UP CPMT-2005

SOLUTIONS

277495 The pair of components which cannot exist together in solution is

1

{NaHCO}_{3}

and

NaOH

2

{NaHCO}_{3}

and

H_{2} O

3

{NaHCO}_{3}

and

{Na}_{2} {CO}_{3}

4

{Na}_{2} {CO}_{3}

and

NaOH

Explanation:

From the given options, ${NaHCO}_{3}$ and $NaOH$ is the only pair cannot exist together in the solution.
${NaHCO}_{3}$ is acidic and is decomposed by $NaOH$ forming ${Na}_{2} {CO}_{3}$ . The reaction is a follows:
${NaHCO}_{3} + NaOH \to {Na}_{2} {CO}_{3} + H_{2} O$

Assam CEE-2014

SOLUTIONS

277501 Which one of the following statements regarding Henry's law is not correct?

1 Different gases have different

K_{H}

(Henry's law constant) values at the same temperature

2 Higher the value of

K_{H}

at a given pressure, higher is the solubility of the gas in the liquids

3 The value of

K_{H}

increases with increase of temperature and

K_{H}

is function of the nature of the gas

4 The partial pressure of the gas in vapour phase is proportional to the mole fraction of the gas in the solution

Explanation:

For liquid solution,
$P_{Gas} = K_{H} \times X_{Gas}$
So, higher the value of $K_{H}$ at 0 given pressure, higher is the solubility of the gas in the liquids.

[JEE Main-09.01.2019 Shift-I]

SOLUTIONS

277499 Henry's constant (in kbar) for four gases $α, β, γ$ and $δ$ in water at $298 K$ is given below :
| | $α$ | $β$ | $γ$ | $δ$ |
| :---: | :---: | :---: | :---: | :---: |
| $K_{H}$ | 50 | 2 | $2 \times 10^{- 5}$ | 0.5 |
density of water $= 10^{3} kg m^{- 3}$ at $298 K$ ). This table implies that

1

α

has the highest solubility in water at a given pressure

2 Solubility of

γ

at

308 K

is lower than at

298 K

3 The pressure of a 55.5 molal solution of

γ

is 1 bar

4 The pressure of a 55.5 molal solution of

δ

is 250 bar

Explanation:

$: P_{γ} = K_{H} X_{γ}$
$\begin{aligned} P_{γ} & = 2 \times 10^{- 15} \times \frac{55.5}{55.5 + \frac{1000}{18}} \\ = 2 \times 10^{- 2} bar \end{aligned}$
Now for,
$\begin{aligned} P_{δ} & = K_{H} X_{δ} \\ P_{δ} & = 0.5 \times \frac{55.5}{55.5 + \frac{1000}{18}} \\ = 0.249 K bar \\ = 249 bar \end{aligned}$
So, it is clear that $P = K_{H}$
Where $X =$ mole fraction of gas in liquid.
On increasing temperature solubility of gases decreases.

[JEE Main 2020

SOLUTIONS

277518 Which one of the following salts give an acidic solution in water?

1

{CH}_{3} COONa

2

{NH}_{4} Cl

3

NaCl

4

{CH}_{3} {COONH}_{4}

Explanation:

${NH}_{4} Cl ⇌ {NH}_{4} + {Cl}^{-}$
${NH}_{4} Cl + H_{2} O ⇌ {NH}_{4} OH + H^{+} {Cl}^{-}$
So, ${NH}_{4} Cl$ salt gives an acidic solution in water.

CG PET -2007

SOLUTIONS

277519 Normal solution is

1 inert solution

2 acidic solution

3 one litre containing one equivalent

4 basic solution

Explanation:

Normal solution has one gram equivalent of solute dissolved in $1 L$ of solution.

UP CPMT-2005

SOLUTIONS

277495 The pair of components which cannot exist together in solution is

1

{NaHCO}_{3}

and

NaOH

2

{NaHCO}_{3}

and

H_{2} O

3

{NaHCO}_{3}

and

{Na}_{2} {CO}_{3}

4

{Na}_{2} {CO}_{3}

and

NaOH

Explanation:

From the given options, ${NaHCO}_{3}$ and $NaOH$ is the only pair cannot exist together in the solution.
${NaHCO}_{3}$ is acidic and is decomposed by $NaOH$ forming ${Na}_{2} {CO}_{3}$ . The reaction is a follows:
${NaHCO}_{3} + NaOH \to {Na}_{2} {CO}_{3} + H_{2} O$

Assam CEE-2014

SOLUTIONS

277501 Which one of the following statements regarding Henry's law is not correct?

1 Different gases have different

K_{H}

(Henry's law constant) values at the same temperature

2 Higher the value of

K_{H}

at a given pressure, higher is the solubility of the gas in the liquids

3 The value of

K_{H}

increases with increase of temperature and

K_{H}

is function of the nature of the gas

4 The partial pressure of the gas in vapour phase is proportional to the mole fraction of the gas in the solution

Explanation:

For liquid solution,
$P_{Gas} = K_{H} \times X_{Gas}$
So, higher the value of $K_{H}$ at 0 given pressure, higher is the solubility of the gas in the liquids.

[JEE Main-09.01.2019 Shift-I]

SOLUTIONS

277499 Henry's constant (in kbar) for four gases $α, β, γ$ and $δ$ in water at $298 K$ is given below :
| | $α$ | $β$ | $γ$ | $δ$ |
| :---: | :---: | :---: | :---: | :---: |
| $K_{H}$ | 50 | 2 | $2 \times 10^{- 5}$ | 0.5 |
density of water $= 10^{3} kg m^{- 3}$ at $298 K$ ). This table implies that

1

α

has the highest solubility in water at a given pressure

2 Solubility of

γ

at

308 K

is lower than at

298 K

3 The pressure of a 55.5 molal solution of

γ

is 1 bar

4 The pressure of a 55.5 molal solution of

δ

is 250 bar

Explanation:

$: P_{γ} = K_{H} X_{γ}$
$\begin{aligned} P_{γ} & = 2 \times 10^{- 15} \times \frac{55.5}{55.5 + \frac{1000}{18}} \\ = 2 \times 10^{- 2} bar \end{aligned}$
Now for,
$\begin{aligned} P_{δ} & = K_{H} X_{δ} \\ P_{δ} & = 0.5 \times \frac{55.5}{55.5 + \frac{1000}{18}} \\ = 0.249 K bar \\ = 249 bar \end{aligned}$
So, it is clear that $P = K_{H}$
Where $X =$ mole fraction of gas in liquid.
On increasing temperature solubility of gases decreases.

[JEE Main 2020

SOLUTIONS

277518 Which one of the following salts give an acidic solution in water?

1

{CH}_{3} COONa

2

{NH}_{4} Cl

3

NaCl

4

{CH}_{3} {COONH}_{4}

Explanation:

${NH}_{4} Cl ⇌ {NH}_{4} + {Cl}^{-}$
${NH}_{4} Cl + H_{2} O ⇌ {NH}_{4} OH + H^{+} {Cl}^{-}$
So, ${NH}_{4} Cl$ salt gives an acidic solution in water.

CG PET -2007

SOLUTIONS

277519 Normal solution is

1 inert solution

2 acidic solution

3 one litre containing one equivalent

4 basic solution

Explanation:

Normal solution has one gram equivalent of solute dissolved in $1 L$ of solution.

UP CPMT-2005

SOLUTIONS

277495 The pair of components which cannot exist together in solution is

1

{NaHCO}_{3}

and

NaOH

2

{NaHCO}_{3}

and

H_{2} O

3

{NaHCO}_{3}

and

{Na}_{2} {CO}_{3}

4

{Na}_{2} {CO}_{3}

and

NaOH

Explanation:

From the given options, ${NaHCO}_{3}$ and $NaOH$ is the only pair cannot exist together in the solution.
${NaHCO}_{3}$ is acidic and is decomposed by $NaOH$ forming ${Na}_{2} {CO}_{3}$ . The reaction is a follows:
${NaHCO}_{3} + NaOH \to {Na}_{2} {CO}_{3} + H_{2} O$

Assam CEE-2014

SOLUTIONS

277501 Which one of the following statements regarding Henry's law is not correct?

1 Different gases have different

K_{H}

(Henry's law constant) values at the same temperature

2 Higher the value of

K_{H}

at a given pressure, higher is the solubility of the gas in the liquids

3 The value of

K_{H}

increases with increase of temperature and

K_{H}

is function of the nature of the gas

4 The partial pressure of the gas in vapour phase is proportional to the mole fraction of the gas in the solution

Explanation:

For liquid solution,
$P_{Gas} = K_{H} \times X_{Gas}$
So, higher the value of $K_{H}$ at 0 given pressure, higher is the solubility of the gas in the liquids.

[JEE Main-09.01.2019 Shift-I]

SOLUTIONS

277499 Henry's constant (in kbar) for four gases $α, β, γ$ and $δ$ in water at $298 K$ is given below :
| | $α$ | $β$ | $γ$ | $δ$ |
| :---: | :---: | :---: | :---: | :---: |
| $K_{H}$ | 50 | 2 | $2 \times 10^{- 5}$ | 0.5 |
density of water $= 10^{3} kg m^{- 3}$ at $298 K$ ). This table implies that

1

α

has the highest solubility in water at a given pressure

2 Solubility of

γ

at

308 K

is lower than at

298 K

3 The pressure of a 55.5 molal solution of

γ

is 1 bar

4 The pressure of a 55.5 molal solution of

δ

is 250 bar

Explanation:

$: P_{γ} = K_{H} X_{γ}$
$\begin{aligned} P_{γ} & = 2 \times 10^{- 15} \times \frac{55.5}{55.5 + \frac{1000}{18}} \\ = 2 \times 10^{- 2} bar \end{aligned}$
Now for,
$\begin{aligned} P_{δ} & = K_{H} X_{δ} \\ P_{δ} & = 0.5 \times \frac{55.5}{55.5 + \frac{1000}{18}} \\ = 0.249 K bar \\ = 249 bar \end{aligned}$
So, it is clear that $P = K_{H}$
Where $X =$ mole fraction of gas in liquid.
On increasing temperature solubility of gases decreases.

[JEE Main 2020

SOLUTIONS

277518 Which one of the following salts give an acidic solution in water?

1

{CH}_{3} COONa

2

{NH}_{4} Cl

3

NaCl

4

{CH}_{3} {COONH}_{4}

Explanation:

${NH}_{4} Cl ⇌ {NH}_{4} + {Cl}^{-}$
${NH}_{4} Cl + H_{2} O ⇌ {NH}_{4} OH + H^{+} {Cl}^{-}$
So, ${NH}_{4} Cl$ salt gives an acidic solution in water.

CG PET -2007

SOLUTIONS

277519 Normal solution is

1 inert solution

2 acidic solution

3 one litre containing one equivalent

4 basic solution

Explanation:

Normal solution has one gram equivalent of solute dissolved in $1 L$ of solution.

UP CPMT-2005

SOLUTIONS

277495 The pair of components which cannot exist together in solution is

1

{NaHCO}_{3}

and

NaOH

2

{NaHCO}_{3}

and

H_{2} O

3

{NaHCO}_{3}

and

{Na}_{2} {CO}_{3}

4

{Na}_{2} {CO}_{3}

and

NaOH

Explanation:

From the given options, ${NaHCO}_{3}$ and $NaOH$ is the only pair cannot exist together in the solution.
${NaHCO}_{3}$ is acidic and is decomposed by $NaOH$ forming ${Na}_{2} {CO}_{3}$ . The reaction is a follows:
${NaHCO}_{3} + NaOH \to {Na}_{2} {CO}_{3} + H_{2} O$

Assam CEE-2014

SOLUTIONS

277501 Which one of the following statements regarding Henry's law is not correct?

1 Different gases have different

K_{H}

(Henry's law constant) values at the same temperature

2 Higher the value of

K_{H}

at a given pressure, higher is the solubility of the gas in the liquids

3 The value of

K_{H}

increases with increase of temperature and

K_{H}

is function of the nature of the gas

4 The partial pressure of the gas in vapour phase is proportional to the mole fraction of the gas in the solution

Explanation:

For liquid solution,
$P_{Gas} = K_{H} \times X_{Gas}$
So, higher the value of $K_{H}$ at 0 given pressure, higher is the solubility of the gas in the liquids.

[JEE Main-09.01.2019 Shift-I]