230727
How many litres of oxygen (at STP) are required for complete combustion of $39 \mathrm{~g}$ of liquid benzene? (atomic weights : $\mathrm{C}=12, \mathrm{O}=16, \mathrm{H}=1$ )
1 84
2 22.4
3 42
4 11.2
Explanation:
$\left.\mathrm{C}_6 \mathrm{H}_6(l)+\frac{15}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow 6 \mathrm{CO}_2(\mathrm{~g})\right)+3 \mathrm{H}_2 \mathrm{O}(\mathrm{g})$ Molar mass of $\mathrm{C}_6 \mathrm{H}_6=78 \mathrm{~g} / \mathrm{mol}$ 39 gms of $\mathrm{C}_6 \mathrm{H}_6(\mathrm{l})=\frac{39}{78}$ moles $=0.5$ moles For 2 moles, we require 15 moles of $\mathrm{O}_2$, for 0.5 moles we will require- $\begin{array}{r} \Rightarrow \quad \frac{0.5}{2} \times 15=\frac{15}{4} \text { moles of } \mathrm{O}_2 \\ =\frac{15}{4} \times 22.4 \text { litres }=84 \text { litres } \end{array}$
A.P.EAMCET-2001
Hydrocarbons
230724
Benzene reacts with $\mathrm{H}_2$ at $150^{\circ} \mathrm{C}$ at 30 atm pressure in the presence of $\mathrm{Ni}$ catalyst to give-
1 Cyclohexene
2 Cyclohexane
3 $n$-hexane
4 No reaction occur
Explanation:
: Benzene treated with $\mathrm{H}_2$ in the presence of $\mathrm{Ni}$ catalyst of $150^{\circ} \mathrm{C}$ and $30 \mathrm{~atm}$ then cyclo hexane is formed. This is the example of addition reaction.
CG PET-22.05.2022
Hydrocarbons
230725
In benzene, the triple bond consists of
1 one sp-sp sigma bond and two $\mathrm{p}-\mathrm{p}$ pi bonds
2 two $\mathrm{sp}$-sp sigma bonds and one $\mathrm{p}-\mathrm{p}$ pi bond
3 one $s \mathrm{p}^2-\mathrm{sp} \mathrm{p}^2$ sigma bond, one $\mathrm{p}-\mathrm{p}$ pi bond
4 one $s \mathrm{sp}^2-\mathrm{sp} \mathrm{p}^2$ sigma bond, one $s \mathrm{p}^2-\mathrm{sp}^2$ pi bond and one $\mathrm{p}-\mathrm{p}$ pi bond
Explanation:
: Benzene is also know as 1,2-dehydrobenzeile of an aryne. It is a neutral and highly reactive reaction intermediate. It one $s p^2-s p^2 \sigma$-bond, one $s p^2-s p^2, \pi$ bond and one $\mathrm{p}-\mathrm{p}-\pi$ bond.
VITEEE-2021
Hydrocarbons
230726
The overlapping of orbitals in benzene is of the type
1 sp-sp
2 p-p
3 $s p^2-s p^2$
4 $\mathrm{sp}^3-\mathrm{sp}^3$
Explanation:
: The molecular orbital picture of benzene shows that in it all the six carbon atoms are $\mathrm{sp}^2$ hybridised. Out of these three $\mathrm{sp}^2$ hybrid orbitals of each $\mathrm{C}$ atom, two orbitals overlap with $\mathrm{sp}^2$ hybrid orbitals of adjacent $\mathrm{C}$ atoms to form six $\mathrm{C}-\mathrm{C}$ single bonds. The remaining $\mathrm{sp}^2$ orbital of each $\mathrm{C}$ atom overlAPs with $\mathrm{s}-$ orbital of each hydrogen atom to form six $\mathrm{C}-\mathrm{H}$ single sigma bonds. Each $\mathrm{C}$ atom is now left with one unhybridised p-orbital perpendicular to the plane of the ring.
230727
How many litres of oxygen (at STP) are required for complete combustion of $39 \mathrm{~g}$ of liquid benzene? (atomic weights : $\mathrm{C}=12, \mathrm{O}=16, \mathrm{H}=1$ )
1 84
2 22.4
3 42
4 11.2
Explanation:
$\left.\mathrm{C}_6 \mathrm{H}_6(l)+\frac{15}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow 6 \mathrm{CO}_2(\mathrm{~g})\right)+3 \mathrm{H}_2 \mathrm{O}(\mathrm{g})$ Molar mass of $\mathrm{C}_6 \mathrm{H}_6=78 \mathrm{~g} / \mathrm{mol}$ 39 gms of $\mathrm{C}_6 \mathrm{H}_6(\mathrm{l})=\frac{39}{78}$ moles $=0.5$ moles For 2 moles, we require 15 moles of $\mathrm{O}_2$, for 0.5 moles we will require- $\begin{array}{r} \Rightarrow \quad \frac{0.5}{2} \times 15=\frac{15}{4} \text { moles of } \mathrm{O}_2 \\ =\frac{15}{4} \times 22.4 \text { litres }=84 \text { litres } \end{array}$
A.P.EAMCET-2001
Hydrocarbons
230724
Benzene reacts with $\mathrm{H}_2$ at $150^{\circ} \mathrm{C}$ at 30 atm pressure in the presence of $\mathrm{Ni}$ catalyst to give-
1 Cyclohexene
2 Cyclohexane
3 $n$-hexane
4 No reaction occur
Explanation:
: Benzene treated with $\mathrm{H}_2$ in the presence of $\mathrm{Ni}$ catalyst of $150^{\circ} \mathrm{C}$ and $30 \mathrm{~atm}$ then cyclo hexane is formed. This is the example of addition reaction.
CG PET-22.05.2022
Hydrocarbons
230725
In benzene, the triple bond consists of
1 one sp-sp sigma bond and two $\mathrm{p}-\mathrm{p}$ pi bonds
2 two $\mathrm{sp}$-sp sigma bonds and one $\mathrm{p}-\mathrm{p}$ pi bond
3 one $s \mathrm{p}^2-\mathrm{sp} \mathrm{p}^2$ sigma bond, one $\mathrm{p}-\mathrm{p}$ pi bond
4 one $s \mathrm{sp}^2-\mathrm{sp} \mathrm{p}^2$ sigma bond, one $s \mathrm{p}^2-\mathrm{sp}^2$ pi bond and one $\mathrm{p}-\mathrm{p}$ pi bond
Explanation:
: Benzene is also know as 1,2-dehydrobenzeile of an aryne. It is a neutral and highly reactive reaction intermediate. It one $s p^2-s p^2 \sigma$-bond, one $s p^2-s p^2, \pi$ bond and one $\mathrm{p}-\mathrm{p}-\pi$ bond.
VITEEE-2021
Hydrocarbons
230726
The overlapping of orbitals in benzene is of the type
1 sp-sp
2 p-p
3 $s p^2-s p^2$
4 $\mathrm{sp}^3-\mathrm{sp}^3$
Explanation:
: The molecular orbital picture of benzene shows that in it all the six carbon atoms are $\mathrm{sp}^2$ hybridised. Out of these three $\mathrm{sp}^2$ hybrid orbitals of each $\mathrm{C}$ atom, two orbitals overlap with $\mathrm{sp}^2$ hybrid orbitals of adjacent $\mathrm{C}$ atoms to form six $\mathrm{C}-\mathrm{C}$ single bonds. The remaining $\mathrm{sp}^2$ orbital of each $\mathrm{C}$ atom overlAPs with $\mathrm{s}-$ orbital of each hydrogen atom to form six $\mathrm{C}-\mathrm{H}$ single sigma bonds. Each $\mathrm{C}$ atom is now left with one unhybridised p-orbital perpendicular to the plane of the ring.
230727
How many litres of oxygen (at STP) are required for complete combustion of $39 \mathrm{~g}$ of liquid benzene? (atomic weights : $\mathrm{C}=12, \mathrm{O}=16, \mathrm{H}=1$ )
1 84
2 22.4
3 42
4 11.2
Explanation:
$\left.\mathrm{C}_6 \mathrm{H}_6(l)+\frac{15}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow 6 \mathrm{CO}_2(\mathrm{~g})\right)+3 \mathrm{H}_2 \mathrm{O}(\mathrm{g})$ Molar mass of $\mathrm{C}_6 \mathrm{H}_6=78 \mathrm{~g} / \mathrm{mol}$ 39 gms of $\mathrm{C}_6 \mathrm{H}_6(\mathrm{l})=\frac{39}{78}$ moles $=0.5$ moles For 2 moles, we require 15 moles of $\mathrm{O}_2$, for 0.5 moles we will require- $\begin{array}{r} \Rightarrow \quad \frac{0.5}{2} \times 15=\frac{15}{4} \text { moles of } \mathrm{O}_2 \\ =\frac{15}{4} \times 22.4 \text { litres }=84 \text { litres } \end{array}$
A.P.EAMCET-2001
Hydrocarbons
230724
Benzene reacts with $\mathrm{H}_2$ at $150^{\circ} \mathrm{C}$ at 30 atm pressure in the presence of $\mathrm{Ni}$ catalyst to give-
1 Cyclohexene
2 Cyclohexane
3 $n$-hexane
4 No reaction occur
Explanation:
: Benzene treated with $\mathrm{H}_2$ in the presence of $\mathrm{Ni}$ catalyst of $150^{\circ} \mathrm{C}$ and $30 \mathrm{~atm}$ then cyclo hexane is formed. This is the example of addition reaction.
CG PET-22.05.2022
Hydrocarbons
230725
In benzene, the triple bond consists of
1 one sp-sp sigma bond and two $\mathrm{p}-\mathrm{p}$ pi bonds
2 two $\mathrm{sp}$-sp sigma bonds and one $\mathrm{p}-\mathrm{p}$ pi bond
3 one $s \mathrm{p}^2-\mathrm{sp} \mathrm{p}^2$ sigma bond, one $\mathrm{p}-\mathrm{p}$ pi bond
4 one $s \mathrm{sp}^2-\mathrm{sp} \mathrm{p}^2$ sigma bond, one $s \mathrm{p}^2-\mathrm{sp}^2$ pi bond and one $\mathrm{p}-\mathrm{p}$ pi bond
Explanation:
: Benzene is also know as 1,2-dehydrobenzeile of an aryne. It is a neutral and highly reactive reaction intermediate. It one $s p^2-s p^2 \sigma$-bond, one $s p^2-s p^2, \pi$ bond and one $\mathrm{p}-\mathrm{p}-\pi$ bond.
VITEEE-2021
Hydrocarbons
230726
The overlapping of orbitals in benzene is of the type
1 sp-sp
2 p-p
3 $s p^2-s p^2$
4 $\mathrm{sp}^3-\mathrm{sp}^3$
Explanation:
: The molecular orbital picture of benzene shows that in it all the six carbon atoms are $\mathrm{sp}^2$ hybridised. Out of these three $\mathrm{sp}^2$ hybrid orbitals of each $\mathrm{C}$ atom, two orbitals overlap with $\mathrm{sp}^2$ hybrid orbitals of adjacent $\mathrm{C}$ atoms to form six $\mathrm{C}-\mathrm{C}$ single bonds. The remaining $\mathrm{sp}^2$ orbital of each $\mathrm{C}$ atom overlAPs with $\mathrm{s}-$ orbital of each hydrogen atom to form six $\mathrm{C}-\mathrm{H}$ single sigma bonds. Each $\mathrm{C}$ atom is now left with one unhybridised p-orbital perpendicular to the plane of the ring.
230727
How many litres of oxygen (at STP) are required for complete combustion of $39 \mathrm{~g}$ of liquid benzene? (atomic weights : $\mathrm{C}=12, \mathrm{O}=16, \mathrm{H}=1$ )
1 84
2 22.4
3 42
4 11.2
Explanation:
$\left.\mathrm{C}_6 \mathrm{H}_6(l)+\frac{15}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow 6 \mathrm{CO}_2(\mathrm{~g})\right)+3 \mathrm{H}_2 \mathrm{O}(\mathrm{g})$ Molar mass of $\mathrm{C}_6 \mathrm{H}_6=78 \mathrm{~g} / \mathrm{mol}$ 39 gms of $\mathrm{C}_6 \mathrm{H}_6(\mathrm{l})=\frac{39}{78}$ moles $=0.5$ moles For 2 moles, we require 15 moles of $\mathrm{O}_2$, for 0.5 moles we will require- $\begin{array}{r} \Rightarrow \quad \frac{0.5}{2} \times 15=\frac{15}{4} \text { moles of } \mathrm{O}_2 \\ =\frac{15}{4} \times 22.4 \text { litres }=84 \text { litres } \end{array}$
A.P.EAMCET-2001
Hydrocarbons
230724
Benzene reacts with $\mathrm{H}_2$ at $150^{\circ} \mathrm{C}$ at 30 atm pressure in the presence of $\mathrm{Ni}$ catalyst to give-
1 Cyclohexene
2 Cyclohexane
3 $n$-hexane
4 No reaction occur
Explanation:
: Benzene treated with $\mathrm{H}_2$ in the presence of $\mathrm{Ni}$ catalyst of $150^{\circ} \mathrm{C}$ and $30 \mathrm{~atm}$ then cyclo hexane is formed. This is the example of addition reaction.
CG PET-22.05.2022
Hydrocarbons
230725
In benzene, the triple bond consists of
1 one sp-sp sigma bond and two $\mathrm{p}-\mathrm{p}$ pi bonds
2 two $\mathrm{sp}$-sp sigma bonds and one $\mathrm{p}-\mathrm{p}$ pi bond
3 one $s \mathrm{p}^2-\mathrm{sp} \mathrm{p}^2$ sigma bond, one $\mathrm{p}-\mathrm{p}$ pi bond
4 one $s \mathrm{sp}^2-\mathrm{sp} \mathrm{p}^2$ sigma bond, one $s \mathrm{p}^2-\mathrm{sp}^2$ pi bond and one $\mathrm{p}-\mathrm{p}$ pi bond
Explanation:
: Benzene is also know as 1,2-dehydrobenzeile of an aryne. It is a neutral and highly reactive reaction intermediate. It one $s p^2-s p^2 \sigma$-bond, one $s p^2-s p^2, \pi$ bond and one $\mathrm{p}-\mathrm{p}-\pi$ bond.
VITEEE-2021
Hydrocarbons
230726
The overlapping of orbitals in benzene is of the type
1 sp-sp
2 p-p
3 $s p^2-s p^2$
4 $\mathrm{sp}^3-\mathrm{sp}^3$
Explanation:
: The molecular orbital picture of benzene shows that in it all the six carbon atoms are $\mathrm{sp}^2$ hybridised. Out of these three $\mathrm{sp}^2$ hybrid orbitals of each $\mathrm{C}$ atom, two orbitals overlap with $\mathrm{sp}^2$ hybrid orbitals of adjacent $\mathrm{C}$ atoms to form six $\mathrm{C}-\mathrm{C}$ single bonds. The remaining $\mathrm{sp}^2$ orbital of each $\mathrm{C}$ atom overlAPs with $\mathrm{s}-$ orbital of each hydrogen atom to form six $\mathrm{C}-\mathrm{H}$ single sigma bonds. Each $\mathrm{C}$ atom is now left with one unhybridised p-orbital perpendicular to the plane of the ring.
