230460
Which of the following reagents when heated with ethyl chloride, forms ethylene?
1 Aueous $\mathrm{KOH}$
2 $\mathrm{Zn} / \mathrm{HCl}$
3 Alcoholic $\mathrm{KOH}$
4 $\mathrm{HI}$
Explanation:
: When ethylchloride $\left(\mathrm{CH}_5-\mathrm{CH}_2 \mathrm{Cl}\right)$ react with alcoholic $\mathrm{KOH}$ in presence of heat the product is ethylene
: $\mathrm{Al}_2\left(\mathrm{C}_2 \mathrm{H}_4\right)_6+\mathrm{TiCl}_4$ is Ziegler-Natta catalyst.
JCECE - 2010]
Hydrocarbons
230463
An alkene 'A' contains three $C-C$, eight $C-H$ $\sigma$-bonds and one $C-C-\pi$ bond. 'A' on ozonolysis gives two moles of an aldehyde of molar mass $44 \mathrm{u}$. IUPAC name of $A$ is
1 but-1-ene
2 but-2-ene
3 2-methylpropane
4 None of these
Explanation:
$=$ Compound 'A' is but-2-ene.
JCECE - 2013
Hydrocarbons
230464
One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of $44 \mathrm{u}$. The alkene is
1 ethene
2 propene
3 but-1-ene
4 but-2-ene
Explanation:
: The aldehyde with molecular mass 44 u is $\mathrm{CH}_3 \mathrm{CHO}$ (acetaldehyde). Therefore, the symmetrical alkene is but-2-ene.
230460
Which of the following reagents when heated with ethyl chloride, forms ethylene?
1 Aueous $\mathrm{KOH}$
2 $\mathrm{Zn} / \mathrm{HCl}$
3 Alcoholic $\mathrm{KOH}$
4 $\mathrm{HI}$
Explanation:
: When ethylchloride $\left(\mathrm{CH}_5-\mathrm{CH}_2 \mathrm{Cl}\right)$ react with alcoholic $\mathrm{KOH}$ in presence of heat the product is ethylene
: $\mathrm{Al}_2\left(\mathrm{C}_2 \mathrm{H}_4\right)_6+\mathrm{TiCl}_4$ is Ziegler-Natta catalyst.
JCECE - 2010]
Hydrocarbons
230463
An alkene 'A' contains three $C-C$, eight $C-H$ $\sigma$-bonds and one $C-C-\pi$ bond. 'A' on ozonolysis gives two moles of an aldehyde of molar mass $44 \mathrm{u}$. IUPAC name of $A$ is
1 but-1-ene
2 but-2-ene
3 2-methylpropane
4 None of these
Explanation:
$=$ Compound 'A' is but-2-ene.
JCECE - 2013
Hydrocarbons
230464
One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of $44 \mathrm{u}$. The alkene is
1 ethene
2 propene
3 but-1-ene
4 but-2-ene
Explanation:
: The aldehyde with molecular mass 44 u is $\mathrm{CH}_3 \mathrm{CHO}$ (acetaldehyde). Therefore, the symmetrical alkene is but-2-ene.
NEET Test Series from KOTA - 10 Papers In MS WORD
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Hydrocarbons
230460
Which of the following reagents when heated with ethyl chloride, forms ethylene?
1 Aueous $\mathrm{KOH}$
2 $\mathrm{Zn} / \mathrm{HCl}$
3 Alcoholic $\mathrm{KOH}$
4 $\mathrm{HI}$
Explanation:
: When ethylchloride $\left(\mathrm{CH}_5-\mathrm{CH}_2 \mathrm{Cl}\right)$ react with alcoholic $\mathrm{KOH}$ in presence of heat the product is ethylene
: $\mathrm{Al}_2\left(\mathrm{C}_2 \mathrm{H}_4\right)_6+\mathrm{TiCl}_4$ is Ziegler-Natta catalyst.
JCECE - 2010]
Hydrocarbons
230463
An alkene 'A' contains three $C-C$, eight $C-H$ $\sigma$-bonds and one $C-C-\pi$ bond. 'A' on ozonolysis gives two moles of an aldehyde of molar mass $44 \mathrm{u}$. IUPAC name of $A$ is
1 but-1-ene
2 but-2-ene
3 2-methylpropane
4 None of these
Explanation:
$=$ Compound 'A' is but-2-ene.
JCECE - 2013
Hydrocarbons
230464
One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of $44 \mathrm{u}$. The alkene is
1 ethene
2 propene
3 but-1-ene
4 but-2-ene
Explanation:
: The aldehyde with molecular mass 44 u is $\mathrm{CH}_3 \mathrm{CHO}$ (acetaldehyde). Therefore, the symmetrical alkene is but-2-ene.
230460
Which of the following reagents when heated with ethyl chloride, forms ethylene?
1 Aueous $\mathrm{KOH}$
2 $\mathrm{Zn} / \mathrm{HCl}$
3 Alcoholic $\mathrm{KOH}$
4 $\mathrm{HI}$
Explanation:
: When ethylchloride $\left(\mathrm{CH}_5-\mathrm{CH}_2 \mathrm{Cl}\right)$ react with alcoholic $\mathrm{KOH}$ in presence of heat the product is ethylene
: $\mathrm{Al}_2\left(\mathrm{C}_2 \mathrm{H}_4\right)_6+\mathrm{TiCl}_4$ is Ziegler-Natta catalyst.
JCECE - 2010]
Hydrocarbons
230463
An alkene 'A' contains three $C-C$, eight $C-H$ $\sigma$-bonds and one $C-C-\pi$ bond. 'A' on ozonolysis gives two moles of an aldehyde of molar mass $44 \mathrm{u}$. IUPAC name of $A$ is
1 but-1-ene
2 but-2-ene
3 2-methylpropane
4 None of these
Explanation:
$=$ Compound 'A' is but-2-ene.
JCECE - 2013
Hydrocarbons
230464
One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of $44 \mathrm{u}$. The alkene is
1 ethene
2 propene
3 but-1-ene
4 but-2-ene
Explanation:
: The aldehyde with molecular mass 44 u is $\mathrm{CH}_3 \mathrm{CHO}$ (acetaldehyde). Therefore, the symmetrical alkene is but-2-ene.