: Those compound which have keto methyl group to give a iodoform test. In acetic acid $\left(\mathrm{CH}_3 \mathrm{COOH}\right)$ would not respond to iodoform test. In first step base deprotonates most acidic alpha $H$ atom. In acetic acid, the most acidic proton is attached to $\mathrm{O}$ atom So, deprotonation of $\propto$-hydrogen does not occur so $\mathrm{CH}_3 \mathrm{COOH}$ not respond the iodoform test.
WB-JEE-2016
Hydrocarbons
230289
Haloform reaction with $\mathrm{I}_2$ and $\mathrm{KOH}$ will be responded by
1
2
3
4
Explanation:
,b) : Halo form reaction is oxidising in nature. It requires a methyl group near a carbonyl group near a carbonyl carbon to give a positive test.
WB-JEE-2019
Hydrocarbons
230131
Which of the following compounds cannot be prepared singly by the Wurtz reaction?
: Unsymmetrical hydrocarbon cannot be Singly prepared by wurtz reaction. A mixture of two different alkyl halides is heated with sodium metal, three different alkenes will be produced.
VITEEE-2014
Hydrocarbons
230058
Which one of the following compounds is most acidic?
1 $\mathrm{CH}_3 \mathrm{Cl}$
2 $\mathrm{CH}_3 \mathrm{OH}$
3 $\mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2$
4 $\mathrm{HC} \equiv \mathrm{CH}$
Explanation:
: $\mathrm{CH}_3 \mathrm{OH}$ is most acidic nature because it release $\mathrm{H}^{+}$ion (proton). $\mathrm{CH}_3 \mathrm{OH} \rightarrow \mathrm{CH}_3 \mathrm{O}^{-}+\mathrm{H}^{+}$
A.P.EAMCET-1996
Hydrocarbons
230093
Isopropyl chloride and isobutyl chloride reacts with sodium in ether to give
: Those compound which have keto methyl group to give a iodoform test. In acetic acid $\left(\mathrm{CH}_3 \mathrm{COOH}\right)$ would not respond to iodoform test. In first step base deprotonates most acidic alpha $H$ atom. In acetic acid, the most acidic proton is attached to $\mathrm{O}$ atom So, deprotonation of $\propto$-hydrogen does not occur so $\mathrm{CH}_3 \mathrm{COOH}$ not respond the iodoform test.
WB-JEE-2016
Hydrocarbons
230289
Haloform reaction with $\mathrm{I}_2$ and $\mathrm{KOH}$ will be responded by
1
2
3
4
Explanation:
,b) : Halo form reaction is oxidising in nature. It requires a methyl group near a carbonyl group near a carbonyl carbon to give a positive test.
WB-JEE-2019
Hydrocarbons
230131
Which of the following compounds cannot be prepared singly by the Wurtz reaction?
: Unsymmetrical hydrocarbon cannot be Singly prepared by wurtz reaction. A mixture of two different alkyl halides is heated with sodium metal, three different alkenes will be produced.
VITEEE-2014
Hydrocarbons
230058
Which one of the following compounds is most acidic?
1 $\mathrm{CH}_3 \mathrm{Cl}$
2 $\mathrm{CH}_3 \mathrm{OH}$
3 $\mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2$
4 $\mathrm{HC} \equiv \mathrm{CH}$
Explanation:
: $\mathrm{CH}_3 \mathrm{OH}$ is most acidic nature because it release $\mathrm{H}^{+}$ion (proton). $\mathrm{CH}_3 \mathrm{OH} \rightarrow \mathrm{CH}_3 \mathrm{O}^{-}+\mathrm{H}^{+}$
A.P.EAMCET-1996
Hydrocarbons
230093
Isopropyl chloride and isobutyl chloride reacts with sodium in ether to give
: Those compound which have keto methyl group to give a iodoform test. In acetic acid $\left(\mathrm{CH}_3 \mathrm{COOH}\right)$ would not respond to iodoform test. In first step base deprotonates most acidic alpha $H$ atom. In acetic acid, the most acidic proton is attached to $\mathrm{O}$ atom So, deprotonation of $\propto$-hydrogen does not occur so $\mathrm{CH}_3 \mathrm{COOH}$ not respond the iodoform test.
WB-JEE-2016
Hydrocarbons
230289
Haloform reaction with $\mathrm{I}_2$ and $\mathrm{KOH}$ will be responded by
1
2
3
4
Explanation:
,b) : Halo form reaction is oxidising in nature. It requires a methyl group near a carbonyl group near a carbonyl carbon to give a positive test.
WB-JEE-2019
Hydrocarbons
230131
Which of the following compounds cannot be prepared singly by the Wurtz reaction?
: Unsymmetrical hydrocarbon cannot be Singly prepared by wurtz reaction. A mixture of two different alkyl halides is heated with sodium metal, three different alkenes will be produced.
VITEEE-2014
Hydrocarbons
230058
Which one of the following compounds is most acidic?
1 $\mathrm{CH}_3 \mathrm{Cl}$
2 $\mathrm{CH}_3 \mathrm{OH}$
3 $\mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2$
4 $\mathrm{HC} \equiv \mathrm{CH}$
Explanation:
: $\mathrm{CH}_3 \mathrm{OH}$ is most acidic nature because it release $\mathrm{H}^{+}$ion (proton). $\mathrm{CH}_3 \mathrm{OH} \rightarrow \mathrm{CH}_3 \mathrm{O}^{-}+\mathrm{H}^{+}$
A.P.EAMCET-1996
Hydrocarbons
230093
Isopropyl chloride and isobutyl chloride reacts with sodium in ether to give
: Those compound which have keto methyl group to give a iodoform test. In acetic acid $\left(\mathrm{CH}_3 \mathrm{COOH}\right)$ would not respond to iodoform test. In first step base deprotonates most acidic alpha $H$ atom. In acetic acid, the most acidic proton is attached to $\mathrm{O}$ atom So, deprotonation of $\propto$-hydrogen does not occur so $\mathrm{CH}_3 \mathrm{COOH}$ not respond the iodoform test.
WB-JEE-2016
Hydrocarbons
230289
Haloform reaction with $\mathrm{I}_2$ and $\mathrm{KOH}$ will be responded by
1
2
3
4
Explanation:
,b) : Halo form reaction is oxidising in nature. It requires a methyl group near a carbonyl group near a carbonyl carbon to give a positive test.
WB-JEE-2019
Hydrocarbons
230131
Which of the following compounds cannot be prepared singly by the Wurtz reaction?
: Unsymmetrical hydrocarbon cannot be Singly prepared by wurtz reaction. A mixture of two different alkyl halides is heated with sodium metal, three different alkenes will be produced.
VITEEE-2014
Hydrocarbons
230058
Which one of the following compounds is most acidic?
1 $\mathrm{CH}_3 \mathrm{Cl}$
2 $\mathrm{CH}_3 \mathrm{OH}$
3 $\mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2$
4 $\mathrm{HC} \equiv \mathrm{CH}$
Explanation:
: $\mathrm{CH}_3 \mathrm{OH}$ is most acidic nature because it release $\mathrm{H}^{+}$ion (proton). $\mathrm{CH}_3 \mathrm{OH} \rightarrow \mathrm{CH}_3 \mathrm{O}^{-}+\mathrm{H}^{+}$
A.P.EAMCET-1996
Hydrocarbons
230093
Isopropyl chloride and isobutyl chloride reacts with sodium in ether to give
: Those compound which have keto methyl group to give a iodoform test. In acetic acid $\left(\mathrm{CH}_3 \mathrm{COOH}\right)$ would not respond to iodoform test. In first step base deprotonates most acidic alpha $H$ atom. In acetic acid, the most acidic proton is attached to $\mathrm{O}$ atom So, deprotonation of $\propto$-hydrogen does not occur so $\mathrm{CH}_3 \mathrm{COOH}$ not respond the iodoform test.
WB-JEE-2016
Hydrocarbons
230289
Haloform reaction with $\mathrm{I}_2$ and $\mathrm{KOH}$ will be responded by
1
2
3
4
Explanation:
,b) : Halo form reaction is oxidising in nature. It requires a methyl group near a carbonyl group near a carbonyl carbon to give a positive test.
WB-JEE-2019
Hydrocarbons
230131
Which of the following compounds cannot be prepared singly by the Wurtz reaction?
: Unsymmetrical hydrocarbon cannot be Singly prepared by wurtz reaction. A mixture of two different alkyl halides is heated with sodium metal, three different alkenes will be produced.
VITEEE-2014
Hydrocarbons
230058
Which one of the following compounds is most acidic?
1 $\mathrm{CH}_3 \mathrm{Cl}$
2 $\mathrm{CH}_3 \mathrm{OH}$
3 $\mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2$
4 $\mathrm{HC} \equiv \mathrm{CH}$
Explanation:
: $\mathrm{CH}_3 \mathrm{OH}$ is most acidic nature because it release $\mathrm{H}^{+}$ion (proton). $\mathrm{CH}_3 \mathrm{OH} \rightarrow \mathrm{CH}_3 \mathrm{O}^{-}+\mathrm{H}^{+}$
A.P.EAMCET-1996
Hydrocarbons
230093
Isopropyl chloride and isobutyl chloride reacts with sodium in ether to give
to give a iodoform test.
