230121
Assertion (A): Cyclohexane is the most stable cycloalkane. Reason (R): Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain. The correct answer is
1 Both (A) and (R) are true but (R) is not the correct explanation of $(A)$.
2 (A) is true but ( $R$ ) is not true.
3 (A) is not true but (R) is true.
4 Both (A) and (R) are true and (R) is the correct explanation of $(A)$.
Explanation:
: In cycloalkane heat of combustion is lowest than cyclohexane so it is most stable cycloalkane. Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain. Therefore cylopropane and cylobutane are reactive cycloalkane.
AP-EAMCET- (Engg.)-2011
Hydrocarbons
230149 The product $P$ is-
1
2
3
4
Explanation:
: The reaction of alkyl bromide react with sodium in the presence of ether is known wurtz reaction.
BCECE-2016
Hydrocarbons
230160
In which case the $\mathrm{N}_{\mathrm{N}}$, will attack at the meta position
1 I, II, III
2 II, IV
3 II and III only
4 II only
Explanation:
: $\mathrm{N}_2$ is an electrophile. The nucleophile attack on meta position the group, $-\mathrm{CCl} 3,-\stackrel{-}{\mathrm{NO}_2}, \mathrm{NH}_3^{+}$ are electron withdrawing group its generate the positive charge on ortho and para group. Hence, the nucleophile will be attack on the metaposition.
BITSAT- 2012
Hydrocarbons
230173
In the following sequence of reactions the $P$ is: \(+\mathrm{Mg} \underset{\text { ether }}{\text { Dry }}(A) \xrightarrow{\text { Ethanol }}\)(P)[Major product]
1
2
3
4
Explanation:
:
27 Aug Shift-I]**
Hydrocarbons
230175
The major product(s) obtained in the following reaction is/are: \(\xrightarrow[\text { (ii) } \mathrm{O}_3 / \mathrm{Me}_2 \mathrm{~S}]{\text { (i) }KO^{t}Bu}\)
230121
Assertion (A): Cyclohexane is the most stable cycloalkane. Reason (R): Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain. The correct answer is
1 Both (A) and (R) are true but (R) is not the correct explanation of $(A)$.
2 (A) is true but ( $R$ ) is not true.
3 (A) is not true but (R) is true.
4 Both (A) and (R) are true and (R) is the correct explanation of $(A)$.
Explanation:
: In cycloalkane heat of combustion is lowest than cyclohexane so it is most stable cycloalkane. Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain. Therefore cylopropane and cylobutane are reactive cycloalkane.
AP-EAMCET- (Engg.)-2011
Hydrocarbons
230149 The product $P$ is-
1
2
3
4
Explanation:
: The reaction of alkyl bromide react with sodium in the presence of ether is known wurtz reaction.
BCECE-2016
Hydrocarbons
230160
In which case the $\mathrm{N}_{\mathrm{N}}$, will attack at the meta position
1 I, II, III
2 II, IV
3 II and III only
4 II only
Explanation:
: $\mathrm{N}_2$ is an electrophile. The nucleophile attack on meta position the group, $-\mathrm{CCl} 3,-\stackrel{-}{\mathrm{NO}_2}, \mathrm{NH}_3^{+}$ are electron withdrawing group its generate the positive charge on ortho and para group. Hence, the nucleophile will be attack on the metaposition.
BITSAT- 2012
Hydrocarbons
230173
In the following sequence of reactions the $P$ is: \(+\mathrm{Mg} \underset{\text { ether }}{\text { Dry }}(A) \xrightarrow{\text { Ethanol }}\)(P)[Major product]
1
2
3
4
Explanation:
:
27 Aug Shift-I]**
Hydrocarbons
230175
The major product(s) obtained in the following reaction is/are: \(\xrightarrow[\text { (ii) } \mathrm{O}_3 / \mathrm{Me}_2 \mathrm{~S}]{\text { (i) }KO^{t}Bu}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Hydrocarbons
230121
Assertion (A): Cyclohexane is the most stable cycloalkane. Reason (R): Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain. The correct answer is
1 Both (A) and (R) are true but (R) is not the correct explanation of $(A)$.
2 (A) is true but ( $R$ ) is not true.
3 (A) is not true but (R) is true.
4 Both (A) and (R) are true and (R) is the correct explanation of $(A)$.
Explanation:
: In cycloalkane heat of combustion is lowest than cyclohexane so it is most stable cycloalkane. Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain. Therefore cylopropane and cylobutane are reactive cycloalkane.
AP-EAMCET- (Engg.)-2011
Hydrocarbons
230149 The product $P$ is-
1
2
3
4
Explanation:
: The reaction of alkyl bromide react with sodium in the presence of ether is known wurtz reaction.
BCECE-2016
Hydrocarbons
230160
In which case the $\mathrm{N}_{\mathrm{N}}$, will attack at the meta position
1 I, II, III
2 II, IV
3 II and III only
4 II only
Explanation:
: $\mathrm{N}_2$ is an electrophile. The nucleophile attack on meta position the group, $-\mathrm{CCl} 3,-\stackrel{-}{\mathrm{NO}_2}, \mathrm{NH}_3^{+}$ are electron withdrawing group its generate the positive charge on ortho and para group. Hence, the nucleophile will be attack on the metaposition.
BITSAT- 2012
Hydrocarbons
230173
In the following sequence of reactions the $P$ is: \(+\mathrm{Mg} \underset{\text { ether }}{\text { Dry }}(A) \xrightarrow{\text { Ethanol }}\)(P)[Major product]
1
2
3
4
Explanation:
:
27 Aug Shift-I]**
Hydrocarbons
230175
The major product(s) obtained in the following reaction is/are: \(\xrightarrow[\text { (ii) } \mathrm{O}_3 / \mathrm{Me}_2 \mathrm{~S}]{\text { (i) }KO^{t}Bu}\)
230121
Assertion (A): Cyclohexane is the most stable cycloalkane. Reason (R): Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain. The correct answer is
1 Both (A) and (R) are true but (R) is not the correct explanation of $(A)$.
2 (A) is true but ( $R$ ) is not true.
3 (A) is not true but (R) is true.
4 Both (A) and (R) are true and (R) is the correct explanation of $(A)$.
Explanation:
: In cycloalkane heat of combustion is lowest than cyclohexane so it is most stable cycloalkane. Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain. Therefore cylopropane and cylobutane are reactive cycloalkane.
AP-EAMCET- (Engg.)-2011
Hydrocarbons
230149 The product $P$ is-
1
2
3
4
Explanation:
: The reaction of alkyl bromide react with sodium in the presence of ether is known wurtz reaction.
BCECE-2016
Hydrocarbons
230160
In which case the $\mathrm{N}_{\mathrm{N}}$, will attack at the meta position
1 I, II, III
2 II, IV
3 II and III only
4 II only
Explanation:
: $\mathrm{N}_2$ is an electrophile. The nucleophile attack on meta position the group, $-\mathrm{CCl} 3,-\stackrel{-}{\mathrm{NO}_2}, \mathrm{NH}_3^{+}$ are electron withdrawing group its generate the positive charge on ortho and para group. Hence, the nucleophile will be attack on the metaposition.
BITSAT- 2012
Hydrocarbons
230173
In the following sequence of reactions the $P$ is: \(+\mathrm{Mg} \underset{\text { ether }}{\text { Dry }}(A) \xrightarrow{\text { Ethanol }}\)(P)[Major product]
1
2
3
4
Explanation:
:
27 Aug Shift-I]**
Hydrocarbons
230175
The major product(s) obtained in the following reaction is/are: \(\xrightarrow[\text { (ii) } \mathrm{O}_3 / \mathrm{Me}_2 \mathrm{~S}]{\text { (i) }KO^{t}Bu}\)
230121
Assertion (A): Cyclohexane is the most stable cycloalkane. Reason (R): Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain. The correct answer is
1 Both (A) and (R) are true but (R) is not the correct explanation of $(A)$.
2 (A) is true but ( $R$ ) is not true.
3 (A) is not true but (R) is true.
4 Both (A) and (R) are true and (R) is the correct explanation of $(A)$.
Explanation:
: In cycloalkane heat of combustion is lowest than cyclohexane so it is most stable cycloalkane. Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain. Therefore cylopropane and cylobutane are reactive cycloalkane.
AP-EAMCET- (Engg.)-2011
Hydrocarbons
230149 The product $P$ is-
1
2
3
4
Explanation:
: The reaction of alkyl bromide react with sodium in the presence of ether is known wurtz reaction.
BCECE-2016
Hydrocarbons
230160
In which case the $\mathrm{N}_{\mathrm{N}}$, will attack at the meta position
1 I, II, III
2 II, IV
3 II and III only
4 II only
Explanation:
: $\mathrm{N}_2$ is an electrophile. The nucleophile attack on meta position the group, $-\mathrm{CCl} 3,-\stackrel{-}{\mathrm{NO}_2}, \mathrm{NH}_3^{+}$ are electron withdrawing group its generate the positive charge on ortho and para group. Hence, the nucleophile will be attack on the metaposition.
BITSAT- 2012
Hydrocarbons
230173
In the following sequence of reactions the $P$ is: \(+\mathrm{Mg} \underset{\text { ether }}{\text { Dry }}(A) \xrightarrow{\text { Ethanol }}\)(P)[Major product]
1
2
3
4
Explanation:
:
27 Aug Shift-I]**
Hydrocarbons
230175
The major product(s) obtained in the following reaction is/are: \(\xrightarrow[\text { (ii) } \mathrm{O}_3 / \mathrm{Me}_2 \mathrm{~S}]{\text { (i) }KO^{t}Bu}\)
The product $P$ is-
