01. Solubility and Solubility Product Constant
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Ionic Equilibrium

229371 The solubility product of Ni(OH)2 at 298 K is 2×1015 mol3dm9. The pH value if, its aqueous and saturated solution is

1 5
2 7.5
3 9
4 13
Ionic Equilibrium

229372 The [Ag+]in a saturated solution of Ag2CrO4 is 1.5×104 M. What is the solubility product of Ag2CrO4 ?

1 3.375×1012M3
2 1.6875×1010M3
3 1.6875×1011M3
4 1.6875×1012M3
Ionic Equilibrium

229373 The Solubility of AgBr(s) having solubility product 5×1010 in 0.2MNaBr solution equals

1 5×1010M
2 25×1010M
3 0.5M
4 0.002M
Ionic Equilibrium

229370 If the molar solubility (in mol.L 1 ) of a sparingly soluble salt AB4 is ' S ', and the corresponding solubility product is ' Ksp ', then S in terms of Ksp is given by the relation

1 S=(Ksp256)1/4
2 S=(Ksp256)1/5
3 S=(256 Ksp)1/5
4 S=(128 Ksp)1/4
Ionic Equilibrium

229371 The solubility product of Ni(OH)2 at 298 K is 2×1015 mol3dm9. The pH value if, its aqueous and saturated solution is

1 5
2 7.5
3 9
4 13
Ionic Equilibrium

229372 The [Ag+]in a saturated solution of Ag2CrO4 is 1.5×104 M. What is the solubility product of Ag2CrO4 ?

1 3.375×1012M3
2 1.6875×1010M3
3 1.6875×1011M3
4 1.6875×1012M3
Ionic Equilibrium

229373 The Solubility of AgBr(s) having solubility product 5×1010 in 0.2MNaBr solution equals

1 5×1010M
2 25×1010M
3 0.5M
4 0.002M
Ionic Equilibrium

229370 If the molar solubility (in mol.L 1 ) of a sparingly soluble salt AB4 is ' S ', and the corresponding solubility product is ' Ksp ', then S in terms of Ksp is given by the relation

1 S=(Ksp256)1/4
2 S=(Ksp256)1/5
3 S=(256 Ksp)1/5
4 S=(128 Ksp)1/4
Ionic Equilibrium

229371 The solubility product of Ni(OH)2 at 298 K is 2×1015 mol3dm9. The pH value if, its aqueous and saturated solution is

1 5
2 7.5
3 9
4 13
Ionic Equilibrium

229372 The [Ag+]in a saturated solution of Ag2CrO4 is 1.5×104 M. What is the solubility product of Ag2CrO4 ?

1 3.375×1012M3
2 1.6875×1010M3
3 1.6875×1011M3
4 1.6875×1012M3
Ionic Equilibrium

229373 The Solubility of AgBr(s) having solubility product 5×1010 in 0.2MNaBr solution equals

1 5×1010M
2 25×1010M
3 0.5M
4 0.002M
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Ionic Equilibrium

229370 If the molar solubility (in mol.L 1 ) of a sparingly soluble salt AB4 is ' S ', and the corresponding solubility product is ' Ksp ', then S in terms of Ksp is given by the relation

1 S=(Ksp256)1/4
2 S=(Ksp256)1/5
3 S=(256 Ksp)1/5
4 S=(128 Ksp)1/4
Ionic Equilibrium

229371 The solubility product of Ni(OH)2 at 298 K is 2×1015 mol3dm9. The pH value if, its aqueous and saturated solution is

1 5
2 7.5
3 9
4 13
Ionic Equilibrium

229372 The [Ag+]in a saturated solution of Ag2CrO4 is 1.5×104 M. What is the solubility product of Ag2CrO4 ?

1 3.375×1012M3
2 1.6875×1010M3
3 1.6875×1011M3
4 1.6875×1012M3
Ionic Equilibrium

229373 The Solubility of AgBr(s) having solubility product 5×1010 in 0.2MNaBr solution equals

1 5×1010M
2 25×1010M
3 0.5M
4 0.002M