230193
Which of the following alkenes gives only acetaldehyde on ozonolysis?
1 ethene
2 propene
3 1-butene
4 2-butene
Explanation:
: Ozonolysis involves the breaking of double bond and insertion of $\mathrm{O}$ atoms in place of double bond. Therefore, the structure of alkene is as-
J and K CET-(2008)
Hydrocarbons
230194
Bromination of alkanes involves
1 Carbanions
2 Carbocations
3 Carbenes
4 Free radicals
Explanation:
: In bromination of alkane involve in the presence of uv light, alkane will reaction. Uv light is the condition under the reaction will form a free radicals. During this reaction, bromine atoms substitute this hydrogen atom to producing bromo alkane.
J and K CET-(2005)
Hydrocarbons
230197
Lindlar's catalyst is
1 pd and $\mathrm{CO}_2$
2 pd and $\mathrm{H}_2$
3 Palladised charcoal deactivated with sulphur
4 $\mathrm{Pd}$ and $\mathrm{CaCO}_3$
Explanation:
: A Lindlar catalyst is a heterogeneous catalyst that consists of palladium deposed on calcium carbonate or barium sulfate which is then poisoned with venous forms of lead or sulfur. It is used for the hydrogenation of alkynes to alkene. The palladium content of the supported catalyst is usually $5 \%$ by weight.
J and K CET-(2000)
Hydrocarbons
230198
Which of the following is the correct statement for $\mathrm{C}_4 \mathrm{H}$ ?
1 It must have a double bond
2 It must have a triple bond
3 It should not have either a double or triple bond
4 Such a compound is impossible
Explanation:
: For $\mathrm{C}_4 \mathrm{H}$ compound is impossible because carbon has four valency not satisfied by the carbon. So, such a compound is impossible.
230193
Which of the following alkenes gives only acetaldehyde on ozonolysis?
1 ethene
2 propene
3 1-butene
4 2-butene
Explanation:
: Ozonolysis involves the breaking of double bond and insertion of $\mathrm{O}$ atoms in place of double bond. Therefore, the structure of alkene is as-
J and K CET-(2008)
Hydrocarbons
230194
Bromination of alkanes involves
1 Carbanions
2 Carbocations
3 Carbenes
4 Free radicals
Explanation:
: In bromination of alkane involve in the presence of uv light, alkane will reaction. Uv light is the condition under the reaction will form a free radicals. During this reaction, bromine atoms substitute this hydrogen atom to producing bromo alkane.
J and K CET-(2005)
Hydrocarbons
230197
Lindlar's catalyst is
1 pd and $\mathrm{CO}_2$
2 pd and $\mathrm{H}_2$
3 Palladised charcoal deactivated with sulphur
4 $\mathrm{Pd}$ and $\mathrm{CaCO}_3$
Explanation:
: A Lindlar catalyst is a heterogeneous catalyst that consists of palladium deposed on calcium carbonate or barium sulfate which is then poisoned with venous forms of lead or sulfur. It is used for the hydrogenation of alkynes to alkene. The palladium content of the supported catalyst is usually $5 \%$ by weight.
J and K CET-(2000)
Hydrocarbons
230198
Which of the following is the correct statement for $\mathrm{C}_4 \mathrm{H}$ ?
1 It must have a double bond
2 It must have a triple bond
3 It should not have either a double or triple bond
4 Such a compound is impossible
Explanation:
: For $\mathrm{C}_4 \mathrm{H}$ compound is impossible because carbon has four valency not satisfied by the carbon. So, such a compound is impossible.
230193
Which of the following alkenes gives only acetaldehyde on ozonolysis?
1 ethene
2 propene
3 1-butene
4 2-butene
Explanation:
: Ozonolysis involves the breaking of double bond and insertion of $\mathrm{O}$ atoms in place of double bond. Therefore, the structure of alkene is as-
J and K CET-(2008)
Hydrocarbons
230194
Bromination of alkanes involves
1 Carbanions
2 Carbocations
3 Carbenes
4 Free radicals
Explanation:
: In bromination of alkane involve in the presence of uv light, alkane will reaction. Uv light is the condition under the reaction will form a free radicals. During this reaction, bromine atoms substitute this hydrogen atom to producing bromo alkane.
J and K CET-(2005)
Hydrocarbons
230197
Lindlar's catalyst is
1 pd and $\mathrm{CO}_2$
2 pd and $\mathrm{H}_2$
3 Palladised charcoal deactivated with sulphur
4 $\mathrm{Pd}$ and $\mathrm{CaCO}_3$
Explanation:
: A Lindlar catalyst is a heterogeneous catalyst that consists of palladium deposed on calcium carbonate or barium sulfate which is then poisoned with venous forms of lead or sulfur. It is used for the hydrogenation of alkynes to alkene. The palladium content of the supported catalyst is usually $5 \%$ by weight.
J and K CET-(2000)
Hydrocarbons
230198
Which of the following is the correct statement for $\mathrm{C}_4 \mathrm{H}$ ?
1 It must have a double bond
2 It must have a triple bond
3 It should not have either a double or triple bond
4 Such a compound is impossible
Explanation:
: For $\mathrm{C}_4 \mathrm{H}$ compound is impossible because carbon has four valency not satisfied by the carbon. So, such a compound is impossible.
230193
Which of the following alkenes gives only acetaldehyde on ozonolysis?
1 ethene
2 propene
3 1-butene
4 2-butene
Explanation:
: Ozonolysis involves the breaking of double bond and insertion of $\mathrm{O}$ atoms in place of double bond. Therefore, the structure of alkene is as-
J and K CET-(2008)
Hydrocarbons
230194
Bromination of alkanes involves
1 Carbanions
2 Carbocations
3 Carbenes
4 Free radicals
Explanation:
: In bromination of alkane involve in the presence of uv light, alkane will reaction. Uv light is the condition under the reaction will form a free radicals. During this reaction, bromine atoms substitute this hydrogen atom to producing bromo alkane.
J and K CET-(2005)
Hydrocarbons
230197
Lindlar's catalyst is
1 pd and $\mathrm{CO}_2$
2 pd and $\mathrm{H}_2$
3 Palladised charcoal deactivated with sulphur
4 $\mathrm{Pd}$ and $\mathrm{CaCO}_3$
Explanation:
: A Lindlar catalyst is a heterogeneous catalyst that consists of palladium deposed on calcium carbonate or barium sulfate which is then poisoned with venous forms of lead or sulfur. It is used for the hydrogenation of alkynes to alkene. The palladium content of the supported catalyst is usually $5 \%$ by weight.
J and K CET-(2000)
Hydrocarbons
230198
Which of the following is the correct statement for $\mathrm{C}_4 \mathrm{H}$ ?
1 It must have a double bond
2 It must have a triple bond
3 It should not have either a double or triple bond
4 Such a compound is impossible
Explanation:
: For $\mathrm{C}_4 \mathrm{H}$ compound is impossible because carbon has four valency not satisfied by the carbon. So, such a compound is impossible.
