230362
The alkene that will give the same product with HBr in the absence as well as in the presence of peroxide is
1 2-butene
2 1-butene
3 propene
4 1-hexene
Explanation:
: When an unsymmetrical alkene is treated with the unsymmetrical reagent in the presence of peroxide, then addition takes place against the markownikoff's rule i.e negative part of reagent adds to that carbon to carbon-carbon double bond which carries more number of hydrogen atoms. In 2-butene will give the same product with $\mathrm{HBr}$ in the absence as well as presence of peroxide when treated with $\mathrm{HBr}$.
AIIMS-2016
Hydrocarbons
230367
Which of the following sequence of reactions (reagents) can be used for the conversion of $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{CH}_3$ into $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CH}_2$ ?
230370
The major product obtained on treatment of $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}(\mathrm{F}) \mathrm{CH}_3$ with $\mathrm{CH}_3 \mathrm{O}^{-} / \mathrm{CH}_3 \mathrm{OH}$ is:
230362
The alkene that will give the same product with HBr in the absence as well as in the presence of peroxide is
1 2-butene
2 1-butene
3 propene
4 1-hexene
Explanation:
: When an unsymmetrical alkene is treated with the unsymmetrical reagent in the presence of peroxide, then addition takes place against the markownikoff's rule i.e negative part of reagent adds to that carbon to carbon-carbon double bond which carries more number of hydrogen atoms. In 2-butene will give the same product with $\mathrm{HBr}$ in the absence as well as presence of peroxide when treated with $\mathrm{HBr}$.
AIIMS-2016
Hydrocarbons
230367
Which of the following sequence of reactions (reagents) can be used for the conversion of $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{CH}_3$ into $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CH}_2$ ?
230370
The major product obtained on treatment of $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}(\mathrm{F}) \mathrm{CH}_3$ with $\mathrm{CH}_3 \mathrm{O}^{-} / \mathrm{CH}_3 \mathrm{OH}$ is:
230362
The alkene that will give the same product with HBr in the absence as well as in the presence of peroxide is
1 2-butene
2 1-butene
3 propene
4 1-hexene
Explanation:
: When an unsymmetrical alkene is treated with the unsymmetrical reagent in the presence of peroxide, then addition takes place against the markownikoff's rule i.e negative part of reagent adds to that carbon to carbon-carbon double bond which carries more number of hydrogen atoms. In 2-butene will give the same product with $\mathrm{HBr}$ in the absence as well as presence of peroxide when treated with $\mathrm{HBr}$.
AIIMS-2016
Hydrocarbons
230367
Which of the following sequence of reactions (reagents) can be used for the conversion of $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{CH}_3$ into $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CH}_2$ ?
230370
The major product obtained on treatment of $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}(\mathrm{F}) \mathrm{CH}_3$ with $\mathrm{CH}_3 \mathrm{O}^{-} / \mathrm{CH}_3 \mathrm{OH}$ is:
230362
The alkene that will give the same product with HBr in the absence as well as in the presence of peroxide is
1 2-butene
2 1-butene
3 propene
4 1-hexene
Explanation:
: When an unsymmetrical alkene is treated with the unsymmetrical reagent in the presence of peroxide, then addition takes place against the markownikoff's rule i.e negative part of reagent adds to that carbon to carbon-carbon double bond which carries more number of hydrogen atoms. In 2-butene will give the same product with $\mathrm{HBr}$ in the absence as well as presence of peroxide when treated with $\mathrm{HBr}$.
AIIMS-2016
Hydrocarbons
230367
Which of the following sequence of reactions (reagents) can be used for the conversion of $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{CH}_3$ into $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CH}_2$ ?
230370
The major product obtained on treatment of $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}(\mathrm{F}) \mathrm{CH}_3$ with $\mathrm{CH}_3 \mathrm{O}^{-} / \mathrm{CH}_3 \mathrm{OH}$ is:
