229328 For the process, $\frac{3}{2} \mathrm{~A} \rightarrow \mathrm{B}$, at $298 \mathrm{~K}, \Delta \mathrm{G}^{0}$ is $163 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The composition of the reaction mixture is $[\mathrm{B}]=1$ and $[A]=10000$. Predict the direction of the reaction and the relation between reaction quotient $(Q)$ and he equilibrium constant $(K)$

229329 In the $\ln K$ vs. $\frac{1}{T}$ plot of a chemical process having $\Delta S^{0}>0$ and $\Delta H^{0}<0$ the slope is proportional to (where $K$ is equilibrium constant)

229330 For the equilibrium,
$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})$;
$\mathrm{K}_{\mathrm{p}}=1.64 \mathrm{~atm}$ at $1000 \mathrm{~K}$
$50 \mathrm{~g}$ of $\mathrm{CaCO}_{3}$ in a $10 \mathrm{~L}$ closed vessel is heated to $1000 \mathrm{~K}$. Percentage of $\mathrm{CaCO}_{3}$ that remains unreacted at equilibrium is
(Given, $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )

229331 The equilibrium constant of a reaction is 0.008 at $298 \mathrm{~K}$. The standard free energy change of the reaction at the same temperature is

229332 Assertion: Reaction quotient is defined in the same way as equilibrium constant at any stage of the reaction.
Reason: If $\mathrm{Q}_{\mathrm{c}}$ (reaction quotient) $<\mathrm{K}_{\mathrm{c}}$ (equilibrium constant) reaction moves in direction of reactants.
Objective Chemistry Volume-I

229328 For the process, $\frac{3}{2} \mathrm{~A} \rightarrow \mathrm{B}$, at $298 \mathrm{~K}, \Delta \mathrm{G}^{0}$ is $163 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The composition of the reaction mixture is $[\mathrm{B}]=1$ and $[A]=10000$. Predict the direction of the reaction and the relation between reaction quotient $(Q)$ and he equilibrium constant $(K)$

229329 In the $\ln K$ vs. $\frac{1}{T}$ plot of a chemical process having $\Delta S^{0}>0$ and $\Delta H^{0}<0$ the slope is proportional to (where $K$ is equilibrium constant)

229330 For the equilibrium,
$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})$;
$\mathrm{K}_{\mathrm{p}}=1.64 \mathrm{~atm}$ at $1000 \mathrm{~K}$
$50 \mathrm{~g}$ of $\mathrm{CaCO}_{3}$ in a $10 \mathrm{~L}$ closed vessel is heated to $1000 \mathrm{~K}$. Percentage of $\mathrm{CaCO}_{3}$ that remains unreacted at equilibrium is
(Given, $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )

229331 The equilibrium constant of a reaction is 0.008 at $298 \mathrm{~K}$. The standard free energy change of the reaction at the same temperature is

229332 Assertion: Reaction quotient is defined in the same way as equilibrium constant at any stage of the reaction.
Reason: If $\mathrm{Q}_{\mathrm{c}}$ (reaction quotient) $<\mathrm{K}_{\mathrm{c}}$ (equilibrium constant) reaction moves in direction of reactants.
Objective Chemistry Volume-I

229328 For the process, $\frac{3}{2} \mathrm{~A} \rightarrow \mathrm{B}$, at $298 \mathrm{~K}, \Delta \mathrm{G}^{0}$ is $163 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The composition of the reaction mixture is $[\mathrm{B}]=1$ and $[A]=10000$. Predict the direction of the reaction and the relation between reaction quotient $(Q)$ and he equilibrium constant $(K)$

229329 In the $\ln K$ vs. $\frac{1}{T}$ plot of a chemical process having $\Delta S^{0}>0$ and $\Delta H^{0}<0$ the slope is proportional to (where $K$ is equilibrium constant)

229330 For the equilibrium,
$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})$;
$\mathrm{K}_{\mathrm{p}}=1.64 \mathrm{~atm}$ at $1000 \mathrm{~K}$
$50 \mathrm{~g}$ of $\mathrm{CaCO}_{3}$ in a $10 \mathrm{~L}$ closed vessel is heated to $1000 \mathrm{~K}$. Percentage of $\mathrm{CaCO}_{3}$ that remains unreacted at equilibrium is
(Given, $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )

229331 The equilibrium constant of a reaction is 0.008 at $298 \mathrm{~K}$. The standard free energy change of the reaction at the same temperature is

229332 Assertion: Reaction quotient is defined in the same way as equilibrium constant at any stage of the reaction.
Reason: If $\mathrm{Q}_{\mathrm{c}}$ (reaction quotient) $<\mathrm{K}_{\mathrm{c}}$ (equilibrium constant) reaction moves in direction of reactants.
Objective Chemistry Volume-I

229328 For the process, $\frac{3}{2} \mathrm{~A} \rightarrow \mathrm{B}$, at $298 \mathrm{~K}, \Delta \mathrm{G}^{0}$ is $163 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The composition of the reaction mixture is $[\mathrm{B}]=1$ and $[A]=10000$. Predict the direction of the reaction and the relation between reaction quotient $(Q)$ and he equilibrium constant $(K)$

229329 In the $\ln K$ vs. $\frac{1}{T}$ plot of a chemical process having $\Delta S^{0}>0$ and $\Delta H^{0}<0$ the slope is proportional to (where $K$ is equilibrium constant)

229330 For the equilibrium,
$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})$;
$\mathrm{K}_{\mathrm{p}}=1.64 \mathrm{~atm}$ at $1000 \mathrm{~K}$
$50 \mathrm{~g}$ of $\mathrm{CaCO}_{3}$ in a $10 \mathrm{~L}$ closed vessel is heated to $1000 \mathrm{~K}$. Percentage of $\mathrm{CaCO}_{3}$ that remains unreacted at equilibrium is
(Given, $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )

229331 The equilibrium constant of a reaction is 0.008 at $298 \mathrm{~K}$. The standard free energy change of the reaction at the same temperature is

229332 Assertion: Reaction quotient is defined in the same way as equilibrium constant at any stage of the reaction.
Reason: If $\mathrm{Q}_{\mathrm{c}}$ (reaction quotient) $<\mathrm{K}_{\mathrm{c}}$ (equilibrium constant) reaction moves in direction of reactants.
Objective Chemistry Volume-I

229328 For the process, $\frac{3}{2} \mathrm{~A} \rightarrow \mathrm{B}$, at $298 \mathrm{~K}, \Delta \mathrm{G}^{0}$ is $163 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The composition of the reaction mixture is $[\mathrm{B}]=1$ and $[A]=10000$. Predict the direction of the reaction and the relation between reaction quotient $(Q)$ and he equilibrium constant $(K)$

229329 In the $\ln K$ vs. $\frac{1}{T}$ plot of a chemical process having $\Delta S^{0}>0$ and $\Delta H^{0}<0$ the slope is proportional to (where $K$ is equilibrium constant)

229330 For the equilibrium,
$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})$;
$\mathrm{K}_{\mathrm{p}}=1.64 \mathrm{~atm}$ at $1000 \mathrm{~K}$
$50 \mathrm{~g}$ of $\mathrm{CaCO}_{3}$ in a $10 \mathrm{~L}$ closed vessel is heated to $1000 \mathrm{~K}$. Percentage of $\mathrm{CaCO}_{3}$ that remains unreacted at equilibrium is
(Given, $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )

229331 The equilibrium constant of a reaction is 0.008 at $298 \mathrm{~K}$. The standard free energy change of the reaction at the same temperature is

229332 Assertion: Reaction quotient is defined in the same way as equilibrium constant at any stage of the reaction.
Reason: If $\mathrm{Q}_{\mathrm{c}}$ (reaction quotient) $<\mathrm{K}_{\mathrm{c}}$ (equilibrium constant) reaction moves in direction of reactants.
Objective Chemistry Volume-I