230205
Which of the following alcohol give positive iodoform test?
1 Methanol
2 Ethyl carbinol
3 Pentanol-3
4 Methyl carbinol
Explanation:
: The molecular formula of methyl carbinal $\left(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}\right)$. It gives a iodoform test and it is oxidised to acetaldehyele in basic conditions. $\begin{array}{r} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}+6 \mathrm{NaOH}+4 \mathrm{I}_2 \rightarrow \mathrm{CHI}_3+ \\ \mathrm{HCOONa}+5 \mathrm{NaI}+3 \mathrm{H}_2 \mathrm{O} \end{array}$
JCECE - 2004]
Hydrocarbons
230207
Which one of the following aqueous solution will exhibit highest boiling point?
1 $0.01 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$
2 $0.01 \mathrm{M} \mathrm{KNO}_3$
3 $0.015 \mathrm{M}$ urea
4 $0.015 \mathrm{M}$ glucose
Explanation:
: Molecular mass is highest then boiling point is highest. The elevation in boiling point is a colligative property of the solution i.e. elevation in boiling point is directly proportional to solute particle concentration. The dissociation of sodium sulphate $\mathrm{Na}_2 \mathrm{SO}_4 \rightarrow 2 \mathrm{Na}^{+}+\mathrm{SO}_4^{2-}$ $\therefore$ Concentration of ions is $0.01 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$ solution is $=3 \times 0.01=0.03 \mathrm{M}$.
**JCECE - 2008
Hydrocarbons
230209
Which of the following liquid on electrolysis produce $\mathrm{H}_2$ at cathode and $\mathrm{Cl}_2$ at anode?
1 $\mathrm{NaCl}$ solution in water
2 $\mathrm{CuCl}_2$ solution in water
3 Pure water
4 $\mathrm{H}_2 \mathrm{SO}_4$ Solution
Explanation:
: $\mathrm{NaCl}$ solution in water gives $\mathrm{H}_2$ at cathode and $\mathrm{Cl}_2$ at anode because of low discharge potential of $\mathrm{H}^{+}$ions as compared to $\mathrm{Na}^{+}$(at cathode) and of $\mathrm{Cl}^{-}$as compared to $\mathrm{OH}^{-}$ions (due to over voltage). $\begin{aligned} & 2 \mathrm{H}^{+} \stackrel{+2 \mathrm{o}^{-}}{\longrightarrow} \mathrm{H}_2(\mathrm{~g}) \text { (at cathode) } \\ & 2 \mathrm{Cl}^{-} \stackrel{-20^{-}}{\longrightarrow} \mathrm{Cl}_2 \text { (g) (at anode) } \end{aligned}$
: (i) In the presence of $\mathrm{H}_2 \mathrm{O}$ and Grignard reagent, all compounds having acidic (reactive- $\mathrm{H}$ ) hydrogen will give alkane. (ii) $\mathrm{R}-\mathrm{X}$ in the presence of $\mathrm{H}_2 \mathrm{O}$ gives alkane in place of Grignard reagent.
JCECE - 2016
Hydrocarbons
230212
Which one of the following does not undergo iodoform reaction
1 Secondary butyl alcohol
2 ISo-propels alcohol
3 Diethyl ketone
4 Ethyl alcohol
Explanation:
: Those compound which have methyl Keto group have give iodoform reaction. Those compound that contains terminal methyl keto group or can be oxidised to methyl keto group can undergo iodoform reaction. So, diethyl ketone does not undergo iodoform reaction because it does not contain methyl keto group.
230205
Which of the following alcohol give positive iodoform test?
1 Methanol
2 Ethyl carbinol
3 Pentanol-3
4 Methyl carbinol
Explanation:
: The molecular formula of methyl carbinal $\left(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}\right)$. It gives a iodoform test and it is oxidised to acetaldehyele in basic conditions. $\begin{array}{r} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}+6 \mathrm{NaOH}+4 \mathrm{I}_2 \rightarrow \mathrm{CHI}_3+ \\ \mathrm{HCOONa}+5 \mathrm{NaI}+3 \mathrm{H}_2 \mathrm{O} \end{array}$
JCECE - 2004]
Hydrocarbons
230207
Which one of the following aqueous solution will exhibit highest boiling point?
1 $0.01 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$
2 $0.01 \mathrm{M} \mathrm{KNO}_3$
3 $0.015 \mathrm{M}$ urea
4 $0.015 \mathrm{M}$ glucose
Explanation:
: Molecular mass is highest then boiling point is highest. The elevation in boiling point is a colligative property of the solution i.e. elevation in boiling point is directly proportional to solute particle concentration. The dissociation of sodium sulphate $\mathrm{Na}_2 \mathrm{SO}_4 \rightarrow 2 \mathrm{Na}^{+}+\mathrm{SO}_4^{2-}$ $\therefore$ Concentration of ions is $0.01 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$ solution is $=3 \times 0.01=0.03 \mathrm{M}$.
**JCECE - 2008
Hydrocarbons
230209
Which of the following liquid on electrolysis produce $\mathrm{H}_2$ at cathode and $\mathrm{Cl}_2$ at anode?
1 $\mathrm{NaCl}$ solution in water
2 $\mathrm{CuCl}_2$ solution in water
3 Pure water
4 $\mathrm{H}_2 \mathrm{SO}_4$ Solution
Explanation:
: $\mathrm{NaCl}$ solution in water gives $\mathrm{H}_2$ at cathode and $\mathrm{Cl}_2$ at anode because of low discharge potential of $\mathrm{H}^{+}$ions as compared to $\mathrm{Na}^{+}$(at cathode) and of $\mathrm{Cl}^{-}$as compared to $\mathrm{OH}^{-}$ions (due to over voltage). $\begin{aligned} & 2 \mathrm{H}^{+} \stackrel{+2 \mathrm{o}^{-}}{\longrightarrow} \mathrm{H}_2(\mathrm{~g}) \text { (at cathode) } \\ & 2 \mathrm{Cl}^{-} \stackrel{-20^{-}}{\longrightarrow} \mathrm{Cl}_2 \text { (g) (at anode) } \end{aligned}$
: (i) In the presence of $\mathrm{H}_2 \mathrm{O}$ and Grignard reagent, all compounds having acidic (reactive- $\mathrm{H}$ ) hydrogen will give alkane. (ii) $\mathrm{R}-\mathrm{X}$ in the presence of $\mathrm{H}_2 \mathrm{O}$ gives alkane in place of Grignard reagent.
JCECE - 2016
Hydrocarbons
230212
Which one of the following does not undergo iodoform reaction
1 Secondary butyl alcohol
2 ISo-propels alcohol
3 Diethyl ketone
4 Ethyl alcohol
Explanation:
: Those compound which have methyl Keto group have give iodoform reaction. Those compound that contains terminal methyl keto group or can be oxidised to methyl keto group can undergo iodoform reaction. So, diethyl ketone does not undergo iodoform reaction because it does not contain methyl keto group.
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Hydrocarbons
230205
Which of the following alcohol give positive iodoform test?
1 Methanol
2 Ethyl carbinol
3 Pentanol-3
4 Methyl carbinol
Explanation:
: The molecular formula of methyl carbinal $\left(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}\right)$. It gives a iodoform test and it is oxidised to acetaldehyele in basic conditions. $\begin{array}{r} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}+6 \mathrm{NaOH}+4 \mathrm{I}_2 \rightarrow \mathrm{CHI}_3+ \\ \mathrm{HCOONa}+5 \mathrm{NaI}+3 \mathrm{H}_2 \mathrm{O} \end{array}$
JCECE - 2004]
Hydrocarbons
230207
Which one of the following aqueous solution will exhibit highest boiling point?
1 $0.01 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$
2 $0.01 \mathrm{M} \mathrm{KNO}_3$
3 $0.015 \mathrm{M}$ urea
4 $0.015 \mathrm{M}$ glucose
Explanation:
: Molecular mass is highest then boiling point is highest. The elevation in boiling point is a colligative property of the solution i.e. elevation in boiling point is directly proportional to solute particle concentration. The dissociation of sodium sulphate $\mathrm{Na}_2 \mathrm{SO}_4 \rightarrow 2 \mathrm{Na}^{+}+\mathrm{SO}_4^{2-}$ $\therefore$ Concentration of ions is $0.01 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$ solution is $=3 \times 0.01=0.03 \mathrm{M}$.
**JCECE - 2008
Hydrocarbons
230209
Which of the following liquid on electrolysis produce $\mathrm{H}_2$ at cathode and $\mathrm{Cl}_2$ at anode?
1 $\mathrm{NaCl}$ solution in water
2 $\mathrm{CuCl}_2$ solution in water
3 Pure water
4 $\mathrm{H}_2 \mathrm{SO}_4$ Solution
Explanation:
: $\mathrm{NaCl}$ solution in water gives $\mathrm{H}_2$ at cathode and $\mathrm{Cl}_2$ at anode because of low discharge potential of $\mathrm{H}^{+}$ions as compared to $\mathrm{Na}^{+}$(at cathode) and of $\mathrm{Cl}^{-}$as compared to $\mathrm{OH}^{-}$ions (due to over voltage). $\begin{aligned} & 2 \mathrm{H}^{+} \stackrel{+2 \mathrm{o}^{-}}{\longrightarrow} \mathrm{H}_2(\mathrm{~g}) \text { (at cathode) } \\ & 2 \mathrm{Cl}^{-} \stackrel{-20^{-}}{\longrightarrow} \mathrm{Cl}_2 \text { (g) (at anode) } \end{aligned}$
: (i) In the presence of $\mathrm{H}_2 \mathrm{O}$ and Grignard reagent, all compounds having acidic (reactive- $\mathrm{H}$ ) hydrogen will give alkane. (ii) $\mathrm{R}-\mathrm{X}$ in the presence of $\mathrm{H}_2 \mathrm{O}$ gives alkane in place of Grignard reagent.
JCECE - 2016
Hydrocarbons
230212
Which one of the following does not undergo iodoform reaction
1 Secondary butyl alcohol
2 ISo-propels alcohol
3 Diethyl ketone
4 Ethyl alcohol
Explanation:
: Those compound which have methyl Keto group have give iodoform reaction. Those compound that contains terminal methyl keto group or can be oxidised to methyl keto group can undergo iodoform reaction. So, diethyl ketone does not undergo iodoform reaction because it does not contain methyl keto group.
230205
Which of the following alcohol give positive iodoform test?
1 Methanol
2 Ethyl carbinol
3 Pentanol-3
4 Methyl carbinol
Explanation:
: The molecular formula of methyl carbinal $\left(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}\right)$. It gives a iodoform test and it is oxidised to acetaldehyele in basic conditions. $\begin{array}{r} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}+6 \mathrm{NaOH}+4 \mathrm{I}_2 \rightarrow \mathrm{CHI}_3+ \\ \mathrm{HCOONa}+5 \mathrm{NaI}+3 \mathrm{H}_2 \mathrm{O} \end{array}$
JCECE - 2004]
Hydrocarbons
230207
Which one of the following aqueous solution will exhibit highest boiling point?
1 $0.01 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$
2 $0.01 \mathrm{M} \mathrm{KNO}_3$
3 $0.015 \mathrm{M}$ urea
4 $0.015 \mathrm{M}$ glucose
Explanation:
: Molecular mass is highest then boiling point is highest. The elevation in boiling point is a colligative property of the solution i.e. elevation in boiling point is directly proportional to solute particle concentration. The dissociation of sodium sulphate $\mathrm{Na}_2 \mathrm{SO}_4 \rightarrow 2 \mathrm{Na}^{+}+\mathrm{SO}_4^{2-}$ $\therefore$ Concentration of ions is $0.01 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$ solution is $=3 \times 0.01=0.03 \mathrm{M}$.
**JCECE - 2008
Hydrocarbons
230209
Which of the following liquid on electrolysis produce $\mathrm{H}_2$ at cathode and $\mathrm{Cl}_2$ at anode?
1 $\mathrm{NaCl}$ solution in water
2 $\mathrm{CuCl}_2$ solution in water
3 Pure water
4 $\mathrm{H}_2 \mathrm{SO}_4$ Solution
Explanation:
: $\mathrm{NaCl}$ solution in water gives $\mathrm{H}_2$ at cathode and $\mathrm{Cl}_2$ at anode because of low discharge potential of $\mathrm{H}^{+}$ions as compared to $\mathrm{Na}^{+}$(at cathode) and of $\mathrm{Cl}^{-}$as compared to $\mathrm{OH}^{-}$ions (due to over voltage). $\begin{aligned} & 2 \mathrm{H}^{+} \stackrel{+2 \mathrm{o}^{-}}{\longrightarrow} \mathrm{H}_2(\mathrm{~g}) \text { (at cathode) } \\ & 2 \mathrm{Cl}^{-} \stackrel{-20^{-}}{\longrightarrow} \mathrm{Cl}_2 \text { (g) (at anode) } \end{aligned}$
: (i) In the presence of $\mathrm{H}_2 \mathrm{O}$ and Grignard reagent, all compounds having acidic (reactive- $\mathrm{H}$ ) hydrogen will give alkane. (ii) $\mathrm{R}-\mathrm{X}$ in the presence of $\mathrm{H}_2 \mathrm{O}$ gives alkane in place of Grignard reagent.
JCECE - 2016
Hydrocarbons
230212
Which one of the following does not undergo iodoform reaction
1 Secondary butyl alcohol
2 ISo-propels alcohol
3 Diethyl ketone
4 Ethyl alcohol
Explanation:
: Those compound which have methyl Keto group have give iodoform reaction. Those compound that contains terminal methyl keto group or can be oxidised to methyl keto group can undergo iodoform reaction. So, diethyl ketone does not undergo iodoform reaction because it does not contain methyl keto group.
230205
Which of the following alcohol give positive iodoform test?
1 Methanol
2 Ethyl carbinol
3 Pentanol-3
4 Methyl carbinol
Explanation:
: The molecular formula of methyl carbinal $\left(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}\right)$. It gives a iodoform test and it is oxidised to acetaldehyele in basic conditions. $\begin{array}{r} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}+6 \mathrm{NaOH}+4 \mathrm{I}_2 \rightarrow \mathrm{CHI}_3+ \\ \mathrm{HCOONa}+5 \mathrm{NaI}+3 \mathrm{H}_2 \mathrm{O} \end{array}$
JCECE - 2004]
Hydrocarbons
230207
Which one of the following aqueous solution will exhibit highest boiling point?
1 $0.01 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$
2 $0.01 \mathrm{M} \mathrm{KNO}_3$
3 $0.015 \mathrm{M}$ urea
4 $0.015 \mathrm{M}$ glucose
Explanation:
: Molecular mass is highest then boiling point is highest. The elevation in boiling point is a colligative property of the solution i.e. elevation in boiling point is directly proportional to solute particle concentration. The dissociation of sodium sulphate $\mathrm{Na}_2 \mathrm{SO}_4 \rightarrow 2 \mathrm{Na}^{+}+\mathrm{SO}_4^{2-}$ $\therefore$ Concentration of ions is $0.01 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$ solution is $=3 \times 0.01=0.03 \mathrm{M}$.
**JCECE - 2008
Hydrocarbons
230209
Which of the following liquid on electrolysis produce $\mathrm{H}_2$ at cathode and $\mathrm{Cl}_2$ at anode?
1 $\mathrm{NaCl}$ solution in water
2 $\mathrm{CuCl}_2$ solution in water
3 Pure water
4 $\mathrm{H}_2 \mathrm{SO}_4$ Solution
Explanation:
: $\mathrm{NaCl}$ solution in water gives $\mathrm{H}_2$ at cathode and $\mathrm{Cl}_2$ at anode because of low discharge potential of $\mathrm{H}^{+}$ions as compared to $\mathrm{Na}^{+}$(at cathode) and of $\mathrm{Cl}^{-}$as compared to $\mathrm{OH}^{-}$ions (due to over voltage). $\begin{aligned} & 2 \mathrm{H}^{+} \stackrel{+2 \mathrm{o}^{-}}{\longrightarrow} \mathrm{H}_2(\mathrm{~g}) \text { (at cathode) } \\ & 2 \mathrm{Cl}^{-} \stackrel{-20^{-}}{\longrightarrow} \mathrm{Cl}_2 \text { (g) (at anode) } \end{aligned}$
: (i) In the presence of $\mathrm{H}_2 \mathrm{O}$ and Grignard reagent, all compounds having acidic (reactive- $\mathrm{H}$ ) hydrogen will give alkane. (ii) $\mathrm{R}-\mathrm{X}$ in the presence of $\mathrm{H}_2 \mathrm{O}$ gives alkane in place of Grignard reagent.
JCECE - 2016
Hydrocarbons
230212
Which one of the following does not undergo iodoform reaction
1 Secondary butyl alcohol
2 ISo-propels alcohol
3 Diethyl ketone
4 Ethyl alcohol
Explanation:
: Those compound which have methyl Keto group have give iodoform reaction. Those compound that contains terminal methyl keto group or can be oxidised to methyl keto group can undergo iodoform reaction. So, diethyl ketone does not undergo iodoform reaction because it does not contain methyl keto group.
have give iodoform reaction.